I want Grizzly to serve static files from within a .jar, which contains a JAX-RS application, Grizzly and all other libs. I'm using org.glassfish.grizzly.http.server.StaticHttpHandler to serve the static files.
public class Main {
// ...
public static void main(String[] args) throws IOException, URISyntaxException {
final HttpServer server = startServer();
server.getServerConfiguration().addHttpHandler(
new StaticHttpHandler(getTemplatePath()), "/static");
System.in.read();
server.stop();
}
private static String getTemplatePath() throws URISyntaxException {
return Main.class.getClassLoader().getResource("templates/static").getPath();
}
}
But it works only, if I start the application with my IDE. If I pack a .jar and run it, the static files are not found.
Is it possible to serve static files from within a .jar with grizzly's StaticHttpHandler? And how?
You have to use CLStaticHttpHandler instead of StaticHttpHandler.
Please take a look at this question
html server grizzly+jersey (.html from .jar archive)
Related
I am trying to check if file exists in project. When I start my application through Intellij idea and check if file exists it's return true but when I create jlink build and start it through .bat and check if file exists it's always return false.
public class App {
public static String getPathToDllTest(String filename) throws URISyntaxException {
return Paths.get(App.class.getResource("files/" + filename + ".txt").toURI()).toString();
}
public static void main(String[] args) throws Exception {
File txt = new File(App.getPathToDllTest("test"));
System.out.println(txt.exists());
}
}
Here is basic Maven project resources structure I use:
src
main
java
com
example
App.java
resources
com
example
files
test.txt
Is there problem in path? How can I fix it?
I have a Java program that is able to change the wallpaper taking in input an image using WINAPI.
Everything works fine when I run it inside Eclipse IDE, but when I run the JAR I got the error:
Caused by: java.lang.IllegalArgumentException: URI is not hierarchical
public class Main {
//INIT USER32 for WINAPI
public static interface User32 extends Library {
User32 INSTANCE = (User32) Native.loadLibrary("user32",User32.class,W32APIOptions.DEFAULT_OPTIONS);
boolean SystemParametersInfo (int one, int two, String s ,int three);
}
public static void main(String[] args) throws IOException, URISyntaxException {
//Change wallpaper
System.out.println("Change wallpaper");
URL url = Main.class.getResource("/resources/img.jpg");
File f = new File(url.toURI());
String path = f.getPath();
User32.INSTANCE.SystemParametersInfo(0x0014, 0, path , 1);
}
}
The image is shipped within the JAR, so maybe the error is related to this since the program is not able to correctly read to URL inside the JAR.
Is there a way to solve this?
A jar file is just a compressed file when the resource is bundled as a jar java will be treated as a single file, which means it will not access to your resources.
try using this instead getResourceAsStream(...);
I am using Grizzly to serve my REST service which can have multiple "modules". I'd like to be able to use the same base URL for the service and for static content so I can access all these urls:
http://host:port/index.html
http://host:port/module1/index.html
http://host:port/module1/resource
http://host:port/module2/index.html
http://host:port/module2/resource
The code I'm trying to set this up with looks like this:
private HttpServer createServer(String host, int port, ResourceConfig config)
{
HttpServer server = GrizzlyHttpServerFactory.createHttpServer(URI.create("http://" + host + ":" + port + "/"), config, false);
HttpHandler httpHandler = new CLStaticHttpHandler(HttpServer.class.getClassLoader(), "docs/");
server.getServerConfiguration().addHttpHandler(httpHandler, "/");
return server;
}
With this code, I am only able to see the html pages and I get a "Resource identified by path does not exist" response when I try to get my resources.
When I comment out the code to add the HttpHandler, then I am able to access my resources (but don't have the docs of course).
What do I need to do to access both my resources and my static content?
I ended up writing a service to handle static resources myself. I decided to serve my files from the file system, but this approach would also work for serving them from a jar - you'd just have to get the file as a resource instead of creating the File directly.
#Path("/")
public class StaticService
{
#GET
#Path("/{docPath:.*}.{ext}")
public Response getHtml(#PathParam("docPath") String docPath, #PathParam("ext") String ext, #HeaderParam("accept") String accept)
{
File file = new File(cleanDocPath(docPath) + "." + ext);
return Response.ok(file).build();
}
#GET
#Path("{docPath:.*}")
public Response getFolder(#PathParam("docPath") String docPath)
{
File file = null;
if ("".equals(docPath) || "/".equals(docPath))
{
file = new File("index.html");
}
else
{
file = new File(cleanDocPath(docPath) + "/index.html");
}
return Response.ok(file).build();
}
private String cleanDocPath(String docPath)
{
if (docPath.startsWith("/"))
{
return docPath.substring(1);
}
else
{
return docPath;
}
}
}
One thing you can do is run Grizzly as a servlet container. That way you can run Jersey as servlet filter, and add a default servlet to handle the static content. For example
public class Main {
public static HttpServer createServer() {
WebappContext context = new WebappContext("GrizzlyContext", "");
createJerseyFilter(context);
createDefaultServlet(context);
HttpServer server = GrizzlyHttpServerFactory
.createHttpServer(URI.create("http://localhost:8080/"));
context.deploy(server);
return server;
}
private static void createJerseyFilter(WebappContext context) {
ResourceConfig rc = new ResourceConfig().packages("com.grizzly.test");
// This causes Jersey to forward 404s to default servlet
// which will catch all the static content requests.
rc.property(ServletProperties.FILTER_FORWARD_ON_404, true);
FilterRegistration reg = context.addFilter("JerseyApp", new ServletContainer(rc));
reg.addMappingForUrlPatterns(EnumSet.allOf(DispatcherType.class), "/*");
}
private static void createDefaultServlet(WebappContext context) {
ArraySet<File> baseDir = new ArraySet<>(File.class);
baseDir.add(new File("."));
ServletRegistration defaultServletReg
= context.addServlet("DefaultServlet", new DefaultServlet(baseDir) {});
defaultServletReg.addMapping("/*");
}
public static void main(String[] args) throws IOException {
HttpServer server = createServer();
System.in.read();
server.stop();
}
}
You will need to add the Jersey Grizzly servlet dependency
<dependency>
<groupId>org.glassfish.jersey.containers</groupId>
<artifactId>jersey-container-grizzly2-servlet</artifactId>
<version>${jersey2.version}</version>
</dependency>
The only problem with this approach is that the default servlet is meant to serve files from the file system, not from the classpath, as you are currently trying to do. You can see in the createDefaultServlet method I just set the base directory to the current working directory. So that's where all your files would need to be. You can change it to "docs" so all your files would be in the docs folder, which would be in the current working directory.
If you want to read files from the classpath, you may need to implement your own servlet. You can look at the source code for DefaultServlet and try to modify it to serve from the classpath. You can also check out Dropwizard's AssetServlet, which already does serve content from the classpath.
Or you can just say forget it, and just serve from the file system :-)
I have a dropwizard project and I have maintained a config.yml file at the ROOT of the project (basically at the same level as pom.xml). Here I have specified the HTTP port to be used as follows:
http:
port:9090
adminPort:9091
I have the following code in my TestService.java file
public class TestService extends Service<TestConfiguration> {
#Override
public void initialize(Bootstrap<TestConfiguration> bootstrap) {
bootstrap.setName("test");
}
#Override
public void run(TestConfiguration config, Environment env) throws Exception {
// initialize some resources here..
}
public static void main(String[] args) throws Exception {
new TestService().run(new String[] { "server" });
}
}
I expect the config.yml file to be used to determine the HTTP port. However the app always seems to start with the default ports 8080 and 8081. Also note that I am running this from eclipse.
Any insights as to what am I doing wrong here ?
Try running your service as follows:
Rewrite your main method into:
public static void main(String[] args) throws Exception {
new TestService().run(args);
}
Then in eclipse go to Run --> Run configurations...., create a new run configuration for your class, go to arguments and add "server path/to/config.yml" in "program arguments". If you put it in the root directory, it would be "server config.yml"
I believe you are not passing the location/name of the .yml file and thus your configurations are not being loaded. Another solution is to just add the location of your config file to the array you're passing into run ;)
I'm trying to write a test for a Mule flow that will involve dropping a file in a location, waiting for it to be processed by my flow and compare the output to see if it has been transformed correctly. My flow looks as follows:
<flow name="mainFlow" processingStrategy="synchronous">
<file:inbound-endpoint name="fileIn" path="${inboundPath}">
<file:filename-regex-filter pattern="myFile.csv" caseSensitive="true"/>
</file:inbound-endpoint>
...
<file:outbound-endpoint path="${outboundPath}" outputPattern="out.csv"/>
</flow>
Is there a way I can access the inboundPath and outboundPath Mule properties inside of my test class so that I can drop files and wait for output in the correct places?
The test class I'm using is:
public class MappingTest extends BaseFileToFileFunctionalTest {
#Override
protected String getConfigResources() {
return "mappingtest.xml";
}
#Test
public void testMapping() throws Exception {
dropInputFileIntoPlace("myFile.csv");
waitForOutputFile("out.csv", 100);
assertEquals(getExpectedOutputFile("expected-out.csv"), getActualOutputFile("out.csv"));
}
}
Which extends this class:
public abstract class BaseFileToFileFunctionalTest extends FunctionalTestCase {
private static final File INPUT_DIR = new File("/tmp/muletest/input");
private static final File OUTPUT_DIR = new File("/tmp/muletest/output");
private static final Charset CHARSET = Charsets.UTF_8;
#Before
public void setup() {
new File("/tmp/muletest/input").mkdirs();
new File("/tmp/muletest/output").mkdirs();
empty(INPUT_DIR);
empty(OUTPUT_DIR);
}
private void empty(File inputDir) {
for (File file : inputDir.listFiles()) {
file.delete();
}
}
protected File waitForOutputFile(String expectedFileName, int retryAttempts) throws InterruptedException {
boolean polling = true;
int attemptsRemaining = retryAttempts;
File outputFile = new File(OUTPUT_DIR, expectedFileName);
while (polling) {
Thread.sleep(100L);
if (outputFile.exists()) {
polling = false;
}
if (attemptsRemaining == 0) {
VisibleAssertions.fail("Output file did not appear within expected time");
}
attemptsRemaining--;
}
outputFile.deleteOnExit();
return outputFile;
}
protected void dropInputFileIntoPlace(String inputFileResourceName) throws IOException {
File inputFile = new File(INPUT_DIR, inputFileResourceName);
Files.copy(Resources.newInputStreamSupplier(Resources.getResource(inputFileResourceName)), inputFile);
inputFile.deleteOnExit();
}
protected String getActualOutputFile(String outputFileName) throws IOException {
File outputFile = new File(OUTPUT_DIR, outputFileName);
return Files.toString(outputFile, CHARSET);
}
protected String getExpectedOutputFile(String resourceName) throws IOException {
return Resources.toString(Resources.getResource(resourceName), CHARSET);
}
}
As you can see I'm currently creating temporary input/output directories. I'd like to make this part read from the Mule properties if possible? Thanks in advance.
After observing your test classes and code I could see that you want to dynamically create temp folders place files in them. And the flow should read the files from Temp Directory and write output to another Temp directory. Point to be noted is that Mule's Endpoints are created when the configuration is loaded. So the ${inbound} and ${outbound} should be provided to the mule flow by the time they are provided.
So one option can be to create a dummy flow pointing to the temp folders for testing.
or
Create a test properties file pointing to the temp folders and load that to your flow config, so that your flow endpoints will get the temp folder paths.
In any way path cannot be provided to the flow inbound endpoints after they have been created(on config load).
Update1:
As per your comment the solution with option would be like the following.
Seperate the properties loading part of the config into another config.
Like "mapping-core-config.xml,mappingtest.xml" where the mapping-core-config will have the tags to load the properties file.
Now create a test config file for the mapping-core-config.xml file which loads the test properties file. This should be used in your test config. This way without modifying or disturbing your main code, you can test your flows pointing to temp folders.
"mapping-core-test-config.xml,mappingtest.xml"
Note: The test config can reside in the src/test/resources folders.
Hope this helps.