I have implementing the android application for split the file path and get the actual file name in text-view. When I run the application it displays all the String name from file path. I want only one file name (introduction.ppt). How can I get this file name in text-view?
Here is my code:
String path = "/mnt/sdcard/coverted/introduction.ppt";
String[] strAfterSpilt = path.split("/");
for(int j = 0; j < strAfterSpilt.length; j++) {
if(strAfterSpilt[j].length() > 0) {
String strFinalSplit = strAfterSpilt[j];
System.out.println("strFinalSplit :-> " + strFinalSplit);
function_arg1.setText(strFinalSplit);
} else { break; }
}
And also I have to try this way of split the file path;
String[] strAfterSpilt = path.split("/");
for (String str : strAfterSpilt) {
System.out.println("str" + str.lastIndexOf(strAfterSpilt[i]));
}
String path = "/mnt/sdcard/coverted/introduction.ppt";
String fileName = path.substring(path.lastIndexOf("/")+1);
will do your job.
String[] tokens = path.split("/");
String fileName = tokens[tokens.length - 1];
Just try following code.. specifying the start and end position of required string.
String path = "/mnt/sdcard/coverted/introduction.ppt";
String fileName = path.substring(path.lastIndexOf("/"), path.length);
Try out following codes
public class MainActivity extends Activity {
String path = "/mnt/sdcard/coverted/introduction.ppt";
String fileName;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// To get the File name
fileName = path.substring(path.lastIndexOf("/")+1);
TextView remotefilePath =(TextView)findViewById(R.id.txtFileName);
remotefilePath.setText(fileName);
}
}
Related
I am trying to read package and class name from file. In the below code fileEntry.getName() is giving me output C:User\mywork\Myproject\target\generated-source\java\demo\Project.java. I want to get only demo.Project as an output. Appreciate suggestion thank you
public void listFilesForFolder(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
} else {
System.out.println(fileEntry.getName());
//C:User\mywork\Myproject\target\generated-source\java\demo\Project.java
}
}
}
I suppose you only need to find java class files and you want inner packages declared as package1.package2.demo.Project. You can do some String manipulation to get that output.
public static String FILE_SEPARATOR = System.getProperty("file.separator");
public static void listFilesForFolder(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
} else {
if (!fileEntry.getName().endsWith(".java")) {
continue;
}
String absolutePath = fileEntry.getAbsolutePath();
String javaPackageSeparator = FILE_SEPARATOR + "java" + FILE_SEPARATOR;
int indexOf = absolutePath.indexOf(javaPackageSeparator);
if (indexOf > -1) {
String javaFilePath = absolutePath.substring(indexOf, absolutePath.length());
String strippedJavaSeparator = javaFilePath.replace(javaPackageSeparator, "");
String[] constructProperPackageName = strippedJavaSeparator.split(Pattern.quote(FILE_SEPARATOR));
String packageName = "";
String className = "";
for (int i = 0; i < constructProperPackageName.length; i++) {
if (i == constructProperPackageName.length - 1) {
className = constructProperPackageName[i].replace(".java", "");
continue;
}
packageName += constructProperPackageName[i] + ".";
}
System.out.println(packageName + className);
}
}
}
}
Produces output as following:
com.company.exception.handler.AbstractExceptionHandler
com.company.exception.handler.IExceptionHandler
com.company.exception.handler.APIRequestExceptionHandler
...
A simple scan across the root / source directory using Files.find will return all java files, and then you can adjust the path to generate package name.
Path srcDir = Path.of("src");
BiPredicate<Path, BasicFileAttributes> dotjava = (p,a) -> a.isRegularFile() && p.getFileName().toString().endsWith(".java");
try(var java = Files.find(srcDir, Integer.MAX_VALUE, dotjava)) {
java.map(p -> srcDir.relativize(p).toString().replaceAll("\\.java$", "").replace(File.separator, "."))
.forEach(System.out::println);
}
How can I increment the filename if the file already exists?
Here's the code that I am using -
int num = 0;
String save = at.getText().toString() + ".jpg";
File file = new File(myDir, save);
if (file.exists()) {
save = at.getText().toString() + num + ".jpg";
file = new File(myDir, save);
num++;
}
This code works, but only two files are saved, like file.jpg and file2.jpg.
This problem is to always initialize num = 0, so if file exists, it saves file0.jpg and does not check whether file0.jpg exists.
So, to code work. You should check until it is available:
int num = 0;
String save = at.getText().toString() + ".jpg";
File file = new File(myDir, save);
while(file.exists()) {
save = at.getText().toString() + (num++) + ".jpg";
file = new File(myDir, save);
}
Try this:
File file = new File(myDir, at.getText().toString() + ".jpg");
for (int num = 0; file.exists(); num++) {
file = new File(myDir, at.getText().toString() + num + ".jpg");
}
// Now save/use your file here
In addition to the first answer, I made some more changes:
private File getUniqueFileName(String folderName, String searchedFilename) {
int num = 1;
String extension = getExtension(searchedFilename);
String filename = searchedFilename.substring(0, searchedFilename.lastIndexOf("."));
File file = new File(folderName, searchedFilename);
while (file.exists()) {
searchedFilename = filename + "(" + (num++) + ")" + extension;
file = new File(folderName, searchedFilename);
}
return file;
}
int i = 0;
String save = at.getText().toString();
String filename = save +".jpg";
File f = new File(filename);
while (f.exists()) {
i++;
filename =save+ Integer.toString(i)+".jpg";
f = new File(filename);
}
f.createNewFile();
You can avoid the code repetition of some of the answers here by using a do while loop
Here's an example using the newer NIO Path API introduced in Java 7
Path candidate = null;
int counter = 0;
do {
candidate = Paths.get(String.format("%s-%d",
path.toString(), ++counter));
} while (Files.exists(candidate));
Files.createFile(candidate);
Kotlin version:
private fun checkAndRenameIfExists(name: String): File {
var filename = name
val extension = "pdf"
val root = Environment.getExternalStorageDirectory().absolutePath
var file = File(root, "$filename.$extension")
var n = 0
while (file.exists()) {
n += 1
filename = "$name($n)"
file = File(root, appDirectoryName + File.separator + "$filename.$extension")
}
return file
}
Another simple logic solution to get the unique file name under a directory using Apache Commons IO using WildcardFileFilter to match the file name and get the number of exists with the given name and increment the counter.
public static String getUniqueFileName(String directory, String fileName) {
String fName = fileName.substring(0, fileName.lastIndexOf("."));
Collection<File> listFiles = FileUtils.listFiles(new File(directory), new WildcardFileFilter(fName + "*", IOCase.INSENSITIVE), DirectoryFileFilter.DIRECTORY);
if(listFiles.isEmpty()) {
return fName;
}
return fName.concat(" (" + listFiles.size() + ")");
}
This is the solution I use to handle this case. It works for folders as well as for files.
var destination = File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS), "MyFolder")
if (!destination.exists()) {
destination.mkdirs()
} else {
val numberOfFileAlreadyExist =
destination.listFiles().filter { it.name.startsWith("MyFolder") }.size
destination = File(
Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS),
"MyFolder(${numberOfFileAlreadyExist + 1})"
)
destination.mkdirs()
}
Having needed to solve this problem in my own code, I took Tejas Trivedi's answer, made it work like Windows when you happen to download the same file several times.
// This function will iteratively to find a unique file name to use when given a file: example (###).txt
// More or less how Windows will save a new file when one already exists: 'example.txt' becomes 'example (1).txt'.
// if example.txt already exists
private File getUniqueFileName(File file) {
File originalFile = file;
try {
while (file.exists()) {
String newFileName = file.getName();
String baseName = newFileName.substring(0, newFileName.lastIndexOf("."));
String extension = getExtension(newFileName);
Pattern pattern = Pattern.compile("( \\(\\d+\\))\\."); // Find ' (###).' in the file name, if it exists
Matcher matcher = pattern.matcher(newFileName);
String strDigits = "";
if (matcher.find()) {
baseName = baseName.substring(0, matcher.start(0)); // Remove the (###)
strDigits = matcher.group(0); // Grab the ### we'll want to increment
strDigits = strDigits.substring(strDigits.indexOf("(") + 1, strDigits.lastIndexOf(")")); // Strip off the ' (' and ').' from the match
// Increment the found digit and convert it back to a string
int count = Integer.parseInt(strDigits);
strDigits = Integer.toString(count + 1);
} else {
strDigits = "1"; // If there is no (###) match then start with 1
}
file = new File(file.getParent() + "/" + baseName + " (" + strDigits + ")" + extension); // Put the pieces back together
}
return file;
} catch (Error e) {
return originalFile; // Just overwrite the original file at this point...
}
}
private String getExtension(String name) {
return name.substring(name.lastIndexOf("."));
}
Calling getUniqueFileName(new File('/dir/example.txt') when 'example.txt' already exists while generate a new File targeting '/dir/example (1).txt' if that too exists it'll just keep incrementing number between the parentheses until a unique file is found, if an error happens, it'll just give the original file name.
I hope this helps some one needing to generate a unique file in Java on Android or another platform.
This function returns the exact new file with an increment number for all kind of extensions.
private File getFileName(File file) {
if (file.exists()) {
String newFileName = file.getName();
String simpleName = file.getName().substring(0, newFileName.indexOf("."));
String strDigit = "";
try {
simpleName = (Integer.parseInt(simpleName) + 1 + "");
File newFile = new File(file.getParent() + "/" + simpleName + getExtension(file.getName()));
return getFileName(newFile);
}
catch (Exception e){
}
for (int i=simpleName.length()-1; i>=0; i--) {
if (!Character.isDigit(simpleName.charAt(i))) {
strDigit = simpleName.substring(i + 1);
simpleName = simpleName.substring(0, i+1);
break;
}
}
if (strDigit.length() > 0) {
simpleName = simpleName + (Integer.parseInt(strDigit) + 1);
}
else {
simpleName += "1";
}
File newFile = new File(file.getParent() + "/" + simpleName + getExtension(file.getName()));
return getFileName(newFile);
}
return file;
}
private String getExtension(String name) {
return name.substring(name.lastIndexOf("."));
}
building an Android app i came across the need to do some file copying. I would like a way to get new filenames in the event of a filename allready being used by adding a "(increment)" string in the filename. for example
text.txt ---> text(1).txt
The algorith should account for the following
1) if text.txt exists the new file name should NEVER be text.txt(1)
2) if text(1).txt exists then new filename should be text(2).txt not text(1)(1).txt
3) if text(1)foo.txt exists the new filename should be text(1)foo(1).txt
I've allready done the first but I'm having difficulties with the second. Regular expressions is not my strong suit!(It's not mandatory to use Regex. every approach is welcome) Some help ?
ANSWER:
combining my original code and one of the answers here I ended up with this which works very well for me in all cases regardless of file having an extension or not:
public static File getFinalNewDestinationFile(File destinationFolder, File fileToCopy){
String destFolderPath = destinationFolder.getAbsolutePath()+File.separator;
File newFile = new File(destFolderPath + fileToCopy.getName());
String filename=fileToCopy.getName();
String nameWithoutExtentionOrIncrement;
String extension = getFileExtension(filename);
if(extension!=null){
extension="."+extension;
int extInd = filename.lastIndexOf(extension);
nameWithoutExtentionOrIncrement = new StringBuilder(filename).replace(extInd, extInd+extension.length(),"").toString();
}
else{
extension="";
nameWithoutExtentionOrIncrement = filename;
}
int c=0;
int indexOfClose = nameWithoutExtentionOrIncrement.lastIndexOf(")");
int indexOfOpen = nameWithoutExtentionOrIncrement.lastIndexOf("(");
if(indexOfClose!=-1 && indexOfClose!=-1 && indexOfClose==nameWithoutExtentionOrIncrement.length()-1 && indexOfClose > indexOfOpen && indexOfOpen!=0){
String possibleNumber = nameWithoutExtentionOrIncrement.substring(indexOfOpen+1, indexOfClose);
try{
c = Integer.parseInt(possibleNumber);
nameWithoutExtentionOrIncrement=nameWithoutExtentionOrIncrement.substring(0, indexOfOpen);
}catch(Exception e){c=0;}
}
while(newFile.exists()){
c++;
String path = destFolderPath + nameWithoutExtentionOrIncrement +"(" + Integer.toString(c) + ")" + extension;
newFile = new File(path);
}
return newFile;
}
public static String getFileExtension(String filename) {
if (filename == null) { return null; }
int lastUnixPos = filename.lastIndexOf('/');
int lastWindowsPos = filename.lastIndexOf('\\');
int indexOfLastSeparator = Math.max(lastUnixPos, lastWindowsPos);
int extensionPos = filename.lastIndexOf('.');
int lastSeparator = indexOfLastSeparator;
int indexOfExtension = lastSeparator > extensionPos ? -1 : extensionPos;
int index = indexOfExtension;
if (index == -1) {
return null;
} else {
return filename.substring(index + 1).toLowerCase();
}
}
Using one regex pattern:
final static Pattern PATTERN = Pattern.compile("(.*?)(?:\\((\\d+)\\))?(\\.[^.]*)?");
String getNewName(String filename) {
if (fileExists(filename)) {
Matcher m = PATTERN.matcher(filename);
if (m.matches()) {
String prefix = m.group(1);
String last = m.group(2);
String suffix = m.group(3);
if (suffix == null) suffix = "";
int count = last != null ? Integer.parseInt(last) : 0;
do {
count++;
filename = prefix + "(" + count + ")" + suffix;
} while (fileExists(filename));
}
}
return filename;
}
The regex pattern explanation:
(.*?) a non greedy "match everything" starting at the beginning
(?:\\((\\d+)\\))? a number in parenthesis (optional)
(?:____________) - is a non capturing group
___\\(______\\)_ - matches ( and )
______(\\d+)____ - matches and captures the one or more digits
(\\.[^.]+)? a dot followed by anything but a dot (optional)
Here's one way of doing it:
String fileName;
File file = new File(fileName);
if(file.exists()) {
int dot = fileName.lastIndexOf('.'), open = fileName.lastIndexOf('('), incr;
boolean validNum = false;
if(fileName.charAt(dot-1) == ')' && open != -1){
String n = fileName.substring(open+1, dot-1);
try {
incr = Integer.parseInt(n);
validNum = true;
} catch(NumberFormatException e) {
validNum = false;
}
}
if(validNum) {
String pre = fileName.substring(0, open+1), post = fileName.substring(0, dot-1);
while(new File(pre + ++incr + post).exists());
fileName = pre + incr + post;
} else {
fileName = fileName.substring(0, dot) + "(1)" + fileName.substring(dot);
}
}
I assume a couple of things:
1) A method called fileExists(String fileName) is available. It returns true if a file with the specified name is already present in the file system.
2) There is a constant called FILE_NAME which in your example case is equal to "text".
if (!fileExists(FILE_NAME)) {
//create file with FILE_NAME.txt as name
}
int availableIndex = 1;
while (true) {
if (!fileExists(currentName)) {
//create file with FILE_NAME(availableIndex).txt
break;
}
availableIndex++;
}
I am not very sure about Android but since its a Java program, you may be able to create File object of the directory in which you want to write.
Once you have this you can see the list of file names already present inside it and other related information. Then you can decide the file name as per your above logic.
File dir = new File("<dir-path>");
if(dir.isDirectory()){
String[] files = dir.list();
for(String fileName : files){
<logic for finding filename>
}
}
If all filenames have an extenstion you could do something like this (just an example you will have to change it to work in your case):
public static void main(String[] args)
{
String test = "test(1)foo.txt";
String test1 = "test(1)foo(1).txt";
Pattern pattern = Pattern.compile("((?<=\\()\\d+(?=\\)\\.))");
Matcher matcher = pattern.matcher(test);
String fileOutput = "";
String temp = null;
int newInt = -1;
while(matcher.find())
{
temp = matcher.group(0);
}
if(temp != null)
{
newInt = Integer.parseInt(temp);
newInt++;
fileOutput = test.replaceAll("\\(\\d+\\)(?=\\.(?!.*\\.))", "(" + newInt + ")");
}
else
{
fileOutput = test;
}
System.out.println(fileOutput);
matcher = pattern.matcher(test1);
fileOutput = "";
temp = null;
while(matcher.find())
{
temp = matcher.group(0);
}
if(temp != null)
{
newInt = Integer.parseInt(temp);
newInt++;
fileOutput = test1.replaceAll("\\(\\d+\\)(?=\\.(?!.*\\.))", "(" + newInt + ")");
}
else
{
fileOutput = test1;
}
System.out.println(fileOutput);
}
Output:
test(1)foo.txt
test(1)foo(2).txt
This uses regex to look for a number in the () right before the last ..
Update
replaceAll() changed to handle case where there is a . after the first (1) in test(1).foo(1).txt.
i get an example from here
https://github.com/nostra13/Android-Universal-Image-Loader
In the Constants.java is for the image source link. The thing that i want is scan the specific folder in sdcard, then get all image url in dynamic.
Not one by one type the image url.
Not this type one by one. ---> "file:///sdcard/Universal Image Loader ##&=+-_.,!()~'%20.png"
Here is my code. But it can't work. Any solution about this? Thanks.
public class Constants {
private String[] mFileStrings;
private File[] listFile;
static List<String> test = new ArrayList<String>();
public void getFromSdcard()
{
System.out.println("testing here can");
File file= new File(android.os.Environment.getExternalStorageDirectory(),"file:///sdcard/bluetooth/"); //sdcard/bluetooth
if (file.isDirectory())//if files is directory
{
listFile = file.listFiles();
mFileStrings = new String[listFile.length];
for (int i = 0; i < listFile.length; i++)
{
mFileStrings[i] = listFile[i].getAbsolutePath();//mFileStrings with uri of images
test.add(listFile[i].getAbsolutePath());
}
}
}
static String simpleArray = test.toString();
//String img = mFileStrings.toString();
public static final String[] IMAGES = new String[] {simpleArray};
private Constants() {
}
To get image from sdcard, use following code.
String fileName= listFile[i];
fileName = fileName.replace(':', '/');
fileName = fileName.replace('/', '_');
String loadURL="file://"+Environment.getExternalStorageDirectory()+"/"+folder+"/"+fileName;
Now, you have absolute path of your image in "loadURL".
if (file.isDirectory())//if files is directory
{
listFile = file.listFiles();
mFileStrings = new String[listFile.length];
for (int i = 0; i < listFile.length; i++)
{
String fileName=listFile[i];
fileName = fileName.replace(':', '/');
fileName = fileName.replace('/', '_');
String loadURL="file://"+Environment.getExternalStorageDirectory()+"/"+folder+"/"+fileName;
test.add(loadURL);
}
}
I have this code in Java. The randomName() function returns a string with (unsurprisingly) a random string.
File handle = new File(file);
String parent = handle.getParent();
String lastName = "";
for (int i = 0; i < 14; i++)
{
lastName = parent + File.separator + randomName();
handle.renameTo(new File(lastName));
}
return lastName;
I have the appropriate permissions, and when I log to logcat the randomName() function does all the strings, but upon the end of the loop handle appears to have a file name of the value of the first randomName() call.
The reason this didn't work as expected is because once the file was renamed the first time, handle no longer referred to the file. That is why the subsequent rename operations failed. File represents a path name, not an actual object on disk.
This is my solution:
File handle = null;
String parent = "";
String lastName = "";
for (int i = 0; i < 14; i++)
{
if (i == 0)
{
handle = new File(file);
parent = handle.getParent();
}
else
{
lastName = parent + File.separator + randomName();
handle.renameTo(new File(lastName));
handle = new File(lastName);
}
}