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Map with object and list of objects to Json

I have got two main model classes: Customer and Product
public class Customer {
String name;
String surname;
int age;
BigDecimal cash;
}
public class Product {
String name;
Category category;
BigDecimal price;
}
I want to build json file with Map<Customer, List<Product>>
When I write to json file data with my method which works correct - I am sure about this - the json file shows this syntax
{
"Customer{name\u003d\u0027Custo1\u0027, surname\u003d\u0027Surname\u0027, age\u003d18, cash\u003d1200}": [
{
"name": "prod1",
"category": "CLOTHES",
"price": 12000
},
{
"name": "prod2",
"category": "ELECTRONIC",
"price": 15000
}
]
}
Then when i want to read this file, the error Exception in thread "main" java.util.NoSuchElementException: No value present occurs so I think that the Customer syntax from json file is not recognized.
So I tried to write data to json file on my own with this syntax below, but it does not work
[
{
"name": "Abc",
"surname": "Def",
"age": 14,
"cash": "2000"
}
:
[
{
"name": "prod1",
"category": "CLOTHES",
"price": 12000
},
{
"name": "prod2",
"category": "ELECTRONIC",
"price": 15000
}
]
]
json converter method:
public void toJson(final T item) {
try (FileWriter fileWriter = new FileWriter(jsonFilename)) {
fileWriter.write(gson.toJson(item));
} catch (Exception e) {
throw new ValidatorException(e.getMessage());
}
}

#Tom is right on the issues you've faced with. I'll explain why and suggest one more solution.
Your first JSON is technically a valid JSON but it cannot be deserialized, because the map keys are results of the Customer.toString() method Gson uses by default. This is why it looks weird, acts like a debug string, and can't be deserialized back: there it is almost always no way to restore an object from the toString() result (toString is designed mostly for debugging/logging purposes providing basic information regarding the state of a particular object that does not need to expose its all internals at all).
Your second JSON is invalid JSON. Period.
Tom's suggestion of making the list of products a part of the customer class is totally fine. Having it implemented like that lets you to serialize everything as a list like this:
[
{
"name": "john",
"products": [
{"name": "prod1"},
{"name": "prod2"}
]
}
]
Hint: separating domain objects (Customer and Product) and representation objects for data transfer (CustomerDto and ProductDto) is usually a fine idea too since it allows to create representation for any concrete representation implementation (one for various JSON implementation libraries, two for other-format-oriented tools, third for persistence, four for UI views, etc), so it might be implemented like converting Map<Customer, List<Product>> to List<CustomerDto> and back (possibly by using mapper-generators like MapStruct).
If for whatever reason it is not possible to reorganize your domain classes or create Gson-friendly DTO-mappings, or you're fine to keep it as simple as possible and you're fine with having not that trivial JSON structure (as long as you understand implications of the format in this solution: evolution, distribution, etc), then you can enable special Gson mode to support this kind of maps. It generates valid JSONs that can be serialized and deserialized back, but the way it is implemented looks a bit of anti-pattern to me because of losing semantics due to using arrays as the data container.
#AllArgsConstructor
#EqualsAndHashCode
#ToString
final class Customer {
final String name;
}
#AllArgsConstructor
#EqualsAndHashCode
#ToString
final class Product {
final String name;
}
public final class MapTest {
private static final Gson gson = new GsonBuilder()
.enableComplexMapKeySerialization()
.create();
private static final TypeToken<Map<Customer, List<Product>>> customerToProducts = new TypeToken<Map<Customer, List<Product>>>() {};
#Test
public void test() {
final Map<Customer, List<Product>> ordersBefore = ImmutableMap.of(
new Customer("john"), ImmutableList.of(new Product("prod1"), new Product("prod2"))
);
final String json = gson.toJson(ordersBefore, customerToProducts.getType());
Assertions.assertEquals("[[{\"name\":\"john\"},[{\"name\":\"prod1\"},{\"name\":\"prod2\"}]]]", json);
final Map<Customer, List<Product>> ordersAfter = gson.fromJson(json, customerToProducts.getType());
Assertions.assertEquals(ordersBefore, ordersAfter);
}
}
Note that it generates JSON like this (index 0 means the key, index 1 means the value):
[
[
{"name": "john"},
[
{"name": "prod1"},
{"name": "prod2"}
]
]
]

Map JSON to POJO Using Jackson

I'm trying to get map a JSON to a POJO using jackson and I keep getting the following error:
> Can not deserialize instance of java.lang.String out of START_OBJECT token\n at [Source: (String)\"{\"checkstyle\
The JSON Im trying to parse is the following:
{
"checkstyle": {
"file": [
{
"name": "src\\main\\java\\com\\report\\uploader\\controller\\RandomController.java",
"error": [
{
"severity": "error",
"line": 0,
"source": "com.puppycrawl.tools.checkstyle.checks.javadoc.JavadocPackageCheck",
"message": "Missing package-info.java file."
}
]
}
],
"version": 6.18
}
}
For this I create the following classes:
public class Checkstyle {
#JsonProperty("checkstyle")
private Linter linterName;
}
public class Linter {
#JsonProperty("file")
private List<File> files;
#JsonProperty("version")
private String version;
}
public class File {
#JsonProperty("name")
private String name;
#JsonProperty("error")
private List<Error> errores;
}
public class Error {
#JsonProperty("severity")
private String severity;
#JsonProperty("line")
private int line;
#JsonProperty("source")
private String source;
#JsonProperty("message")
private String message;
}
But when I run the code I get the error mentioned above. The way I get this JSON is by converting an XML file to a JSONObject using the org.json dependency and then the JSONobject I convert it to a String.
Then I convert then I try to convert the String into my POJO the following way:
ObjectMapper mapper = new ObjectMapper();
Checkstyle checkstyle = mapper.readValue(object.toString(), Checkstyle.class);
If anyone could point me out what I'm doing wrong I would appreciate.

This is the line causing error in your program mapper.readValue(object.toString(), Checkstyle.class). You have already read the json into an anonymous object, and then using its toString() representation in ObjectMapper to map to Checkstyle class, which will never work. As you already have lost the json string into java default toString representation of object: someObjectClassname#hashcodenumber.
Below are the some of the commonly used signature of readValue method to do correrct de-serialization:
readValue(InputStream in, Class c)
readValue(Reader rd, Class c)
readValue(String json, Class c)

How to get plain JSON data in jersey REST implementation?

If we have a POJO class, then we can map it with some incoming JSON. I am struggling to find out a way by which I can just have all plain json value inside.
For ex.
{
"macro_tasks": [
{
"id": "cc5cee68-c1e5-4396-987b-c68559399186",
"label": "consi-1",
"name": "Consi 1",
"project_id": "82d1e463-1bb1-42d3-9adc-9e0d5848d139",
"creator_id": null,
"created_at": null,
"updated_at": null,
"meta_data": {
"key1": "value1",
"key2": 321
}
}
]
}
Here meta_data is of JSON type which can keep changing its values inside. So I cannot map it with some POJO class.
public class MacroTask {
private UUID id;
private String label;
private String name;
private UUID projectId;
private UUID creatorId;
private String createdAt;
private String updatedAt;
private <some data type> meta_data;
//getter and setter
Is there any way to get plain JSON data and use it in code and dump into DB [we are using PostgreSQL, which supports jsonb type.]

I solved it by using Generic JSON type, Jackson's JsonNode. It has some drawbacks as I heard, but I am giving it a try. So far, it's working as per expectations. I will update if I face any challenge or I find any better solution.

You can use map; like
private Map<String, Object> meta_data;

I got following error
Can not deserialize instance of java.lang.String out of START_OBJECT
I was using this code for json string to HasMap conversion.
Map map = mapper.readValue(jsonString, new TypeReference<HashMap<String,String>>(){});
I replaced it with.
Map map = mapper.readValue(jsonString, new TypeReference<HashMap<String,Object>>(){});

How to get java objects from JSONArray url using Jackson in Android

This is my JSON from URL
https://api.myjson.com/bins/142jr
[
{
"serviceNo":"SR0000000001",
"serDate":"17",
"serMonth":"DEC",
"serYear":"2015",
"serTime":"02.30 AM",
"serApartmentName":"Galaxy Apartments"
},
{
"serviceNo":"SR0000000002",
"serDate":"19",
"serMonth":"JUN",
"serYear":"2016",
"serTime":"03.30 AM",
"serApartmentName":"The Great Apartments"
}
]
I have one ListView I want populate details from online JSON,above i given a link and sample json anybody given sample jackson code in java
Thanks for advance,
Rajesh Rajendiran

To use jackson you need to create a model class:
[
{
"serviceNo":"SR0000000001",
"serDate":"17",
"serMonth":"DEC",
"serYear":"2015",
"serTime":"02.30 AM",
"serApartmentName":"Galaxy Apartments"
},
{
"serviceNo":"SR0000000002",
"serDate":"19",
"serMonth":"JUN",
"serYear":"2016",
"serTime":"03.30 AM",
"serApartmentName":"The Great Apartments"
}
]
For the above the json the model class would be:
public class SomeClass {
private String serviceNo;
private String serDate;
private String serMonth;
private String serYear;
private String serTime;
private String serApartmentName;
#JsonProperty("serviceNo") //to bind it to serviceNo attribute of the json string
public String getServiceNo() {
return serviceNo;
}
public void setServiceNo(String sNo) { //#JsonProperty need not be specified again
serviceNo = sNo;
}
//create getter setters like above for all the properties.
//if you want to avoid a key-value from getting parsed use #JsonIgnore annotation
}
Now whenever you have the above json as string stored in a variable say jsonString use the following code to parse it:
ObjectMapper mapper = new ObjectMapper(); // create once, reuse
ArrayList<SomeClass> results = mapper.readValue(jsonString,
new TypeReference<ArrayList<ResultValue>>() { } );
results should now contain two SomeClass objects having the above json parsed as respective objects.
PS: Its been a long time since I have used Jackson for parsing so this code might need some improvements.

If you are getting this as http response then I would suggest to use spring rest template for android.
It has support for Message Converters. That way the onus of marshaling and unmarshalling.
[Update]
Here is a blog for the same :http://www.journaldev.com/2552/spring-restful-web-service-example-with-json-jackson-and-client-program
Refer Docs for more details:
http://docs.spring.io/spring-android/docs/current/reference/html/rest-template.html

Convert JSON String to Pretty Print JSON output using Jackson

This is the JSON string I have:
{"attributes":[{"nm":"ACCOUNT","lv":[{"v":{"Id":null,"State":null},"vt":"java.util.Map","cn":1}],"vt":"java.util.Map","status":"SUCCESS","lmd":13585},{"nm":"PROFILE","lv":[{"v":{"Party":null,"Ads":null},"vt":"java.util.Map","cn":2}],"vt":"java.util.Map","status":"SUCCESS","lmd":41962}]}
I need to convert the above JSON String into Pretty Print JSON Output (using Jackson), like below:
{
"attributes": [
{
"nm": "ACCOUNT",
"lv": [
{
"v": {
"Id": null,
"State": null
},
"vt": "java.util.Map",
"cn": 1
}
],
"vt": "java.util.Map",
"status": "SUCCESS",
"lmd": 13585
},
{
"nm": "PROFILE
"lv": [
{
"v": {
"Party": null,
"Ads": null
},
"vt": "java.util.Map",
"cn": 2
}
],
"vt": "java.util.Map",
"status": "SUCCESS",
"lmd": 41962
}
]
}
Can anyone provide me an example based on my example above? How to achieve this scenario? I know there are lot of examples, but I am not able to understand those properly. Any help will be appreciated with a simple example.
Updated:
Below is the code I am using:
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.defaultPrettyPrintingWriter().writeValueAsString(jsonString));
But this doesn't works with the way I needed the output as mentioned above.
Here's is the POJO I am using for the above JSON:
public class UrlInfo implements Serializable {
private List<Attributes> attribute;
}
class Attributes {
private String nm;
private List<ValueList> lv;
private String vt;
private String status;
private String lmd;
}
class ValueList {
private String vt;
private String cn;
private List<String> v;
}
Can anyone tell me whether I got the right POJO for the JSON or not?
Updated:
String result = restTemplate.getForObject(url.toString(), String.class);
ObjectMapper mapper = new ObjectMapper();
Object json = mapper.readValue(result, Object.class);
String indented = mapper.defaultPrettyPrintingWriter().writeValueAsString(json);
System.out.println(indented);//This print statement show correct way I need
model.addAttribute("response", (indented));
Below line prints out something like this:
System.out.println(indented);
{
"attributes" : [ {
"nm" : "ACCOUNT",
"error" : "null SYS00019CancellationException in CoreImpl fetchAttributes\n java.util.concurrent.CancellationException\n\tat java.util.concurrent.FutureTask$Sync.innerGet(FutureTask.java:231)\n\tat java.util.concurrent.FutureTask.",
"status" : "ERROR"
} ]
}
which is the way I needed to be shown. But when I add it to model like this:
model.addAttribute("response", (indented));
And then shows it out in a resultform jsp page like below:
<fieldset>
<legend>Response:</legend>
<strong>${response}</strong><br />
</fieldset>
I get something like this:
{ "attributes" : [ { "nm" : "ACCOUNT", "error" : "null
SYS00019CancellationException in CoreImpl fetchAttributes\n
java.util.concurrent.CancellationException\n\tat
java.util.concurrent.FutureTask$Sync.innerGet(FutureTask.java:231)\n\tat
java.util.concurrent.FutureTask.", "status" : "ERROR" } ] }
which I don't need. I needed the way it got printed out above. Can anyone tell me why it happened this way?

To indent any old JSON, just bind it as Object, like:
Object json = mapper.readValue(input, Object.class);
and then write it out with indentation:
String indented = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(json);
this avoids your having to define actual POJO to map data to.
Or you can use JsonNode (JSON Tree) as well.

The simplest and also the most compact solution (for v2.3.3):
ObjectMapper mapper = new ObjectMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
mapper.writeValueAsString(obj)

The new way using Jackson 1.9+ is the following:
Object json = OBJECT_MAPPER.readValue(diffResponseJson, Object.class);
String indented = OBJECT_MAPPER.writerWithDefaultPrettyPrinter()
.writeValueAsString(json);
The output will be correctly formatted!

ObjectMapper.readTree() can do this in one line:
mapper.readTree(json).toPrettyString();
Since readTree produces a JsonNode, this should pretty much always produce equivalent pretty-formatted JSON, as it JsonNode is a direct tree representation of the underlying JSON string.
Prior to Jackson 2.10
The JsonNode.toPrettyString() method was added in Jackson 2.10. Prior to that, a second call to the ObjectMapper was needed to write the pretty formatted result:
mapper.writerWithDefaultPrettyPrinter()
.writeValueAsString(mapper.readTree(json));

For Jackson 1.9, We can use the following code for pretty print.
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.enable(SerializationConfig.Feature.INDENT_OUTPUT);

I think, this is the simplest technique to beautify the json data,
String indented = (new JSONObject(Response)).toString(4);
where Response is a String.
Simply pass the 4(indentSpaces) in toString() method.
Note: It works fine in the android without any library. But in java you have to use the org.json library.

You can achieve this using bellow ways:
1. Using Jackson
String formattedData=new ObjectMapper().writerWithDefaultPrettyPrinter()
.writeValueAsString(YOUR_JSON_OBJECT);
Import bellow class:
import com.fasterxml.jackson.databind.ObjectMapper;
It's gradle dependency is :
compile 'com.fasterxml.jackson.core:jackson-core:2.7.3'
compile 'com.fasterxml.jackson.core:jackson-annotations:2.7.3'
compile 'com.fasterxml.jackson.core:jackson-databind:2.7.3'
2. Using Gson from Google
String formattedData=new GsonBuilder().setPrettyPrinting()
.create().toJson(YOUR_OBJECT);
Import bellow class:
import com.google.gson.Gson;
It's gradle is:
compile 'com.google.code.gson:gson:2.8.2'
Here, you can also download correct updated version from repository.

This looks like it might be the answer to your question. It says it's using Spring, but I think that should still help you in your case. Let me inline the code here so it's more convenient:
import java.io.FileReader;
import org.codehaus.jackson.map.ObjectMapper;
import org.codehaus.jackson.map.ObjectWriter;
public class Foo
{
public static void main(String[] args) throws Exception
{
ObjectMapper mapper = new ObjectMapper();
MyClass myObject = mapper.readValue(new FileReader("input.json"), MyClass.class);
// this is Jackson 1.x API only:
ObjectWriter writer = mapper.defaultPrettyPrintingWriter();
// ***IMPORTANT!!!*** for Jackson 2.x use the line below instead of the one above:
// ObjectWriter writer = mapper.writer().withDefaultPrettyPrinter();
System.out.println(writer.writeValueAsString(myObject));
}
}
class MyClass
{
String one;
String[] two;
MyOtherClass three;
public String getOne() {return one;}
void setOne(String one) {this.one = one;}
public String[] getTwo() {return two;}
void setTwo(String[] two) {this.two = two;}
public MyOtherClass getThree() {return three;}
void setThree(MyOtherClass three) {this.three = three;}
}
class MyOtherClass
{
String four;
String[] five;
public String getFour() {return four;}
void setFour(String four) {this.four = four;}
public String[] getFive() {return five;}
void setFive(String[] five) {this.five = five;}
}

Since jackson-databind:2.10 JsonNode has the toPrettyString() method to easily format JSON:
objectMapper
.readTree("{}")
.toPrettyString()
;
From the docs:
public String toPrettyString()
Alternative to toString() that will
serialize this node using Jackson default pretty-printer.
Since:
2.10

If you format the string and return object like RestApiResponse<String>, you'll get unwanted characters like escaping etc: \n, \". Solution is to convert your JSON-string into Jackson JsonNode object and return RestApiResponse<JsonNode>:
ObjectMapper mapper = new ObjectMapper();
JsonNode tree = objectMapper.readTree(jsonString);
RestApiResponse<JsonNode> response = new RestApiResponse<>();
apiResponse.setData(tree);
return response;

Anyone using POJO, DDO, or response class for returning their JSON can use spring.jackson.serialization.indent-output=true in their property file. It auto-formats the response.