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Convert String of type "2015-23-07T00:00:00Z" to XMLGregorianCalender of format "07/23/2015T00:00:00Z"

I am calling a Web Service which accepts date as Xmlgregoriancalendar of format "07/23/2015T00:00:00Z" but what I have currently from my database is "2015-23-07T00:00:00Z".
How to convert this String type of XMLGregorianCalender of type
"MM/dd/yyyy'T'HH:mm:ss.SSS'Z'"
Since that service is hosted by some third party I can't change the schema and need to implement this conversion.
I tried this
Date d = new Date();
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy/MM/dd'T'HH:mm:ss.SSS'Z'");
String formattedDate1 = sdf1.format(d);
Date date = sdf1.parse(formattedDate1);
GregorianCalendar gregorianCalendar;
XMLGregorianCalendar result = null;
gregorianCalendar = (GregorianCalendar)GregorianCalendar.getInstance();
gregorianCalendar.setTime(date);
result = DatatypeFactory.newInstance().newXMLGregorianCalendar(gregorianCalendar);

java.text.DateFormat outputFormat =new java.text.SimpleDateFormat("MM/dd/yyyy'T'HH:mm:ss'Z'");
java.text.DateFormat outputFormat1 =new java.text.SimpleDateFormat("yyyy-dd-MM'T'HH:mm:ss'Z'");
System.out.println(outputFormat.format(outputFormat1.parse("2015-23-07T00:00:00Z")));//07/23/2015T00:00:00Z

You can using SimpleDateFormat to do this.
Grab the string from database, find and replace "-" with "\" then parse String to Date. Actually, SimpleDateFormat would accept "MM-dd-yyyy'T'HH:mm:ss.SSS'Z'" type as well as "MM/dd/yyyy'T'HH:mm:ss.SSS'Z'" and you can do some calculation on it.

Setting date into "dd"-"mm"-"yy" format from "dd"-"mm"-"yyyy" in java

I have a date in the format dd-mm-yyyy format(inside my db).I need to convert it to dd-mm-yy format.I retrieved date from db and stored it inside a string.
String date=doc.getString("date");
for example: 05-19-1990
to
05-19-90.
That 1990 is not fully needed only 90 is needed.Using split() in java i tried some thing but it wont helps me.Can anyone please help.Any help will be highly appreciated.......

Use DateFormat for that issue:
DateFormat df = SimpleDateFormat("dd-MM-yyyy");
DateFormat df1 = SimpleDateFormat("dd-MM-yy");
df1.format(df.parse(date));

Try below code
try {
SimpleDateFormat sdf= new SimpleDateFormat("MM-dd-yy");
Date d = sdf.parse("05-19-1990");
System.out.println(sdf.format(d));
} catch (ParseException ex) {
ex.printStackTrace();
}

Use two SimpleDateFormats, one to parse it, one to format it..
SimpleDateFormat in = new SimpleDateFormat("MM-dd-yyyy");
Date inDate = in.parse(date); // 05-19-1990
SimpleDateFormat out = new SimpleDateFormat("MM-dd-yy");
String newDate = out.format(inDate);
or
SimpleDateFormat out = new SimpleDateFormat("dd-MM-yy");
String newDate = out.format(inDate);
If you really want 19-05-90 as per the title of your question ;)
Check java.text.SimpleDateFormat for more details

Try this..
DateFormat df2 = new SimpleDateFormat("dd-mm-yy");
String formattedDate2 = df2.format(theDate);

convert a date object to Oracle timestamp type string

I want to convert a date object, ex: new Date(), to a string which has a format like Oracle's time stamp type, ex: 21-OCT-13 11.08.13.858000000 AM. I know I could just get each piece of information in the date object like day, month, year, hour, minute, ... to form the Oracle format string but I really want to know is there a utility to do that instead?

Using SimpleDateFormat#format() you would print a Date as
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yy hh.mm.ss.SSSSSSSSS a");
System.out.println(sdf.format(new Date()).toUpperCase());
Output :
21-OCT-13 10.01.38.000000614 AM
See JavaDocs for Date and Time patterns.

Try taking a look at SimpleDateFormats - That would be your best bet and easiest way of doing it.
Eg:
Date date = new Date();
SimpleDateFormat dateFormat = new SimpleDateFormat("hh:mm:ss"); //Hours:Minutes:Seconds
String strDate = dateFormat.format(date);

Use SimpleDateFormat.
Date date = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("your_format_here"); // dd/MM/yy h:mm:ss a
String formattedDate = sdf.format(date);
System.out.println(formattedDate);

how to convert datetime to timestamp in java

forum member
I am having one problem with date time in java. Actually I am receiving the startdate in format 2012-02-27T01:10:10 and I want to insert the received date to my database having datetime datatype.
Actually I tried to convert the startdate received to datetime by below code
String sDate = jsonObject.get("StartDate").toString();
String eDate = jsonObject.get("EndDate").toString();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Date startD = sdf.format(sDate);
Date endD = sdf.format(eDate);
but with the above code only date gets added to my database like 2012-02-27 00:00:00
I want to add the time also to my database but when I change the SimpleDateFormat to SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); nothing works.
please suggest me some solution I can apply so my time also gets added to database. I am using Hibernate JPA as my persistence layer.

SimpleDateFormat's format() method doesn't return a Date type.
try this:
Date startDate = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss").parse(sDate);

Try this,
yyyy-MM-dd'T'HH:mm:ss

String sDate = jsonObject.get("StartDate").toString();
String eDate = jsonObject.get("EndDate").toString();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Date startD = sdf.format(sDate);
Timestamp startTime = new Timestamp(startD.getTime());
Date endD = sdf.format(eDate);
Timestamp endTime = new Timestamp(endD.getTime());

Of course only the date is parsed, since the pattern you provided to the SimpleDateFormat constructor only contains the date part! Add the time part to it and it will parse the time too just fine.

you can try like this....
DateFormat format = new SimpleDateFormat("MMddyyHHmmss");
Date date = format.parse("022310141505");

Extract time from date String

How can I format the "2010-07-14 09:00:02" date string to depict just "9:00"?

Use DateTimeFormatter to convert between a date string and a real LocalDateTime object. with a LocalDateTime as starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the DateTimeFormatter.
String originalString = "2010-07-14 09:00:02";
LocalDateTime dateTime = LocalDateTime.parse(originalString, DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss"));
String newString = DateTimeFormatter.ofPattern("H:mm").format(dateTime); // 9:00
In case you're not on Java 8 or newer yet, use SimpleDateFormat to convert between a date string and a real Date object. with a Date as starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the SimpleDateFormat.
String originalString = "2010-07-14 09:00:02";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(originalString);
String newString = new SimpleDateFormat("H:mm").format(date); // 9:00

Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse("2010-07-14 09:00:02");
String time = new SimpleDateFormat("H:mm").format(date);
http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html

A very simple way is to use Formatter (see date time conversions) or more directly String.format as in
String.format("%tR", new Date())

The other answers were good answers when the question was asked. Time moves on, Date and SimpleDateFormat get replaced by newer and better classes and go out of use. In 2017, use the classes in the java.time package:
String timeString = LocalDateTime.parse(dateString, DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss"))
.format(DateTimeFormatter.ofPattern("H:mm"));
The result is the desired, 9:00.

I'm assuming your first string is an actual Date object, please correct me if I'm wrong. If so, use the SimpleDateFormat object: http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html. The format string "h:mm" should take care of it.

If you have date in integers, you could use like here:
Date date = new Date();
date.setYear(2010);
date.setMonth(07);
date.setDate(14)
date.setHours(9);
date.setMinutes(0);
date.setSeconds(0);
String time = new SimpleDateFormat("HH:mm:ss").format(date);

let datestring = "2017-02-14 02:16:28"
let formatter = DateFormatter()
formatter.dateStyle = DateFormatter.Style.full
formatter.timeStyle = DateFormatter.Style.full
formatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
let date = formatter.date(from: datestring)
let date2 = formatter.String(from: date)