Using a Flood Fill Algorith to create an Array - java

I'm using a flood fill algorithm to sort through an image. If it encounters the same color, I want it copy that pixel over into an identically sized array called filled. The array filled is then transformed back into an image and saved as a jpg. However, when I open the jpg, it appears entirely black.
public static void findFace(int[][] image) throws IOException {
int height = image.length;
int width = image[0].length;
Color centerStart = new Color(image[width / 2][height / 2]);
int[][] filled = new int[width][height];
floodFill(width / 2, height / 2, centerStart, image, filled);
//construct the filled array as image. Show if the face was found.
BufferedImage bufferImage2 = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
int Pixel = filled[x][y] << 16 | filled[x][y] << 8 | filled[x][y];
bufferImage2.setRGB(x, y, Pixel);
}
}
//save filled array as image file
File outputfile = new File("/home/lily/Pictures/APicaDay/saved.jpg");
ImageIO.write(bufferImage2, "jpg", outputfile);
}
public static int[][] floodFill(int x, int y, Color targetColor, int[][] image, int[][] filled) {
if (image[x][y] != targetColor.getRGB()) {
return filled;
}
filled[x][y] = image[x][y];
floodFill(x - 1, y, targetColor, image, filled);
floodFill(x + 1, y, targetColor, image, filled);
floodFill(x, y - 1, targetColor, image, filled);
floodFill(x, y + 1, targetColor, image, filled);
return filled;
}
bonus question: I would like the flood fill to also accept colors that are similar, but not the exact same, since I'm dealing with a photograph.

The floodFill function you've posted is missing two important elements:
If the area containing the same color as the first pixel extends all the way to the boundary of the image, the function will try to access image at an invalid index. You can fix this by first checking the x and y coordinates of the pixel you are checking, and returning immediately if they are out of bounds.
If there is more than one adjacent pixel of the same color, the function will cause recurse infinitely, since the initial call will call floodFill on the second pixel, which will then proceed to call floodFill on the first pixel, and so on. You need a way to make sure that you only call floodFill on a particular pixel once.
Since you're not observing either of these two symptoms, and you don't observe anything from the resulting image, I guess that the initial pixel's color check is not correct. When you pass an integer to the Color constructor, are you sure that it uses an RBG interpretation of that integer?

Related

display grayscale image in java

I created 2D array of floats in java, representing gray scale image, when each pixel is normalized - it between [0,1].
How can I take the 2D array and display the image (in gray scale of course)?
ty!
The easiest way is to make a BufferedImage out of it. To do that, you'll have to convert the values into colors:
int toRGB(float value) {
int part = Math.round(value * 255);
return part * 0x10101;
}
That first converts the 0-1 range into 0-255 range, then produces a color where all three channels (RGB - red, green and blue) have the same value, which makes a gray.
Then, to make the whole image, set all the pixel values:
BufferedImage image = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);
for (int y = 0; y < height; y++)
for (int x = 0; x < width; x++)
image.setRGB(x, y, toRGB(theFloats[y][x]));
Once you have the image, you can save it to a file:
ImageIO.save(image, 'png', new File('some/path/file.png'));
Or, display it in some way, perhaps with Swing.. See for example this question.

Why isn't my method for removing this color working?

I'm trying to make a Mario game clone, and right now, in my constructor, I have a method that is supposed to make a certain color transparent instead of the current pinkish (R: 255, G: 0, B: 254). According to Photoshop, the hex value is ff00fe. My method is:
public Mario(){
this.state = MarioState.SMALL;
this.x = 54;
this.y = 806;
URL spriteAtLoc = getClass().getResource("sprites/Mario/SmallStandFaceRight.bmp");
try{
sprite = ImageIO.read(spriteAtLoc);
int width = sprite.getWidth();
int height = sprite.getHeight();
int[] pixels = new int[width * height];
sprite.getRGB(0, 0, width, height, pixels, 0, width);
for (int i = 0; i < pixels.length; i++) {
if (pixels[i] == 0xFFff00fe) {
pixels[i] = 0x00ff00fe; //this is supposed to set alpha value to 0 and make the target color transparent
}
}
} catch(IOException e){
System.out.println("sprite not found");
e.printStackTrace();
}
}
it runs and compiles, but sprite comes out exactly the same when I render it. (edit: perhaps of note I do not have super.paintComponent(g) in my paintComponent(g) method. The sprites are .bmps.
You are only retrieving the pixels using BufferedImage.getRGB. That returns a copy of the data in a certain area of the BufferedImage.
Any change you make to the int[] returned is not automatically reflected back into the image.
To update the image, you need to call BufferedImage.setRGB after you change the int[]:
sprite.setRGB(0, 0, width, height, pixels, 0, width);
Another change you should probably make (and this involves a little guesswork as I don't have your bmp to test with) - the BufferedImage returned by ImageIO.read may have type BufferedImage.TYPE_INT_RGB - meaning that it doesn't have an alpha channel. You can verify by printing sprite.getType(), if that prints 1 it's TYPE_INT_RGB without an alpha channel.
To get an alpha channel, create a new BufferedImage of the right size and then set the converted int[] on that image, then use the new image from then on:
BufferedImage newSprite = new BufferedImage(width, height, BufferedImage.TYPE_INT_ARGB);
newSprite.setRGB(0, 0, width, height, pixels, 0, width);
sprite = newSprite; // Swap the old sprite for the new one with an alpha channel
BMP images don't provide an alpha channel, you have to set it manually (as you do in your code)...
when you check your pixel to have a certain color you have to check without alpha (BMP has no alpha it's always 0x0).
if (pixels[i] == 0x00ff00fe) { //THIS is the color WITHOUT alpha
pixels[i] = 0xFFff00fe; //set alpha to 0xFF to make this pixel transparent
}
so in short: you did all right but mixed it up a bit ^^
This works:
private BufferedImage switchColors(BufferedImage img) {
int w = img.getWidth();
int h = img.getHeight();
BufferedImage bi = new BufferedImage(w, h, BufferedImage.TYPE_INT_ARGB);
// top left pixel is presumed to be BG color
int rgb = img.getRGB(0, 0);
for (int xx=0; xx<w; xx++) {
for (int yy=0; yy<h; yy++) {
int rgb2 = img.getRGB(xx, yy);
if (rgb2!=rgb) {
bi.setRGB(xx, yy, rgb2);
}
}
}
return bi;
}

Cropping image lowers quality and border looks bad

Using some math, i created the following java-function, to input a Bitmap, and have it crop out a centered square in which a circle is cropped out again with a black border around it.
The rest of the square should be transparent.
Additionatly, there is a transparent distance to the sides to not damage the preview when sending the image via Messengers.
The code of my function is as following:
public static Bitmap edit_image(Bitmap src,boolean makeborder) {
int width = src.getWidth();
int height = src.getHeight();
int A, R, G, B;
int pixel;
int middlex = width/2;
int middley = height/2;
int seitenlaenge,startx,starty;
if(width>height)
{
seitenlaenge=height;
starty=0;
startx = middlex - (seitenlaenge/2);
}
else
{
seitenlaenge=width;
startx=0;
starty = middley - (seitenlaenge/2);
}
int kreisradius = seitenlaenge/2;
int mittx = startx + kreisradius;
int mitty = starty + kreisradius;
int border=2;
int seitenabstand=55;
Bitmap bmOut = Bitmap.createBitmap(seitenlaenge+seitenabstand, seitenlaenge+seitenabstand, Bitmap.Config.ARGB_8888);
bmOut.setHasAlpha(true);
for(int x = 0; x < width; ++x) {
for(int y = 0; y < height; ++y) {
int distzumitte = (int) (Math.pow(mittx-x,2) + Math.pow(mitty-y,2)); // (Xm-Xp)^2 + (Ym-Yp)^2 = dist^2
distzumitte = (int) Math.sqrt(distzumitte);
pixel = src.getPixel(x, y);
A = Color.alpha(pixel);
R = (int)Color.red(pixel);
G = (int)Color.green(pixel);
B = (int)Color.blue(pixel);
int color = Color.argb(A, R, G, B);
int afterx=x-startx+(seitenabstand/2);
int aftery=y-starty+(seitenabstand/2);
if(x < startx || y < starty || afterx>=seitenlaenge+seitenabstand || aftery>=seitenlaenge+seitenabstand) //seitenrand
{
continue;
}
else if(distzumitte > kreisradius)
{
color=0x00FFFFFF;
}
else if(distzumitte > kreisradius-border && makeborder) //border
{
color = Color.argb(A, 0, 0, 0);
}
bmOut.setPixel(afterx, aftery, color);
}
}
return bmOut;
}
This function works fine, but there are some problems occuring that i wasn't able to resolve yet.
The quality of the image is decreased significantly
The border is not really round, but appears to be flat at the edges of the image (on some devices?!)
I'd appreciate any help regarding that problems. I got to admit that i'm not the best in math and there should probably be a better formula to ceate the border.
your source code is hard to read, since it is a mix of German and English in the variable names. Additionally you don't say which image library you use, so we don't exactly know where the classes Bitmap and Color come from.
Anyway, it is very obvious, that you are operating only on a Bitmap. Bitmap means the whole image is stored in the RAM pixel by pixel. There is no lossy compression. I don't see anything in your source code, that can affect the quality of the image.
It is very likely, that the answer is in the Code that you don't show us. Additionally, what you describe (botrh of the problems) sounds like a very typical low quality JPEG compression. I am sure, somewhere after you call you function, you convert/save the image to a JPEG. Try to do that at that position to BMP, TIFF or PNG and see that the error disappears magically. Maybe you can also set the quality level of the JPEG somewhere to avoid that.
To make it easier for others (maybe) also to find a good answer, please allow me to translate your code to English:
public static Bitmap edit_image(Bitmap src,boolean makeborder) {
int width = src.getWidth();
int height = src.getHeight();
int A, R, G, B;
int pixel;
int middlex = width/2;
int middley = height/2;
int sideLength,startx,starty;
if(width>height)
{
sideLength=height;
starty=0;
startx = middlex - (sideLength/2);
}
else
{
sideLength=width;
startx=0;
starty = middley - (sideLength/2);
}
int circleRadius = sideLength/2;
int middleX = startx + circleRadius;
int middleY = starty + circleRadius;
int border=2;
int sideDistance=55;
Bitmap bmOut = Bitmap.createBitmap(sideLength+sideDistance, sideLength+sideDistance, Bitmap.Config.ARGB_8888);
bmOut.setHasAlpha(true);
for(int x = 0; x < width; ++x) {
for(int y = 0; y < height; ++y) {
int distanceToMiddle = (int) (Math.pow(middleX-x,2) + Math.pow(middleY-y,2)); // (Xm-Xp)^2 + (Ym-Yp)^2 = dist^2
distanceToMiddle = (int) Math.sqrt(distanceToMiddle);
pixel = src.getPixel(x, y);
A = Color.alpha(pixel);
R = (int)Color.red(pixel);
G = (int)Color.green(pixel);
B = (int)Color.blue(pixel);
int color = Color.argb(A, R, G, B);
int afterx=x-startx+(sideDistance/2);
int aftery=y-starty+(sideDistance/2);
if(x < startx || y < starty || afterx>=sideLength+sideDistance || aftery>=sideLength+sideDistance) //margin
{
continue;
}
else if(distanceToMiddle > circleRadius)
{
color=0x00FFFFFF;
}
else if(distanceToMiddle > circleRadius-border && makeborder) //border
{
color = Color.argb(A, 0, 0, 0);
}
bmOut.setPixel(afterx, aftery, color);
}
}
return bmOut;
}
I think that you need to check PorterDuffXferMode.
You will find some technical informations about compositing images modes HERE.
There is some good example of making bitmap with rounded edges HERE. You just need to tweak a bit source code and you're ready to go...
Hope it will help.
Regarding the quality I can't see anything wrong with your method. Running the code with Java Swing no quality is lost. The only problem is that the image has aliased edges.
The aliasing problem will tend to disappear as the screen resolution increases and would be more noticeable for lower resolutions. This might explain why you see it in some devices only.The same problem applies to your border but in that case it would be more noticable since the color is single black.
Your algorithm defines a square area of the original image. To find the square it starts from the image's center and expand to either the width or the height of the image whichever is smaller. I am referring to this area as the square.
The aliasing is caused by your code that sets the colors (I am using pseudo-code):
if ( outOfSquare() ) {
continue; // case 1: this works but you depend upon the new image' s default pixel value i.e. transparent black
} else if ( insideSquare() && ! insideCircle() ) {
color = 0x00FFFFFF; // case 2: transparent white. <- Redundant
} else if ( insideBorder() ) {
color = Color.argb(A, 0, 0, 0); // case 3: Black color using the transparency of the original image.
} else { // inside the inner circle
// case 4: leave image color
}
Some notes about the code:
Case 1 depends upon the default pixel value of the original image i.e. transparent black. It works but better to set it explicitly
Case 2 is redundant. Handle it in the same way you handle case 1. We are only interested in what happens inside the circle.
Case 3 (when you draw the border) is not clear what it expects. Using the alpha of the original image has the potential of messing up your new image if it happens that the original alpha varies along the circle's edges. So this is clearly wrong and depending on the image, can potentially be another cause of your problems.
Case 4 is ok.
Now at your circle's periphery the following color transitions take place:
If border is not used: full transparency -> full image color (case 2 and 4 in the pseudocode)
If border is used: full transparency -> full black -> full image color (cases 2, 3 and 4)
To achieve a better quality at the edges you need to introduce some intermediate states that would make the transitions smoother (the new transitions are shown in italics):
Border is not used: full transparency -> partial transparency with image color -> full image color
Border is used: full transparency -> partial transparency of Black color -> full Black color -> partial transparency of Black color + Image color (i.e. blending) -> Full image color
I hope that helps

ImageIO.write is saving image with distortion

Here is my painting method:
BufferedImage bi = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);
bi.setRGB(0, 0, width, height, rgbIntArray, 0, width);
ImageIO.write(bi, "bmp", new File("C:/Users/Felipe/Desktop/img2.bmp"));
This is how I populate the rgbIntArray:
rgbIntArray = new int[(rgbArray.length / 3)];
int j = 0;
for (int i = 0; i < rgbArray.length; i += 3)
{
rgbIntArray[j] = unsignedToBytes(rgbArray[i]) +
unsignedToBytes(rgbArray[i + 1]) * 256 +
unsignedToBytes(rgbArray[i + 2]) * 65536;
j++;
}
I tested these values, they seem to be correct.
I think the problem is on the last parameter of setRGB, it asks for the "scanline stride", what to be honest I don`t have a clue what it is. (but I found somewhere it could be the width of the image). I'm assuming the other parameters are correct.
Here are the results:
Original image:
Original image http://i.minus.com/jy7iVQxtghO0l.bmp
Result:
Result http://i.minus.com/jz86D3YkuPPhG.bmp
I will manipulate the image after. I'm just opening and saving the same image.
I don't know how you initialize rgbArray, but each row ends with a black pixel (outside the image). It might represent a new line if you initialized rgbArray by reading the bytes directly from the image file. Or you didn't initialize rgbArray correctly.
The black pixels show on the sheared image as a diagonal line.
You can skip the black pixels at the end of each row by changing this:
bi.setRGB(0, 0, width, height, rgbIntArray, 0, width);
to this:
bi.setRGB(0, 0, width, height, rgbIntArray, 0, width + 1);
The last parameter, width + 1, basically says that if a given row starts at a certain index in the array, then the next row will start at the index which is width + 1 higher in the same array.

Java: Composite

I'm implementing a diagram that shows the level of a container. Depending on the fill level, the colour of the line should change (for instance, close to the maximum it should show red). Rather than calculating different segments of the line and setting their colours manually, I'd like to define a band in which the colour automatically changes. I thought to do this with a custom Composite/CompositeContext, but I seem not to be able to work out the locations of the pixels returned by the raster. My idea is to check for their y-Values and change the colour if a colour value is defined in the source and if the y-Value exceeds a threshold value.
My CompositeContext looks like this:
CompositeContext context = new CompositeContext() {
#Override
public void compose(Raster src, Raster dstIn, WritableRaster dstOut) {
int width = Math.min(src.getWidth(), dstIn.getWidth());
int height = Math.min(src.getHeight(), dstIn.getHeight());
int[] dstPixels = new int[width];
for (int y = 0; y < height; y++) {
dstIn.getDataElements(0, y, width, 1, dstPixels);
for (int x = 0; x < width; x++) {
if ( y ??? > 50) {
dstPixels[x] = 1;
} else {
// copy pixels from src
}
}
dstOut.setDataElements(0, y, width, 1, dstPixels);
}
}
"y" seems to be related to something, but it does not contain the absolute y-Value (in fact the compose method is called several times with 32x32 rasters). Maybe someone knows how to retrieve the position on the component or even a better way to define an area in which a given pixel value is replaced by another value.
Can't you just fill with a gradient with 0 alpha and then draw the line with full alpha?

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