Develop Reference

java.io.FileNotFoundException: /u01/app/webapps/out/pj/Create.xlsx

I am trying to Compare last modified date of two excel files and replace the old file with new file.
In Scenario : When there is no file in the first place, so the code copies the file to that location and later reads it.
Issue is : It throws a FileNotFound exception when the excel file is not present on the server,even after writing the file to the
server(via code),but the file is not seen on the server. It works on
my machine(windows),but fails when deployed on server.
Again, it works like charm when the file is present on the server,while the old is being replaced by the new file.
Can you please help and explain on why its failing in the above scenario,and only on server ?
if(row.getValue("fileType").toString().equals("xlsx")&&checkindatefolder.after(localdate))
{
messagelist.add("we are going to get the replace file in the server");
InputStream inp=folder.getFile();
ZipInputStream izs = new ZipInputStream(inp);
ZipEntry e = null;
while ((e = izs.getNextEntry()) != null) {
System.out.println("e.isDirectory(): "+e.isDirectory());
if (!e.isDirectory()) {
filename=e.getName();
System.out.println("filename: "+filename);
FileOutputStream os=new FileOutputStream("path"+e.getName());
byte[] buffer = new byte[4096];
int read=0;
System.out.println("writing to file");
while ((read=izs.read(buffer))> 0) {
System.out.println("1111");
os.write(buffer,0,read);
}
System.out.println("writing to file complete");
inp.close();
os.flush();
os.close();
}
}

Do all parts of the path exist?
So in your example:
/u01/app/webapps/out/pj/Create.xlsx
Do all subdirectories exist?
/u01/app/webapps/out/pj
If not, than trying to write there might fail with a FileNotFoundException.
You should create the directories with Files.creatDirectories(Path) first.

java.io.FileNotFoundException: (Access is denied)

I'm trying to create some files dynamically in my Java project root. but I get the following error when I run the code.
java.io.FileNotFoundException: D:\POS_ALL\T_POS_NEWEST\TouchPosApplication\WebContent\zharaimages\279 (Access is denied)
Is it possible to write a file to the root project folder in Java? Here is the code used.
private void createImage(PosItemImageDTO imageDTO,String path) throws IOException {
byte[] bytes = imageDTO.getPosItemImage();
path = path + "\\";
if(bytes!=null && bytes.length>0){
OutputStream out = null;
// BufferedImage img = ImageIO.read(new ByteArrayInputStream(bytes));
File l = new File(path);
out = new BufferedOutputStream(new FileOutputStream(path));
out.write(bytes);
if (out != null) {
out.close();
}
}
}

Its because it seems like you are trying to open and read a directory here. Your file as you say it, doesn't have any extension specified so java takes it as a directory. use isFile() method to check for a file before opening. You can use listFiles() method to obtain files of the directory.

Please make sure path = path + "\\"; is a correct path. If there is a directory, the program will show you Access is denied. You should add some checks before open the file, just like if (l.isDirectory()).

Extract a .tar.gz file in java (JSP)

I can't seem to import the packages needed or find any online examples of how to extract a .tar.gz file in java.
What makes it worse is I'm using JSP pages and am having trouble importing packages into my project. I'm copying the .jar's into WebContent/WEB-INF/lib/ and then right clicking on the project and selecting import external jar and importing it. Sometimes the packages resolve, other times they don't. Can't seem to get GZIP to import either. The imports in eclipse for jsp aren't intuitive like they are in normal Java code where you can right click a recognized package and select import.
I've tried the Apache commons library, the ice and another one called JTar. Ice has imported, but I can't find any examples of how to use it?
I guess I need to uncompress the gzipped part first, then open it with the tarstream?
Any help is greatly appreciated.

The accepted answer works fine, but I think it is redundant to have a write to file operation.
You could use something like
TarArchiveInputStream tarInput =
new TarArchiveInputStream(new GZipInputStream(new FileInputStream("Your file name")));
TarArchiveEntry currentEntry = tarInput.getNextTarEntry();
while(currentEntry != null) {
File f = currentEntry.getFile();
// TODO write to file as usual
}
Hope this help.
Maven Repo

Ok, i finally figured this out, here is my code in case this helps anyone in the future.
Its written in Java, using the apache commons io and compress librarys.
File dir = new File("directory/of/.tar.gz/files/here");
File listDir[] = dir.listFiles();
if (listDir.length!=0){
for (File i:listDir){
/* Warning! this will try and extract all files in the directory
if other files exist, a for loop needs to go here to check that
the file (i) is an archive file before proceeding */
if (i.isDirectory()){
break;
}
String fileName = i.toString();
String tarFileName = fileName +".tar";
FileInputStream instream= new FileInputStream(fileName);
GZIPInputStream ginstream =new GZIPInputStream(instream);
FileOutputStream outstream = new FileOutputStream(tarFileName);
byte[] buf = new byte[1024];
int len;
while ((len = ginstream.read(buf)) > 0)
{
outstream.write(buf, 0, len);
}
ginstream.close();
outstream.close();
//There should now be tar files in the directory
//extract specific files from tar
TarArchiveInputStream myTarFile=new TarArchiveInputStream(new FileInputStream(tarFileName));
TarArchiveEntry entry = null;
int offset;
FileOutputStream outputFile=null;
//read every single entry in TAR file
while ((entry = myTarFile.getNextTarEntry()) != null) {
//the following two lines remove the .tar.gz extension for the folder name
String fileName = i.getName().substring(0, i.getName().lastIndexOf('.'));
fileName = fileName.substring(0, fileName.lastIndexOf('.'));
File outputDir = new File(i.getParent() + "/" + fileName + "/" + entry.getName());
if(! outputDir.getParentFile().exists()){
outputDir.getParentFile().mkdirs();
}
//if the entry in the tar is a directory, it needs to be created, only files can be extracted
if(entry.isDirectory){
outputDir.mkdirs();
}else{
byte[] content = new byte[(int) entry.getSize()];
offset=0;
myTarFile.read(content, offset, content.length - offset);
outputFile=new FileOutputStream(outputDir);
IOUtils.write(content,outputFile);
outputFile.close();
}
}
//close and delete the tar files, leaving the original .tar.gz and the extracted folders
myTarFile.close();
File tarFile = new File(tarFileName);
tarFile.delete();
}
}

Acces file from other project where the source is

I have a project(project source) with .txt file which I want to access from other project (project caller). caller has dependecy over source. So caller should see source as .jar. Well, the question, I have to access to this .jar to obtenin the .txt file but I cannot. I have tried thinks like:
getClass().getResourceAsStream("classpath:/cc.txt"); with InsputStream
and getClass().getResource("cc.txt"); with URL object
but I always got a null. All forums I ve read speaks about this way to access.
How do I suposse to access to a .jar file to get the .txt file?
thanks all!!

Extract the Contents of ZIP/JAR Files Programmatically. Suppose jarFile is the jar/zip file to be extracted. destDir is the path where it will be extracted:
java.util.jar.JarFile jar = new java.util.jar.JarFile(jarFile);
java.util.Enumeration enum = jar.entries();
while (enum.hasMoreElements())
{
java.util.jar.JarEntry file = (java.util.jar.JarEntry) enum.nextElement();
java.io.File f = new java.io.File(destDir + java.io.File.separator + file.getName());
if (file.isDirectory()) // if its a directory, create it
{
f.mkdir();
continue;
}
java.io.InputStream is = jar.getInputStream(file); // get the input stream
java.io.FileOutputStream fos = new java.io.FileOutputStream(f);
while (is.available() > 0) // write contents of 'is' to 'fos'
{
fos.write(is.read());
}
fos.close();
is.close();
}
the same question can be found here...

Java appending files into a zip [duplicate]

This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Appending files to a zip file with Java
I have a zip that contains a few folders in it but the important one is dir and inside that is another folder called folder and folder contains a lot of files that I need to be able to update.
I have now a dir outside of the zip called dir and in that is folder with the files i need to update in so the paths are the same. How can i update those files into the zip?
The tricky part is that dir is at the root of the zip and it contains a lot of folders not just folder but i only need to update the files in folder i can't mess with any of the files out side of folders but still in dir.
Can this be done? I know this can be done in bash using the -u modifier but I would prefer to do this with java if it's possible.
Thank you for any help with this issue
Just to be clearer
Inside Zip
/dir/folder/filestoupdate
Outside the zip
/dir/folder/filestomoveintozip

Alright well here is the final method it's the same method i pastebinned before which i actually got from the stackoverflow topic in the link #Qwe posted before but i added the path variable so that it could add files to folders inside the zip
Alright so now how to use it in my example above i wanted to add a file into a folder that was inside another folder i would do that using my setup in the question like this
private void addFilesToZip(File source, File[] files, String path){
try{
File tmpZip = File.createTempFile(source.getName(), null);
tmpZip.delete();
if(!source.renameTo(tmpZip)){
throw new Exception("Could not make temp file (" + source.getName() + ")");
}
byte[] buffer = new byte[4096];
ZipInputStream zin = new ZipInputStream(new FileInputStream(tmpZip));
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(source));
for(int i = 0; i < files.length; i++){
InputStream in = new FileInputStream(files[i]);
out.putNextEntry(new ZipEntry(path + files[i].getName()));
for(int read = in.read(buffer); read > -1; read = in.read(buffer)){
out.write(buffer, 0, read);
}
out.closeEntry();
in.close();
}
for(ZipEntry ze = zin.getNextEntry(); ze != null; ze = zin.getNextEntry()){
if(!zipEntryMatch(ze.getName(), files, path)){
out.putNextEntry(ze);
for(int read = zin.read(buffer); read > -1; read = zin.read(buffer)){
out.write(buffer, 0, read);
}
out.closeEntry();
}
}
out.close();
tmpZip.delete();
}catch(Exception e){
e.printStackTrace();
}
}
private boolean zipEntryMatch(String zeName, File[] files, String path){
for(int i = 0; i < files.length; i++){
if((path + files[i].getName()).equals(zeName)){
return true;
}
}
return false;
}
Thanks for the link ended up being able to improve that method a bit so that it could add in files that weren't in the root and now i'm a happy camper :) hope this helps someone else out as well
EDIT
I worked a bit more on the method so that it could not only append to the zip but it also is able to update files within the zip
Use the method like this
File[] files = {new File("/path/to/file/to/update/in")};
addFilesToZip(new File("/path/to/zip"), files, "folder/dir/");
You wouldn't start the path (last variable) with / as that's not how it's listed in the zip entries

Unfortunately, Java can't update Zip files. The request to enhance that was submitted 14 years ago ;-)
You will need to unpack it to a temp folder, add files there and pack it back again.