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How to convert String to array in Java [closed]

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I have a string String myStringArray = "[491174, 414529, 414557]";. I want output 491174, 414529, 414557 just this part. I tried many methods to convert string to array and many other things. I tried something I'm adding the code below.
My Code
String myStringArray = "[491174, 414529, 414557]";
String newArray = myStringArray.replaceAll(" ", "");
System.out.println("Before Remove : " + newArray);
String remove = newArray.replaceAll("[^a-zA-Z0-9]", ",");
String rm = remove.replaceFirst(",", "");
System.out.println("After Remove : " + rm);
Output
Before Remove : [491174,414529,414557]
After Remove : 491174,414529,414557,
As you can see I have , in the end and I don't know how to remove this ,. Please help me if you can.

rm = rm.substring(0, rm.length() - 1);

How to add a letter the end of each word per its word index? [closed]

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I have a problem about adding a letter the end of each word per its word index.
I cannot handle with that. How can I fix it?
Here is my code shown below.
for(int i=0;i<sentenceOfArray.length;i++) {
sentenceOfArray[i] = sentenceOfArray[i] + "c";
}

Here is the solution with the usage of repeat method.
for(int i=0;i<sentenceOfArray.length;i++) {
sentenceOfArray[i] = sentenceOfArray[i] + "a".repeat(i+1);
}

Other approach:
String [] sentenceOfArray = {"abg", "ert", "mlk"};
for(int i=0;i<sentenceOfArray.length;i++) {
char lastLetter = sentenceOfArray[i].charAt(sentenceOfArray[i].length() - 1);
sentenceOfArray[i] = sentenceOfArray[i] + "c";
System.out.println(sentenceOfArray[i]+"\n");
}
Output:
abgc
ertc
mlkc

should i use remmove and is this correct in java? [closed]

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in the exercise they told if string contain 00 or 0 remove it
String rse="12+00+9+88";
String re="[0]{1,2}\\+";
String oper[]=chaine.split("[0-9]{1,2}\\+");
for(int i=1;i<oper.length;i++) {
if (oper.equals(re)) {
}
}

You may juse use String.replaceAll and use 2 regexes
(0+)\+ to remove zeros followed by a +
\+(0+), specific case when zeros are the last one, the + is before it
List<String> values = Arrays.asList(
"12+00+9+88",
"12+0+9+88",
"00+9+88",
"0+9+88",
"12+00",
"12+0"
);
for (String s : values) {
String r = s.replaceAll("(0+)\\+", "").replaceAll("\\+(0+)", "");
System.out.println(r);
}
12+9+88
12+9+88
9+88
9+88
12
12

Extract Verbs from Sentence [closed]

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I would like to know if there is a way to extract verbs from a string.
As an example :
I'll eliminate you.
I want it to only extract "eliminate".

You probably want to be looking at using the Stanford PoS tagger (http://nlp.stanford.edu/software/tagger.shtml). It will tag the string with it's classification (e.g. verb, noun). You can then use a regular expression to pull out the verbs.

ArrayList<String> verbs = new ArrayList<>();
verbs.add("eliminate");
String yourtext = "I'll eliminate you";
for (String verb : verbs) {
int index = yourtext.indexOf(verb);
if (index >= 0) {
System.out.println("Found verb: " + verb + " at position: " + index);
}
}
I'll leave filling the verbs array up to you.

php take raw input to a variable [closed]

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Consider this piece of Java code
I need to do this in php
String SEPARATOR = "S39Er#T0R";
String input = "someS39Er#T0RDataS39Er#T0Rhere";
String[] val = input.split(SEPERATOR);
for (int i = 0; i < val.length; i++) {
}
I need to store the data received from file_get_contents('php://input') which returns the raw post
and then from that string I need it to split and run a for loop
Can any one suggest how to implement the same code in php ?

explode function splits a string by a string;
preg_split splits a string by a regex;
foreach construct iterates over arrays or objects;
Combination of these is pretty straightforward:
$separator = 'S39Er#T0R';
$postData = file_get_contents('php://input');
$splitPostData = explode($separator, $postData);
foreach($splitPostData as $postDataItem)
{
// do something with $postDataItem
}