I am a receiving a JSON object and I need to save the values to my DB. But I'm having an issue figuring out how to retrieve the particular values in the JSON object.
In this case, I want to retrieve the values of 'originationNumber' and 'messageBody'
The response object -
{"originationNumber":"***","destinationNumber":"***","messageKeyword":"KEYWORD_***","messageBody":"Answer ","previousPublishedMessageId":"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0","inboundMessageId":"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb"}
Method to receive message -
public String getReceivedMessages(Messaging receivedMessage) {
BasicAWSCredentials awsCredentials = new BasicAWSCredentials(awsAccessKey, awsSecretKey);
AmazonSQS sqsClient = AmazonSQSClientBuilder.standard()
.withCredentials(new AWSStaticCredentialsProvider(awsCredentials))
.withRegion(String.valueOf(awsRegion)).build();
StringBuilder sb = new StringBuilder();
String queueUrl = "https://sqs.us-east-1.amazonaws.com/1234567/GetReceivedMessages";
List<Message> messages = sqsClient.receiveMessage(new ReceiveMessageRequest(queueUrl)
.withMaxNumberOfMessages(1).withWaitTimeSeconds(20)).getMessages();
for (Message message : messages) {
sb.append(message.getBody());
sqsClient.deleteMessage(queueUrl, message.getReceiptHandle());
}
// Save messages to DB
String userId = connectionRequestRepository.getUserId();
Date date = new Date();
Timestamp now = new Timestamp(date.getTime());
receivedMessage.setUserId(userId);
receivedMessage.setOriginationNumber("");
receivedMessage.setDestinationNumber("***");
receivedMessage.setMessageBody("");
receivedMessage.setMessageType("RECEIVED");
receivedMessage.setCreatedAt(now);
messagingRepository.save(receivedMessage);
System.out.println(sb); <--- Prints response object to console
return sb.toString();
}
You can use jackson library for that.
Solution 1: You can use ObjectMapper as below:
Message Class to map JSON to Java Object:
public class Message {
private String originationNumber;
private String messageBody;
// public getter and setters methods
}
Create Object From JSON String:
Message message = null;
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
try {
message = objectMapper.readValue(payload, Message.class);
} catch (JsonProcessingException e) {
// Log Or do some action as per need
}
Here message will have those values. DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES is used here to skip exception as there are other fields also in JSON and not present in Java Class (as we don't need them).
Solution 2: Alternatively you can use JsonNode from same Jackson library and read nodes one by one as below:
ObjectMapper mapper = new ObjectMapper();
JsonNode actualObj = mapper.readTree("{\"originationNumber\":\"***\",\"destinationNumber\":\"***\",\"messageKeyword\":\"KEYWORD_***\",\"messageBody\":\"Answer \",\"previousPublishedMessageId\":\"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0\",\"inboundMessageId\":\"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb\"}");
String originationNumber = actualObj.get("originationNumber");
String messageBody = actualObj.get("messageBody");
In this approach you won't need to create Message class.
You can convert the json string into a json object
https://www.javatpoint.com/how-to-convert-string-to-json-object-in-java
String string = "{\"originationNumber\":\"***\",\"destinationNumber\":\"***\",\"messageKeyword\":\"KEYWORD_***\",\"messageBody\":\"Answer \",\"previousPublishedMessageId\":\"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0\",\"inboundMessageId\":\"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb\"}";
JSONObject json = new JSONObject(string);
System.out.println(json.toString());
String destinationNumber = json.getString("destinationNumber");
System.out.println(destinationNumber);
where ur json like
{"originationNumber":"***",
"destinationNumber":"***",
"messageKeyword":"KEYWORD_***",
"messageBody":"Answer","previousPublishedMessageId":"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0",
"inboundMessageId":"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb"
}
it like
"key":Value
i think ur code will be like
receivedMessage.setUserId(userId);
receivedMessage.setOriginationNumber("originationNumber");
receivedMessage.setDestinationNumber("destinationNumber");
receivedMessage.setMessageBody("messageBody");
receivedMessage.setMessageType("RECEIVED");
receivedMessage.setCreatedAt(now);
messagingRepository.save(receivedMessage);
The API below accept a json string from client, and the map it into a Email object. How can I get request body (email) as a raw String? (I want both raw-string and typed version of email parameter)
PS: This question is NOT a duplicate of: How to access plain json body in Spring rest controller?
#PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(#RequestBody Email email) {
//...
return new ResponseEntity<>(HttpStatus.OK);
}
You can do it in more than one way, listing two
1. **Taking string as the paramater**,
#PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(#RequestBody String email) {
//... the email is the string can be converted to Json using new JSONObject(email) or using jackson.
return new ResponseEntity<>(HttpStatus.OK);
}
2. **Using Jackson**
#PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(#RequestBody Email email) {
//...
ObjectMapper mapper = new ObjectMapper();
String email = mapper.writeValueAsString(email); //this is in string now
return new ResponseEntity<>(HttpStatus.OK);
}
Spring uses Jackson for this in the back, you could use it to serialize it to an string. Like so:
#Autowired private ObjectMapper jacksonMapper;
#PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(#RequestBody Email email) {
//...
log.info("Object as String: " + jacksonMapper.writeValueAsString(email));
return new ResponseEntity<>(HttpStatus.OK);
}
you can create json of type string using GSON library
Gson gson = new Gson();
#PostMapping(value = "/endpoint")
public ResponseEntity<Void> actionController(#RequestBody Car car) {
//...
log.info("Object as String: " + this.gson.toJson(car));
return new ResponseEntity<>(HttpStatus.OK);
}
I did not get all things about this question, but I try to answer as I understand. Well,
if you want to get request body:
as you say How to access plain json body in Spring rest controller? here already writen how to do this. If something wrong, maybe you send wrong json or not suitable type as you wite inside Email class. Maybe your request comes url filter
second way try like this:
private final ObjectMapper mapper = new ObjectMapper();
#PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(HttpServletRequest req) {
// read request body
InputStream body = req.getInputStream();
byte[] result = ByteStreams.toByteArray(body);
String text =new String(result,"UTF-8");
//convert to object
Email email = mapper.readValue(body, Email .class);
return new ResponseEntity<>(HttpStatus.OK);
}
If you want to convert object to json string read this post
I am writing automation script to validate json responses of REST APIs and i am using faster xml to serialize and convert java object to json format.
I have a user case where I have to get the json response and add a new array element to an existing array and post it back.
The json response after GET looks like this :
{
"name":"test",
"id":"1234",
"nodes":[
{
"nodeId":"node1"
},
{
"nodeId":"node2"
}
]
}
To this json response, I need to add a third entry for nodes array
{ "nodeId": "node3" } and then post this.
Can someone please help me understand how to add a new array element to an existing array?
You can try:
//Your JSON response will be in this format
String response = "{ \"name\":\"test\", \"id\":\"1234\", \"nodes\":[ { \"nodeId\":\"node1\" }, { \"nodeId\":\"node2\" } ] }";
try {
JSONObject jsonResponse = new JSONObject(response);
JSONArray nodesArray = jsonResponse.getJSONArray("nodes");
JSONObject newEntry = new JSONObject();
newEntry.put("nodeId","node3");
nodesArray.put(newEntry);
jsonResponse.put("nodes",nodesArray);
} catch (JSONException e) {
e.printStackTrace();
}
Now you can post your jsonResponse.toString() as required.
I would rather go for cleaner approach, create Object with below structure -
public class Response{
private String name;
private int id;
private List<Node> nodes;
<Getter & Setter>
}
public class Node{
private String nodeId;
}
Serialize the json -
Response response = objectMapper.readValue(responseJson,
Response.class);
Add the new incoming node object to response -
response.getNodes().add(New Node("{new node Value}"));
Deserialize before post -
objectMapper.writeValueAsString(response);
I will like to use the JSON response inside a controller. I am calling a method that returns the JSON. See my code below. Please how do I loop through the Json object returned inside my controller. I need to use the properties like sending mail to the email addresses from another method inside my controller .
My method that does that returns the JSON :
#ResponseBody
private ResponseEntity<?> queryIsw(String ref, String amt) throws Exception{
String pdtid = "62";
String salt = "D3D1D05AFE42AD50818167EAC73C109168A0F108";
RestTemplate restt = new RestTemplate();
String uri = "https://bestng.com/gettransaction.json";
MultiValueMap<String, String> params = new LinkedMultiValueMap<String, String>();
params.add("productid", pdtid);
params.add("transactionreference", ref);
params.add("amount", amt);
UriComponents uriComponents = UriComponentsBuilder.fromHttpUrl(uri).queryParams(params).build();
URI oro = uriComponents.toUri();
HttpHeaders hea = new HttpHeaders();
String hs = pasher(pdtid, ref, salt);
hea.add("hash", hs);
HttpEntity<String> hent = new HttpEntity<String>(hea);
ResponseEntity<Object> resp = restt.exchange(oro, HttpMethod.GET, hent, Object.class);
return resp;
}
Below is my call to this method above from another method :
ResponseEntity<?> dres = queryIsw(dref,ama);
Kindly explain how I can use properties of 'dres' returned in my controller .
Thanks
Try taking a look at the Jackson JSON to Java mapping tools and specifically the ObjectMapper. It can convert a properly formatted JSON string into an object hierarchy from which you can pull out the data that you need. Jackson is a frequently used tool for this activity. Take a look at the tutorial for more details:
http://www.mkyong.com/java/how-to-convert-java-object-to-from-json-jackson/
If you need more help, do ask.
I am assuming that it will return within the body of the ResponseEntity.
Try:
String body = dres.getBody();
You can use something that can parse that string to a json object. Something like:
JSONObject jObject = new JSONObject(body);
See:
http://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/http/ResponseEntity.html
Java String to JSON conversion
I have String variable called jsonString:
{"phonetype":"N95","cat":"WP"}
Now I want to convert it into JSON Object. I searched more on Google but didn't get any expected answers!
Using org.json library:
try {
JSONObject jsonObject = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");
}catch (JSONException err){
Log.d("Error", err.toString());
}
To anyone still looking for an answer:
JSONParser parser = new JSONParser();
JSONObject json = (JSONObject) parser.parse(stringToParse);
You can use google-gson. Details:
Object Examples
class BagOfPrimitives {
private int value1 = 1;
private String value2 = "abc";
private transient int value3 = 3;
BagOfPrimitives() {
// no-args constructor
}
}
(Serialization)
BagOfPrimitives obj = new BagOfPrimitives();
Gson gson = new Gson();
String json = gson.toJson(obj);
==> json is {"value1":1,"value2":"abc"}
Note that you can not serialize objects with circular references since that will result in infinite recursion.
(Deserialization)
BagOfPrimitives obj2 = gson.fromJson(json, BagOfPrimitives.class);
==> obj2 is just like obj
Another example for Gson:
Gson is easy to learn and implement, you need to know is the following two methods:
-> toJson() – convert java object to JSON format
-> fromJson() – convert JSON into java object
import com.google.gson.Gson;
public class TestObjectToJson {
private int data1 = 100;
private String data2 = "hello";
public static void main(String[] args) {
TestObjectToJson obj = new TestObjectToJson();
Gson gson = new Gson();
//convert java object to JSON format
String json = gson.toJson(obj);
System.out.println(json);
}
}
Output
{"data1":100,"data2":"hello"}
Resources:
Google Gson Project Home Page
Gson User Guide
Example
There are various Java JSON serializers and deserializers linked from the JSON home page.
As of this writing, there are these 22:
JSON-java.
JSONUtil.
jsonp.
Json-lib.
Stringtree.
SOJO.
json-taglib.
Flexjson.
Argo.
jsonij.
fastjson.
mjson.
jjson.
json-simple.
json-io.
google-gson.
FOSS Nova JSON.
Corn CONVERTER.
Apache johnzon.
Genson.
cookjson.
progbase.
...but of course the list can change.
Java 7 solution
import javax.json.*;
...
String TEXT;
JsonObject body = Json.createReader(new StringReader(TEXT)).readObject()
;
To convert String into JSONObject you just need to pass the String instance into Constructor of JSONObject.
Eg:
JSONObject jsonObj = new JSONObject("your string");
String to JSON using Jackson with com.fasterxml.jackson.databind:
Assuming your json-string represents as this: jsonString = {"phonetype":"N95","cat":"WP"}
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
/**
* Simple code exmpl
*/
ObjectMapper mapper = new ObjectMapper();
JsonNode node = mapper.readTree(jsonString);
String phoneType = node.get("phonetype").asText();
String cat = node.get("cat").asText();
I like to use google-gson for this, and it's precisely because I don't need to work with JSONObject directly.
In that case I'd have a class that will correspond to the properties of your JSON Object
class Phone {
public String phonetype;
public String cat;
}
...
String jsonString = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}";
Gson gson = new Gson();
Phone fooFromJson = gson.fromJson(jsonString, Phone.class);
...
However, I think your question is more like, How do I endup with an actual JSONObject object from a JSON String.
I was looking at the google-json api and couldn't find anything as straight forward as
org.json's api which is probably what you want to be using if you're so strongly in need of using a barebones JSONObject.
http://www.json.org/javadoc/org/json/JSONObject.html
With org.json.JSONObject (another completely different API) If you want to do something like...
JSONObject jsonObject = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");
System.out.println(jsonObject.getString("phonetype"));
I think the beauty of google-gson is that you don't need to deal with JSONObject. You just grab json, pass the class to want to deserialize into, and your class attributes will be matched to the JSON, but then again, everyone has their own requirements, maybe you can't afford the luxury to have pre-mapped classes on the deserializing side because things might be too dynamic on the JSON Generating side. In that case just use json.org.
Those who didn't find solution from posted answers because of deprecation issues, you can use JsonParser from com.google.gson.
Example:
JsonObject jsonObject = JsonParser.parseString(jsonString).getAsJsonObject();
System.out.println(jsonObject.get("phonetype"));
System.out.println(jsonObject.get("cat"));
you must import org.json
JSONObject jsonObj = null;
try {
jsonObj = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");
} catch (JSONException e) {
e.printStackTrace();
}
Codehaus Jackson - I have been this awesome API since 2012 for my RESTful webservice and JUnit tests. With their API, you can:
(1) Convert JSON String to Java bean
public static String beanToJSONString(Object myJavaBean) throws Exception {
ObjectMapper jacksonObjMapper = new ObjectMapper();
return jacksonObjMapper.writeValueAsString(myJavaBean);
}
(2) Convert JSON String to JSON object (JsonNode)
public static JsonNode stringToJSONObject(String jsonString) throws Exception {
ObjectMapper jacksonObjMapper = new ObjectMapper();
return jacksonObjMapper.readTree(jsonString);
}
//Example:
String jsonString = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}";
JsonNode jsonNode = stringToJSONObject(jsonString);
Assert.assertEquals("Phonetype value not legit!", "N95", jsonNode.get("phonetype").getTextValue());
Assert.assertEquals("Cat value is tragic!", "WP", jsonNode.get("cat").getTextValue());
(3) Convert Java bean to JSON String
public static Object JSONStringToBean(Class myBeanClass, String JSONString) throws Exception {
ObjectMapper jacksonObjMapper = new ObjectMapper();
return jacksonObjMapper.readValue(JSONString, beanClass);
}
REFS:
Codehaus Jackson
JsonNode API - How to use, navigate, parse and evaluate values from a JsonNode object
Tutorial - Simple tutorial how to use Jackson to convert JSON string to JsonNode
Converting String to Json Object by using org.json.simple.JSONObject
private static JSONObject createJSONObject(String jsonString){
JSONObject jsonObject=new JSONObject();
JSONParser jsonParser=new JSONParser();
if ((jsonString != null) && !(jsonString.isEmpty())) {
try {
jsonObject=(JSONObject) jsonParser.parse(jsonString);
} catch (org.json.simple.parser.ParseException e) {
e.printStackTrace();
}
}
return jsonObject;
}
To convert a string to json and the sting is like json. {"phonetype":"N95","cat":"WP"}
String Data=response.getEntity().getText().toString(); // reading the string value
JSONObject json = (JSONObject) new JSONParser().parse(Data);
String x=(String) json.get("phonetype");
System.out.println("Check Data"+x);
String y=(String) json.get("cat");
System.out.println("Check Data"+y);
Use JsonNode of fasterxml for the Generic Json Parsing. It internally creates a Map of key value for all the inputs.
Example:
private void test(#RequestBody JsonNode node)
input String :
{"a":"b","c":"d"}
If you are using http://json-lib.sourceforge.net
(net.sf.json.JSONObject)
it is pretty easy:
String myJsonString;
JSONObject json = JSONObject.fromObject(myJsonString);
or
JSONObject json = JSONSerializer.toJSON(myJsonString);
get the values then with
json.getString(param) or/and json.getInt(param) and so on.
No need to use any external library.
You can use this class instead :) (handles even lists , nested lists and json)
public class Utility {
public static Map<String, Object> jsonToMap(Object json) throws JSONException {
if(json instanceof JSONObject)
return _jsonToMap_((JSONObject)json) ;
else if (json instanceof String)
{
JSONObject jsonObject = new JSONObject((String)json) ;
return _jsonToMap_(jsonObject) ;
}
return null ;
}
private static Map<String, Object> _jsonToMap_(JSONObject json) throws JSONException {
Map<String, Object> retMap = new HashMap<String, Object>();
if(json != JSONObject.NULL) {
retMap = toMap(json);
}
return retMap;
}
private static Map<String, Object> toMap(JSONObject object) throws JSONException {
Map<String, Object> map = new HashMap<String, Object>();
Iterator<String> keysItr = object.keys();
while(keysItr.hasNext()) {
String key = keysItr.next();
Object value = object.get(key);
if(value instanceof JSONArray) {
value = toList((JSONArray) value);
}
else if(value instanceof JSONObject) {
value = toMap((JSONObject) value);
}
map.put(key, value);
}
return map;
}
public static List<Object> toList(JSONArray array) throws JSONException {
List<Object> list = new ArrayList<Object>();
for(int i = 0; i < array.length(); i++) {
Object value = array.get(i);
if(value instanceof JSONArray) {
value = toList((JSONArray) value);
}
else if(value instanceof JSONObject) {
value = toMap((JSONObject) value);
}
list.add(value);
}
return list;
}
}
To convert your JSON string to hashmap use this :
HashMap<String, Object> hashMap = new HashMap<>(Utility.jsonToMap(
For setting json single object to list
ie
"locations":{
}
in to List<Location>
use
ObjectMapper mapper = new ObjectMapper();
mapper.configure(DeserializationConfig.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY, true);
jackson.mapper-asl-1.9.7.jar
NOTE that GSON with deserializing an interface will result in exception like below.
"java.lang.RuntimeException: Unable to invoke no-args constructor for interface XXX. Register an InstanceCreator with Gson for this type may fix this problem."
While deserialize; GSON don't know which object has to be intantiated for that interface.
This is resolved somehow here.
However FlexJSON has this solution inherently. while serialize time it is adding class name as part of json like below.
{
"HTTPStatus": "OK",
"class": "com.XXX.YYY.HTTPViewResponse",
"code": null,
"outputContext": {
"class": "com.XXX.YYY.ZZZ.OutputSuccessContext",
"eligible": true
}
}
So JSON will be cumber some; but you don't need write InstanceCreator which is required in GSON.
Using org.json
If you have a String containing JSON format text, then you can get JSON Object by following steps:
String jsonString = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}";
JSONObject jsonObj = null;
try {
jsonObj = new JSONObject(jsonString);
} catch (JSONException e) {
e.printStackTrace();
}
Now to access the phonetype
Sysout.out.println(jsonObject.getString("phonetype"));
Better Go with more simpler way by using org.json lib. Just do a very simple approach as below:
JSONObject obj = new JSONObject();
obj.put("phonetype", "N95");
obj.put("cat", "WP");
Now obj is your converted JSONObject form of your respective String. This is in case if you have name-value pairs.
For a string you can directly pass to the constructor of JSONObject. If it'll be a valid json String, then okay otherwise it'll throw an exception.