If I have an xml with namespaces and want to apply some values replacement, what do I have to change?
http://xslt.online-toolz.com/tools/xslt-transformation.php
<?xml version="1.0"?>
<accounts>
<account>
<name>Alex</name>
</account>
<account>
<name>Fiona</name>
</account>
</accounts>
This will change alle name values to "Johndoe":
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node() | #*">
<xsl:copy>
<xsl:apply-templates select="node() | #*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="account/name/text()">
<xsl:text>JohnDoe</xsl:text>
</xsl:template>
</xsl:stylesheet>
But what if I have a namespace before very tag, like:
<?xml version="1.0"?>
<my:accounts>
<my:account>
<my:name>Alex</my:name>
</my:account>
<my:account>
<my:name>Fiona</my:name>
</my:account>
</my:accounts>
Two ways of doing this. Either include the 'my' namespace in the stylesheet tag like this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="(insertnamespacehere)">
and do
<xsl:template match="my:account/my:name/text()">
or do the rather clumsier:
<xsl:template match="*[local-name()='account']/*[local-name()='name']/text()">
I'd be inclined to discourage the latter approach though- namespaces exist to distinguish between elements that have the same local name (such as employee:name and company:name for example), by using local-name() you ignore that distinction. In other words, if your document happens to contains foo:account/foo:name, you'll accidentally replace that too.
Incidentally, your last sample XML isn't valid- the my namespace is not declared. Your root my:accounts would need to include this with <my:accounts xlmns:my="(insertnamespacehere)">
Related
Wondering if anyone can help with an XSLT issue I am facing.
I am trying to create an xslt script which will take take as input an xml document and change the values of several fields to "xxxx" I have managed to get this part working however I would now only like this to run if one field in the input xml is of a specific value (e.g. if username is jbond)
I like to have this condition within my XSLT if possible however I am having difficulty.
My current XML, XSLT, Output and expected outputs are as follows
XML:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl"?>
<rootDoc>
<user>test</user>
<tel>12345</tel>
<zip>abcd</zip>
</rootDoc>
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" >
<xsl:output method="xml" omit-xml-declaration="no" indent="yes"/>
<xsl:template match="node()|#*">
<xsl:if test="user = 'test'">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:if>
</xsl:template>
<xsl:template match="tel/text()">XXXX</xsl:template>
<xsl:template match="zip/text()">XXXX</xsl:template>
</xsl:stylesheet>
Output:
<?xml version="1.0" encoding="UTF-8"?>
<rootDoc/>
Expected:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl"?><rootDoc>
<user>test</user>
<tel>XXXX</tel>
<zip>XXXX</zip>
</rootDoc>
If you leave the identity transform alone, but add specific matches, XSLT will automagically find the closest match. You can customize the select="" or add more templates as necessary. hth
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" >
<xsl:output method="xml" omit-xml-declaration="no" indent="yes"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="tel"><tel>XXXX</tel></xsl:template>
<xsl:template match="zip"><zip>XXXX</zip></xsl:template>
</xsl:stylesheet>
Putting the test into the identity transformation template does not make much sense, if you want to perform certain changes when a condition holds then the templates
<xsl:template match="tel/text()">XXXX</xsl:template>
<xsl:template match="zip/text()">XXXX</xsl:template>
should be changed to
<xsl:template match="rootDoc[user = 'test']/tel/text()">XXXX</xsl:template>
<xsl:template match="rootDoc[user = 'test']/zip/text()">XXXX</xsl:template>
which could be joined into
<xsl:template match="rootDoc[user = 'test']/tel/text() | rootDoc[user = 'test']/zip/text()">XXXX</xsl:template>
With a single condition, assuming it is the rootNode, you can use
<xsl:template match="/rootNode[not(user = 'test')]">
<xsl:copy-of select="."/>
</xsl:template>
then the other cases are handled by the identity transformation and the specialized templates.
I am trying to replace namespace string using xslt.
I have the source namespace string and target namespace string in another xml file in the format of "namespace source="xxx" target="xxx"". All source namespace strings in my to-be-transformed xml should be changed to the corresponding target value. Only elements need to be considered as attributes don't have namespace.
I'm using the JDK default xalan xslt processor, which supports xslt 1.0. I'd like to stick to xslt 1.0 if possible, but I can change processor and use xslt 2.0 if really needed.
For example, to-be-transformed input xml:
<root xmlns="http://ns1" xmlns:ns2="http://ns2-old" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-old">
<ElementB/>
<ns2:elementD/>
</ElementA>
</root>
The output xml should be ("http://ns2-old" is changed to "http://ns2-new", and "http://ns4-old" is changed to "http://ns4-new"):
<root xmlns="http://ns1" xmlns:ns2="http://ns2-new" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-new">
<ElementB/>
<ns2:elementD/>
</ElementA>
</root>
Here is my xsl that is not working:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:variable name="nsmapdoc" select="document('my-map-file')"/>
<xsl:key name="nsmap" match="//namespace/#target" use="#source"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- process each element -->
<xsl:template match="element()">
<xsl:for-each select="namespace::*">
<!-- for each namespace node of the element, save the string value-->
<xsl:variable name="sourceuri"><xsl:value-of select="."/>
</xsl:variable>
<!-- get the target value for this namespace-->
<xsl:variable name="targeturi">
<xsl:for-each select="$nsmapdoc">
<xsl:value-of select="key('nsmap', $sourceuri)"/>
</xsl:for-each>
</xsl:variable>
<!-- if target value exists, replace the current namespace node string value with the target value-->
<xsl:if test="$targeturi">
<xsl:value-of select="$targeturi"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I have a few questions:
For the identity template that do the copy, why doing "match="node()|#*" instead of just "match="node()"? Is attribute also a node?
I am not sure if I did correctly to get the namespace string value (like "http://ns1", "http://ns2-old") for the element.
I think I got the key correctly. However, I am not sure if I used the type correctly---looks like targeturi variable is not a string. If key does not have the entry, what will lookup the entry return? In my case, I should replace the namespace value only for the namespace that has an entry in the map.
How to write a new string value for the namespace node?
I need to process each namespace nodes for the element. Is it the right way to define a variable inside ?
please help to see what is wrong with my xsl. Any suggestion is appreciated.
I think you have two, possibly three, separate questions here.
The first question is: how to move elements from one namespace to another, using a "map" of source-to-target namespaces. Let me answer this question first. Given:
XML
<root xmlns="http://ns1" xmlns:ns2="http://ns2-old" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-old">
<ElementB/>
<ns2:ElementD/>
</ElementA>
</root>
map.xml
<root>
<namespace source="http://ns2-old" target="http://ns2-new"/>
<namespace source="http://ns4-old" target="http://ns4-new"/>
</root>
The following stylesheet:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:param name="nsmapdoc" select="document('map.xml')"/>
<xsl:template match="*">
<xsl:variable name="old-ns" select="namespace-uri()"/>
<xsl:variable name="map-entry" select="$nsmapdoc/root/namespace[#source=$old-ns]"/>
<xsl:variable name="new-ns">
<xsl:choose>
<xsl:when test="$map-entry">
<xsl:value-of select="$map-entry/#target"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$old-ns"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:element name="{local-name()}" namespace="{$new-ns}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
will return:
<?xml version="1.0" encoding="utf-8"?>
<root xmlns="http://ns1">
<ElementA xmlns="http://ns4-new">
<ElementB/>
<ElementD xmlns="http://ns2-new"/>
</ElementA>
</root>
Note:
ElementA and its child ElementB have been moved from namespace URI "http://ns4-old" to URI "http://ns4-new";
ElementD has been moved from namespace URI "http://ns2-old" to URI "http://ns2-new";
The prefix of ElementD has been stripped off; this is a meaningless, cosmetic change, and it should not present any problems for the receiving application;
The root element has remained in its original namespace;
Unused namespace declarations have been discarded.
Note also that we are not using a key to lookup the new namespace: using a key across documents is quite awkward in XSLT 1.0 and I have chosen to do without.
The second question is how to copy the unused namespace declarations. There are several possible answers to choose from:
It's not necessary to copy them, since that are not used for anything;
It's not possible to copy them;
It is possible to copy them by copying some element from the source document; however copying an element also copies its namespace - so this can be done only if there is a known element that is supposed to stay in its original namespace. For example, if you know beforehand that the root element is not supposed to be moved to another namespace, you can add another template to the stylesheet:
to get this result:
<?xml version="1.0" encoding="utf-8"?>
<root xmlns="http://ns1" xmlns:ns2="http://ns2-old" xmlns:ns3="http://ns3">
<ElementA xmlns="http://ns4-new">
<ElementB/>
<ElementD xmlns="http://ns2-new"/>
</ElementA>
</root>
I have a number of XSD schemas with too much documentation in them which makes them hard to read and use, how can I write a program to produce the equivalent XSD files with all the xs:annotation elements (including any xs:appinfo, xs:documentation or other elements they contain) removed whenever they may be found?
You could run each of your files through an XSLT to strip out the unwanted elements:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xs:annotation" />
</xsl:stylesheet>
As noted by #IanRoberts You only really need to remove the xs:annotation elements and the other two types of elements will be removed along with them.
For example I have XML:
<a>
<b>c</b>
</a>
xsdA.xsd:
<xs:import schemaLocation="xsdB.xsd"/>
<xs:element name="a" xmlns:xsa="http://www.example.org/a" type="xsa:aType"></xs:element>
xsdB.xsd:
<xs:element name="b" xmlns:xsb="http://www.example.org/b" type="xsb:bType"></xs:element>
I want to somehow transform XML into this:
<xsa:a xmlns:xsa="http://www.example.org/a">
<xsb:b xmlns:xsb="http://www.example.org/b">c</xsb:b>
</xsa:a>
I hear that it can be done by JAXB, but is there any way to do this without code generation?
I use Java.
EDIT:
It's just example. I can add namespaces by xslt or manualy in DOM object, but my xsds is 170K size now. And it often changes. I want just replace the xsd and program keep working.
How can i found namespace of element with given localname in bunch of xsd files?
EDIT2:
All localnames seems to be different in my xsds.
As laune suggested, a very basic XSLT that should get you started.
XSLT:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsa="http://www.example.org/a"
xmlns:xsb="http://www.example.org/b">
<xsl:output omit-xml-declaration="no" indent="yes" />
<xsl:template match="a">
<xsa:a><xsl:apply-templates select="node() | #*" /></xsa:a>
</xsl:template>
<xsl:template match="b">
<xsb:b><xsl:apply-templates select="node() | #*" /></xsb:b>
</xsl:template>
<xsl:template match="node() | #*">
<xsl:copy>
<xsl:apply-templates select="node() | #*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Input:
<a>
<b>c</b>
</a>
Output:
<xsa:a xmlns:xsa="http://www.example.org/a" xmlns:xsb="http://www.example.org/b">
<xsb:b>c</xsb:b>
</xsa:a>
I want to convert XML to XML using XSLT in JAVA. How to add namespace name and it's value in XSLT file? I have tried many ways to get the namespace value but didn't get the output what i expect. So Please do the needful.
This is my XML,
<?xml version="1.0" encoding="ISO-8859-1"?>
<root xmlns="namespacename">
<child>A</child>
<child>B</child>
</root>
XSLT file,
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:element name="root" namespace="namespacename">
<xsl:element name="child-one">
<xsl:value-of select="root/child"/>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I need the output XML file like this.
<?xml version="1.0" encoding="ISO-8859-1"?>
<root xmlns="namespacename">
<child-one>A</child-one>
</root>
If you know the namespace, then simply add it as the default namespace and write the result as literal elements.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="namespacename"
xmlns:i="namespacename"
exclude-result-prefixes="i">
<xsl:template match="/">
<root>
<child-one>
<xsl:value-of select="i:root/i:child"/>
</child-one>
</root>
</xsl:template>
</xsl:stylesheet>
Note that the XPath expression root/child normally doesn't respect the default namespace, so you have to declare an additional namespace with a prefix (e.g. i) so the path becomes i:root/i:child. However, this also requires excluding the namespace for the result using exclude-result-prefixes="i".