I want this format 6 Dec 2012 12:10
String time = "2012-12-08 13:39:57 +0000 ";
DateFormat sdf = new SimpleDateFormat("hh:mm:ss");
Date date = sdf.parse(time);
System.out.println("Time: " + date);
You need to first parse your date string (Use DateFormat#parse() method) to get the Date object using a format that matches the format of date string.
And then format that Date object (Use DateFormat#format() method) using the required format in SimpleDateFormat to get string.
String time = "2012-12-08 13:39:57 +0000";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z").parse(time);
String str = new SimpleDateFormat("dd MMM yyyy HH:mm:ss").format(date);
System.out.println(str);
Output: -
08 Dec 2012 19:09:57
Z in the first format is for RFC 822 TimeZone to match +0000 in your date string. See SimpleDateFormat for various other options to be used in your date format.
change SimpleDateFormat to:
String time = "2012-12-08 13:39:57 +0000";
DateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss Z");
Date date = sdf.parse(time);
DateFormat sdf = new SimpleDateFormat("dd MMM yyyy HH:mm:ss");
String formatedTime = sdf.format(date);
System.out.println("Time: " + formatedTime);
Take a look at SimpleDateFormat. The code goes something like this:
SimpleDateFormat fromUser = new SimpleDateFormat("dd/MM/yyyy");
SimpleDateFormat myFormat = new SimpleDateFormat("yyyy-MM-dd");
String reformattedStr = myFormat.format(fromUser.parse(inputString));
SimpleDateFormat simpleDateFormat=new SimpleDateFormat("dd-MM-yyyy");
Date date=simpleDateFormat.parse("23-09-2008");
You can use the SimpleDateFormat Class to do this!
such:
DateFormat mydate1 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date1 = mydate1.parse(time);
Related
This question already has answers here:
Comparing two times in android
(4 answers)
12:xx shown as 00:xx in SimpleDateFormat.format("hh:mm:ss")
(1 answer)
Closed 3 years ago.
I am trying to use Date objects and calculate time differences for an android app. But I face a problem when time is in '12:00'. I mean when I input date as 12:12:00 Java AM/PM formatter returns 12:12:00AM but it should be 12:12:00PM.
I can't find any way to solve it.
Date date = new Date();
String stringDate = "2019-09-13 12:12:00";
SimpleDateFormat formatter6=new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
Date date6 = formatter6.parse(stringDate);
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm:ss a");
System.out.println(sdf.format(date6));
It returns 12:12:00 AM
but it should be 12:12:00 PM for correct calculations
In Line:
SimpleDateFormat formatter6=new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
The hh makes sure that hours are parsed as AM/PM values b/w 1-12. To get the desired result, you can use HH marker which parses hour values between 0-23. So, the code should be:
SimpleDateFormat formatter6=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Use DateTimeFormatter and LocalDateTime
String stringDate = "2019-09-13 12:12:00";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime date = LocalDateTime.parse(stringDate, formatter);
DateTimeFormatter formatter2 = DateTimeFormatter.ofPattern("hh:mm:ss a");
System.out.println(formatter2.format(date));
You might also want to set a Locale for your second formatter depending on where you live.
DateTimeFormatter formatter2 = DateTimeFormatter.ofPattern("hh:mm:ss a", Locale.US);
System.out.println(formatter2.format(date));
12:12:00 PM
Pass the AM/PM in the time
Date date = new Date();
String stringDate = "2019-09-13 12:12:00 PM";
SimpleDateFormat formatter6 = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss a");
Date date6 = formatter6.parse(stringDate);
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm:ss a");
System.out.println(sdf.format(date6));
Try to do it the modern way, that is using java.time:
String stringDate = "2019-09-13 12:12:00";
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime datetime = LocalDateTime.parse(stringDate, dtf);
DateTimeFormatter dtfA = DateTimeFormatter.ofPattern("yyyy-MM-dd hh:mm:ss a");
System.out.println(datetime.format(dtfA));
// receive the time part and format it
LocalTime timePart = datetime.toLocalTime();
DateTimeFormatter tf = DateTimeFormatter.ofPattern("hh:mm:ss a");
System.out.println(timePart.format(tf));
This outputs
2019-09-13 12:12:00 PM
12:12:00 PM
on my system.
Note that your pattern String used for parsing is wrong since you are not using capital "H" for the hours of day, but "h" instead. That will definitely not work (correctly).
Two solutions,
1.
Date date = new Date();
String stringDate = "2019-09-13 12:12:00 PM";
SimpleDateFormat formatter6=new SimpleDateFormat("yyyy-MM-dd hh:mm:ss a");
2.
Date date = new Date();
String stringDate = "2019-09-13 12:12:00";
SimpleDateFormat formatter6=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
If you are using java 8 or above then you should definitely use LocalDateTime and DateTimeFormatter makes it way easier to work with date times.
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd hh:mm:ss a");
String am = LocalDateTime.now().format(formatter);
String pm = LocalDateTime.now().plusHours(2).format(formatter);
System.out.println(am);
System.out.println(pm);
Now I am assuming that I run this code during am hours just 2 hours before it changes to pm you can also try out #Joakim Danielson answer which should not be dependent on when it is run.
checkout the documentation for LocalDateTime and DateTimeFormatter
i have a common doubt for a long while. During date formation if the input date in the format like "2019/05/22 02:00:23" then with the help following line we can format the date,
String inputDate = "2019/05/22 02:00:23";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
Date toDate = dateFormatter.parse(inputDate);
I can see both input format and the required format is same. Suppose if i change the input date like below, it is showing the java.text.ParseException: Unparseable date: exception.
String inputDate = "31.12.9999";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy.MM.dd HH:mm:ss");
Date toDate = dateFormatter.parse(inputDate);
Please suggest how to achieve this.
Please try below i mentioned date format code,I hope it will help you,
From this,
String inputDate = "31.12.9999";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy.MM.dd HH:mm:ss");
Date toDate = dateFormatter.parse(inputDate);
To Change:
Date date = new SimpleDateFormat("dd.MM.yyyy").parse("31.12.9999");
String formattedDate = new SimpleDateFormat("yyyy.MM.dd HH:mm:ss").format(date);
System.out.println("formattedDate :: " + formattedDate);
Thanks,.
I get Unparseable error when I run below code. How can I convert dd MMM yyyy format to dd/MM/yyyy format?
public Calendar myMethod(){
String dateStr = "16 Dec 2014"
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
Date thedate = formatter.parse(dateStr);
Calendar cal = Calendar.getInstance();
cal.setTime(thedate);
return cal;
}
Assuming you fix the blatant syntax errors, then:
String dateStr = "16 Dec 2014" // <== This date is in dd MMM yyyy
formatter = new SimpleDateFormat(dd/MM/yyyy); // <== This SDF is in dd/MM/yyyy
Date thedate = formatter.parse(dateStr); // <== So how can it be expected to parse?
What you do is create a parser for the format you need to parse, and a formatter for the format you want:
String dateStr = "16 Dec 2014";
SimpleDateFormat parser = new SimpleDateFormat("dd MMM yyyy");
Date thedate = parser.parse(dateStr);
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
String dateStrReformatted = formatter.format(thedate);
I have my Date as String: 2014-06-23 22:00
To get the Date as java.util.date I parse it by using SimpleDateFormat
Date listDate = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-DD HH:mm",Locale.GERMANY);
listDate = sdf.parse(gameList.get(position).getTime());
but my output
System.out.println(listDate)
is 2014-04-118 19:37
What's going on here??
DD should be dd (in small) below are the available formats in Java7
String str2="April 30, 2013";
simpleDateFormat s= new simpleDateFormat();
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
SimpleDateFormat formatter2 = new SimpleDateFormat("yyyy-MM-dd");
Date dateObject = null;
I have string like "April 30,2013", I am getting this as string from form. I want to convert this into date object as 04/30/2013. Is there any way to do it?
I tried with simpleDateFormat() but I didn't found proper output.
Use MMMMM dd, yyyy to parse and MM/dd/yyyy to format
Use the following code.
String str2="April 30, 2013";
SimpleDateFormat input = new SimpleDateFormat("MMMM dd, yyyy");
SimpleDateFormat output = new SimpleDateFormat("MM/dd/yyyy");
Date date = input.parse(str2);
System.out.println(output.format(date));
This is how you can convert it String date to Date object:
SimpleDateFormat dateFormat = new SimpleDateFormat("MMMM d,yyyy");
SimpleDateFormat yourNewDateFormat = new SimpleDateFormat("MM/dd/yyyy");
Date date = dateFormat.parse("April 30,2013");
System.out.println(yourNewDateFormat.format(date));