I am a beginner in both Java and PHP
I am working on an app that has 2 part:
Android client(Java) both and PHP server.
I tried many of the available tutorials and read about mistakes users made but failed to succeed in any!
This is one of the tutorials I am using:
Java File
package org.postandget;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;
public class Main extends Activity {
TextView tv;
String text;
#Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
tv = (TextView)findViewById(R.id.textview);
text = "";
try {
postData();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public void postData() throws JSONException{
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/ReceiveLocation.php");
JSONObject json = new JSONObject();
try {
// JSON data:
json.put("name", "Fahmi Rahman");
json.put("position", "sysdev");
JSONArray postjson=new JSONArray();
postjson.put(json);
// Post the data:
httppost.setHeader("json",json.toString());
httppost.getParams().setParameter("jsonpost",postjson);
// Execute HTTP Post Request
System.out.print(json);
HttpResponse response = httpclient.execute(httppost);
// for JSON:
if(response != null)
{
InputStream is = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
text = sb.toString();
}
tv.setText(text);
}catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
}
this is the php file
<?php
include('ConnectionFunctions.php');
Connection();
$json = $_POST['jsonpost'];
echo "JSON: \n";
echo "--------------\n";
var_dump($json);
echo "\n\n";
$data = json_decode($json);
echo "Array: \n";
echo "--------------\n";
var_dump($data);
echo "\n\n";
$name = $data->name;
$pos = $data->position;
echo "Result: \n";
echo "--------------\n";
echo "Name : ".$name."\n Position : ".$pos;
?>
this is the error that appears when i run the php
Notice: Undefined index: HTTP_JSON in C:\xampp\htdocs\ReceiveLocation.php on line 5
JSON: -------------- NULL Array: -------------- NULL
Notice: Trying to get property of non-object in C:\xampp\htdocs\ReceiveLocation.php on line 17
Notice: Trying to get property of non-object in C:\xampp\htdocs\ReceiveLocation.php on line 18
Result: -------------- Name : Position :
Access the JSON data using:
$json = $_POST['jsonpost'];
You were trying to access an invalid field in your php file, it should have been
$json = $_POST['jsonpost'];
OR
$json = $_REQUEST['jsonpost'];
Remember to also sterilize your data from bad input in your php file if you plan to do database work with the data. ALso maybe your localhost path should be changed from
HttpPost httppost = new HttpPost("http://127.0.0.1/ReceiveLocation.php");
TO
HttpPost httppost = new HttpPost("http://10.0.2.2/ReceiveLocation.php");
Hope i helped.
You have a Problem with your code, JSON Data is only added to the header and not to the POST Section of HTTP Request.
So when you output:
print_r(getallheaders());
$headers = getallheaders();
$json = json_decode($headers['json']);
print_r($json);
You should see your data. I right now have not a fix, but i am working on it.
Related
i'm trying to make android food order for my thesis and because this error i'm running out of time :(
error on logcat :
Error parsing dataorg.json.JSONException: Value cannot be converted to JSONObject
org.json.JSONException: Value to JSONObject
here's my JSONParser :
package com.makanan.restotradisional;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.utils.URLEncodedUtils;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.util.Log;
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
public JSONParser() {
}
// fungsi abil json url lewat method HTTP POST atau GET
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {
try {
if (method == "POST") {
// jika request method adalah POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} else if (method == "GET") {
// jika request method adalah GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error Converting result" + e.toString());
}
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data" + e.toString());
e.printStackTrace();
}
return jObj;
}
}
this my PHP & Java : http://www.4shared.com/rar/1lGplX19ba/Java_and_PHP.html
and this is my database on phpmyadmin :http://www.4shared.com/rar/y_UMtL7_ce/rumah_makan.html
please help me
Remove any of the <br> statements or echo statements from your php file except the one that you are using to pass json..
Check the output of your file in browser, remove all the unwanted things other than json..
Please print and check if your string json is in right format as expected by the JSONObject constructor. Per documentation, valid json string to construct JSONObject should be -- A string beginning with { (left brace) and ending with } (right brace).
Please refer this.
Go inside JSONParser and do this so u see in logcat whats comming from php. Probably its a php error.
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
//This line is what u need to add
Log.d("Whats wrong?", json.toString());
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
This my connector class that should call on the php script to access the database. When debugging I find that httpEntity is returning null therefore not detecting any results from the database. The url works fine in the browser so im not sure whether or not this is the issue.
import android.os.StrictMode;
import android.util.Log;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.json.JSONArray;
import org.json.JSONException;
import java.io.IOException;
public class ApiConnector {
public JSONArray GetAllCustomers()
{
// URL for getting all customers
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
String url = "mydburl";
// Get HttpResponse Object from url.
// Get HttpEntity from Http Response Object
HttpEntity httpEntity = null;
try
{
DefaultHttpClient httpClient = new DefaultHttpClient(); // Default HttpClient
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
Log.v("response code", httpResponse.getStatusLine()
.getStatusCode() + "");
httpEntity = httpResponse.getEntity();
} catch (ClientProtocolException e) {
// Signals error in http protocol
e.printStackTrace();
//Log Errors Here
} catch (IOException e) {
e.printStackTrace();
}
// Convert HttpEntity into JSON Array
JSONArray jsonArray = null;
if (httpEntity != null) {
try {
String entityResponse = EntityUtils.toString(httpEntity);
Log.e("Entity Response : ", entityResponse);
jsonArray = new JSONArray(entityResponse);
} catch (JSONException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
return jsonArray;
}
}
php Script (works in browser)
<?php
$con = $con = mysql_connect("localhost","root","");
// Check connection
if (!$con)
{
echo "Failed to connect to MySQL: " . mysql_error();
}
mysql_select_db("dbname", $con);
$sql = 'SELECT * FROM `locations` ';
$result = mysql_query($sql);
while($row=mysql_fetch_assoc($result))
{
$output[]=$row;
}
print(json_encode($output));
mysql_close($con);
?>
There was in fact two problems here, the first was to do with my php script, once i modified it to run mysqli instead of my sql it ran correctly.
Another was to do with the ip address i was passing through, the device was trying to read from the localhost from my device rather than the localhost of my laptop. To fix this i entered my ipv4 address.
I'm using Eclipse, for an application where I have to read a JSON file from an URL.
The code I'm using is this one:
http://collegewires.com/android/2012/06/json-parsing-in-android/
Ok, the CLASS which I'm using for reading JSON files is called Parser.java:
package com.cw.json;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
public class Parser {
static InputStream is = null;
static JSONObject jsonObject = null;
static String json = "";
// class constructor
public Parser() {
}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException exception) {
exception.printStackTrace();
} catch (ClientProtocolException exception) {
exception.printStackTrace();
} catch (IOException exception) {
exception.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sBuilder = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sBuilder.append(line + "\n");
}
is.close();
json = sBuilder.toString();
} catch (Exception exception) {
exception.printStackTrace();
}
// Parsing the string to a JSON object
try {
jsonObject = new JSONObject(json);
} catch (JSONException exception) {
exception.printStackTrace();
}
// JSON String
return jsonObject;
}
}
I was using this code for reading a JSON file which is directly an ARRAY, but the code gives me an error.
My question is: is it possible to read an Array instead always reading an Object??
maybe using another class?
Try to modify your Parser.java to this, so you gat a Array not a Object. And please buy you a JAVA Book for beginners, so you do learn how to speak JAVA
public JSONArray getJSONFromUrl(String url) {
....
static JSONArray jsonArray = null;
....
// Parsing the string to a JSON Array
try {
jsonArray = new JSONArray(json);
} catch (JSONException exception) {
exception.printStackTrace();
}
return jsonArray;
}
I am getting this error in my LogCat:
Error parsing data org.json.JSONException: Value of type java.lang.String cannot be converted to JSONArray
Below are every file I could show you! Please let me know the problem and its solution ASAP. What I guess is:
1. Maybe the is problem is with parsing data in JSON array.
2. Maybe the problem is with my php api, I think I am not properly encoding the json_encode because it gives me RAW JSON, like every thing in one line.
as below
[{"uid":"120","name":"MyFirstName MyLastName"}]
Please also let me know, their is some difference in working of both format, 1. Raw JSON and 2. Intented Json
below is the intented json format
[
{
"uid":"120",
"name":"MyFirstName MyLastName"
}
]
Here is the JSONUseActivity.java
package com.example.oncemore;
import java.util.ArrayList;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.os.StrictMode;
import com.example.oncemore.CustomHttpClient;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class JSONUseActivity extends Activity {
EditText email,password;
Button submit;
TextView tv; // TextView to show the result of MySQL query
String returnString; // to store the result of MySQL query after decoding
// JSON
/** Called when the activity is first created. */
#Override
public void onCreate(Bundle savedInstanceState) {
StrictMode.setThreadPolicy(new StrictMode.ThreadPolicy.Builder()
.detectDiskReads().detectDiskWrites().detectNetwork() // StrictMode is
// most commonly
// used to catch
// accidental
// disk or
// network
// access on the
// application's
// main thread
.penaltyLog().build());
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_jsonuse);
email = (EditText) findViewById(R.id.email);
password = (EditText) findViewById(R.id.password);
submit = (Button) findViewById(R.id.submitbutton);
tv = (TextView) findViewById(R.id.showresult);
// define the action when user clicks on submit button
submit.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// declare parameters that are passed to PHP script i.e. the
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
// define the parameter
postParameters.add(new BasicNameValuePair("email",email.getText().toString()));
postParameters.add(new BasicNameValuePair("password",password.getText().toString()));
String response = null;
// call executeHttpPost method passing necessary parameters
try {
response = CustomHttpClient.executeHttpPost(
"http://mywebsite.com/android/api.php",
postParameters);
// store the result returned by PHP script that runs MySQL
// query
String result = response.toString();
// parse json data
try {
returnString = "";
//I think the line below is creating some problem
JSONArray jArray = new JSONArray(result);
for (int i = 0; i < jArray.length(); i++) {
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag",
"id: " + json_data.getInt("uid")+", name: " + json_data.getString("name"));
// Get an output to the screen
returnString += "\n" + json_data.getString("name")
+ " -> " + json_data.getInt("uid");
}
}catch (JSONException e) {
Log.e("log_tag", "Error parsing data " + e.toString());
}
try {
tv.setText(returnString);
}
catch (Exception e) {
Log.e("log_tag", "Error in Display!" + e.toString());
;
}
}
catch (Exception e) {
Log.e("log_tag",
"Error in http connection!!" + e.toString());
}
}
});
}
}
Here is the CustomHttpClient.java
package com.example.oncemore;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URI;
import java.util.ArrayList;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.conn.params.ConnManagerParams;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;
import android.util.Log;
public class CustomHttpClient {
/** The time it takes for our client to timeout */
public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds
/** Single instance of our HttpClient */
private static HttpClient mHttpClient;
/**
* Get our single instance of our HttpClient object.
*
* #return an HttpClient object with connection parameters set
*/
private static HttpClient getHttpClient() {
if (mHttpClient == null) {
mHttpClient = new DefaultHttpClient();
final HttpParams params = mHttpClient.getParams();
HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT);
HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT);
ConnManagerParams.setTimeout(params, HTTP_TIMEOUT);
}
return mHttpClient;
}
/**
* Performs an HTTP Post request to the specified url with the specified
* parameters.
*
* #param url
* The web address to post the request to
* #param postParameters
* The parameters to send via the request
* #return The result of the request
* #throws Exception
*/
public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception {
BufferedReader in = null;
try {
HttpClient client = getHttpClient();
HttpPost request = new HttpPost(url);
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
request.setEntity(formEntity);
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
String result = sb.toString();
return result;
} finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
Log.e("log_tag", "Error converting result "+e.toString());
e.printStackTrace();
}
}
}
}
/**
* Performs an HTTP GET request to the specified url.
*
* #param url
* The web address to post the request to
* #return The result of the request
* #throws Exception
*/
public static String executeHttpGet(String url) throws Exception {
BufferedReader in = null;
try {
HttpClient client = getHttpClient();
HttpGet request = new HttpGet();
request.setURI(new URI(url));
HttpResponse response = client.execute(request);
in = new BufferedReader(new InputStreamReader(response.getEntity()
.getContent()));
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
String result = sb.toString();
return result;
} finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
Log.e("log_tag", "Error converting result "+e.toString());
e.printStackTrace();
}
}
}
}
}
Here is the api.php
<?php
require_once("../contactdb.php");
$myusername=$_REQUEST["email"];
$mypassword=$_REQUEST["password"];
// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);
$sql="SELECT uid,name FROM u_info WHERE email='".$myusername."' AND password ='".$mypassword."'";
$result=mysql_query($sql);
// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
if($count==1){
while($row=mysql_fetch_assoc($result))
$output[]=$row;
echo json_encode($output);
mysql_close();
}else{
echo "Error Occured!";
}
?>
Finally, When I goto browser and write like this
http://mywebsite.com/android/api.php?email=myname#yahoo.com&password=1234
I got this json array!
[{"uid":"120","name":"MyFirstName MyLastName"}]
So Far I google, I have found different formats of json array! I found everywhere Intented Json. My json array is currently in Raw Json format. I don't find anywhere how to convert Raw Json format into Intented Json format.
Thanks in advance guys!
Any help would be appreciated! If possible, please provide the correct code!
That is NOT valid JSON syntax:
{
"employees": [
{ "firstName":"John" , "lastName":"Doe" },
{ "firstName":"Anna" , "lastName":"Smith" },
{ "firstName":"Peter" , "lastName":"Jones" }
]
}
Is Valid.
Note: This is also valid:
{"employees": [ { "firstName":"John" , "lastName":"Doe" }, { "firstName":"Anna" , "lastName":"Smith" }, { "firstName":"Peter" , "lastName":"Jones" } ] }
The syntax structure is the important part, not the formatting in terms of indentation.
As otherwise said, to use the fomat you're returning, you need to cut the substring from the response, i.e get rid of the square brackets surrounding the braces.
In PHP I create a proper json response as follows:
// array for JSON response
$response = array();
$response["apps"] = array();
$apps = array();
$apps["name"] = $row["name"];
$apps["package"] = $row["package"];
$apps["version"] = $row["version"];
$apps["dateversion"] = $row["dateversion"];
array_push($response["apps"], $apps);
$response["success"] = 1;
echo json_encode($response);
This basically gives
{ "success":"1", "apps":{["name":"NAME", "package":"PACKAGE", "version":"VERSION", "dateversion":"DATEVERSION"]}}
which can be parsed correctly by any of the abundant examples of JSON classes which you can make use of. Hacking and using substring to manually remove the first N characters is NOT good practice...
I am new to android development. I have the following class for downloading some data in JSON format. I keep getting a Source not found error on the
HttpResponse httpResponse = httpClient.execute(httpPost);
line... I'm sure this must be a simple fix... Here is the class code...
package com.example.tankandroid;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.util.Log;
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
Put this code in onCreate method
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
.permitAll().build();
StrictMode.setThreadPolicy(policy);
Use Apache HttpCore and HttpClient libraries. Put these two libraries into your lib folder, its automatically add these into your build path.
One reason for this situation may be missing internet permissions in AndroidManifest.xml file. Adding this line in manifest will fix the issue.
<uses-permission android:name="android.permission.INTERNET" />
You need to provide some more information I think. Where do you get the "Source not found" error? Is it an Eclipse error that prevents you from compiling. Is it during compilation? Is it a runtime error? Could this be a possible duplicate of: Source not found Android? ?
Question: Why are you doing an HTTP POST if you don't intend to add any POST data? A GET seems more appropriate.
And since you also ask "I'm sure this must be a simple fix" then yes, it is. I'd really suggest that you rip out your HTTP code and switch to Android Asynchronous Http Client. It's super easy to work with and very well suited for getting an HTTP response and parsing it. Example:
AsyncHttpClient client = new AsyncHttpClient();
RequestParams rp = new RequestParams();
rp.put("some_param", "some value");
rp.put("another_param", "some other value");
client.post("http://www.simonsayssolutions.co.uk/index.php", rp, new AsyncHttpResponseHandler() {
#Override
public final void onSuccess(String response) {
// handle your response and parse JSON here
}
#Override
public void onFailure(Throwable e, String response) {
// something went wrong
}
});
or GET:
client.get("http://www.simonsayssolutions.co.uk/index.php", rp, new AsyncHttpResponseHandler() {
...
}
And finally if you want to simplify JSON parsing have a look at Jackson or Gson. Especially if you want to parse JSON data to Java objects and vice versa.