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what is the format in SimpleDateFormat for parsing a string ie 07/12/2013 into a date type? I am using the following code, but desired format is not comimg.
SimpleDateFormat formatter ;
Date notBeforeDate ,notAfterDate;
formatter = new SimpleDateFormat("DD/MM/YYYY");
notBeforeDate = (Date)formatter.parse(notBeforeValue);
notAfterDate = (Date)formatter.parse(notAfterValue);
Assuming you are looking for a Java solution. Change the format string :
DateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
Date date = formatter.parse("07/12/2013");
Refer the documentation for the exact format string information.
Try this :
SimpleDateFormat formatter=new SimpleDateFormat("dd/MM/yyyy"); ;
Date notBeforeDate ,notAfterDate;
notBeforeDate =formatter.parse("Your String format Date");
notAfterDate =formatter.parse("Your String format Date");
Read More.
Hope it will help you.
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How can I get the current date and time and how can I transfer it into the following String format?
06-04-2020 05:00 PM
After that I need to add few minutes to the date? Please help!
Your answer should look something like this:
String dateTimePattern = "dd-MM-yyyy HH:mm a";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(dateTimePattern );
LocalDateTime yourDay= LocalDateTime.of(2020, 4, 6, 17, 00);
System.out.println(formatter.format(ZonedDateTime.of(yourDay, ZoneId.of("UTC-5"))));
Please look this up for more info on the available formats.
Date yourDate = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy h:m a");
String formatedDate= sdf.format(yourDate);
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java.util.Date tempin = pLabIn.getDate();
System.out.println(tempin);
java.util.Date tempout = pLabOut.getDate();
java.sql.Date labIn = new java.sql.Date(tempin.getTime());
System.out.println(labIn);
java.sql.Date labOut = new java.sql.Date(tempout.getTime());
The first System.out shows "Thu Feb 27 22:50:06 PKT 2014"
and the second "2014-02-27"
So it miss time. I want to take time as well.
Use a java.sql.Timestamp instead.
The toString() implementation for java.sql.Date will only give you the date in the format year-month-day.
This is also precised in the documentation:
Formats a date in the date escape format yyyy-mm-dd.
If you want to keep the time in your print statement, you can use a SimpleDateFormat instead.
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
System.out.println(sdf.format(labIn));
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I have dates mainly in the forms of yyyy-MM-dd and yyyy-MM-dd hh:mm:ss. I want to pattern match yyyy-MM-dd hh:mm:ss.
Is it trivial to write an regex for this purpose? I am new to regex so would appreciate any resource tat could get me up to speed?
If you are trying to find these date notations in a String, then regexes is indeed a good choice. You could use this regex:
\b\d{4}-\d{2}-\d{2} \d{1,2}:\d{2}:\d{2}\b
See it in action here: http://rubular.com/r/qZOTsUikbo. Note: this matches "dates" like
9999-99-99 99:99:99 as well. If that is a problem for you, you could verify them after you found the potential Strings.
If you want to parse them, then use a SimpleDateFormat.
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
Date date = sdf.parse("2013-12-24 18:31:20");
You don't need to write reg expression for it.
Java already has support for it. Here is the link to follow.
http://developer.android.com/reference/java/text/SimpleDateFormat.html
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I have a query with the following data
85343
125242
65252
125655
185658
235758
Those are 24 hour times without the format. I tried parsing it with HHmmss to then give it the format hh:mm:ss a it kind of worked with the hours 12+ but with 12- it went to hell giving wrong times. I worked it out with the following code:
DateFormat dateFormat2 = new SimpleDateFormat("Hmmss");
DateFormat dateFormat21 = new SimpleDateFormat("HHmmss");
DateFormat dateFormat5 = new SimpleDateFormat("hh:mm:ss a");
System.out.println((Query.getString(1).length() == 5) ?
dateFormat5.format(dateFormat2.parse(Query.getString(1)))
: dateFormat5.format(dateFormat21.parse(Query.getString(1))));
it solves the problem with the time errors as I get the correct times
8:53:43AM
12:52:42PM
6:52:52 AM
12:56:55 PM
6:56:58 PM
11:57:58PM
Is there anyway to make this better?
I wouldn't use two different DateFormat for parsing but only one :
DateFormat dateFormat21 = new SimpleDateFormat("HHmmss");
DateFormat dateFormat5 = new SimpleDateFormat("hh:mm:ss a");
String s = Query.getString(1);
if (s.length()==5) s = "0"+s;
System.out.println(dateFormat5.format(dateFormat21.parse(s)));
But there's no real problem in your code apart calling getString more than necessary.
Try using some regex like this:
(\d?\d)(\d\d)(\d\d)
Match group 1 is the hours, match group 2 the minute, match group 3 the seconds.
For more about regex in Java see here:
http://www.regular-expressions.info/java.html
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I am living in India so my timezone is IST so when I want to fix meeting with the UK client then I just put my time in field like 10 A.M to 11 A.M. Now How to convert this in GMT0000 that is UK time zone?
Basically I have textfied to enter time then after inserted there is one dropdown box that is containing all available timezone then when I select UK timezone then how to convert this process using Java?
Thanks in advance.. tell me to solve my issue..
Note: I don't want to do this manually? cause of selection it will be converted? that is my task.. hope you understand my problem..
Regards..
India time is GMT + 5.30. Then 10.00 -5.30 can consider as GMT time.
In java you can do something like this
DateFormat df = new SimpleDateFormat("HH:mm");
Date dateIST=df.parse("10:00"); // india time
df.setTimeZone(TimeZone.getTimeZone("GMT"));
System.out.println(df.format(dateIST));// This is UK time
(JAVA answer) In textfield(s) you just need to enter your local time. Take an input from that textfield(s) and pass it in following code.
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("GMT"));//or whatever timezone u want.
String gmtStrDate = simpleDateFormat.format(Calendar.getInstance().getTime());
Or you may find this code suited to your need (your question is unclear):
SimpleDateFormat inputFormat = new SimpleDateFormat("HH:mm");
Date date = inputFormat.parse("time from textfield");//like 11:44
inputFormat.setTimeZone((TimeZone.getTimeZone("IST")));
SimpleDateFormat outputFormat = new SimpleDateFormat("HH:mm");
outputFormat.setTimeZone((TimeZone.getTimeZone("GMT")));
String outputText = outputFormat.format(date);
Now outputText is your desired time in UK format.
Note : Here i assumed you are entering time in textfield like 13:44. You can accordingly change that in formatters.