Develop Reference

Check a particular string and delete part of string in android

I have a string format stored in shared preference. I would like to check if a particular word exists. If yes, then delete those few words which start from x and ends at y.
Something like this: For example:
String items = "Veggies=Beans-Carrot-Potato-Onions--DailyUse=Milk-Yogurt-Soap--Fruits=Apple-Banana-Grapes-Pears";
I would like to check if the above string items has "DailyUse=" if so delete all the words that are after "DailyUse=" until "--". So that my string looks like:
String Newitems = "Veggies=Beans-Carrot-Potato-Onions--Fruits=Apple-Banana-Grapes-Pears";
Is this possible? If so, how do I go about doing this?
Thanks!

Try this.
public static void main(String[] args) {
String items = "Veggies=Beans-Carrot-Potato-Onions--DailyUse=Milk-Yogurt-Soap--Fruits=Apple-Banana-Grapes-Pears";
String[] newItems = items.split("--");
System.out.println(newItems[0] + "--"+ newItems[2]);
}

I tried to put the DailyUse element in first, second and third position and this code seems to work. I think it can be improved, but here's an idea.
String items = "DailyUse=Milk-Yogurt-Soap--Veggies=Beans-Carrot-Potato-Onions--Fruits=Apple-Banana-Grapes-Pears";
String result = "";
if (items.contains("--DailyUse=")){ // not in first position
String[] a = items.split("--DailyUse=");
result = a[0];
if (a[1].contains("--")){ // Daily use is not the last element
String[] b = a[1].split("--");
result = result + "--" + b[1] ;
}
}
else if (items.contains("DailyUse=")){ // first position
String[] b = items.split("--");
result = items.replace(b[0]+"--", ""); // Delete the dailyuse part
}

Using regex
String [] tests = {
"DailyUse=Milk-Yogurt-Soap--Veggies=Beans-Carrot-Potato-Onions--DailyUse=Milk-Yogurt-Soap--Fruits=Apple-Banana-Grapes-Pears--DailyUse=Milk-Yogurt-Soap"
,"DailyUse=Milk-Yogurt-Soap"
,"DailyUse=Milk-Yogurt-Soap--DailyUse=Milk-Yogurt-Soap"
};
String key = "DailyUse";
for (String test : tests) {
String newItems = test;
// Replace only one at beginning
String regexp = "(^" + key + "=.+?(--|$))";
while(newItems.matches(regexp)) {
newItems = newItems.replaceAll(regexp, "");
}
// Regex to replace all other
regexp = "(--" + key + "=.+?)(--|$)";
newItems = newItems.replaceAll(regexp,"$2");
System.out.println("Before " + test);
System.out.println("After " + newItems);
}
UPDATE based on comments

Capitalizing first char in every word in a String in java (but ignoring specific word)

Can anyone please tell me why the following code prints 1 the high street and not 1 The High Street?:
String propertyPageTitle = "1-the-high-street";
propertyPageTitle = propertyPageTitle.replace("-", " ");
WordUtils.capitalizeFully(propertyPageTitle);
System.out.println(propertyPageTitle);
EDIT to show solution:
String propertyPageTitle = "1-the-high-street";
propertyPageTitle = propertyPageTitle.replace("-", " ");
propertyPageTitle = WordUtils.capitalizeFully(propertyPageTitle);
System.out.println(propertyPageTitle);
Supposing I wanted to ignore the word 'and' if it appears (I'm reading values from a .csv) and NOT change to titlecase? how would that be possible.

WordUtils.capitalizeFully does not change the original String, but instead returns the capitalized String.
propertyPageTitle = WordUtils.capitalizeFully(propertyPageTitle);

This happens because capitalizeFully(String) of WordUtils returns a String which has the expected answer. So try:
propertyPageTitle = WordUtils.capitalizeFully(propertyPageTitle);
And then it will work.

String firstStr = "i am fine";
String capitalizedStr = WordUtils.capitalizeFully(firstStr);
System.out.println(capitalizedStr);
The return should be taken to get the output of a method. It is common for all methods in Java String

String toBeCapped = "1 the high street and 2 low street";
String[] tokens = toBeCapped.split("\\s");
StringBuilder builder = new StringBuilder();
for (int i = 0; i < tokens.length; i++) {
if (!tokens[i].equalsIgnoreCase("and")) {
char capLetter = Character.toUpperCase(tokens[i].charAt(0));
builder.append(" ");
builder.append(capLetter);
builder.append(tokens[i].substring(1, tokens[i].length()));
} else {
builder.append(" and");
}
}
toBeCapped = builder.toString().trim();
System.out.println(toBeCapped);
output:
1 The High Street and 2 Low Street

Checking whether the String contains multiple words

I am getting the names as String. How can I display in the following format: If it's single word, I need to display the first character alone. If it's two words, I need to display the first two characters of the word.
John : J
Peter: P
Mathew Rails : MR
Sergy Bein : SB
I cannot use an enum as I am not sure that the list would return the same values all the time. Though they said, it's never going to change.
String name = myString.split('');
topTitle = name[0].subString(0,1);
subTitle = name[1].subString(0,1);
String finalName = topTitle + finalName;
The above code fine, but its not working. I am not getting any exception either.

There are few mistakes in your attempted code.
String#split takes a String as regex.
Return value of String#split is an array of String.
so it should be:
String[] name = myString.split(" ");
or
String[] name = myString.split("\\s+);
You also need to check for # of elements in array first like this to avoid exception:
String topTitle, subTitle;
if (name.length == 2) {
topTitle = name[0].subString(0,1);
subTitle = name[1].subString(0,1);
}
else
topTitle = name.subString(0,1);

The String.split method split a string into an array of strings, based on your regular expression.
This should work:
String[] names = myString.split("\\s+");
String topTitle = names[0].subString(0,1);
String subTitle = names[1].subString(0,1);
String finalName = topTitle + finalName;

First: "name" should be an array.
String[] names = myString.split(" ");
Second: You should use an if function and the length variable to determine the length of a variable.
String initial = "";
if(names.length > 1){
initial = names[0].subString(0,1) + names[1].subString(0,1);
}else{
initial = names[0].subString(0,1);
}
Alternatively you could use a for loop
String initial = "";
for(int i = 0; i < names.length; i++){
initial += names[i].subString(0,1);
}

You were close..
String[] name = myString.split(" ");
String finalName = name[0].charAt(0)+""+(name.length==1?"":name[1].charAt(0));
(name.length==1?"":name[1].charAt(0)) is a ternary operator which would return empty string if length of name array is 1 else it would return 1st character

This will work for you
public static void getString(String str) throws IOException {
String[] strr=str.split(" ");
StringBuilder sb=new StringBuilder();
for(int i=0;i<strr.length;i++){
sb.append(strr[i].charAt(0));
}
System.out.println(sb);
}

Extract string text into another strings

I got a string like this:
String text = number|name|url||number2|name2|url2
Now I have written a loop
int initialiaze = 0;
for(i = initialize; i > text.length(); i++) {
//do the work
}
In this loop I want to extract number to one string, name to one string, url to one string and if I reach || do a action (e.g insert this three string into db) if this action is done, start again an extract number2, name2 and url2 into string and do a action.
Is this possible? Can you tell me how? I dont get it.

you can use .split() method for strings.
String[] bigParts = myString.split("\\|\\|");
for(String part : bigParts)
{
String[] words = part.split("\\|");
//save to db or what you want
}

for your case
StringTokenizer stPipe = null;
StringTokenizer stDblPipe = null;
String firstPipeElement=null;
stPipe = new StringTokenizer(text, "|");
if (stPipe.hasMoreElements())
{
firstPipeElement= stPipe.nextElement().toString();
.......
if(firstPipeElement.equals("||"))
{
stDblPipe = new StringTokenizer(firstPipeElement , "||");
.....
}
}
hope this helps

Java is not my language, but worth try,
String text = number|name|url||number2|name2|url2
String[] temp;
String[] temp2;
int i ;
temp = text.split("\\|\\|")
for(i=0;i<temp.length();i++){
temp2 = temp[i].split("\\|");
String no = temp2[0];
String name = temp2[1];
String url = temp2[2];
// Do processing with no, name, url
}
I hope, this would help

string tokenizer in Java

I have a text file which contains data seperated by '|'. I need to get each field(seperated by '|') and process it. The text file can be shown as below :
ABC|DEF||FGHT
I am using string tokenizer(JDK 1.4) for getting each field value. Now the problem is, I should get an empty string after DEF.However, I am not getting the empty space between DEF & FGHT.
My result should be - ABC,DEF,"",FGHT but I am getting ABC,DEF,FGHT

From StringTokenizer documentation :
StringTokenizer is a legacy class that
is retained for compatibility reasons
although its use is discouraged in new
code. It is recommended that anyone
seeking this functionality use the
split method of String or the
java.util.regex package instead.
The following code should work :
String s = "ABC|DEF||FGHT";
String[] r = s.split("\\|");

Use the returnDelims flag and check two subsequent occurrences of the delimiter:
String str = "ABC|DEF||FGHT";
String delim = "|";
StringTokenizer tok = new StringTokenizer(str, delim, true);
boolean expectDelim = false;
while (tok.hasMoreTokens()) {
String token = tok.nextToken();
if (delim.equals(token)) {
if (expectDelim) {
expectDelim = false;
continue;
} else {
// unexpected delim means empty token
token = null;
}
}
System.out.println(token);
expectDelim = true;
}
this prints
ABC
DEF
null
FGHT
The API isn't pretty and therefore considered legacy (i.e. "almost obsolete"). Use it only with where pattern matching is too expensive (which should only be the case for extremely long strings) or where an API expects an Enumeration.
In case you switch to String.split(String), make sure to quote the delimiter. Either manually ("\\|") or automatically using string.split(Pattern.quote(delim));

StringTokenizer ignores empty elements. Consider using String.split, which is also available in 1.4.
From the javadocs:
StringTokenizer is a legacy class that
is retained for compatibility reasons
although its use is discouraged in new
code. It is recommended that anyone
seeking this functionality use the
split method of String or the
java.util.regex package instead.

you can use the constructor that takes an extra 'returnDelims' boolean, and pass true to it.
this way you will receive the delimiters, which will allow you to detect this condition.
alternatively you can just implement your own string tokenizer that does what you need, it's not that hard.

Here is another way to solve this problem
String str = "ABC|DEF||FGHT";
StringTokenizer s = new StringTokenizer(str,"|",true);
String currentToken="",previousToken="";
while(s.hasMoreTokens())
{
//Get the current token from the tokenize strings
currentToken = s.nextToken();
//Check for the empty token in between ||
if(currentToken.equals("|") && previousToken.equals("|"))
{
//We denote the empty token so we print null on the screen
System.out.println("null");
}
else
{
//We only print the tokens except delimiters
if(!currentToken.equals("|"))
System.out.println(currentToken);
}
previousToken = currentToken;
}

Here is a way to split a string into tokens (a token is one or more letters)
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String s = scan.nextLine();
s = s.replaceAll("[^A-Za-z]", " ");
StringTokenizer arr = new StringTokenizer(s, " ");
int n = arr.countTokens();
System.out.println(n);
while(arr.hasMoreTokens()){
System.out.println(arr.nextToken());
}
scan.close();
}

package com.java.String;
import java.util.StringTokenizer;
public class StringWordReverse {
public static void main(String[] kam) {
String s;
String sReversed = "";
System.out.println("Enter a string to reverse");
s = "THIS IS ASHIK SKLAB";
StringTokenizer st = new StringTokenizer(s);
while (st.hasMoreTokens()) {
sReversed = st.nextToken() + " " + sReversed;
}
System.out.println("Original string is : " + s);
System.out.println("Reversed string is : " + sReversed);
}
}
Output:
Enter a string to reverse
Original string is : THIS IS ASHIK SKLAB
Reversed string is : SKLAB ASHIK IS THIS