I'm hoping someone can help me with my hibernate issue as I've been banging my head against Google for around an hour without result.
So the issue is that I have a SortedMap in a class, using Integer as the Key (and its natural built-in compareTo method) and another class as the value type. I'm using the key to keep the user-defined order of the value type and trying to get Hibernate to persist this.
For whatever reason, Hibernate has defaulted to disregarding the key I have inputted and instead using the value type's primary key as the key instead. When I load my Map back out of the database all of my keys have been changed in this way.
Definition of the Map is shown below (I'm using annotation-style Hibernate);
#ManyToMany(cascade = CascadeType.ALL)
#MapKey
#Sort(type = SortType.NATURAL)
private SortedMap<Integer, Column> columnOrder;
I can't use the Column type to store the order itself as the Column may be used in many instances of the containing type, with a different key value each time. Any guidance would be most appreciated.
So I found the answer after discovering this StackOverflow question with a similar issue: Sorted map of Java primitives using JPA2 and Hibernate?
By changing the #MapKey annotation to the #MapKeyColumn annotation, I was able to give Hibernate the instruction to persist the key in the column name I specified, as below;
#ManyToMany(cascade = CascadeType.ALL)
#MapKeyColumn(name = "hierarchyOrdering")
#Sort(type = SortType.NATURAL)
private SortedMap<Integer, Column> columnOrder;
Thanks for the help.
From the javadoc of javax.persistence.OrderColumn:
Specifies a column that is used to maintain the persistent order of a list. The persistence provider is responsible for maintaining the order upon retrieval and in the database. The persistence provider is responsible for updating the ordering upon flushing to the database to reflect any insertion, deletion, or reordering affecting the list.
So it is possible to use a list for that.
The JPA 2.0 spec states in section 2.2 Persistent Fields and Properties:
Collection-valued persistent fields and properties must be defined in terms of one of the following collection-
valued interfaces regardless of whether the entity class otherwise adheres to the JavaBeans
method conventions noted above and whether field or property access is used: java.util.Collection,
java.util.Set, java.util.List[3], java.util.Map. The collection implementation
type may be used by the application to initialize fields or properties before the entity is made
persistent. Once the entity becomes managed (or detached), subsequent access must be through the
interface type.
So it seems as if a SortedMap is not supported by JPA.
Related
I've been trying to do a simple one to many object binding in DataNucleus JDO. It's just two classes (i stripped a simple fields):
#PersistenceCapable(table="ORDER",schema="mgr")
public class Order {
#PrimaryKey(column="id")
#Persistent(valueStrategy=IdGeneratorStrategy.NATIVE,column="id")
private Long id;
#Persistent(defaultFetchGroup="false",column="customer_id")
#Element(column="customer_id")
private Customer customer;
}
And a class Customer having a list of orders
#PersistenceCapable(table="customer",schema="mgr",identityType=IdentityType.DATASTORE)
#DatastoreIdentity(strategy=IdGeneratorStrategy.NATIVE)
public class Customer {
#PrimaryKey
#Persistent(valueStrategy=IdGeneratorStrategy.NATIVE,column="id")
private Long id;
#Persistent(mappedBy="customer")
private List<Order> orders;
}
The database table setup is extremely simple(a table for customer and a table for orders with a foreign key (customer_id) referencing customer). Yet, when i try to insert some orders for customer i receive an error
javax.jdo.JDODataStoreException: Insert of object
"test.Order#17dd585" using statement "INSERT INTO
ORDER
(USER_COMMENT,ORDER_DATE,STATUS,CUSTOMER_ID,ORDERS_INTEGER_IDX)
VALUES (?,?,?,?,?)" failed : Unknown column 'ORDERS_INTEGER_IDX' in
'field list'
Somehow DataNucleus is assuming, there is a column ORDERS_INTEGER_IDX (such column does not exist in the database). The only idea, that came to my mind is http://www.datanucleus.org/products/datanucleus/jdo/metadata_xml.html
In some situations DataNucleus will add a special datastore column to
a join table so that collections can allow the storage of duplicate
elements. This extension allows the specification of the column name
to be used. This should be specified within the field at the
collection end of the relationship. JDO2 doesnt allow a standard place
for such a specification and so is an extension tag.
So cool! 'in some situations'. I have no idea how to make my situation not to be a subset of 'some situations' but I have no idea, how to get this working. Perhaps someone has allready met the "INTEGER_IDX" problem? Or (it is also highly possible) - im not binding the data correctly :/
So you create the schema yourself. Your schema is inconsistent with metadata. You run persistence without validating your metadata against schema, and an exception results. DataNucleus provides you with SchemaTool to create or validate the schema against your metadata, so that would mean that you can detect the problem.
You're using an indexed list, so it needs an index for each element (or how else is it to know what position an element is in?). How can it assume there is an index? well it's a thing called the JDO spec (publically available), which defines indexed lists. If you don't want positions of elements storing then don't use a List (the Java util class for retaining the position of elements) ... so I'd suggest using a Set since that doesn't need position info (hence no index).
You also have a class marked as datastore identity, and then have a primary-key. That is a contradiction ... you have one or the other. The docs define all of that, as well as how to have a 1-N List relation ("JDO API" -> "Mapping" -> "Fields/Properties" -> "1-N Relations" -> "Lists" or "Sets")
I'm changing a Collection to a SortedSet because I need it to always be in the same consistent order that they were created in. I've changed my model property from
#OneToMany(cascade = CascadeType.ALL, mappedBy = "contentId")
private Collection<Footnote> footnoteCollection;
to
#OneToMany(cascade = CascadeType.ALL, mappedBy = "contentId")
private SortedSet<Footnote> footnoteSortedSet;
and all relevant functions so Netbeans no longer shows any errors. When I run the app I get the error: Exception Description: Could not load the field named [footnoteSortedSet] on the class [class com.mysite.cmt.model.Content_]. Ensure there is a corresponding field with that name defined on the class.
Since I've just changed this properly and relaunched my app I'm struggling to figure out why it's saying it's not set...
The error you are getting seems to be coming from the JPA metamodel. I assume you are generating this in some way, if you don't use the metamodel in Criteria, then you don't need this and the error will go away.
The issue is that JPA only allows the collection interfaces, Map, List, Set, Collection. So, while you could use a SortedSet in your new instances, object read from the database will use a special lazy List implementation.
In EclipseLink, you can use a SortedSet if you mark the mapping as EAGER.
I think the metamodel error was fixed, try the latest release.
SortedSet javadoc to the rescue:
All elements inserted into a sorted set must implement the Comparable interface (or be accepted by the specified comparator).
Almost certainly, Footnote does not implement Comparable
I have a simple jpa entity 'ApplicationForm' with a one to many list in it:
#OneToMany(cascade=CascadeType.REMOVE, mappedBy="textQuestion")
private List<Dictionary> questions;
The variable Dictionary contained in ApplicationForm is just another plain entity with just the text of the question.
The corresponding database table mapped by Dictionary is:
'locale' 'text' 'formId'
en my question 123
it mia domanda 123
I was wondering if it's possible with jpa or hibernate, to build a query for retrieving an ApplicationForm entity with a Dictionary for a specific locale, for example 'it' only.
That would be easy enough to do with standard sql, but I cannot translate in hql.
If not possible, could you suggest an alternative way ? I have tried to manually iterate the Dictionary questions list and remove the not required locale, but is not really elegant, and also I got a jpa/hibernate error.
I hope I made myself clear, and code supplied is enough.
thanks
I was wondering if it's possible with jpa or hibernate, to build a query for retrieving an ApplicationForm entity with a Dictionary for a specific locale, for example 'it' only.
Not with standard JPA. But Hibernate allows to apply arbitrary filters to a collection load during a given session. From the Hibernate Annotations Reference Guide:
2.4.8. Filters
Hibernate has the ability to apply
arbitrary filters on top of your data.
Those filters are applied at runtime
on a given session. First, you need to
define them.
#org.hibernate.annotations.FilterDef
or #FilterDefs define filter
definition(s) used by filter(s) using
the same name. A filter definition has
a name() and an array of
parameters(). A parameter will allow
you to adjust the behavior of the
filter at runtime. Each parameter is
defined by a #ParamDef which has a
name and a type. You can also define a
defaultCondition() parameter for a
given #FilterDef to set the default
condition to use when none are defined
in each individual #Filter. A
#FilterDef(s) can be defined at the
class or package level.
We now need to define the SQL filter
clause applied to either the entity
load or the collection load. #Filter
is used and placed either on the
entity or the collection element
#Entity
#FilterDef(name="minLength", parameters=#ParamDef( name="minLength", type="integer" ) )
#Filters( {
#Filter(name="betweenLength", condition=":minLength <= length and :maxLength >= length"),
#Filter(name="minLength", condition=":minLength <= length")
} )
public class Forest { ... }
When the collection use an association
table as a relational representation,
you might want to apply the filter
condition to the association table
itself or to the target entity table.
To apply the constraint on the target
entity, use the regular #Filter
annotation. However, if you wan to
target the association table, use the
#FilterJoinTable annotation.
#OneToMany
#JoinTable
//filter on the target entity table
#Filter(name="betweenLength", condition=":minLength <= length and :maxLength >= length")
//filter on the association table
#FilterJoinTable(name="security", condition=":userlevel >= requredLevel")
public Set<Forest> getForests() { ... }
See also
Chapter 17. Filtering data In the Hibernate Core Reference Documentation.
Hibernate3 Filters
I have a field aliases of type java.util.Set in one Entity. This Set doesn't denote any relationship to an Entity.
How can I store this aliases field through JPA?
How this field get stored in database? I think that for the database, this field is a multi-valued attribute.
How can I store this aliases field through JPA?
JPA 1.0 doesn't support collections of basic types so you'll have to either:
Introduce an entity and map it as a #OneToMany ~or~
Get your Set stored in a BLOB (as a Serializable) ~or~
Mark it #Transient and use another getter/setter to store it using a custom string representation (using a seperator) ~or~
Use an extension of your JPA provider supporting collection of basic types (e.g. Hibernate has the #CollectionOfElements annotation).
Solution #1 would be the cleanest portable solution. Solution #2 can lead to some troubles on upgrades. Solution #3 is a ugly workaround for #2. Solution #4 is clean but non portable.
In JPA 2.0, there is the #ElementCollection annotation for this use case (this is of course the ideal solution).
How this field get stored in database
Depending on the chosen implementation, it may be in a BLOB, in a VARCHAR, in another table.
In legacy database tables we have numbered columns like C1, C2, C3, C100 or M1, M2, M3, M100.
This columns represent BLOB data.
It is not possible to change anything it this database.
By using JPA Embeddable we map all of the columns to single fields. And then during embedding we override names by using 100 override annotations.
Recently we have switched to Hibernate and I've found things like UserCollectionType and CompositeUserType. But I hadn't found any use cases that are close to mine.
Is it possible to implement some user type by using Hibernate to be able to map a bundle of columns to a collection without additional querying?
Edit:
As you probably noticed the names of columns can differ from table to table. I want to create one type like "LegacyArray" with no need to specify all of the #Columns each time I use this type.
But instead I'd use
#Type(type = "LegacyArrayUserType",
parameters =
{
#Parameter(name = "prefix", value = "A"),
#Parameter(name = "size", value = "128")
})
List<Integer> legacyA;
#Type(type = "LegacyArrayUserType",
parameters =
{
#Parameter(name = "prefix", value = "B"),
#Parameter(name = "size", value = "64")
})
List<Integer> legacyB;
I can think of a couple of ways that I would do this.
1. Create views for the collection information that simulates a normalized table structure, and map it to Hibernate as a collection:
Assuming your existing table is called primaryentity, I would create a view that's similar to the following:
-- untested SQL...
create view childentity as
(select primaryentity_id, c1 from primaryentity union
select primaryentity_id, c2 from primaryentity union
select primaryentity_id, c3 from primaryentity union
--...
select primaryentity_id, c100 from primaryentity)
Now from Hibernate's perspective, childentity is just a normalized table that has a foreign key to primarykey. Mapping this should be pretty straight forward, and is covered here:
http://docs.jboss.org/hibernate/stable/core/reference/en/html/collections.html
The benefits of this approach:
From Hibernate's point of view, the tables are normalized, it's a fairly simple mapping
No updates to your existing tables
The drawbacks:
Data is read-only, I don't think your view can be defined in an updatable manner (I could be wrong)
Requires change to the database, you may need to create lots of views
Alternately, if your DBA won't even let you add a view to the database, or if you need to perform updates:
2. Use Hibernate's dynamic model mapping facility to map your C1, C2, C3 properties to a Map, and have some code you your DAO layer do the appropriate conversation between the Map and the Collection property:
I have never done this myself, but I believe Hibernate does allow you to map tables to HashMaps. I'm not sure how dynamically Hibernate allows you to do this (i.e., Can you get away with simply specifying the table name, and having Hibernate automatically map all the columns?), but it's another way I can think of doing this.
If going with this approach though, be sure to use the data access object pattern, and ensure that the internal implementation (use of HashMaps) is hidden from the client code. Also be sure to check before writing to the database that the size of your collection does not exceed the number of available columns.
The benefits of this approach:
No change to the database at all
Data is updatable
O/R Mapping is relatively simple
The drawbacks:
Lots of plumbing in the DAO layer to map the appropriate types
Uses experimental Hibernate features that may change in the future
Personally, I think that design sounds like it breaks first normal form for relational databases. What happens if you need C101 or M101? Change your schema again? I think it's very intrusive.
If you add Hibernate to the mix it's even worse. Adding C101 or M101 means having to alter your Java objects, your Hibernate mappings, everything.
If you have 1:m relationships with C and M tables, you'd be able handle the cases I just cited by adding additional rows. Your Java objects contain Collection<C> or Collection<M>. Your Hibernate mappings are one-to-many that don't change.
Maybe the reason that you don't see any Hibernate examples to match your case because it's a design that's not recommended.
If you must, maybe you should look at Hibernate Component Mapping.
UPDATE: The fact that this is legacy is duly noted. My point in bringing up first normal form is as much for others who might find this question in the future as it is for the person who posted the question. I would not want to answer the question in such a way that it silently asserted this design as "good".
Pointing out Hibernate component mapping is pertinent because knowing the name of what you're looking for can be the key when you're searching. Hibernate allows an object model to be finer grained than the relational model it maps. You are free to model a denormalized schema (e.g., Name and Address objects as part of a larger Person object). That's just the name they give such a technique. It might help find other examples as well.
Sorry if I'm misunderstanding your problem here, I don't know much about Hibernate. But couldn't you just concatenate during selection from database to get something like what you want?
Like:
SELECT whatever
, C1||C2||C3||C4||...||C100 AS CDATA
, M1||M2||M3||M4||...||M100 AS MDATA
FROM ...
WHERE ...
(Of course, the concatenation operator differs between RDBMSs.)
[EDIT] I suggest to use a CompositeUserType. Here is an example. There is also a good example on page 228f in the book "Java Persistence With Hibernate".
That allows you to handle the many columns as a single object in Java.
The mapping looks like this:
#org.hibernate.annotations.Columns(columns = {
#Column(name="C1"),
#Column(name="C2"),
#Column(name="C3"),
...
})
private List<Integer> c;
Hibernate will load all columns at once during the normal query.
In your case, you must copy the int values from the list into a fixed number of columns in nullSafeSet. Pseudocode:
for (int i=1; i<numColumns; i++)
if (i < list.size())
resultSet.setInt(index+i, list.get(i));
else
resultSet.setNull(index+i, Hibernate.INTEGER.sqlType());
In nullSafeGet you must create a list and stop adding elements when a column is NULL. For additional safety, I suggest to create your own list implementation which doesn't allow to grow beyond the number of columns (inherit from ArrayList and override ensureCapacity()).
[EDIT2] If you don't want to type all the #Column annotations, use a code generator for them. That can be as simple as script which you give a name and a number and it prints #Column(...) to System.out. After the script ran, just cut&paste the data into the source.
The only other solution would be to access the internal Hibernate API to build that information at runtime but that API is internal, so a lot of stuff is private. You can use Java reflection and setAccessible(true) but that code probably won't survive the next update of Hibernate.
You can use UserTypes to map a given number of columns to any type you wish. This could be a collection if (for example) for collections are always bounded in size by a known number of items.
It's been a while (> 3 years) since I used Hibernate so I'm pretty rusty but I recall it being very easy to do; your BespokeUserType class gets passed the ResultSet to hydrate your object from it.
I too have never used Hibernate.
I suggest writing a small program in an interpreted language (such as Python) in which you can execute a string as if it were a command. You could construct a statement which takes the tedious work out of doing what you want to do manually.