I am having a string,I want to convert to link,But I am not able to do the same,My code is given below:
Content.append("<a href=\""+System.getProperty("application.middleware.webapplication.host")).append(":")"/"/">);
what about a simple solution like this ?
String host = System.getProperty("application.middleware.webapplication.host");
String url = "http://" + host;
String linkText = "please click here";
Content.append("<a href='"+ url + "'>" + linkText + "</a>" );
The above doesn't compile. If you didn't try to put everything on one line, you would understand why more easily
Start by creating a variable for System.getProperty("..."). Then put one instruction per line. Then don't mix append() and the + concatenation operator. The code becomes:
String host = System.getProperty("application.middleware.webapplication.host");
content.append("<a href=\"");
content.append(host);
content.append(":")"/"/">);
And the last instruction isn't valid. To become valid, and make it a link, you would need something like
String host = System.getProperty("application.middleware.webapplication.host");
content.append("<a href=\"");
content.append(host);
content.append("\">Click here</a>");
Respecting the Java naming conventions (variables start with a lowercase letter) is also crucial in making code readable and understandable.
Content.append("<a href=\"")
.append(System.getProperty("application.middleware.webapplication.host"))
.append("\">My Link</a>");
Related
I want to replace particular string values with "XXXX". The issue is the pattern is very dynamic and it won't have a fixed pattern in input data.
My input data
https://internetbanking.abc.co.uk/personal/logon/login/?userId=Templ3108&password=Got1&reme
I need to replace the values of userId and password with "XXXX".
My output should be -
https://internetbanking.abc.co.uk/personal/logon/login/?userId=XXXX&password=XXXX&reme
This is an one off example. There are other cases where only userId and password is present -
userId=12345678&password=stackoverflow&rememberID=
I am using Regex in java to achieve the above, but have not been successful yet. Appreciate any guidance.
[&]([^\\/?&;]{0,})(userId=|password=)=[^&;]+|((?<=\\/)|(?<=\\?)|(?<=;))([^\\/?&;]{0,})(userId=|password=)=[^&]+|(?<=\\?)(userId=|password=)=[^&]+|(userId=|password=)=[^&]+
PS : I am not an expert in Regex. Also, please do let me know if there are any other alternatives to achieve this apart from Regex.
This may cover given both cases.
String maskUserNameAndPassword(String input) {
return input.replaceAll("(userId|password)=[^&]+", "$1=XXXXX");
}
String inputUrl1 =
"https://internetbanking.abc.co.uk/personal/logon/login/?userId=Templ3108&password=Got1&reme";
String inputUrl2 =
"userId=12345678&password=stackoverflow&rememberID=";
String input = "https://internetbanking.abc.co.uk/personal/logon/login/?userId=Templ3108&password=Got1&reme";
String maskedUrl1 = maskUserNameAndPassword(inputUrl1);
System.out.println("Mask url1: " + maskUserNameAndPassword(inputUrl1));
String maskedUrl2 = maskUserNameAndPassword(inputUrl1);
System.out.println("Mask url2: " + maskUserNameAndPassword(inputUrl2));
Above will result:
Mask url1: https://internetbanking.abc.co.uk/personal/logon/login/?userId=XXXXX&password=XXXXX&reme
Mask url2: userId=XXXXX&password=XXXXX&rememberID=
String url = "https://internetbanking.abc.co.uk/personal/logon/login/?userId=Templ3108&password=Got1&reme";
String masked = url.replaceAll("(userId|password)=[^&]+", "$1=XXXX");
See online demo and regex explanation.
Please note, that sending sensitive data via the query string is a big security issue.
I would rather use a URL parser than regex. The below example uses the standard URL class available in java but third party libraries can do it much better.
Function<Map.Entry<String, String>, Map.Entry<String, String>> maskUserPasswordEntries = e ->
(e.getKey().equals("userId") || e.getKey().equals("password")) ? Map.entry(e.getKey(), "XXXX") : e;
Function<List<String>, Map.Entry<String, String>> transformParamsToMap = p ->
Map.entry(p.get(0), p.size() == 1 ? "" : p.get(p.size() - 1));
URL url = new URL("https://internetbanking.abc.co.uk/personal/logon/login/?userId=Templ3108&password=Got1&reme");
String maskedQuery = Stream.of(url.getQuery().split("&"))
.map(s -> List.of(s.split("=")))
.map(transformParamsToMap)
.map(maskUserPasswordEntries).map(e -> e.getKey() + "=" + e.getValue())
.collect(Collectors.joining("&"));
System.out.println(url.getProtocol() + "://" + url.getAuthority() + url.getPath() + "?" + maskedQuery);
Output:
https://internetbanking.abc.co.uk/personal/logon/login/?userId=XXXX&password=XXXX&reme=
Just use the methods replace/replaceAll from the String class, they support Charset aswell as regex.
String url = "https://internetbanking.abc.co.uk/personal/logon/login/?userId=Templ3108&password=Got1&reme";
url = url.replaceAll("(userId=.+?&)", "userId=XXXX&");
url = url.replaceAll("(password=.+?&)", "password=XXXX&");
System.out.println(url);
I'm not a regex expert either, but if you find it useful, I usually use this website to test my expressions and as a online Cheatsheet:
https://regexr.com
Use:
(?<=(\?|&))(userId|password)=(.*?)(?=(&|$))
(?<=(\?|&)) makes sure it’s preceded by ? or & (but not part of the match)
(userId|password)= matches either userId or password, then =
(.*?) matches any char as long as the next instruction cannot be executed
(?=(&|$)) makes sure the next char is either & or end of the string, (but not part of the match)
Then, replace with $2=xxxxx (to keep userId or password) and choose replaceAll.
I want to write a script that will clean my .mp3 files.
I was able to write a few line that change the name but I want to write an automatic script that will erase all the undesired characters $%_!?7 and etc. while changing the name in the next format Artist space dash Song.
File file = new File("C://Users//nikita//Desktop//$%#Artis8t_-_35&Son5g.mp3");
String Original = file.toString();
String New = "Code to change 'Original' to 'Artist - Song'";
File file2 = new File("C://Users//nikita//Desktop//" + New + ".mp3");
file.renameTo(file2);
I feel like I should make a list with all possible characters and then run the String through this list and erase all of the listed characters but I am not sure how to do it.
String test = "$%$#Arti56st_-_54^So65ng.mp3";
Edit 1:
When I try using the method remove, it still doesn't change the name.
String test = "$%$#Arti56st_-_54^So65ng.mp3";
System.out.println("Original: " + test);
test.replace( "[0-9]%#&\\$", "");
System.out.println("New: " + test);
The code above returns the following output
Original: $%$#Arti56st_-_54^So65ng.mp3
New: $%$#Arti56st_-_54^So65ng.mp3
I'd suggest something like this:
public static String santizeFilename(String original){
Pattern p = Pattern.compile("(.*)-(.*)\\.mp3");
Matcher m = p.matcher(original);
if (m.matches()){
String artist = m.group(1).replaceAll("[^a-zA-Z ]", "");
String song = m.group(2).replaceAll("[^a-zA-Z ]", "");
return String.format("%s - %s", artist, song);
}
else {
throw new IllegalArgumentException("Failed to match filename : "+original);
}
}
(Edit - changed whitelist regex to exclude digits and underscores)
Two points in particular - when sanitizing strings, it's a good idea to whitelist permitted characters, rather than blacklisting the ones you want to exclude, so you won't be surprised by edge cases later. (You may want a less restrictive whitelist than I've used here, but it's easy to vary)
It's also a good idea to handle the case that the filename doesn't match the expected pattern. If your code comes across something other than an MP3, how would you like it to respond? Here I've through an exception, so the calling code can catch and handle that appropriately.
String new = original.replace( "[0-9]%#&\\$", "")
this should replace almost all the characters you don't want
or you can come up with your own regex
https://docs.oracle.com/javase/tutorial/essential/regex/
I tried searching for something similar, and couldn't find anything. I'm having difficulty trying to replace a few characters after a specific part in a URL.
Here is the URL: https://scontent-b.xx.fbcdn.net/hphotos-xpf1/v/t1.0-9/s130x130/10390064_10152552351881633_355852593677844144_n.jpg?oh=479fa99a88adea07f6660e1c23724e42&oe=5519DE4B
I want to remove the /v/ part, leave the t1.0-9, and also remove the /s130x130/.I cannot just replace s130x130, because those may be different variables. How do I go about doing that?
I have a previous URL where I am using this code:
if (pictureUri.indexOf("&url=") != -1)
{
String replacement = "";
String url = pictureUri.replaceAll("&", "/");
String result = url.replaceAll("().*?(/url=)",
"$1" + replacement + "$2");
String pictureUrl = null;
if (result.startsWith("/url="))
{
pictureUrl = result.replace("/url=", "");
}
}
Can I do something similar with the above URL?
With the regex
/v/|/s\d+x\d+/
replaced with
/
It turns the string from
https://scontent-b.xx.fbcdn.net/hphotos-xpf1/v/t1.0-9/s130x130/10390064_10152552351881633_355852593677844144_n.jpg?oh=479fa99a88adea07f6660e1c23724e42&oe=5519DE4B
to
https://scontent-b.xx.fbcdn.net/hphotos-xpf1/t1.0-9/10390064_10152552351881633_355852593677844144_n.jpg?oh=479fa99a88adea07f6660e1c23724e42&oe=5519DE4B
as seen here. Is this what you're trying to do?
I have a bunch of strings like this:
Some text, bla-bla http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter
And I need to parse this String to two:
Some text, bla-bla
http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter
I need separate them, but, of course, it's enough to parse only URL.
Can you help me, how can I parse url from string like this.
By using split :
String str = "Some text, bla-bla http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter";
String [] ar = str.split("http\\.*");
System.out.println(ar[0]);
System.out.println("http"+ar[1]);
This depends on how robust you want your parser to be. If you can reasonably expect every url to start with http://, then you can use
string.indexOf("http://");
This returns the index of the first character of the string you pass in (and -1 if the string does not appear).
Full code to return a substring with just the URL:
string.substring(string.indexOf("http://"));
Here's the documentation for Java's String class. Let this become your friend in programming! http://docs.oracle.com/javase/7/docs/api/java/lang/String.html
Try something like this:
String string = "sometext http://www.something.com";
String url = string.substring(string.indexOf("http"), string.length());
System.out.println(url);
or use split.
I know in PHP you'd be able to run the explode() (http://www.php.net/manual/en/function.explode.php) function. You'd choose which character you want to explode at. For instance, you could explode at "http://"
So running the code via PHP would look like:
$string = "Some text, bla-bla http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter";
$pieces = explode("http://", $string);
echo $pieces[0]; // Would print "Some text, bla-bla"
echo $pieces[1]; // Would print "www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter"
I have a string containing a short-code which looks like the one below:
some text...
[video url="http://www.example.com/path/to/my/video.ext"]
...some more text...
I want to be able to first check if the string contains that short-code and second extract the URL from it in Java (specifically Android).
use this regex for checking and grabbing url:
\[\w+\s+url="(?<urllink>)[^"]*"\s*]
and get gorup named urllink
try as:
String str = "[video url=\"http://www.example.com/path/to/my/video.ext\"]";
if (str.contains("url=\""))
{
int indexoff = str.indexOf("url=\"");
int indexofff = str.indexOf("\"]");
String strurl = str.substring(indexoff, indexofff - indexoff);
strurl = strurl.Replace("url=\"", ""); //get url string here
}
Android provides several function for this purpose. SOme of this are:
http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html
String url = "whatever"
Boolean myBool = url.contains("ate");
String contains. Not sure what extract url means, but the string class has lots of useful functions.
A powerful and maintainable manner it to Java URL.class, then, you can mix with Regex