Develop Reference

How to write / convert CURL for Android java

I am trying to implement the MOT history API https://dvsa.github.io/mot-history-api-documentation/ and they give an example using CURL which works with the supplied api key successfully when using an online CURL tool.
I am trying to implement this in Android and realise I have to use something like HttpPost rather than CURL, this is my code:
//Tried with full URL and by adding the registration as a header.
//HttpPost httpPost = new HttpPost("https://beta.check-mot.service.gov.uk/trade/vehicles/mot-tests?registration=" + reg_selected);
HttpPost httpPost = new HttpPost("https://beta.check-mot.service.gov.uk/trade/vehicles/mot-tests");
httpPost.addHeader("Content-Type", "application/json");
httpPost.addHeader("Accept", "application/json+v6");
httpPost.addHeader("x-api-key", "abcdefgh123456");
httpPost.addHeader("registration", reg_selected);
StringEntity entity = new StringEntity(jsonObj.toString(), HTTP.UTF_8);
httpPost.setEntity(entity);
HttpClient client = new DefaultHttpClient();
try {
HttpResponse response = client.execute(httpPost);
if (response.getStatusLine().getStatusCode() == 200) {
InputStream inputStream = response.getEntity().getContent();
bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
String readLine = bufferedReader.readLine();
String jsonStr = readLine;
JSONObject myJsonObj = new JSONObject(jsonStr);
}else if (response.getStatusLine().getStatusCode() == 400){
//Bad Request Invalid data in the request. Check your URL and parameters
error_text = "Bad Request";
}else if (response.getStatusLine().getStatusCode() == 403){
//Unauthorised – The x-api-key is missing or invalid in the header
error_text = "Authentication error"; //<<<< FAILS HERE 403
}
response.getStatusLine().getStatusCode() returns • "403 – Unauthorised – The x-api-key is missing or invalid in the header".
However the x-api-key that I use works correctly with the online CURL test so the actual key is correct but how I am adding it to my android code request must be invalid or similar.
Can anyone throw any light as to the correct way to convert the CURL into Android java so that the server does not return 403?
Thanks

It's easy to do with Jsoup:
// CREATE CONNECTION
Connection conn=Jsoup.connect("URL_GOES_HERE");
// ADD POST/FORM DATA
conn.data("KEY", "VALUE");
// ADD HEADERS HERE
conn.header("KEY", "VALUE");
// SET METHOD AS POST
conn.method(Connection.Method.POST);
// ACCEPT RESPONDING CONTENT TYPE
conn.ignoreContentType(true);
try
{
// GET RESPONSE
String response = conn.execute().body();
// USE RESPONSE HERE
// CREATE JSON OBJECT OR ANYTHING...
} catch(HttpStatusException e)
{
int status = e.getStatusCode();
// HANDLE HTTP ERROR HERE
} catch (IOException e)
{
// HANDLE IO ERRORS HERE
}
Ps: I guess you are confused with Header and Post Data. The key etc (Credentials) must be used as Post Data and Content Type etc as Header.

post encrypted json to external api in java

excuse me everyone, I'm currently having problems connecting my spring boot application with an open api IoT. to send data to the open api, the request body must be encrypted and sent in json form. I have followed the available documentation, but the response says that the request parameter must be in json format.
here is my program code:
HttpPost httppost = new HttpPost(url);
httppost.addHeader("x-random-key", randomSecretKey);
httppost.addHeader("x-access-key", xAccessKey);
httppost.addHeader("Content-type", "application/json;charset=UTF-8");
httppost.addHeader("sys_code", "901");
httppost.addHeader("lang", "_en_US");
String encryptedRequestBody = encrypt(request.toString(), randomMessage);
StringEntity strEntity = new StringEntity(encryptedRequestBody);
strEntity.setContentType("application/json");
httppost.setEntity(strEntity);
CloseableHttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
InputStream inputStream = entity.getContent();

How to send binary file using HttpClient approach

I am trying to send a two binary file to one of the REST API. But I get 400 bad request response from the end point.
Need to send below key and values to endpoint.
userForm - user.xml
structureForm - structure.xdp
Below is the java code, [UPDATED CODE]
HttpPost request = new HttpPost(url);
File userForm = new File("D:\\Downloads\\user.xml");
LOG.info("length ---->" + userForm.length()); // See valid file size
HttpEntity userFormEntity = MultipartEntityBuilder.create()
.addPart("userForm", new FileBody(userForm))
.build();
File structureFile = new File("D:\\Downloads\\structure.xdp");
LOG.info("length structureFile ---->" + structureFile.length()); // See valid file size
HttpEntity structureEntity = MultipartEntityBuilder.create()
.addPart("structureForm", new FileBody(structureFile))
.build();
if (userFormEntity != null && structureEntity != null) {
request.setEntity(userFormEntity);
request.setEntity(structureEntity);
}
final CloseableHttpClient httpClient = HttpClientBuilder.create().build();
CloseableHttpResponse response = httpClient.execute(request);
Seemed like the key 'userForm' and 'structureForm' are not going properly to end point. Is it correct way to send the key?
It is working when I try to submit through postman as below

Why am I getting last response if my server doesn't work?

I use simple code to get XML content.
but I have a trouble if my server doesn't work, I get last success response.
I tried all methods:
send every time another URI
setHeader Cache-Content How to prevent Android from returning a cached response to my HTTP Request?
I tried even HttpURLConnection with GET.
but nothing helps
DefaultHttpClient client = new DefaultHttpClient();
String fullPath = path + name;
HttpGet request = new HttpGet(fullPath);
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
InputStream is = entity.getContent();
//....decode input string

How to send image with post request

I need to send post request with data in format like key=value and I am working that like ( url is url of ws and that is ok )
HttpEntityEnclosingRequestBase post=new HttpPost();
String result = "";
HttpClient httpclient = new DefaultHttpClient();
post.setURI(URI.create(url));
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
for (Entry<String, String> arg : args.entrySet()) {
nameValuePairs.add(new BasicNameValuePair(arg.getKey(), arg
.getValue()));
}
http.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response;
response = httpclient.execute(post);
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
result = getStringFromStream(instream);
instream.close();
}
return result;
This is ok when I send String data. My question is what to modify when one parameter is picture adn others are strings ?

When you are using multiple data types to send over a HttpClient you must use MultipartEntityBuilder(Class in org.apache.http.entity.mime)
try this out
MultipartEntityBuilder s= MultipartEntityBuilder.create();
File file = new File("sample.jpeg");
String message = "This is a multipart post";
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
System.out.println(HttpMultipartMode.BROWSER_COMPATIBLE);
builder.addBinaryBody("upfile", file, ContentType.DEFAULT_BINARY, "sample.jpeg");
builder.addTextBody("text", message, ContentType.DEFAULT_BINARY);
HttpEntity entity = builder.build();
httppost.setEntity(entity);
}

If you are looking to send the image as the data portion of the post request, you can follow some of the links posted in the comments.
If the image / binary data must absolutely be a header (which I wouldn't recommend), then you should use the encodeToString method inside of the Base64 Android class. I wouldn't recommend this for big images though since you need to load the entire image into memory as a byte array before you can even convert it to a string. Once you convert it to a string, its also 4/3 its previous size.

I think the answer you're looking for is in this post:
How to send an image through HTTPPost?
Emmanuel