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I keep getting this error java.util.NoSuchElementException

I am getting a NoSuchElementException which is probably due to Scanner and I get it after I add a student and go back to the menu.
My main method:
import java.util.ArrayList;
import java.util.Scanner;
public class Main {
static ArrayList<Student> students = new ArrayList<>();
static Scanner scan = new Scanner(System.in);
static Student s = new Student();
public static void main(String[] args) {
menu();
}
public static void menu() {
System.out.println(" ***Students Manage***\n");
System.out.println("1 - Insert a student");
System.out.println("2 - Display students");
System.out.println("3 - Remove student\n");
option();
}
public static void option() {
int option;
do {
System.out.print("Choose an option: ");
option = scan.nextInt();
}while(option < 1 || option > 3);
switch(option) {
case 1:
s.addStudent();
students.add(s);
break;
case 2:
showAllStudents();
}
menu();
}
private static void showAllStudents() {
for(int i = 0; i < students.size(); i++) {
students.get(i).toString();
}
}
}
My Student method:
import java.time.LocalDate;
import java.util.Scanner;
public class Student {
String name;
int studentNumber;
static int count = 1;
int yearNumber;
public Student() {
}
public void addStudent() {
Scanner scan = new Scanner(System.in);
LocalDate year = LocalDate.now();
yearNumber = year.getYear();
studentNumber = count++;
studentNumber += yearNumber * 10000;
System.out.print("Enter the student name: ");
name = scan.nextLine();
if(name == null || name.trim().equals("") || !name.contains(" "))
{
do{
if(name.trim().equals("")){
System.out.print("Please enter a valid name.\nEnter your name: ");
} else if(!name.contains(" ")) {
System.out.print("You should write at least 2 names(name and surname).\nEnter your name: ");
}
name = scan.nextLine();
}while(name == null || name.trim().equals("") || !name.contains(" "));
}
scan.close();
System.out.println("The student "+name+" was added to the student list "
+ "and his/her student number is "+studentNumber);
}
#Override
public String toString(){
return name+" - "+studentNumber;
}
}
The error that I'm getting:
Exception in thread "main" java.util.NoSuchElementException
at java.base/java.util.Scanner.throwFor(Scanner.java:937)
at java.base/java.util.Scanner.next(Scanner.java:1594)
at java.base/java.util.Scanner.nextInt(Scanner.java:2258)
at java.base/java.util.Scanner.nextInt(Scanner.java:2212)
at StudentSchool.Main.option(Main.java:29)
at StudentSchool.Main.menu(Main.java:21)
at StudentSchool.Main.option(Main.java:40)
at StudentSchool.Main.menu(Main.java:21)
at StudentSchool.Main.option(Main.java:40)
at StudentSchool.Main.menu(Main.java:21)
at StudentSchool.Main.main(Main.java:13)

You have two problems in how you're using Scanner. The first is that you are opening a second Scanner on System.in while you have one already open and reading from it. This produces strange results due to buffering. You should create and use only a single Scanner object that you never close. You can do this by passing the Scanner you create in your main() method into your addStudent() method so that it can use that same Scanner instead of creating and later closing a new one. So...
public void addStudent(Scanner scan) {
// Scanner scan = new Scanner(System.in);
....
// scan.close();
....
public static void option() {
....
s.addStudent(scan);
...
When you do this, a second problem will arise. When you mix calls to nextInt and nextLine on a Scanner object, you run into a problem where nextInt only reads the numeric digits from the input stream, but leaves the newline character produce by the user hitting Return. When you then call readLine, it reads that newline that's already on the input stream, so instead of waiting for your input, it reads an empty line as the next result. To avoid this problem, you should add an extra call to readLine right after you call readInt to consume this stray newline character. So...
System.out.print("Choose an option: ");
option = scan.nextInt();
scan.nextLine();
Making these two changes should cause your program to behave as you desire.

How can I change input from integers to characters?

I have tried changing int to String and char but neither seemed to work. Any help is greatly appreciated
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter your phrase: ");
int phrase = input.nextInt();
System.out.println("You entered " + phrase);
// closing the scanner object
input.close();
}
}

Calling the nextInt() method attempts to get the next token as an int. If it is not an int, an InputMismatchException is thrown. If you enter input that can be represented as an int, then you will see your phrase printed.
Try this:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter your phrase: ");
String phrase = input.next();
System.out.println("You entered " + phrase);
// closing the scanner object
input.close();
}
}
next() returns the next complete token as a String.
java.util.Scanner documentation
As Lino has pointed out, if you intend on capturing multiple, seperated words, you can instead use nextLine() instead of next().

using the command line prompt in Java Eclipse [duplicate]

I attempted to create a calculator, but I can not get it to work because I don't know how to get user input.
How can I get the user input in Java?

One of the simplest ways is to use a Scanner object as follows:
import java.util.Scanner;
Scanner reader = new Scanner(System.in); // Reading from System.in
System.out.println("Enter a number: ");
int n = reader.nextInt(); // Scans the next token of the input as an int.
//once finished
reader.close();

You can use any of the following options based on the requirements.
Scanner class
import java.util.Scanner;
//...
Scanner scan = new Scanner(System.in);
String s = scan.next();
int i = scan.nextInt();
BufferedReader and InputStreamReader classes
import java.io.BufferedReader;
import java.io.InputStreamReader;
//...
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s = br.readLine();
int i = Integer.parseInt(s);
DataInputStream class
import java.io.DataInputStream;
//...
DataInputStream dis = new DataInputStream(System.in);
int i = dis.readInt();
The readLine method from the DataInputStream class has been deprecated. To get String value, you should use the previous solution with BufferedReader
Console class
import java.io.Console;
//...
Console console = System.console();
String s = console.readLine();
int i = Integer.parseInt(console.readLine());
Apparently, this method does not work well in some IDEs.

You can use the Scanner class or the Console class
Console console = System.console();
String input = console.readLine("Enter input:");

You can get user input using BufferedReader.
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String accStr;
System.out.println("Enter your Account number: ");
accStr = br.readLine();
It will store a String value in accStr so you have to parse it to an int using Integer.parseInt.
int accInt = Integer.parseInt(accStr);

Here is how you can get the keyboard inputs:
Scanner scanner = new Scanner (System.in);
System.out.print("Enter your name");
String name = scanner.next(); // Get what the user types.

The best two options are BufferedReader and Scanner.
The most widely used method is Scanner and I personally prefer it because of its simplicity and easy implementation, as well as its powerful utility to parse text into primitive data.
Advantages of Using Scanner
Easy to use the Scanner class
Easy input of numbers (int, short, byte, float, long and double)
Exceptions are unchecked which is more convenient. It is up to the programmer to be civilized, and specify or catch the exceptions.
Is able to read lines, white spaces, and regex-delimited tokens
Advantages of BufferedInputStream
BufferedInputStream is about reading in blocks of data rather than a single byte at a time
Can read chars, char arrays, and lines
Throws checked exceptions
Fast performance
Synchronized (you cannot share Scanner between threads)
Overall each input method has different purposes.
If you are inputting large amount of data BufferedReader might be
better for you
If you are inputting lots of numbers Scanner does automatic parsing
which is very convenient
For more basic uses I would recommend the Scanner because it is easier to use and easier to write programs with. Here is a quick example of how to create a Scanner. I will provide a comprehensive example below of how to use the Scanner
Scanner scanner = new Scanner (System.in); // create scanner
System.out.print("Enter your name"); // prompt user
name = scanner.next(); // get user input
(For more info about BufferedReader see How to use a BufferedReader and see Reading lines of Chars)
java.util.Scanner
import java.util.InputMismatchException; // import the exception catching class
import java.util.Scanner; // import the scanner class
public class RunScanner {
// main method which will run your program
public static void main(String args[]) {
// create your new scanner
// Note: since scanner is opened to "System.in" closing it will close "System.in".
// Do not close scanner until you no longer want to use it at all.
Scanner scanner = new Scanner(System.in);
// PROMPT THE USER
// Note: when using scanner it is recommended to prompt the user with "System.out.print" or "System.out.println"
System.out.println("Please enter a number");
// use "try" to catch invalid inputs
try {
// get integer with "nextInt()"
int n = scanner.nextInt();
System.out.println("Please enter a decimal"); // PROMPT
// get decimal with "nextFloat()"
float f = scanner.nextFloat();
System.out.println("Please enter a word"); // PROMPT
// get single word with "next()"
String s = scanner.next();
// ---- Note: Scanner.nextInt() does not consume a nextLine character /n
// ---- In order to read a new line we first need to clear the current nextLine by reading it:
scanner.nextLine();
// ----
System.out.println("Please enter a line"); // PROMPT
// get line with "nextLine()"
String l = scanner.nextLine();
// do something with the input
System.out.println("The number entered was: " + n);
System.out.println("The decimal entered was: " + f);
System.out.println("The word entered was: " + s);
System.out.println("The line entered was: " + l);
}
catch (InputMismatchException e) {
System.out.println("\tInvalid input entered. Please enter the specified input");
}
scanner.close(); // close the scanner so it doesn't leak
}
}
Note: Other classes such as Console and DataInputStream are also viable alternatives.
Console has some powerful features such as ability to read passwords, however, is not available in all IDE's (such as Eclipse). The reason this occurs is because Eclipse runs your application as a background process and not as a top-level process with a system console. Here is a link to a useful example on how to implement the Console class.
DataInputStream is primarily used for reading input as a primitive datatype, from an underlying input stream, in a machine-independent way. DataInputStream is usually used for reading binary data. It also provides convenience methods for reading certain data types. For example, it has a method to read a UTF String which can contain any number of lines within them.
However, it is a more complicated class and harder to implement so not recommended for beginners. Here is a link to a useful example how to implement a DataInputStream.

You can make a simple program to ask for user's name and print what ever the reply use inputs.
Or ask user to enter two numbers and you can add, multiply, subtract, or divide those numbers and print the answers for user inputs just like a behavior of a calculator.
So there you need Scanner class. You have to import java.util.Scanner; and in the code you need to use
Scanner input = new Scanner(System.in);
Input is a variable name.
Scanner input = new Scanner(System.in);
System.out.println("Please enter your name : ");
s = input.next(); // getting a String value
System.out.println("Please enter your age : ");
i = input.nextInt(); // getting an integer
System.out.println("Please enter your salary : ");
d = input.nextDouble(); // getting a double
See how this differs: input.next();, i = input.nextInt();, d = input.nextDouble();
According to a String, int and a double varies same way for the rest. Don't forget the import statement at the top of your code.
Also see the blog post "Scanner class and getting User Inputs".

To read a line or a string, you can use a BufferedReader object combined with an InputStreamReader one as follows:
BufferedReader bufferReader = new BufferedReader(new InputStreamReader(System.in));
String inputLine = bufferReader.readLine();

Here, the program asks the user to enter a number. After that, the program prints the digits of the number and the sum of the digits.
import java.util.Scanner;
public class PrintNumber {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int num = 0;
int sum = 0;
System.out.println(
"Please enter a number to show its digits");
num = scan.nextInt();
System.out.println(
"Here are the digits and the sum of the digits");
while (num > 0) {
System.out.println("==>" + num % 10);
sum += num % 10;
num = num / 10;
}
System.out.println("Sum is " + sum);
}
}

Here is your program from the question using java.util.Scanner:
import java.util.Scanner;
public class Example {
public static void main(String[] args) {
int input = 0;
System.out.println("The super insano calculator");
System.out.println("enter the corrosponding number:");
Scanner reader3 = new Scanner(System.in);
System.out.println(
"1. Add | 2. Subtract | 3. Divide | 4. Multiply");
input = reader3.nextInt();
int a = 0, b = 0;
Scanner reader = new Scanner(System.in);
System.out.println("Enter the first number");
// get user input for a
a = reader.nextInt();
Scanner reader1 = new Scanner(System.in);
System.out.println("Enter the scend number");
// get user input for b
b = reader1.nextInt();
switch (input){
case 1: System.out.println(a + " + " + b + " = " + add(a, b));
break;
case 2: System.out.println(a + " - " + b + " = " + subtract(a, b));
break;
case 3: System.out.println(a + " / " + b + " = " + divide(a, b));
break;
case 4: System.out.println(a + " * " + b + " = " + multiply(a, b));
break;
default: System.out.println("your input is invalid!");
break;
}
}
static int add(int lhs, int rhs) { return lhs + rhs; }
static int subtract(int lhs, int rhs) { return lhs - rhs; }
static int divide(int lhs, int rhs) { return lhs / rhs; }
static int multiply(int lhs, int rhs) { return lhs * rhs; }
}

Scanner input = new Scanner(System.in);
String inputval = input.next();

Scanner input=new Scanner(System.in);
int integer=input.nextInt();
String string=input.next();
long longInteger=input.nextLong();

Just one extra detail. If you don't want to risk a memory/resource leak, you should close the scanner stream when you are finished:
myScanner.close();
Note that java 1.7 and later catch this as a compile warning (don't ask how I know that :-)

Here is a more developed version of the accepted answer that addresses two common needs:
Collecting user input repeatedly until an exit value has been entered
Dealing with invalid input values (non-integers in this example)
Code
package inputTest;
import java.util.Scanner;
import java.util.InputMismatchException;
public class InputTest {
public static void main(String args[]) {
Scanner reader = new Scanner(System.in);
System.out.println("Please enter integers. Type 0 to exit.");
boolean done = false;
while (!done) {
System.out.print("Enter an integer: ");
try {
int n = reader.nextInt();
if (n == 0) {
done = true;
}
else {
// do something with the input
System.out.println("\tThe number entered was: " + n);
}
}
catch (InputMismatchException e) {
System.out.println("\tInvalid input type (must be an integer)");
reader.nextLine(); // Clear invalid input from scanner buffer.
}
}
System.out.println("Exiting...");
reader.close();
}
}
Example
Please enter integers. Type 0 to exit.
Enter an integer: 12
The number entered was: 12
Enter an integer: -56
The number entered was: -56
Enter an integer: 4.2
Invalid input type (must be an integer)
Enter an integer: but i hate integers
Invalid input type (must be an integer)
Enter an integer: 3
The number entered was: 3
Enter an integer: 0
Exiting...
Note that without nextLine(), the bad input will trigger the same exception repeatedly in an infinite loop. You might want to use next() instead depending on the circumstance, but know that input like this has spaces will generate multiple exceptions.

import java.util.Scanner;
class Daytwo{
public static void main(String[] args){
System.out.println("HelloWorld");
Scanner reader = new Scanner(System.in);
System.out.println("Enter the number ");
int n = reader.nextInt();
System.out.println("You entered " + n);
}
}

Add throws IOException beside main(), then
DataInputStream input = new DataInputStream(System.in);
System.out.print("Enter your name");
String name = input.readLine();

It is very simple to get input in java, all you have to do is:
import java.util.Scanner;
class GetInputFromUser
{
public static void main(String args[])
{
int a;
float b;
String s;
Scanner in = new Scanner(System.in);
System.out.println("Enter a string");
s = in.nextLine();
System.out.println("You entered string " + s);
System.out.println("Enter an integer");
a = in.nextInt();
System.out.println("You entered integer " + a);
System.out.println("Enter a float");
b = in.nextFloat();
System.out.println("You entered float " + b);
}
}

import java.util.Scanner;
public class Myapplication{
public static void main(String[] args){
Scanner in = new Scanner(System.in);
int a;
System.out.println("enter:");
a = in.nextInt();
System.out.println("Number is= " + a);
}
}

You can get user input like this using a BufferedReader:
InputStreamReader inp = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(inp);
// you will need to import these things.
This is how you apply them
String name = br.readline();
So when the user types in his name into the console, "String name" will store that information.
If it is a number you want to store, the code will look like this:
int x = Integer.parseInt(br.readLine());
Hop this helps!

Can be something like this...
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
System.out.println("Enter a number: ");
int i = reader.nextInt();
for (int j = 0; j < i; j++)
System.out.println("I love java");
}

You can get the user input using Scanner. You can use the proper input validation using proper methods for different data types like next() for String or nextInt() for Integer.
import java.util.Scanner;
Scanner scanner = new Scanner(System.in);
//reads the input until it reaches the space
System.out.println("Enter a string: ");
String str = scanner.next();
System.out.println("str = " + str);
//reads until the end of line
String aLine = scanner.nextLine();
//reads the integer
System.out.println("Enter an integer num: ");
int num = scanner.nextInt();
System.out.println("num = " + num);
//reads the double value
System.out.println("Enter a double: ");
double aDouble = scanner.nextDouble();
System.out.println("double = " + aDouble);
//reads the float value, long value, boolean value, byte and short
double aFloat = scanner.nextFloat();
long aLong = scanner.nextLong();
boolean aBoolean = scanner.nextBoolean();
byte aByte = scanner.nextByte();
short aShort = scanner.nextShort();
scanner.close();

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
System.out.println("Welcome to the best program in the world! ");
while (true) {
System.out.print("Enter a query: ");
Scanner scan = new Scanner(System.in);
String s = scan.nextLine();
if (s.equals("q")) {
System.out.println("The program is ending now ....");
break;
} else {
System.out.println("The program is running...");
}
}
}
}

This is a simple code that uses the System.in.read() function. This code just writes out whatever was typed. You can get rid of the while loop if you just want to take input once, and you could store answers in a character array if you so choose.
package main;
import java.io.IOException;
public class Root
{
public static void main(String[] args)
{
new Root();
}
public Root()
{
while(true)
{
try
{
for(int y = 0; y < System.in.available(); ++y)
{
System.out.print((char)System.in.read());
}
}
catch(IOException ex)
{
ex.printStackTrace(System.out);
break;
}
}
}
}

I like the following:
public String readLine(String tPromptString) {
byte[] tBuffer = new byte[256];
int tPos = 0;
System.out.print(tPromptString);
while(true) {
byte tNextByte = readByte();
if(tNextByte == 10) {
return new String(tBuffer, 0, tPos);
}
if(tNextByte != 13) {
tBuffer[tPos] = tNextByte;
++tPos;
}
}
}
and for example, I would do:
String name = this.readLine("What is your name?")

Keyboard entry using Scanner is possible, as others have posted. But in these highly graphic times it is pointless making a calculator without a graphical user interface (GUI).
In modern Java this means using a JavaFX drag-and-drop tool like Scene Builder to lay out a GUI that resembles a calculator's console.
Note that using Scene Builder is intuitively easy and demands no additional Java skill for its event handlers that what you already may have.
For user input, you should have a wide TextField at the top of the GUI console.
This is where the user enters the numbers that they want to perform functions on.
Below the TextField, you would have an array of function buttons doing basic (i.e. add/subtract/multiply/divide and memory/recall/clear) functions.
Once the GUI is lain out, you can then add the 'controller' references that link each button function to its Java implementation, e.g a call to method in your project's controller class.
This video is a bit old but still shows how easy Scene Builder is to use.

The most simple way to get user input would be to use Scanner. Here's an example of how it's supposed to be used:
import java.util.Scanner;
public class main {
public static void main(String[]args) {
Scanner sc=new Scanner(System.in);
int a;
String b;
System.out.println("Type an integer here: ");
a=sc.nextInt();
System.out.println("Type anything here:");
b=sc.nextLine();
The line of code import java.util.Scanner; tells the program that the programmer will be using user inputs in their code. Like it says, it imports the scanner utility. Scanner sc=new Scanner(System.in); tells the program to start the user inputs. After you do that, you must make a string or integer without a value, then put those in the line a=sc.nextInt(); or a=sc.nextLine();. This gives the variables the value of the user inputs. Then you can use it in your code. Hope this helps.

Using JOptionPane you can achieve it.
Int a =JOptionPane.showInputDialog(null,"Enter number:");

import java.util.Scanner;
public class userinput {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Name : ");
String name = input.next();
System.out.print("Last Name : ");
String lname = input.next();
System.out.print("Age : ");
byte age = input.nextByte();
System.out.println(" " );
System.out.println(" " );
System.out.println("Firt Name: " + name);
System.out.println("Last Name: " + lname);
System.out.println(" Age: " + age);
}
}

class ex1 {
public static void main(String args[]){
int a, b, c;
a = Integer.parseInt(args[0]);
b = Integer.parseInt(args[1]);
c = a + b;
System.out.println("c = " + c);
}
}
// Output
javac ex1.java
java ex1 10 20
c = 30

How can I delay the execution of a command? [duplicate]

This question already has answers here:
How to use java.util.Scanner to correctly read user input from System.in and act on it?
(1 answer)
How to use scanner in java? [duplicate]
(7 answers)
Closed 7 years ago.
I have to say I am a newbie in java programming so I would like some help with the following question:
How can I delay a java program so that it waits for a user to give an input?
Here is my code:
import java.util.Scanner;
public class test {
public static void main(String[] args) {
System.out.println("1st value= ");
Scanner aa1 = new Scanner(System.in);
System.out.println("2nd value= ");
Scanner bb1 = new Scanner(System.in);
What I get now from this code is "1st value= " and "2nd value= " displayed. After that the program requests the input.
Any ideas on how can I make this simple programm to wait for the user's answer before printing "2nd value= " in the console?

Ask for input from the user:
int index = aa1.nextInt();

You don't need to create two Scanner variables. You can use one of them and use the function input.nextInt(); to get both values, where input it's the name of the Scanner variable.
import java.util.Scanner;
public class test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int number1, number2;
System.out.println("1st value= ");
number1 = input.nextInt();
System.out.println("2nd value= ");
number2 = input.nextInt();
}
}

You must first import the Scanner before your Main class.
import java.util.Scanner;
You must then create a Scanner variable. I use "in" in my example:
Scanner in = new Scanner(System.in);
This will force the program to wait for user input.
` import java.util.Scanner;
public class Example{
public static void main( String[] args )
{
String name;
String address;
String cityStateZip;
Scanner in = new Scanner(System.in);
//User input
System.out.println("What is your name?");
name = in.nextLine();
System.out.println("Enter your address:");
address = in.nextLine();
System.out.println("Enter your City, State, and Zip code:");
cityStateZip = in.nextLine();`

You have to use only one Scanner variable. This is the solution :
import java.util.Scanner;
import java.util.*;
public class test {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String str = sc.nextLine();
System.out.println("1st value= " + str);
str = sc.nextLine();
System.out.println("2nd value= " + str);
}
}
You can see the different next***() on the doc on this link http://docs.oracle.com/javase/7/docs/api/java/util/Scanner.html.
I advise you to follow a Java formation if you want to code in this language.

You can use it as:
import java.util.Scanner;
public class test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("1st value= "
+ input.nextInt()
+ "2nd value= "
+ input.nextInt());
}
For further reference to can go through Scanner java doc http://docs.oracle.com/javase/7/docs/api/java/util/Scanner.html

Add necessary imports by pressing control+shift+o after you have typed the main function.
public static void main(String agrs[])
{
// Take Scanner object
Scanner scanner =new Scanner(System.in);
// Ask user for 1st input
System.out.println("Enter 1st value:");
String value=scanner.nextLine();
System.out.println("1st value is ="+s);
// Ask user for 2nd input
System.out.println("Enter 2nd value:");
value=scanner.nextLine();
System.out.println("2nd value is ="+s);
}
NOTE : scanner.nextLine() will read the user input as a String,
If you need the input as int , use scanner.nextInt(); For float use scanner.nextFloat() and so on.
Now the console is halted for user input and then asks for second input.
Hope it helps.

In Java Program Scanner is Working only once whereas i/ve used it twice

import java.util.Scanner;
class Student1{
int a;
String b;
void get(int c, String d){
a = c;
b = d;
}
void show(){
System.out.print("Id is " + a +"\n");
System.out.print("Name is " + b);
}
public static void main(String args[]){
Scanner one = new Scanner(System.in);
System.out.print("Enter Id");
int e = one.nextInt();
System.out.print("Enter Your Name");
String f = one.nextLine();
Student1 s = new Student1();
s.get(e ,f);
s.show();
}
}
when the program is executed it only asks for Id after that it shows result it never asks for Name

it gets complicated when you use nextInt() and nextLine() together. you can try this version which only uses nextLine();
public static void main(String args[]){
Scanner one = new Scanner(System.in);
System.out.print("Enter Id");
String number =one.nextLine();
int e = Integer.parseInt(number);
System.out.print("Enter Your Name");
String f = one.nextLine();
Student1 s = new Student1();
s.get(e ,f);
s.show();
}
why nextInt() and nextline() produce some problems:
Scanner is skipping nextLine() after using next(), nextInt() or other nextFoo() methods

You must be entering a newline after integer. For that that blank string is acting as input for one.nextLine(). To avoid that one way is to add one more one.nextLine() statement before String f = one.nextLine();

Use only nextLine() method and the change the below lines of your code too for efficient
Student1 s = new Student1();
s.get(e ,f);
create constructor for Student1 class
Student1(int c, String d)
{
a = c;
b = d;
}
Inside main() method
Student1 s = new Student1(e,f);
You can initialize the variables at the time of creating object by using constructor.