How can I get the current time in Germany regardless of the location of the user and current device time?
Calendar buttoncal = Calendar.getInstance();
String tdate = new SimpleDateFormat("dd.MM",Locale.GERMANY).format(buttoncal.getTime());
String tday = new SimpleDateFormat("EEEE",Locale.GERMANY).format(buttoncal.getTime());
one_date.setText(tdate.toString());
one_day.setText(tday);
You can specify the timezone that needs to be used:
Calendar c = Calendar.getInstance(TimeZone.getTimeZone("Europe/Berlin"));
For a list of available time zones: TimeZone.getAvailableIDs().
Note: the locale in the SimpleDateFormat is used to read/format strings in that locale - using a German locale, for example, will print the months / days names in German. But it has nothing to do with the time zone.
Try using this:
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm", Locale.GERMANY);
Date date = new Date();
dateFormat.format(date);
You'll get the 'date' in the format "yyyy-MM-dd HH:mm". Then you can use .split() to split the returned string format using space as delimiter. Something like:
String[] str_array = date.toString().split(" ");
String time = str_array[1];
Use android.text.format.Time instead as I suggested over here.
Related
I have a String that formatted MM/dd. I would like to convert it to a Date in format yyyy-MM-dd'T'HH:mm:ss.SSZ.
DateFormat df = new SimpleDateFormat("MM/dd");
String strDate = "06/05";
Date date = new Date();
date = df.parse(strDate);
This makes it a Date, but in the original format.
System.out.println(new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSZ").format(date));
This returns the correct month and day, but nopthing else.
1970-06-05T00:00:00.00-0400
Any idea how I can make it return
CURRENT_YEAR-06-05TCURRENT_TIME
In the question, the date format pattern indicates a desire for 2-digit fractional seconds. SimpleDateFormat cannot do that.
The newer Java 8 Time API can, and you should be using that anyway.
If you're running on Java 6 or 7, get the ThreeTen-Backport library.
To parse a MM/dd formatted string and get a full timestamp with current year and time-of-day, in the default time zone, use the following code:
String strDate = "06/05";
MonthDay monthDay = MonthDay.parse(strDate, DateTimeFormatter.ofPattern("MM/dd"));
ZonedDateTime date = ZonedDateTime.now().with(monthDay);
System.out.println(date.format(DateTimeFormatter.ofPattern("uuuu-MM-dd'T'HH:mm:ss.SSZ")));
Sample Output
2020-06-05T14:52:48.45-0400
I recommend to make use of java.time package. There you go:
var ds = "01/12";
var df = java.time.format.DateTimeFormatter.ofPattern("MM/dd");
var dt = java.time.MonthDay.from(df.parse(ds)).adjustInto(java.time.LocalDateTime.now());
Then you can convert dt to java.util.Date or whatever you like. Or simply use one of java.time formaters to get the desired output.
You are creating a date with only month and day
If you want to use the current year and time, you can create a calendar object and edit the month and day
For something this simple I suggest a different approach, get current time then set month and day from the original string THEN format.
String str = "08/09";
String[] split = str.split("/");
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.MONTH, Integer.parseInt(split[0]));
calendar.set(Calendar.DAY_OF_MONTH, Integer.parseInt(split[1]));
System.out.println(new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS").format(calendar.getTime()));
String strDate = "06-05";
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-"+strDate+"'T'HH:mm:ss.SSZ");
System.out.println(sdf.format(new Date()));
the output:
2020-06-05T23:00:45.306+0400
I have a date stored in a String field in SQLITE with the String value
"/Date(1411472160000+0100)/"
how can I convert this back into a date format , the code below doesn't work. I think I need to convert from the milliseconds first but I cant see how to even get the above text into a long format first ?
any suggestions ?
Date convertedDate = new Date();
SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm",
java.util.Locale.getDefault());
convertedDate = dateFormat.parse(dateString);
return dateFormat.format(convertedDate);
Well, a substring from the indexOf("(") to the indexOf("+") and you should find the date in milli.
From there, I believe you can find the date ;)
String s = "/Date(1411472160000+0100)/";
s = s.substring(s.indexOf("(") + 1, s.indexOf("+"));
Date d = new Date(Long.parseLong(s));
With the same structure, you can find the timezone (+0100) (from "+" to ")") and work with a Calendar to find the right time for the right time area.
First you have to parse out the time value from String i.e. "1411472160000+0100" part.
Here in "1411472160000+0100" , "+0100" is the timezone info. If you don't want to consider the timezone, then you can take following approach.
Approach-1
long timestamp = 1245613885;
Calendar calendar = Calendar.getInstance();
calendar.setTimeZone(TimeZone.getDefault());
calendar.setTimeInMillis(timestamp * 1000);
int year = calendar.get(Calendar.YEAR);
int day = calendar.get(Calendar.DATE);
int hour = calendar.get(Calendar.HOUR_OF_DAY);
int minute = calendar.get(Calendar.MINUTE);
then to get the date in your specified format you can use-
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String dateString = sdf.format(calendar.getTime());
System.out.println(dateString); // 2009-06-21 15:51:25
Besides this approach, there is an excellent Java Date library called JodaTime.
If you want to incorporate the timezone info , you can refer to this constructor from JodaTime.
http://www.joda.org/joda-time/apidocs/org/joda/time/DateTime.html#DateTime-long-org.joda.time.DateTimeZone-
I have used the Calendar class to get the current Date. Now I want to convert that date to Date format so that it can be stored in database with format "yyyy.mm.dd". I tried to convert this using SimpleDateFormat class
String dateString = dateText.getText();
SimpleDateFormat dateFormat = new SimpleDateFormat(" yyyy.mm.dd ");
Date convertedDate = dateFormat.parse(dateString);
but I couldn't convert into Date type.
Try to remove spaces from the format string
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy.mm.dd");
Also if your input date has invalid format you might get a parse exception. Better if you put it into try/catch block.
Notice, that m stands for minute in hour but M for month of year. Make sure you put a valid format pattern.
You havent stated what the error is but its unlikely that you want to use a minute field to parse the month. Use uppercase M:
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy.MM.dd");
get rid of the whitespaces in your pattern
How can I format the "2010-07-14 09:00:02" date string to depict just "9:00"?
Use DateTimeFormatter to convert between a date string and a real LocalDateTime object. with a LocalDateTime as starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the DateTimeFormatter.
String originalString = "2010-07-14 09:00:02";
LocalDateTime dateTime = LocalDateTime.parse(originalString, DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss"));
String newString = DateTimeFormatter.ofPattern("H:mm").format(dateTime); // 9:00
In case you're not on Java 8 or newer yet, use SimpleDateFormat to convert between a date string and a real Date object. with a Date as starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the SimpleDateFormat.
String originalString = "2010-07-14 09:00:02";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(originalString);
String newString = new SimpleDateFormat("H:mm").format(date); // 9:00
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse("2010-07-14 09:00:02");
String time = new SimpleDateFormat("H:mm").format(date);
http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html
A very simple way is to use Formatter (see date time conversions) or more directly String.format as in
String.format("%tR", new Date())
The other answers were good answers when the question was asked. Time moves on, Date and SimpleDateFormat get replaced by newer and better classes and go out of use. In 2017, use the classes in the java.time package:
String timeString = LocalDateTime.parse(dateString, DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss"))
.format(DateTimeFormatter.ofPattern("H:mm"));
The result is the desired, 9:00.
I'm assuming your first string is an actual Date object, please correct me if I'm wrong. If so, use the SimpleDateFormat object: http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html. The format string "h:mm" should take care of it.
If you have date in integers, you could use like here:
Date date = new Date();
date.setYear(2010);
date.setMonth(07);
date.setDate(14)
date.setHours(9);
date.setMinutes(0);
date.setSeconds(0);
String time = new SimpleDateFormat("HH:mm:ss").format(date);
let datestring = "2017-02-14 02:16:28"
let formatter = DateFormatter()
formatter.dateStyle = DateFormatter.Style.full
formatter.timeStyle = DateFormatter.Style.full
formatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
let date = formatter.date(from: datestring)
let date2 = formatter.String(from: date)
I used following code to convert string to date but it is applying timezone of device while conversion.
I don't need this but I want same date/time from that string like
String = "2009-07-31 07:59:17.427"
Date = 2009-07-31 07:59:17.427
Date formatter = new Date(HttpDateParser.parse("2009-07-31 07:59:17.427"));
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
String strCustomDateTime = dateFormat.format(formatter);
You may take in account default timezone offset to date you get after parsing:
public static String StringToDate(String dateToParse) {
Date formatter = new Date(HttpDateParser.parse(dateToParse));
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSS");
int offset = TimeZone.getDefault().getRawOffset();
formatter.setTime(formatter.getTime() + offset);
String strCustomDateTime = dateFormat.format(formatter);
return strCustomDateTime;
}
What is the problem, exactly? You are trying to convert "2009-07-31 07:59:17.427" into a point in time, but, this does not specify a unique point in time -- without a timezone. So you do need a timezone, and the library is necessary picking one, the platform's current timezone.
If the problem is you wish to specify a different time zone, then call DateFormat.setTimeZone():
format.setTimeZone(TimeZone.getTimeZone("your time zone"));