I have a string "name" which I need to add n amount of blank spaces to the end. I have been told to use String.format but for the life of me I cant figure out how to do it.
String formatName = String.format(name, %15s);
return formatName;
But this didn't work, can anyone point me in the right the direction?
Basically I need to make each string 15 characters long with blank spaces appended to the end if the original string is too short.
================
With advice I reversed the paramaters however this throws up an error.
private String format(String name, String number)
{
String formatName = String.format(%15s, name);
String formatNumber = String.format(%15s, number);
return formatName + " - " + formatNumber;
}
However this throws an error - Illegal start of expression.
Can anyone tell me what I'm doing wrong?
formatName = String.format(name + "%15s", "");
OR
formatName = String.format("%-15s", name);
The - appends to the end of the argument.
Related
I want to remove a part of string from one character, that is:
Source string:
manchester united (with nice players)
Target string:
manchester united
There are multiple ways to do it. If you have the string which you want to replace you can use the replace or replaceAll methods of the String class. If you are looking to replace a substring you can get the substring using the substring API.
For example
String str = "manchester united (with nice players)";
System.out.println(str.replace("(with nice players)", ""));
int index = str.indexOf("(");
System.out.println(str.substring(0, index));
To replace content within "()" you can use:
int startIndex = str.indexOf("(");
int endIndex = str.indexOf(")");
String replacement = "I AM JUST A REPLACEMENT";
String toBeReplaced = str.substring(startIndex + 1, endIndex);
System.out.println(str.replace(toBeReplaced, replacement));
String Replace
String s = "manchester united (with nice players)";
s = s.replace(" (with nice players)", "");
Edit:
By Index
s = s.substring(0, s.indexOf("(") - 1);
Use String.Replace():
http://www.daniweb.com/software-development/java/threads/73139
Example:
String original = "manchester united (with nice players)";
String newString = original.replace(" (with nice players)","");
originalString.replaceFirst("[(].*?[)]", "");
https://ideone.com/jsZhSC
replaceFirst() can be replaced by replaceAll()
Using StringBuilder, you can replace the following way.
StringBuilder str = new StringBuilder("manchester united (with nice players)");
int startIdx = str.indexOf("(");
int endIdx = str.indexOf(")");
str.replace(++startIdx, endIdx, "");
You should use the substring() method of String object.
Here is an example code:
Assumption: I am assuming here that you want to retrieve the string till the first parenthesis
String strTest = "manchester united(with nice players)";
/*Get the substring from the original string, with starting index 0, and ending index as position of th first parenthesis - 1 */
String strSub = strTest.subString(0,strTest.getIndex("(")-1);
I would at first split the original string into an array of String with a token " (" and the String at position 0 of the output array is what you would like to have.
String[] output = originalString.split(" (");
String result = output[0];
Using StringUtils from commons lang
A null source string will return null. An empty ("") source string will return the empty string. A null remove string will return the source string. An empty ("") remove string will return the source string.
String str = StringUtils.remove("Test remove", "remove");
System.out.println(str);
//result will be "Test"
If you just need to remove everything after the "(", try this. Does nothing if no parentheses.
StringUtils.substringBefore(str, "(");
If there may be content after the end parentheses, try this.
String toRemove = StringUtils.substringBetween(str, "(", ")");
String result = StringUtils.remove(str, "(" + toRemove + ")");
To remove end spaces, use str.trim()
Apache StringUtils functions are null-, empty-, and no match- safe
Kotlin Solution
If you are removing a specific string from the end, use removeSuffix (Documentation)
var text = "one(two"
text = text.removeSuffix("(two") // "one"
If the suffix does not exist in the string, it just returns the original
var text = "one(three"
text = text.removeSuffix("(two") // "one(three"
If you want to remove after a character, use
// Each results in "one"
text = text.replaceAfter("(", "").dropLast(1) // You should check char is present before `dropLast`
// or
text = text.removeRange(text.indexOf("("), text.length)
// or
text = text.replaceRange(text.indexOf("("), text.length, "")
You can also check out removePrefix, removeRange, removeSurrounding, and replaceAfterLast which are similar
The Full List is here: (Documentation)
// Java program to remove a substring from a string
public class RemoveSubString {
public static void main(String[] args) {
String master = "1,2,3,4,5";
String to_remove="3,";
String new_string = master.replace(to_remove, "");
// the above line replaces the t_remove string with blank string in master
System.out.println(master);
System.out.println(new_string);
}
}
You could use replace to fix your string. The following will return everything before a "(" and also strip all leading and trailing whitespace. If the string starts with a "(" it will just leave it as is.
str = "manchester united (with nice players)"
matched = str.match(/.*(?=\()/)
str.replace(matched[0].strip) if matched
This may seem as a simple problem, but I honestly didn't seem to work this out.
I have a formatted string as follows:
String msg = String.format("Current player: %1$s", status.getCurrentPlayer().getName());
and I want to left-pad it, lets say with 10 spaces. I tried:
String pad = String.format("%1$10s", msg);
but it doesn't seem to work, although I tried it with an unformatted string:
String pad = String.format("%1$10s", "some string");
and obviousely, it worked.
What is it about "msg" that does not let me pad it?
What is it about "msg" that does not let me pad it?
It's longer than 10 characters.
That 10 is the width of the Formatter class.
Reading that documentation, you'll see
The optional width is a non-negative decimal integer indicating the minimum number of characters to be written to the output.
So, minimum, meaning any string longer than that are printed as-is.
If you want to pad, just add 10 to the length of the string.
String msg = "some really, really long message";
String fmt = "%1$" + (10 + msg.length()) + "s";
String pad = String.format(fmt, msg);
// " some really, really long message"
String msg = "Current player: "
+ status.getCurrentPlayer().getName()
+ new String(new char[10]).replace('\0', ' ');
This will add 10 spaces after the name of the player. If you want to take into account the length of the player name you can do this:
String msg = "Current player: "
+ status.getCurrentPlayer().getName()
+ new String(new
char[10 - status.getCurrentPlayer().getName().Length ]).replace('\0', ' ');
Weird one but:
Let's say you've a huge html page and if the page contains an email address (looking for an # sign) you want to return that email.
So far I know I need something like this:
String email;
if (myString.contains("#")) {
email = myString.substring("#")
}
I know how to get to the # but how do I go back in the string to find what's before it etc?
if the myString is the string for email you received from html page then ,
you can return the same string if it has # right. something like below
String email;
if (myString.contains("#")) {
email = myString;
}
whats the challenge here.. can you explain any challenge if so ?
This method will give you a list of all the email addresses contained in a string.
static ArrayList<String> getEmailAdresses(String str) {
ArrayList<String> result = new ArrayList<>();
Matcher m = Pattern.compile("\\S+?#[^. ]+(\\.[^. ]+)*").matcher(str.replaceAll("\\s", " "));
while(m.find()) {
result.add(m.group());
}
return result;
}
String email;
if (myString.contains("#")) {
// Locate the #
int atLocation = myString.indexOf("#");
// Get the string before the #
String start = myString.substring(0, atLocation);
// Substring from the last space before the end
start = start.substring(start.lastIndexOf(" "), start.length);
// Get the string after the #
String end = myString.substring(atLocation, myString.length);
// Substring from the first space after the start (of the end, lol)
end = end.substring(end.indexOf(" "), end.length);
// Stick it all together
email = start + "#" + end;
}
This may be a little off as I've been writing javascript all day. :)
Rather than exact code, I would like to give you an approach.
Checking just by # symbol might not be appropriate as it might be possible in other cases as well.
Search through internet or create your own, a regex pattern which matches an email.
(if you want, you can add a check for email providers as well) [here is a link] (http://www.mkyong.com/regular-expressions/how-to-validate-email-address-with-regular-expression/)
Get the index of a pattern in a string using regex and find out the substring (email in your case).
java.lang.NumberFormatException: For input string: ":"
What does this mean?
I get the above error if I run the code (below).I am a beginner here.
and..
stacktrace:[Ljava.lang.StackTraceElement;#e596c9
the code:
try
{
Class.forName("java.sql.DriverManager");
Connection con=DriverManager.getConnection("jdbc:mysql://localhost/bvdb","root","enter")
Statement stm=con.createStatement();
String m="-",t="-",w="-",th="--",f="-",st="--",s="-",runson;
if(jCheckBox1.isSelected()==true){
m="m";}
if(jCheckBox2.isSelected()==true){
t="t";}
if(jCheckBox3.isSelected()==true){
w="w";}
if(jCheckBox4.isSelected()==true){
th="th";}
if(jCheckBox5.isSelected()==true){
f="f";}
if(jCheckBox6.isSelected()==true){
st="st";}
if(jCheckBox7.isSelected()==true){
s="s";}
runson= m + t + w + th + f + st + s ;
int h1=Integer.valueOf(jTextField10.getText().substring(0,2)
int mins1=Integer.valueOf(jTextField10.getText().substring(3,5));
int h2=Integer.valueOf(jTextField12.getText().substring(0,2));
int mins2=Integer.valueOf(jTextField12.getText().substring(2,3));
Boolean x=jTextField10.getText().substring(2,3).equals(":");
Boolean y=jTextField12.getText().substring(2,3).equals(":");
String time1=jTextField10.getText().substring(0,2)+jTextField10.getText().substring (2,3)+jTextField10.getText().substring(3,5);
String time2=jTextField12.getText().substring(0,2)+jTextField12.getText().substring(2,3)+jTextField12.getText().substring(3,5);
String tfac1=jTextField13.getText();
String tfac2=jTextField14.getText();
String tfac3=jTextField15.getText();
String tfsl=jTextField16.getText();
if(Integer.valueOf(jTextField3.getText())==0){
tfac1="0";
if(Integer.valueOf(jTextField4.getText())==0){
tfac2="0";}
if(Integer.valueOf(jTextField5.getText())==0){
tfac3="0";}
if(Integer.valueOf(jTextField6.getText())==0){
tfsl="0";}
if(y==true&&x==true&&jTextField1.getText().trim().length()<=6&&jTextField2.getText().trim().length()<=30&&h1<=24&&h2<=24&&mins1<=59&&mins2<=59){
String q="INSERT INTO TRAININFO VALUE ("+jTextField1.getText()+",'"+jTextField2.getText()+"','"+jTextField9.getText()+"','"+time1+"','"+jTextField11.getText()+"','"+time2+"','"+runson+"',"+tfac1+","+tfac2+ ","+tfac3+","+tfsl+","+jTextField3.getText()+","+jTextField4.getText()+","+jTextField5.getText()+","+jTextField6.getText()+");";
stm.executeUpdate(q);
JOptionPane.showMessageDialog("ADDED");
}
}
catch (Exception e){
e.printStackTrace();
}
that means you can not convert the String ":" to Number like integer or double
see below link
http://docs.oracle.com/javase/7/docs/api/java/lang/NumberFormatException.html
According to java docs
Thrown to indicate that the application has attempted to convert a
string to one of the
numeric types, but that the string does not have the appropriate format.
It means you want to convert ":" to a number which is not allowed. Hence you are getting the exception. Better show your code
The best way you get responses faster & answered your question is posting your code.
You cannot convert String to number.
As others have said Java can't convert "15:" into a number because ":" is not a digit. And the most probable cause for this is a line like this one:
int h1 = Integer.valueOf(jTextField10.getText().substring(0,2));
where you are splitting a time string at the wrong index which is why you have ":" in it.
UPDATE
Better way of splitting a time string like "12:35:09" is by using String.split():
String timeString = "12:35:09";
String[] parts = timeString.split(":");
boolean validTimeString = parts.length == 3;
The code above will result in the following values:
timeString = "12:35:09"
parts[0] = "12"
parts[1] = "35"
parts[2] = "09"
validTimeString = true
String.split(DELIMITER) will split the string into N + 1 strings where N is the number of occurences of the DELIMITER in target string.
With this string "ADACADABRA". how to extract "CADA" From string "ADACADABRA" in java.
and also how to extract the id between "/" and "?" from the link below.
http://www.youtube-nocookie.com/embed/zaaU9lJ34c5?rel=0
output should be: zaaU9lJ34c5
but should use "/" and "?" in the process.
and also how to extract the id between "/" and "?" from the link below.
http://www.youtube-nocookie.com/embed/zaaU9lJ34c5?rel=0
output should be: zaaU9lJ34c5
Should be :
String url = "http://www.youtube-nocookie.com/embed/zaaU9lJ34c5?rel=0";
String str = url.substring(url.lastIndexOf("/") + 1, url.indexOf("?"));
String s = "ADACADABRA";
String s2 = s.substring(3,7);
Here 3 specifies the beginning index, and 7 specifies the stopping point.
The string returned contains all the characters from the beginning index, up to, but not including, the ending index.
I'm not entirely sure what you mean by extract, so I've provided the code to remove it from the String, I'm not certain if this is what you want.
public static void main (String args[]){
String string = "ADACADABRA";
string = string.replace("CADA", "");
System.out.println(string);
}
This is untested but something like this may help for the youtube part:
String youtubeUrl = "http://www.youtube-nocookie.com/embed/zaaU9lJ34c5?rel=0";
String[] urlParts = youtubeUrl.split("/");
String videoId = urlParts[urlParts.length - 1];
videoId = videoId.substring(0, videoId.indexOf("?"));
Extracting CADA from the string makes no sense. You will need to specify how you have determined that CADA is the string to extract.
E.g. is it because it is the middle 4 characters? Is it because you are stripping off 3 characters each side? Are you just looking for the String "CADA"? Is it characters 3,7 of the String? Is it the first 4 of the last 7 characters of a String? Is it because it contains 2 vowels and 2 consanants? I could go on..
String regex = "CADA";
Pattern p = Pattern.compile(regex, Pattern.MULTILINE);
Matcher m = p.matcher(originalText);
while (m.find()) {
String outputThis = m.group(1);
}
Use this tool http://www.regexplanet.com/advanced/java/index.html
Probably, you don't take in account the fact of java.lang.String immutability. That's why you need to assign the result of substringing to a new variable.