No Java implementations for arrayset - java

How come Java provides several different implementations of the Set type, including HashSet and TreeSet and not ArraySet?

A set based solely on an array of elements in no particular order would always have O(n) time for a containment check. It wouldn't be terribly useful, IMO. When would you want to use that instead of HashSet or TreeSet?
The most useful aspect of an array is that you can get to an element with a particular index extremely quickly. That's not terribly relevant when it comes to sets.

There is CopyOnWriteArraySet which is a set backed by an array.
This is not particularly useful as its performance is not great for large collections.

Android has android.util.ArraySet (introduced in API level 23) and android.util.ArrayMap (introduced in API level 19).

Actually the concrete implementation of Set does not make any sense. Any set stores elements and guaranties their uniqueness.
I cannot be sure but it sounds that you want Set implementation that preserves order of elements. If I am right use LinkedHashSet.

Java provides multiple implementations of its Collection Interfaces that allow for best performance. ArrayList performs good on many List operations.
For Set Operations, which allways require uniquness different implementations offer better performance. If implemented using an array, any modification operation would have to run through all the array elements to check if it is allready in the Set. HashSet and TreeSet simplyfy this check greatly.

The Set interface has no get-by-index method, such as List.get(int), so there's no use suggesting Set can have array like properties.
Ultimately, all "grouping" classes use arrays under the hood to store their elements, but that doesn't mean you have to expose methods for accessing the array.

You can always implement it yourself....now granted there probably is only one extremely, extremely limited case where it would be useful(and in that case you could use better data structures anyway) and that is where you have a very large set that almost never changes then an array set would take up SLIGHTLY less memory(no extra pointers) and you would have ever so slightly faster enumeration of the whole set... If you keep the array sorted then you can still get O(lg n) search time.
However those differences are purely academic. In the real world you would never really want such a beast

Consider indexed-tree-map , you will be able to access elements by index and get index of elements while keeping the sort order. Duplicates can be put into arrays as values under the same key.

Related

Highest and lowest elements in trove TIntSet?

TIntSet is "sorted set" by sense, i.e. it's elements have natural order.
Unfortunately, I can't find any methods similar to first() and last().
Is it possible to overcome this lack somehow?
fastutil is all ways better than Trove. There is IntSortedSet interface with firstInt() and lastInt() methods.
TIntSet is not sorted (it's a hash set) so in order to find the min or max you would need to iterate all values.
Why do you think this set is sorted? It looks like it's not. It doesn't implement SortedSet or NavigableSet interfaces from JDK collections framework - there are no such methods there.
first() and last() methods are actually inherited from interface SortedSet https://docs.oracle.com/javase/7/docs/api/java/util/SortedSet.html#first%28%29
If you want first/last/cell/floor etc type of option then Tree based set is required and trove does not have anything like that. If you want to extend TIntSet to have such thing then
one of the simple option can be maintaining sorted values in parallel int array and use that to serve first/last type of request, but this will required extra memory.
another option is that you can use just one array for values but keep is sorted and use binary search to support map API. This can be little slow for get/put as compared to trove but you can save memory because trove has .5 loadfactor
So you can make decision based on trade off you want .

Sorting a List in parallel without creating a temporary array in Java 8

Java 8 provides java.util.Arrays.parallelSort, which sorts arrays in parallel using the fork-join framework. But there's no corresponding Collections.parallelSort for sorting lists.
I can use toArray, sort that array, and store the result back in my list, but that will temporarily increase memory usage, which if I'm using parallel sorting is already high because parallel sorting only pays off for huge lists. Instead of twice the memory (the list plus parallelSort's working memory), I'm using thrice (the list, the temporary array and parallelSort's working memory). (Arrays.parallelSort documentation says "The algorithm requires a working space no greater than the size of the original array".)
Memory usage aside, Collections.parallelSort would also be more convenient for what seems like a reasonably common operation. (I tend not to use arrays directly, so I'd certainly use it more often than Arrays.parallelSort.)
The library can test for RandomAccess to avoid trying to e.g. quicksort a linked list, so that can't a reason for a deliberate omission.
How can I sort a List in parallel without creating a temporary array?
There doesn't appear to be any straightforward way to sort a List in parallel in Java 8. I don't think this is fundamentally difficult; it looks more like an oversight to me.
The difficulty with a hypothetical Collections.parallelSort(list, cmp) is that the Collections implementation knows nothing about the list's implementation or its internal organization. This can be seen by examining the Java 7 implementation of Collections.sort(list, cmp). As you observed, it has to copy the list elements out to an array, sort them, and then copy them back into the list.
This is the big advantage of the List.sort(cmp) extension method over Collections.sort(list, cmp). It might seem that this is merely a small syntactic advantage being able to write myList.sort(cmp) instead of Collections.sort(myList, cmp). The difference is that myList.sort(cmp), being an interface extension method, can be overridden by the specific List implementation. For example, ArrayList.sort(cmp) sorts the list in-place using Arrays.sort() whereas the default implementation implements the old copyout-sort-copyback technique.
It should be possible to add a parallelSort extension method to the List interface that has similar semantics to List.sort but does the sorting in parallel. This would allow ArrayList to do a straightforward in-place sort using Arrays.parallelSort. (It's not entirely clear to me what the default implementation should do. It might still be worth it to do copyout-parallelSort-copyback.) Since this would be an API change, it can't happen until the next major release of Java SE.
As for a Java 8 solution, there are a couple workarounds, none very pretty (as is typical of workarounds). You could create your own array-based List implementation and override sort() to sort in parallel. Or you could subclass ArrayList, override sort(), grab the elementData array via reflection and call parallelSort() on it. Of course you could just write your own List implementation and provide a parallelSort() method, but the advantage of overriding List.sort() is that this works on the plain List interface and you don't have to modify all the code in your code base to use a different List subclass.
I think you are doomed to use a custom List implementation augmented with your own parallelSort or else change all your other code to store the big data in Array types.
This is the inherent problem with layers of abstract data types. They're meant to isolate the programmer from details of implementation. But when the details of implementation matter - as in the case of underlying storage model for sort - the otherwise splendid isolation leaves the programmer helpless.
The standard List sort documents provide an example. After the explanation that mergesort is used, they say
The default implementation obtains an array containing all elements in this list, sorts the array, and iterates over this list resetting each element from the corresponding position in the array. (This avoids the n2 log(n) performance that would result from attempting to sort a linked list in place.)
In other words, "since we don't know the underlying storage model for a List and couldn't touch it if we did, we make a copy organized in a known way." The parenthesized expression is based on the fact that the List "i'th element accessor" on a linked list is Omega(n), so the normal array mergesort implemented with it would be a disaster. In fact it's easy to implement mergesort efficiently on linked lists. The List implementer is just prevented from doing it.
A parallel sort on List has the same problem. The standard sequential sort fixes it with custom sorts in the concrete List implementations. The Java folks just haven't chosen to go there yet. Maybe in Java 9.
Use the following:
yourCollection.parallelStream().sorted().collect(Collectors.toList());
This will be parallel when sorting, because of parallelStream(). I believe this is what you mean by parallel sort?
Just speculating here, but I see several good reasons for generic sort algorithms preferring to work on arrays instead of List instances:
Element access is performed via method calls. Despite all the optimizations JIT can apply, even for a list that implements RandomAccess, this probably means a lot of overhead compared to plain array accesses which can be optimized very well.
Many algorithms require copying some fragments of the array to temporary structures. There are efficient methods for copying arrays or their fragments. An arbitrary List instance on the other hand, can't be easily copied. New lists would have to be allocated which poses two problems. First, this means allocating some new objects which is likely more costly than allocating arrays. Second, the algorithm would have to choose what implementation of List should be allocated for this temporary structure. There are two obvious solutions, both bad: either just choose some hard-coded implementation, e.g. ArrayList, but then it could just allocate simple arrays as well (and if we're generating arrays then it's much easier if the soiurce is also an array). Or, let the user provide some list factory object, which makes the code much more complicated.
Related to the previous issue: there is no obvious way of copying a list into another due to how the API is designed. The best the List interface offers is addAll() method, but this is probably not efficient for most cases (think of pre-allocating the new list to its target size vs adding elements one by one which many implementations do).
Most lists that need to be sorted will be small enough for another copy to not be an issue.
So probably the designers thought of CPU efficiency and code simplicity most of all, and this is easily achieved when the API accepts arrays. Some languages, e.g. Scala, have sort methods that work directly on lists, but this comes at a cost and probably is less efficient than sorting arrays in many cases (or sometimes there will probably just be a conversion to and from array performed behind the scenes).
By combining the existing answers I came up with this code.
This works if you are not interested in creating a custom List class and if you don't bother to create a temporary array (Collections.sort is doing it anyway).
This uses the initial list and does not create a new one as in the parallelStream solution.
// Convert List to Array so we can use Arrays.parallelSort rather than Collections.sort.
// Note that Collections.sort begins with this very same conversion, so we're not adding overhead
// in comparaison with Collections.sort.
Foo[] fooArr = fooLst.toArray(new Foo[0]);
// Multithread the TimSort. Automatically fallback to mono-thread when size is less than 8192.
Arrays.parallelSort(fooArr, Comparator.comparingStuff(Foo::yourmethod));
// Refill the List using the sorted Array, the same way Collections.sort does it.
ListIterator<Foo> i = fooLst.listIterator();
for (Foo e : fooArr) {
i.next();
i.set(e);
}

default Collection type

Assume you need to store/retrieve items in a Collection, don't care about ordering, and duplicates are allowed, what type of Collection do you use?
By default, I've always used ArrayList, but I remember reading/hearing somewhere that a Queue implementation may be a better choice. A List allows items to be added/retrieved/removed at arbitrary positions, which incurs a performance penalty. As a Queue does not provide this facility it should in theory be faster when this facility is not required.
I realise that all discussions about performance are somewhat meaningless, the only thing that really matters is measurement. Nevertheless, I'm interested to know what others use for a Collection, when they don't care about ordering, and duplicates are allowed, and why?
"It depends". The question you really need to answer first is "What do I want to use the collection for?"
If you often insert / remove items on one of the ends (beginning, end) a Queue will be better than a ArrayList. However in many cases you create a Collection in order to just read from it. In this case a ArrayList is far more efficient: As it is implemented as an array, you can iterate over it quite efficient (same applies for a LinkedList). However a LinkedList uses references to link single items together. So if you do not need random removals of items (in the middle), a ArrayList is better: An ArrayList will use less memory as the items don't need the storage for the reference to the next/prev item.
To sum it up:
ArrayList = good if you insert once and read often (random access or sequential)
LinkedList = good if you insert/remove often at random positions and read only sequential
ArrayDeque (java6 only) = good if you insert/remove at start/end and read random or sequential
As a default, I tend to prefer LinkedList to ArrayList. Obviously, I use them not through the List interface, but rather through the Collection interface.
Over the time, I've indeed found out that when I need a generic collection, it's more or less to put some things in, then iterate over it. If I need more evolved behaviour (say random access, sorting or unicity checks), I will then maybe change the used implementation, but before that I will change the used interface to the most appropriated. This way, I can ensure feature is provided before to concentrate on optimization and implementation.
ArrayList basicly contains an array inside (that's why it is called ArrayList). And operations like addd/remove at arbitrary positions are done in a straightforward way, so if you don't use them - there is no harm to performance.
If ordering and duplicates is not a problem and case is only for storing,
I use ArrayList, As it implements all the list operations. Never felt any performance issues with these operations (Never impacted my projects either). Actually using these operations have simple usage & I don't need to care how its managed internally.
Only if multiple threads will be accessing this list I use Vector because its methods are synchronized.
Also ArrayList and Vector are collections which you learn first :).
It depends on what you know about it.
If I have no clue, I tend to go for a linked list, since the penalty for adding/removing at the end is constant. If I have a rough idea of the maximum size of it, I go for an arraylist with the capacity specified, because it is faster if the estimation is good. If I really know the exact size I tend to go for a normal array; although that isn't really a collection type.
I realise that all discussions about performance are somewhat meaningless, the only thing that really matters is measurement.
That's not necessarily true.
If your knowledge of how the application is going to work tells you that certain collections are going to be very large, then it is a good idea to pick the right collection type. But the right collection type depends crucially on how the collections are going to be used; i.e. on the algorithms.
For example, if your application is likely to be dominated by testing if a collection holds a given object, the fact that Collection.contains(Object) is O(N) for both LinkedList<T> and ArrayList<T> might mean that neither is an appropriate collection type. Instead, maybe you should represent the collection as a HashMap<T, Integer>, where the Integer represents the number of occurrences of a T in the "collection". That will give you O(1) testing and removal, at the cost of more space overheads and slower (though still O(1)) insertion.
But the thing to stress is that if you are likely to be dealing with really large collections, there should be no such thing as a "default" collection type. You need to think about the collection in the context of the algorithms. (And the flip side is that if the collections are always going to be small, it probably makes little difference which collection type you pick.)

How expensive is calling size() on List or Map in Java?

How expensive is calling size() on List or Map in Java? or it is better to save size()'s value in a variable if accessed frequently?
The answer is that it depends on the actual implementation class. For some Map and Collection classes, size() is a cheap constant-time operation. For others, it may entail counting the members.
The Java Collections Cheatsheet (V2) is normally a good source for this kind of information, but the host server is currently a bit sick.
The "coderfriendly.com" domain is no more, but I tracked down a copy of the cheat-sheet on scribd.com.
The cost of size() will also be obvious from looking at the source code. (And this is an "implementation detail" that is pretty much guaranteed to not change ... for the standard collection classes.)
FOLLOWUP
Unfortunately, the cheatsheet only documents the complexity of size for queue implementations. I think that's because it is O(1) for all other collections; see #seanizer's answer.
List and Map are interfaces, so it's impossible to say. For the implementations in the Java Standard API, the size is generally kept in a field and thus not performance-relevant.
For most Collections, calling size() is a constant-time operation. There are however some exceptions. One is ConcurrentLinkedQueue. From the Javadoc of the size() method:
Beware that, unlike in most collections, this method is NOT a constant-time operation. Because of the asynchronous nature of these queues, determining the current number of elements requires an O(n) traversal.
So I'm afraid there's no generic answer, you have to check the documentation of the individual collection you are using.
for ArrayList the implementation is like
public int size() {
return lastIndex - firstIndex;
}
So not over head
You can check the source code for detailed info for your required Impl.
Note: The source given is from openjdk
Implement it, then test it. If it is slow, take a closer look.
"Premature optimisation is the root of all evil." - D. Knuth
Also: You should not require certain implementation features, especially if they are black-boxed. What happens if you replace that list with a concurrent list at a later date? What happens if Oracle decides to rewrite List? Will it still be fast? You just don't know.
You don't have to worry much about that. The list implementations keep track of size. The cost of the call is just O(1). If you are very curious, you can read the source code for the implementations of Collection's concrete classes and see the size() method there.
Implementation gets it from a private pre-computed variable so it's not expensive.
No need to store.Its not at all expensive.Check the source of ArrayList and HashMap.
I think some implementations of LinkedList count the total for each call. The call to a method itself can be a little taxing, but only if we're talking about large iterations or driver coding for hardware would that really be an issue.
In either case, if you save it to a local variable, there won't be any problems.

What is the need of collection framework in java?

What is the need of Collection framework in Java since all the data operations(sorting/adding/deleting) are possible with Arrays and moreover array is suitable for memory consumption and performance is also better compared with Collections.
Can anyone point me a real time data oriented example which shows the difference in both(array/Collections) of these implementations.
Arrays are not resizable.
Java Collections Framework provides lots of different useful data types, such as linked lists (allows insertion anywhere in constant time), resizeable array lists (like Vector but cooler), red-black trees, hash-based maps (like Hashtable but cooler).
Java Collections Framework provides abstractions, so you can refer to a list as a List, whether backed by an array list or a linked list; and you can refer to a map/dictionary as a Map, whether backed by a red-black tree or a hashtable.
In other words, Java Collections Framework allows you to use the right data structure, because one size does not fit all.
Several reasons:
Java's collection classes provides a higher level interface than arrays.
Arrays have a fixed size. Collections (see ArrayList) have a flexible size.
Efficiently implementing a complicated data structures (e.g., hash tables) on top of raw arrays is a demanding task. The standard HashMap gives you that for free.
There are different implementation you can choose from for the same set of services: ArrayList vs. LinkedList, HashMap vs. TreeMap, synchronized, etc.
Finally, arrays allow covariance: setting an element of an array is not guaranteed to succeed due to typing errors that are detectable only at run time. Generics prevent this problem in arrays.
Take a look at this fragment that illustrates the covariance problem:
String[] strings = new String[10];
Object[] objects = strings;
objects[0] = new Date(); // <- ArrayStoreException: java.util.Date
Collection classes like Set, List, and Map implementations are closer to the "problem space." They allow developers to complete work more quickly and turn in more readable/maintainable code.
For each class in the Collections API there's a different answer to your question. Here are a few examples.
LinkedList: If you remove an element from the middle of an array, you pay the cost of moving all of the elements to the right of the removed element. Not so with a linked list.
Set: If you try to implement a set with an array, adding an element or testing for an element's presence is O(N). With a HashSet, it's O(1).
Map: To implement a map using an array would give the same performance characteristics as your putative array implementation of a set.
It depends upon your application's needs. There are so many types of collections, including:
HashSet
ArrayList
HashMap
TreeSet
TreeMap
LinkedList
So for example, if you need to store key/value pairs, you will have to write a lot of custom code if it will be based off an array - whereas the Hash* collections should just work out of the box. As always, pick the right tool for the job.
Well the basic premise is "wrong" since Java included the Dictionary class since before interfaces existed in the language...
collections offer Lists which are somewhat similar to arrays, but they offer many more things that are not. I'll assume you were just talking about List (and even Set) and leave Map out of it.
Yes, it is possible to get the same functionality as List and Set with an array, however there is a lot of work involved. The whole point of a library is that users do not have to "roll their own" implementations of common things.
Once you have a single implementation that everyone uses it is easier to justify spending resources optimizing it as well. That means when the standard collections are sped up or have their memory footprint reduced that all applications using them get the improvements for free.
A single interface for each thing also simplifies every developers learning curve - there are not umpteen different ways of doing the same thing.
If you wanted to have an array that grows over time you would probably not put the growth code all over your classes, but would instead write a single utility method to do that. Same for deletion and insertion etc...
Also, arrays are not well suited to insertion/deletion, especially when you expect that the .length member is supposed to reflect the actual number of contents, so you would spend a huge amount of time growing and shrinking the array. Arrays are also not well suited for Sets as you would have to iterate over the entire array each time you wanted to do an insertion to check for duplicates. That would kill any perceived efficiency.
Arrays are not efficient always. What if you need something like LinkedList? Looks like you need to learn some data structure : http://en.wikipedia.org/wiki/List_of_data_structures
Java Collections came up with different functionality,usability and convenience.
When in an application we want to work on group of Objects, Only ARRAY can not help us,Or rather they might leads to do things with some cumbersome operations.
One important difference, is one of usability and convenience, especially given that Collections automatically expand in size when needed:
Collections came up with methods to simplify our work.
Each one has a unique feature:
List- Essentially a variable-size array;
You can usually add/remove items at any arbitrary position;
The order of the items is well defined (i.e. you can say what position a given item goes in in the list).
Used- Most cases where you just need to store or iterate through a "bunch of things" and later iterate through them.
Set- Things can be "there or not"— when you add items to a set, there's no notion of how many times the item was added, and usually no notion of ordering.
Used- Remembering "which items you've already processed", e.g. when doing a web crawl;
Making other yes-no decisions about an item, e.g. "is the item a word of English", "is the item in the database?" , "is the item in this category?" etc.
Here you find use of each collection as per scenario:
Collection is the framework in Java and you know that framework is very easy to use rather than implementing and then use it and your concern is that why we don't use the array there are drawbacks of array like it is static you have to define the size of row at least in beginning, so if your array is large then it would result primarily in wastage of large memory.
So you can prefer ArrayList over it which is inside the collection hierarchy.
Complexity is other issue like you want to insert in array then you have to trace it upto define index so over it you can use LinkedList all functions are implemented only you need to use and became your code less complex and you can read there are various advantages of collection hierarchy.
Collection framework are much higher level compared to Arrays and provides important interfaces and classes that by using them we can manage groups of objects with a much sophisticated way with many methods already given by the specific collection.
For example:
ArrayList - It's like a dynamic array i.e. we don't need to declare its size, it grows as we add elements to it and it shrinks as we remove elements from it, during the runtime of the program.
LinkedList - It can be used to depict a Queue(FIFO) or even a Stack(LIFO).
HashSet - It stores its element by a process called hashing. The order of elements in HashSet is not guaranteed.
TreeSet - TreeSet is the best candidate when one needs to store a large number of sorted elements and their fast access.
ArrayDeque - It can also be used to implement a first-in, first-out(FIFO) queue or a last-in, first-out(LIFO) queue.
HashMap - HashMap stores the data in the form of key-value pairs, where key and value are objects.
Treemap - TreeMap stores key-value pairs in a sorted ascending order and retrieval speed of an element out of a TreeMap is quite fast.
To learn more about Java collections, check out this article.

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