I need a java regex to extract parts of a URL.
For example, take the following URLs:
http://localhost:81/example
https://test.com/test
http://test.com/
I would want my regex expression to return:
http://localhost:81
https://test.com
http://test.com
I will be using this in a Java patcher.
This is what I have so far, problem is it takes the whole URLs:
^https?:\/\/(?!.*:\/\/)\S+
import Java.net.URL
//snip
URL url = new URL(urlString);
return url.getProtocol() + "://" + url.getAuthority();
The right tool for the right job.
Building off your attempt, try this:
^https?://[^/]+
I'm assuming that you want to capture everything until the first / after http://? (That's what I was getting from your examples - if not, please post some more).
Are these URLs given as one input, or are each a different string?
Edit: It was pointed out that there were unnecessary escapes, so fixed to a more condensed version
Language independent answer:
For the whitespace: replace /^\s+/ with the empty string.
For removing the path information from the URL, if you can assume there aren't any slashes in the path (i.e. you're not dealing with http://localhost:81/foo/bar/baz), replace /\/[^\/]+$/ with the empty string. If there might be more slashes, you might try something like replacing /(^\s*.*:\/\/[^\/]+)\/.*/ with $1.
A simple one: ^(https?://[^/]+)
Related
I need to create Regexes to match URLs of the following forms
/collected/{deliveryId}/deliverer/{userId}
/customer/{userId}/status/active
/users/{userId}/role
Where delivery-id and user-id are UUIDs in the form of: 124r23452-124234234-123123423534 and the other string parts are constant.
For the first one I tried something like this but didnt work:
String urlRegex = "[a-zA-Z-]*/collected/deliverer/(?=\\S*[-])([a-zA-Z-]+)";
You can try this pattern : \/collected\/\w{0,9}\/deliverer\/\w{0,} and use https://regex101.com/ web site. This wikipedia page, gives also some good details on regex.
I currently working on translating a website (Smarty) with Poedit. To get all the text from the .tpl files i'm using regex to get the data between the {t} and {/t}. so an example:
{t}Password incorrect, please try again{/t}
The regex will read Password incorrect, please try again and place it in a .po file. This is all working fine. It goes wrong when it gets a little more advanced.
Sometimes the text between the {t} tags uses a parameter. this looks like this:
{t 1=$email|escape 2=$mailbox}No $1 given, please check your $2{/t}
This is also working great.
The real problem start when i use brackets inside the parameter like this:
{t 1={site info='name'} 2=$mailbox}visit %1 or go to your %2{/t}
My regex will close when it sees the first closing brackets so the result will be 2=$mailbox}visit %1 or go to your %2.
My regex looks like this:
\{t.*?\}?[}]([^\{]+)\{\/t\}|\{t\}([^\{]+)\{\/t\}
The regex is used inside a java program.
Does anybody has a way to fix this problem?
The easiest solution I see on this is to normalize the .tpl files. Just use a regex which matches all tags something like this one:
{[^}]*[^{]*}
I had the same issue to solve and it worked pretty good with the normalizing.
The normalizing-method would look like this:
final String regex = "\\{[^\\}]*[^\\{]*\\}";
private String normalizeContent(String content) {
return content.replaceAll(regex, "");
}
I have certain urls that I am trying to shorten. I want to remove all everything after the / of the url except when that url is equal to plus.google.com
For example:
www.somerubbish.com/about/64848372.meh.php will shorten to www.somerubbish.com
plus.google.com/756934692387498237/about will be left untouched
Any ideas on how I can do this?
My failed attempt is below. I know that the | is saying OR so thats why it is matching the / in the first line as well.
\b!(?:plus.google.com\/.*)\b|\b(?:\/.*)\b
http://regexr.com/3cv6n
Ok I have it.
The answer was to use a negative lookbehind and remove the pipe
(?<!plus.google.com)\b(?:\/.*)\b
https://regex101.com/r/pU3hU4/1
What's wrong with:
if( ! url.contains("plus.google.com")) {
url = StringUtils.substringBefore(url, "/");
}
I need a regex string to match URL starting with "http://", "https://", "www.", "google.com"
the code i tried using is:
//Pattern to check if this is a valid URL address
Pattern p = Pattern.compile("(http://|https://)(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?");
Matcher m;
m=p.matcher(urlAddress);
but this code only can match url such as "http://www.google.com"
I know this ma be a dupicate question but i have tried all of the regex provided and it does not suit my requirement. Willl someone please help me? Thank you.
You need to make (http://|https://) part in your regex as optional one.
^(http:\/\/|https:\/\/)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?$
DEMO
You can use the Apache commons library(org.apache.commons.validator.UrlValidator) for validating a url:
String[] schemes = {"http","https"}.
UrlValidator urlValidator = new UrlValidator(schemes);
And use :-
urlValidator.isValid(your url)
Then there is no need of regex.
Link:-
https://commons.apache.org/proper/commons-validator/apidocs/org/apache/commons/validator/routines/UrlValidator.html
If you use Java, I recommend use this RegEx (I wrote it by myself):
^(https?:\/\/)?(www\.)?([\w]+\.)+[\w]{2,63}\/?$
"^(https?:\\/\\/)?(www\.)?([\\w]+\\.)+[\\w]{2,63}\\/?$" // as Java-String
to explain:
^ = line start
(https?://)? = "http://" or "https://" may occur.
(www.)? = "www." may orrur.
([\w]+.)+ = a word ([a-zA-Z0-9]) has to occur one or more times. (extend here if you need special characters like ü, ä, ö or others in your URL - remember to use IDN.toASCII(url) if you use special characters. If you need to know which characters are legal in general: https://kb.ucla.edu/articles/what-characters-can-go-into-a-valid-http-url
[\w]{2,63} = a word ([a-zA-Z0-9]) with 2 to 63 characters has to occur exactly one time. (a TLD (top level domain (for example .com) can not be shorter than 2 or longer than 63 characters)
/? = a "/"-character may occur. (some people or servers put a / at the end... whatever)
$ = line end
-
If you extend it by special characters it could look like this:
^(https?:\/\/)?(www\.)?([\w\Q$-_+!*'(),%\E]+\.)+[\w]{2,63}\/?$
"^(https?:\\/\\/)?(www\.)?([\\w\\Q$-_+!*'(),%\\E]+\\.)+[\\w]{2,63}\\/?$" // as Java-String
The answer of Avinash Raj is not fully correct.
^(http:\/\/|https:\/\/)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?$
The dots are not escaped what means it matches with any character. Also my version is simpler and I never heard of a domain like "test..com" (which actually matches...)
Demo: https://regex101.com/r/vM7wT6/279
Edit:
As I saw some people needing a regex which also matches servers directories I wrote this:
^(https?:\/\/)?([\w\Q$-_+!*'(),%\E]+\.)+(\w{2,63})(:\d{1,4})?([\w\Q/$-_+!*'(),%\E]+\.?[\w])*\/?$
while this may not be the best one, since I didn't spend too much time with it, maybe it helps someone. You can see how it works here: https://regex101.com/r/vM7wT6/700
It also matches urls like "hello.to/test/whatever.cgi"
Java compatible version of #Avinash's answer would be
//Pattern to check if this is a valid URL address
Pattern p = Pattern.compile("^(http://|https://)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?$");
Matcher m;
m=p.matcher(urlAddress);
boolean matches = m.matches();
pattern="w{3}\.[a-z]+\.?[a-z]{2,3}(|\.[a-z]{2,3})"
this will only accept addresses like e.g www.google.com & www.google.co.in
//I use that
static boolean esURL(String cadena){
boolean bandera = false;
bandera = cadena.matches("\\b(https://?|ftp://|file://|www.)[-a-zA-Z0-9+&##/%?=~_|!:,.;]*[-a-zA-Z0-9+&##/%=~_|]");
return bandera;
}
I am trying to extract the pass number from strings of any of the following formats:
PassID_132
PassID_64
Pass_298
Pass_16
For this, I constructed the following regex:
Pass[I]?[D]?_([\d]{2,3})
-and tested it in Eclipse's search dialog. It worked fine.
However, when I use it in code, it doesn't match anything. Here's my code snippet:
String idString = filename.replaceAll("Pass[I]?[D]?_([\\d]{2,3})", "$1");
int result = Integer.parseInt(idString);
I also tried
java.util.regex.Pattern.compile("Pass[I]?[D]?_([\\d]{2,3})")
in the Expressions window while debugging, but that says "", whereas
java.util.regex.Pattern.compile("Pass[I]?[D]?_([0-9]{2,3})")
compiled, but didn't match anything. What could be the problem?
Instead of Pass[I]?[D]?_([\d]{2,3}) try this:
Pass(?:I)?(?:D)?_([\d]{2,3})
There's nothing invalid with your tegex, but it sucks. You don't need character classes around single character terms. Try this:
"Pass(?:ID)?_(\\d{2,3})"