I want a list of .tar.gz files from a specified directory. For this I am running "ls directory_path/*.tar.gz" using getRuntime.exec() in Java. But it is not giving any output rather it is saying No such file or directory..
But the same command is running on command prompt..
I am running java in unix.
Thanks in advance
This is because exec won't launch a shell just to run your program. It just starts a process. On Unix-like systems the shell is responsible for expanding wildcards to lists of files. So you would need to run ls through a shell to get the desired behaviour.
However, why do you use ls at all? This answer shows how to get a list of files with Java.
1. You will be able to fire processes using the exec() not the command promt..
2. Better use list() to get the names of all the files in a directory, and then use FileFilter to get the .tar.gz files.
Related
I want my directory to give executable permissions (by default) to all the shell scripts which are going to be created in that directory after I run my Java program. I tried the following commands:
setfacl -d -m group:name:rwx /path/to/your/dir
find ./ -name "*.sh" -exec chmod +x {} \;
The first one is not showing any response while the second one works fine but I have to execute this command manually in terminal after my Java program has created all the scripts. This is not what i seek. I want this thing to be automatic. Here is what I am trying to achieve:
My Java program creates the .sh files in a directory.
Now the program would try to execute this script file.
Here is a Java code snippet which shows how it is going to execute the script files:
ExecuteShellComand obj = new ExecuteShellComand();
String command2 = "./script.sh";
String output2 = obj.executeCommand(command2);
It doesn't run unless I give the executable permissions to the script.sh. How do I do it? Is there any way around it? If I am not doing something in a way it should be done, feel free to give your suggestions. Thanks
Default ACL permissions are masked by the file's creation mode as specified in open and mkdir syscalls.
Since files are usually created with a default mode of 0666, execute permissions will be masked instead of inherited.
It's the responsibility of the program that creates the files to create them with the right permissions. If you set the permissions correctly when creating the scripts, you won't need ACL or chmod at all. The best way to fix this would be for your program to set the mode in the open call to 0777.
Java appears to have Files.createFile for this. Additionally, you have a more fuzzy File.setExecutable to do it after the fact, which is not Unix canonical behavior, but probably fine for your use case.
I have a Main.java file and I want to run the program passing it test.txt
I know in command line I can write javac Main.java
After compiling I can write java Main test.txt and this will accomplish running the file and passing test.txt
If I wanted instead to be able to just write main test.txt and have that trigger my Main.class file to run is that possible and if so how?
(Edit: Based on your comment, let me expand to add a couple more situations)
If your goal is to have someone else run your program who does not have Java installed, and you do not wish to have them install a Java runtime environment before running your app, what you need is a program that converts the .class or .jar files into a native executable for the platform you are using. How to do this has been covered in other questions, eg: Compiling a java program into an executable . Essentially, you use a program like JCG (GNU Compiler for Java) or Excelsior JET (a commercial product) to expand the byte code into full native code with a mini-JRE built in.
If your goal is to save typing, there are a number of strategies. Others have suggested alias commands, which work well on linux.
A slightly more portable option that you could ship with your program would be a shell script. Granted, shell scripts only run on linux or other OS's with shell script interpreters installed.
Here is an example shell script. You paste this into a text editor and save it as main with no extensio. The $1 passes the parameter argument fyi.
#!/bin/sh
java Main $1
presuming you name your shell script just "main" with no extension, you could call main test.txt to execute your program now.
If you are on Windows, you might want to create a windows shortcut, and point the shortcut to "java Main test.text", using the full paths if necessary (if the paths are not already set). Of course, this does not make the parameter easy to change every time you run it, you would have to edit the shortcut.
add an alias
e.g. under a mac edit your .bash_profile with the following line
alias main='java main'
don't forget to open a new console to see your alias working
Depends on your operating system. On Linux with the bash shell, for instance, you can set up an alias to expand your main into java -cp myjar.jar main.
Linux can also be configured to 'understand' Java class flies as a binary format directly see here (linux kernel documentation).
If you're on windows, you'll have to wait for answer from someone with more knowledge about that than I.
Good luck!
everyone. I'm quite new here so please be tolerant if I make any mistakes.
I have a .bat file containing a command line to open up a .jar file that contains a program that has a GUI in it. The only line that's in the .bat file is:
java -jar "NewServer.jar"
I've been trying to use Runtime() to get this to run, but most the instructions I find to open a .bat file in a java program are for Windows. I'm currently using Fedora 12 (don't tell me to upgrade, I can't) if that makes a difference and programming using Eclipse. I also found this ProcessBuilder thing, but I couldn't get it to work so unless you have very explicit directions on how to use it, please don't include it in your answer. I would much rather use Runtime. It looked simpler.
Here's my code to test using Runtime in a java program. I'm hoping that if I can get this to work, I can get it to work in my real program.
import java.io.IOException;
public class testbat {
public static void main(String[] args) {
Process proc = null;
try {
proc = Runtime.getRuntime().exec("./ myServer.bat");
} catch (IOException e) {
e.printStackTrace();
}
System.out.println("Cool");
}
The last line is just there for me to see if the program actually ran in case the GUI doesn't open. Also, I've already tried many combinations of things to include in the area after ".exec". I've tried using a path like "~/user/workspace/ProjectServer/dist/myServer.bat" to no avail.
I also already know that .bat files are for windows, but I'm able to execute it in linux, so I don't know if that makes a difference. I also tried using a .sh file the same way and it didn't work.
Please bear in mind that I'm not that great at Java, but I had to use it for this particular program, so if your answers could be really descriptive that would be awesome.
Just take that line out of the bat file, and run it. Yo're making it too hard.
$ java -jar "NewServer.jar"
will work. The quotes aren't necessary, so
$ java -jar NewServer.jar
will work as well. If you want to have the equivalent of your bat file, create a file named, say, run_newserver containing that line. Change its mode to executable:
$ cat > run_newserver
java -jar NewServer.jar
^D
$ chmod a+x run_newserver
$ ./run_newserver
Ideally, since you shouldn't have scripts without comments, do this. In your favorite editor, create a file run_newserver containing
#!/usr/bin/env bash
java -jar NewServer.jar
and chmod that. The line with #! -- often called a "shebang line" -- is UNIX magic that lets you say what interpreter you want. The program env in usr/bin finds your program and runs it (needed because different systems put bash in different directories.)
You could even put explanatory comments in the file too.
I'm a little unclear why you want to use Runtime#exec to run it at all -- it seems you'll just need a shell script to start that program.
Why are you using Java to run a Batch file, that in turn runs a Java program? Why have Batch in the loop at all? Just put the jar in your classpath and call it directly.
Batch (.bat) files are only for Windows environment. So, Try using shell script
Process proc = Runtime.getRuntime().exec("myServer.sh");
Just open up terminal and do this
vi /dir/to/exec/exec.sh
tap "i" and write this
#!/bin/sh
java -jar "NewServer.jar"
or if you want to run it in the background
#!/bin/sh
java -jar "NewServer.jar" & > /tmp/JavaServer.log
hit esc and type ":wq" and you have saved the file.
type this into the terminal
chmod +x /dir/to/exec/exec.sh
this give executable privileges and then you should run the file like
sh /dir/to/exec/exec.sh
Process is only initialized by your first call. You need to run:
proc.waitfor();
to get it to actually run your app.
I'm using a bat file to run my jar. The code in my bat file is this :
#echo off
java -cp analyser.jar be.model.Start
pause
This works fine for windows.
But it doesn't do anything at linux. I also need to be sure it will run on Mac
Bat files are specific to Windows. You would need to execute the command in Linux and Mac in a manner that is specific to those platforms. The actual java call should work the same, I believe. The one change to the java line would be if you had multiple items in the classpath. In that case, you would need to use a colon as a separator instead of a semicolon (which is what Windows uses). (Thanks to khachik for that tip)
For Linux, you would use Shell programming using a BASH script. Here is a link that will describe what you need to do:
http://www.tldp.org/HOWTO/Bash-Prog-Intro-HOWTO.html
For Mac, you would probably use an AppleScript. Here is an article on how to get started with AppleScripts:
http://www.macosxautomation.com/applescript/firsttutorial/index.html
For Linux, why not use a .sh (shell) file?
As Biggs~ alreay said, the actual Java call should remain the same.
Update:
You will also have to make it executable by changing it's user permissions. To do this, use: chmod +x thescript.sh
I am trying to run a perl command with Java runtime exec in linux/ubuntu/gnome. The command generates an pdf file, but it saves it in my home folder. Is there any way that the exec method can set an output path for the commands executed? Thanks in advance.
The exec method just runs the command on the operating system, so you'll want to change the command you're running with exec more than anything in "Java" per se.
There are a few possibilities:
Change the working directory of your java program. The .pdf is being saved in your working directory because this is where the program is being run.
Unfortunately it's not simple to change this value after the program has been launched. It is, however, trivial to change before the program starts; just change the working directory before starting the program.
Move the file to it's desired location after it's been created in your home directory.
Change the command so that it includes the target location. Your perl script may have an option that will enable you to save it's output to a certain location (usually -o or --output). Using this your program would change from:
Runtime.exec("perl someprogram");
to something like:
Runtime.exec("perl someprogram -o /path/to/some.file")
You might be able to use "output redirection", if there is no option to do this.
Try something like what's below as your argument:
Runtime.exec("perl someprogram > /path/to/some.file")
Unfortunately, without knowing more details of your situation I can't provide more concrete advice.
While each approach has benefits and drawbacks, it's probably best to just implement the one that you understand best; if you can't get one to work, try another.
A good, free online resource for learning is Introduction to Linux: A Hands On Guide.
Section 2.2 has details on cd which you can use for 1..
Section 3.3, section 3 teaches about the mv command, which will be useful in 2..
Section 5.1 is about I/O redirection. Knowing about "output redirection" and the > operator, are important for 4..
For 3., you'll have to consult the documentation of the perl program you're using.
You could modify the Perl script to accept an absolute path for the output.
You can trying setting the working directory using exec(java.lang.String[], java.lang.String[], java.io.File) where File is the directory the command is executed from.
If all else fails, you'll can always copy the generated file from the Home directory to your final location.