I have developed a java program that copies the file from source folder to destination folder
there are 10 serialized files that it copies from source folder to destination folder
but one thing is missing in it is that let say if the files are already exists in the destination folder then in that case it should not copy
so basically a look is done within in one second that will check the destination folder contain those 10 serialized files or not
if not then in that case only it should copy and after copying it should again check within in second whether file exists or not , Please advise how to achieve this
//Create a class extends with TimerTask
class ScheduledTask extends TimerTask {
public void run() {
InputStream inStream = null;
OutputStream outStream = null;
try {
File source = new File("C:\\cache\\");
File target = new File("C:\\Authclient\\cache\\");
// Already exists. do not copy
/*if (target.exists()) {
return;
}*/
File[] files = source.listFiles();
for (File file : files) {
inStream = new FileInputStream(file);
outStream = new FileOutputStream(target + "/" + file.getName());
byte[] buffer = new byte[1024];
int length;
// copy the file content in bytes
while ((length = inStream.read(buffer)) > 0) {
outStream.write(buffer, 0, length);
}
inStream.close();
outStream.close();
}
System.out.println("File is copied successful!");
} catch (IOException e) {
e.printStackTrace();
}
}
}
public class Copycache {
public static void main(String args[]) throws InterruptedException {
Timer time = new Timer();
ScheduledTask task = new ScheduledTask();
time.schedule(task, new Date(), TimeUnit.SECONDS.toMillis(1));
}
}
the above exists implementation which is commented is not working correct rite now please advise
I am curious about your exact requirements. Consider this small example:
File file = new File("test.txt");
if (!file.exists())
{
FileOutputStream fis = new FileOutputStream(file);
fis.write("blabla".getBytes());
fis.close();
}
Now put a breakpoint on the line FileOutputStream fis...
Run it and wait at the breakpoint, then create the test.txt manually and put some data in it.
Then continue running the program.
Your program will overwrite the contents of test.txt without warning.
If timing is so crucial here you will need to figure out a different solution.
Edit: I got curious and did some more testing. It seems it won't even throw an exception if you add the line file.createNewFile();, break there, create the file and then continue the application. I wonder why..
Related
i copied this code directly from oracle website. i have two .png file inside d:\barcode. while i run this code myfigs.zip is created in d: drive but it is corruped and 0kb size.
code:-
public class Zip {
static final int BUFFER = 2048;
public static void main (String argv[]) {
try {
BufferedInputStream origin = null;
FileOutputStream dest = new
FileOutputStream("D:\\myfigs.zip");
CheckedOutputStream checksum = new
CheckedOutputStream(dest, new Adler32());
ZipOutputStream out = new
ZipOutputStream(new
BufferedOutputStream(checksum));
//out.setMethod(ZipOutputStream.DEFLATED);
byte data[] = new byte[BUFFER];
// get a list of files from current directory
File f = new File("D:\\barcode");
String files[] = f.list();
for (int i=0; i<files.length; i++) {
System.out.println("Adding: "+files[i]);
FileInputStream fi = new FileInputStream(files[i]);
origin = new BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(files[i]);
out.putNextEntry(entry);
int count;
while((count = origin.read(data, 0,
BUFFER)) != -1) {
out.write(data, 0, count);
}
origin.close();
}
out.close();
System.out.println("checksum: "+checksum.getChecksum().getValue());
} catch(Exception e) {
e.printStackTrace();
}
}
}
to add more information whenever i run the code in debug mode code is successfully compiled to FileInputStream fi line then it is stopped there. the error thrown is
java.io.FileNotFoundException: barcode.png (The system cannot find the file specified)
Adding: barcode.png
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(FileInputStream.java:195)
at java.io.FileInputStream.<init>(FileInputStream.java:138)
at java.io.FileInputStream.<init>(FileInputStream.java:93)
The exception says "file not found". Your "adding" print statement gives you the answer:
Adding: barcode.png
The file "barcode.png" is not the same as the file "D:\barcode\barcode.png". You're just looking for a file named "barcode.png" in whatever your current working directory is set to, and it isn't there.
As per the docs for list() and the conclusion you should have made from your observations of your printed output and exception:
Names denoting the directory itself and the directory's parent directory are not included in the result. Each string is a file name rather than a complete path.
So you need to either:
Change your working directory to "D:\barcode" first, or
Add the parent directory name ("D:\barcode") back to the beginning of your filename ("barcode.png") before opening it, or
Look at some of the other functions File has to offer and see if there's one that helps you avoid this problem entirely.
Couple other minor notes:
It should be no surprise that the zip file was empty, given that your code threw an exception before you wrote anything to it.
"whenever i run the code in debug mode code is successfully compiled to FileInputStream fi line then it is stopped there" - This terminology is not correct. Your error was not a compiler error, it was a runtime error. The code compiled just fine.
The root cause of your problem was blind modification of the code copied from the Oracle site. Note the original comment, "get a list of files from current directory" -- This code assumed the files came from the current working directory. When you added your own directory in, that was no longer the case, and the program broke.
You can use as below code for zip one file:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
/**
* Create by Cuder
*
*/
public class SampleZipFile {
/**
* Create by Cuder
*/
public static void main(String[] args) {
ZipOutputStream zipOutputStream = null;
FileInputStream fileInputStream = null;
try {
File fileInput = new File(
"D:\\eclipse4.4\\workspace\\SampleJava\\resource\\sampleZipFile.txt");
File fileOutput = new File(
"D:\\eclipse4.4\\workspace\\SampleJava\\resource\\sampleZipFile.zip");
FileOutputStream fileOutputStream = new FileOutputStream(fileOutput);
zipOutputStream = new ZipOutputStream(fileOutputStream);
fileInputStream = new FileInputStream(fileInput);
ZipEntry entry = new ZipEntry(fileInput.getName());
zipOutputStream.putNextEntry(entry);
byte[] buf = new byte[1024];
int byteRead = 0;
while ((byteRead = fileInputStream.read(buf)) > 0) {
zipOutputStream.write(buf, 0, byteRead);
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
try {
if (null != fileInputStream) {
fileInputStream.close();
}
if (null != zipOutputStream) {
zipOutputStream.close();
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
During the execution of my program it creates a directory which contains two sub-directories/two folders. Into one of these folders I need to copy a Jar-File. My programm resembles an installation routine. The copying of the Jar file is not the problem here, but the permissions of the created directories.
I tried to set the permissions of the directories (before actually creating them with the mkdirs() method) with File.setWritable(true, false) and also with the .setExecutable and .setReadable methods, but the access to the sub-directories is still denied.
Here's an excerpt of my code for the creation of one of the two sub-directories:
folderfile = new File("my/path/to/directory");
folderfile.setExecutable(true, false);
folderfile.setReadable(true, false);
folderfile.setWritable(true, false);
result = folderfile.mkdirs();
if (result) {
System.out.println("Folder created.");
}else {
JOptionPane.showMessageDialog(chooser, "Error");
}
File source = new File("src/config/TheJar.jar");
File destination = folderfile;
copyJar(source, destination);
And my "copyJar" method:
private void copyJar(File source, File dest) throws IOException {
InputStream is = null;
OutputStream os = null;
try {
is = new FileInputStream(source);
os = new FileOutputStream(dest);
byte[] buffer = new byte[1024];
int length;
while ((length = is.read(buffer))>0) {
os.write(buffer, 0, length);
}
} catch (Exception e) {
e.printStackTrace();
}
is.close();
os.close();
}
At os = new FileOutputStream(dest); the debugger throws a FileNotFoundException with the description that the access to the directory has been denied.
Does anyone have an idea what I am doing wrong or have a better solution for setting the permissions via Java? Thanks in advance!
A similar question was asked there are several years.
A possible solution for Java 7 and Unix system is available here : How do i programmatically change file permissions?
Or, below the best response, a example with JNA.
I hope that that will help you !
I solved the problem. In the end it was much easier to solve than expected.
The main problem was not the permission issue but the FileNotFoundException. The file that is assigned to the OutputStream is not really a file, but just a directory so that the Stream can't find it. You have to create the file before initializing the OutputStream and after that you copy your source file into the newly created file. The code:
private void copyJar(File source, File dest) throws IOException {
InputStream is = null;
File dest2 = new File(dest+"/TheJar.jar");
dest2.createNewFile();
OutputStream os = null;
try {
is = new FileInputStream(source);
os = new FileOutputStream(dest2);
byte[] buffer = new byte[1024];
int length;
while ((length = is.read(buffer))>0) {
os.write(buffer, 0, length);
}
} catch (Exception e) {
e.printStackTrace();
}
is.close();
os.close();
}
I want to copy a file from network location into my local directory. I have written following code for this, but the problem is, it needs to have a file created first, and then the out stream writes the bytes stream into this file.
What i want is, the precondition to first create file locally should not be there. It should simply copy the network file into the mentioned directory directly, thats it! I'm kind of doing this for the first time.
try {
File srcFile = new File("//network//file//path//here");
File dstFileName = new File("//local//drive//file//path//here");
InputStream in = new FileInputStream(srcFile);
OutputStream out = new FileOutputStream(dstFileName);
byte[] buff = new byte[1024];
int length;
while ((length = in.read(buff)) > 0) {
out.write(buff, 0, length);
}
in.close();
out.close();
} catch (Exception ex) {
ex.printStackTrace();
}
You need to create the file, before you can write to it.
if(!dstFileName.exists()){
dstFileName.createNewFile();
}
If the the path does not exist, you can try to create it first with
dstFileName.getParentFile().mkdirs();
I am trying to unzip a file from the internet using the following code. On one of the files("uq.class"), after it has been unzipped from the online source, is missing about 2kb of file size(the original file is 10,084, unzipped I get 8,261). All the other files seem to be completely fine, and when I copy the uq.class file from the zip and place it in manually, it functions perfectly. Can anyone explain whats going on and provide a fix? Below is the unzipping portions of the code.
public static File unpackArchive(URL url, File targetDir) throws IOException {
if (!targetDir.exists()) {
targetDir.mkdirs();
}
InputStream in = new BufferedInputStream(url.openStream(), 2048);
// make sure we get the actual file
File zip = File.createTempFile("arc", ".zip", targetDir);
OutputStream out = new BufferedOutputStream(new FileOutputStream(zip),2048);
copyInputStream(in, out);
out.close();
return unpackArchive(zip, targetDir);
}
public static File unpackArchive(File theFile, File targetDir) throws IOException {
if (!theFile.exists()) {
throw new IOException(theFile.getAbsolutePath() + " does not exist");
}
if (!buildDirectory(targetDir)) {
throw new IOException("Could not create directory: " + targetDir);
}
ZipFile zipFile = new ZipFile(theFile);
for (Enumeration entries = zipFile.entries(); entries.hasMoreElements();) {
ZipEntry entry = (ZipEntry) entries.nextElement();
File file = new File(targetDir, File.separator + entry.getName());
if (!buildDirectory(file.getParentFile())) {
throw new IOException("Could not create directory: " + file.getParentFile());
}
if (!entry.isDirectory()) {
copyInputStream(zipFile.getInputStream(entry), new BufferedOutputStream(new FileOutputStream(file),2048));
} else {
if (!buildDirectory(file)) {
throw new IOException("Could not create directory: " + file);
}
}
}
zipFile.close();
theFile.delete();
return theFile;
}
public static void copyInputStream(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int len = in.read(buffer);
while (len >= 0) {
out.write(buffer, 0, len);
len = in.read(buffer);
}
in.close();
out.close();
}
public static boolean buildDirectory(File file) {
return file.exists() || file.mkdirs();
}
Cannot directly see anything wrong with the code at first sight. What I would recommend you doing however is closing your streams more safely. In your current implementation you close the in and out streams at the same time, close statements can cause exceptions as can read and write statements! If any one of those fails, your files will be left open and in time your application will run out of file descriptors. You're better off doing the closing in a finally statement, that way you're sure they get closed.
I don't know why I cant sign in, but I figured out the issue. I did the whole cart before the horse thing. I extracted the proper file, then extracted the old file over it, so I kept re-integrating the older file. 5 hours of programming out the window. Remember, kiddies, proper programming architecture saves you A TON of headaches.
When I run my code and use the files that are in the resource folder of my project itself, I face no problems. It zips the file successfully and I can extract it using WINZIP. The problem comes when I try to zip a file that is not in the project folder.
When I do the same, I am passing the Absolute Path of both the src and the dest files. My program doesn't give any exceptions, but when I try to open that zip file, I get an error saying, File is Invalid.
Can anyone tell me why this may be happening.
public static void compress(String srcPath, String destPath) {
srcFile = new File(srcPath);
destFile = new File(destPath);
try {
fileInputStream = new FileInputStream(srcFile);
fileOutputStream = new FileOutputStream(destFile);
zipEntry = new ZipEntry(srcPath);
zipOutputStream = new ZipOutputStream(fileOutputStream);
zipOutputStream.putNextEntry(zipEntry);
byte[] data = new byte[12];
while ((fileInputStream.read(data)) != -1) {
zipOutputStream.write(data);
}
} catch (Exception e) {
e.printStackTrace();
} finally {
try{
fileInputStream.close();
zipOutputStream.close();}catch (Exception e) {
e.printStackTrace();
}
}
}
You should not store paths with drive letters in your zip file because when you try to extract your zip, it will try to create a directory with the name of the drive and fail.
You will need to change your code so that it removes the drive letter from the path before creating the ZipEntry.