Develop Reference

Java Gson parse Json object to array

I'm trying to parse the below Json using the Gson lib in Java. When using other languages, such as C#, this JSON is parsed into an array, however it seems Gson converts this into a set of java attributes (which to be honest, makes more sense to me). Does anyone know if I can change this behaviour of the Gson lib?
{
"Outer": {
"0": {
"Attr1": 12345,
"Attr2": 67890
},
"1": {
"Attr1": 54321,
"Attr2": 09876
}
}
}
The below code demonstrates how Gson parses the array as a JsonObject. To be clear, I realise I've referenced outer as a JsonObject but I was just doing this to demonstrate the code. If I try and reference outer as an JsonArray, the code fails.
String json = "{\"Outer\": { \"0\": { \"Attr1\": 12345, \"Attr2\": 67890 }, \"1\": { \"Attr1\": 54321, \"Attr2\": 09876 }}}";
Gson gson = new GsonBuilder()
.disableHtmlEscaping()
.setLenient()
.serializeNulls()
.create();
JsonObject jo = gson.fromJson(json, JsonObject.class);
JsonObject outer = jo.getAsJsonObject("Outer");
System.out.println(outer);
System.out.println(outer.isJsonArray());
Result:
{"0":{"Attr1":12345,"Attr2":67890},"1":{"Attr1":54321,"Attr2":"09876"}}
false
//edit
I'm using this current simple Json as an example, however my application of this code will be to parse Json that's of varying and unknown shape. I therefore need Gson to automatically parse this to an array so that the isJsonArray returns true.

TL;DR: See "Using Deserializer" section at the bottom for parsing straight to array.
That JSON does not contain any arrays. An array would use the [...] JSON syntax.
Normally, a JSON object would map to a POJO, with the name in the name/value pairs mapping to a field of the POJO.
However, a JSON object can also be mapped to a Map, which is especially useful when the names are dynamic, since POJO fields are static.
Using Map
The JSON object with numeric values as names can be mapped to a Map<Integer, ?>, e.g. to parse that JSON to POJOs, do it like this:
class Root {
#SerializedName("Outer")
public Map<Integer, Outer> outer;
#Override
public String toString() {
return "Root[outer=" + this.outer + "]";
}
}
class Outer {
#SerializedName("Attr1")
public int attr1;
#SerializedName("Attr2")
public int attr2;
#Override
public String toString() {
return "Outer[attr1=" + this.attr1 + ", attr2=" + this.attr2 + "]";
}
}
Test
Gson gson = new GsonBuilder().create();
Root root;
try (BufferedReader in = Files.newBufferedReader(Paths.get("test.json"))) {
root = gson.fromJson(in, Root.class);
}
System.out.println(root);
Output
Root[outer={0=Outer[attr1=12345, attr2=67890], 1=Outer[attr1=54321, attr2=9876]}]
Get as Array
You can then add a helper method to the Root class to get that as an array:
public Outer[] getOuterAsArray() {
if (this.outer == null)
return null;
if (this.outer.isEmpty())
return new Outer[0];
int maxKey = this.outer.keySet().stream().mapToInt(Integer::intValue).max().getAsInt();
Outer[] arr = new Outer[maxKey + 1];
this.outer.forEach((k, v) -> arr[k] = v);
return arr;
}
Test
System.out.println(Arrays.toString(root.getOuterAsArray()));
Output
[Outer[attr1=12345, attr2=67890], Outer[attr1=54321, attr2=9876]]
Using Deserializer
However, it would likely be more useful if the conversion to array is done while parsing, so you need to write a JsonDeserializer and tell Gson about it using #JsonAdapter:
class Root {
#SerializedName("Outer")
#JsonAdapter(OuterArrayDeserializer.class)
public Outer[] outer;
#Override
public String toString() {
return "Root[outer=" + Arrays.toString(this.outer) + "]";
}
}
class OuterArrayDeserializer implements JsonDeserializer<Outer[]> {
#Override
public Outer[] deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
// Parse JSON array normally
if (json.isJsonArray())
return context.deserialize(json, Outer[].class);
// Parse JSON object using names as array indexes
JsonObject obj = json.getAsJsonObject();
if (obj.size() == 0)
return new Outer[0];
int maxKey = obj.keySet().stream().mapToInt(Integer::parseInt).max().getAsInt();
Outer[] arr = new Outer[maxKey + 1];
for (Entry<String, JsonElement> e : obj.entrySet())
arr[Integer.parseInt(e.getKey())] = context.deserialize(e.getValue(), Outer.class);
return arr;
}
}
Same Outer class and test code as above.
Output
Root[outer=[Outer[attr1=12345, attr2=67890], Outer[attr1=54321, attr2=9876]]]

I'll asume your JsonObject is a POJO class such like:
public Inner[] outer;
If you want an array of objects you can change your code to:
Inner[] jo = gson.fromJson(json, Inner[].class);

Jackson – Marshall String to JsonNode will be useful in your case.with following pom:-
//POM FILE
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.9.8</version>
</dependency>
//JAVA CODE
//read json file data to String
byte[] jsonData = Files.readAllBytes(Paths.get("employee.txt"));
//create ObjectMapper instance
ObjectMapper objectMapper = new ObjectMapper();
//read JSON like DOM Parser
JsonNode rootNode = objectMapper.readTree(jsonData);
JsonNode idNode = rootNode.path("id");
System.out.println("id = "+idNode.asInt());
JsonNode phoneNosNode = rootNode.path("phoneNumbers");
Iterator<JsonNode> elements = phoneNosNode.elements();
while(elements.hasNext()){
JsonNode phone = elements.next();
System.out.println("Phone No = "+phone.asLong());
}
You can use the JsonNode class's method findParent findValue and findPath which reduce your code as compare to another parsing library.

Please refer below code
1.To get an array of Objects (outerArray)
2.You can extract a JsonArray (outerJsonArray) containing values of inner objects in Outer (in case keys aren't significant for further use)
String json = "{\"Outer\": { \"0\": { \"Attr1\": 12345, \"Attr2\": 67890 }, \"1\": { \"Attr1\": 54321, \"Attr2\": 09876 }}}";
Gson gson = new GsonBuilder().disableHtmlEscaping().setLenient().serializeNulls().create();
JsonObject jo = gson.fromJson(json, JsonObject.class);
JsonObject outer = jo.getAsJsonObject("Outer");
Object[] outerArray = outer.entrySet().toArray();
// outerArray: [0={"Attr1":12345,"Attr2":67890}, 1={"Attr1":54321,"Attr2":"09876"}]
JsonArray outerJsonArray = new JsonArray();
outer.keySet().stream().forEach(key -> {
outerJsonArray.add(outer.get(key));
});
//jsonArray=[{"Attr1":12345,"Attr2":67890},{"Attr1":54321,"Attr2":"09876"}]
System.out.println(outer);
System.out.println(outerJsonArray.isJsonArray() + " " + outerJsonArray);

how to print nested json-object without escapes and quotation marks

i have a json-object named jsonObject
{
"action":"Read",
"infos":[
{
"value":0.0350661,
"key":"first"
}
]
}
i wanna to print the json-object to with the following form
{"action":"Read","infos":[{"value":0.0350661,"key":"first"}]}
if i use jsonObject.toString() method i will get
{"action":"Read","infos":"[{\"value\":0.0350661,\"key\":\"first\"}]"}
if i use StringEscapeUtils.unescapeJava(jsonObject.toString()) method i will get
{"action":"Read","infos":"[{"value":0.0350661,"key":"first"}]"}
if i use jackson mapper with the following code
ObjectMapper mapper = new ObjectMapper();
mapper.setVisibility(PropertyAccessor.FIELD, JsonAutoDetect.Visibility.ANY);
String jsonString = mapper.writeValueAsString(getDebugInfo())
i will get jsonString as
{"nameValuePairs":{"action":"Read","infos":[{"value":0.0350661,"key":"first"}]}}
is there any solution to get the desired output json-string?

JSON Structure
You have that as an object, that is why quotes are not present there.
In your example, an array object is present, at the Json structure.
Code/Java
While printing at Console, the json body's every Key & Value toString() are referred .
That is why the Double Quotes present, as Strings are getting used!

Here I have tried the below code using GSON library, and it is printing me the correct json as shown above.
public static void main ( String [] args ) {
JsonObject jsonObject = new JsonObject();
jsonObject.addProperty("action", "Read");
JsonArray jsonArr = new JsonArray();
JsonObject jsonObject2 = new JsonObject();
jsonObject2.addProperty("value", 0.0350661);
jsonObject2.addProperty("key", "first");
jsonArr.add(jsonObject2);
jsonObject.add("infos", jsonArr);
String jsonString = jsonObject.toString();
Gson gson = new GsonBuilder().setPrettyPrinting().create();
JsonElement json = gson.fromJson(jsonString,JsonElement.class);
String jsonInString = gson.toJson(json);
System.out.println(jsonInString);
}
OUTPUT:
{
"action": "Read",
"infos": [
{
"value": 0.0350661,
"key": "first"
}
]
}
Even if I am forming the jsonObject using org.json, and simple printing it using System.out.println(jsonObject.toString()); on console, m getting the result like this.
{"action":"Read","infos":[{"value":0.0350661,"key":"first"}]}
So here, not sure how you have formed your jsonObject.

How to get deeply nested JSON object in Java

I have a JSON string where i want to get the value of one field which is nested in multiple objects. How can I get that field in a nice and performant way? Here's the code I tried so far. It's working, but it's quite lengthy code. I'm looking for a better solution.
Json Response
{
"status":"success",
"response":{
"setId":1,
"response":{
"match":{
"matches":{
"matchesSchema":{
"rules":[
{
"ruleId":"Abs"
}
]
}
}
}
}
}
lengthy code:
JsonParser jp=new JsonParser();
Object obj = jp.parse(JSONString);
JSONObject jsonObject =(JSONObject) (obj);
JSONObject get1 = jsonObject.getJSONObject("response");
JSONObject get2 = get1 .getJSONObject("response");
JSONObject get3 = get2 .getJSONObject("match");
JSONObject get4 = get3 .getJSONObject("matches");
JSONObject get5 = get4 .getJSONObject("matchesSchema");
JSONObject get6 = get5 .getJSONObject("rules");
JSONArray result = get6 .getJSONArray("rules");
JSONObject result1 = result.getJSONObject(0);
String lat = result1 .getString("rule");
The result is
ruleId = Abs
is there a good alternative for fetching the ruleId from the nested json object (something like response.response.match.matches.matchesSchema.rules.ruleId)

You can use Jackson's JsonNode with JsonPath to get ruleId as follows:
ObjectMapper mapper = new ObjectMapper();
JsonNode jsonObj = mapper.readTree(JSONString);
String lat = jsonObj.at("/response/response/match/matches/matchesSchema/rules/0/ruleId").asText()
It's also null-safe and returns a MissingNode object on a null node that returns an empty string when you do a .asText()

It's super easy with JsonPath.
String ruleId = JsonPath.read(jsonString, "$.response.response.match.matches.matchesSchema.rules[0].ruleId");
Or if you read the path multiple times, it's better to pre-compile JsonPath expression
JsonPath ruleIdPath = JsonPath.compile("$.response.response.match.matches.matchesSchema.rules[0].ruleId");
String ruleId = ruleIdPath.read(json);

How to Split a JSON string to two JSON objects in Java

I have a JSON object as follows:
{
"token":"eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9",
"user":{
"pk":17,
"username":"user1",
"email":"user1#gmail.com",
"first_name":"",
"last_name":""
}
}
I am trying to get two JSON object from it; token and user. I have tried two different ways but both are failing:
//response.body().string() is the above json object
JSONArray jsonArray = new JSONArray(response.body().string());
jsonObjectRoot = new JSONObject(response.body().string());
Could any one please let me know how I could split this to two JSON objects?

You can split it this way:
// source object
JSONObject sourceObject = new JSONObject(sourceJson);
String tokenKey = "token";
// create new object for token
JSONObject tokenObject = new JSONObject();
// transplant token to new object
tokenObject.append(tokenKey, sourceObject.remove(tokenKey));
// if append method does not exist use put
// tokenObject.put(tokenKey, sourceObject.remove(tokenKey));
System.out.println("Token object => " + tokenObject);
System.out.println("User object => " + sourceObject);
Above code prints:
Token object => {"token":["eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9"]}
User object => {"user":{"last_name":"","pk":17,"first_name":"","email":"user1#gmail.com","username":"user1"}}

You can parse a json string with
var obj = JSON.parse(jsonString);
You can filter sub parts of a json object by simply addressing them
var token = obj.token;
var user = obj.user;

The safer / cleaner way to do it is to create a POJO and deserialize your JSON into it using Jackson. Your pojo:
public class MyObject {
String token;
User user;
static class User {
int pk;
String username;
String email;
String first_name;
String last_name;
}
}
Then, when you want to deserialize:
import com.fasterxml.jackson.databind.ObjectMapper;
and
ObjectMapper mapper = new ObjectMapper();
MyObject myObject = mapper.readValue(jsonString, MyObject.class);
String token = myObject.token;
User user = myObject.user;
...

I recently faced the same situation, I used the below code which worked for me:
JSONObject jo1 = new JSONObject(output);
JSONObject tokenObject = new JSONObject();
tokenObject.put("token", jo1.get("token"));
JSONObject userObject = new JSONObject();
userObject.put("user", jo1.get("user"));
Here I am creating a new empty JSONObject and then put the retrieved object from the original object in the newly created JSONObject.
You can also verify the output by just sysout:
System.out.println("token:" + tokenObject.get("token"));
System.out.println("user:" + userObject.get("user"));
Output in my case :
token::eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9
user:{"last_name":"","pk":17,"first_name":"","email":"user1#gmail.com","username":"user1"}

Yep. It is a JSON string.
Using like this
JSONParser jparse=new JSONParser();
JSONObject jObj=(JSONObject)jParse.parse(jsonString);
jObj will contain json Object now.

Convert JSON into List of Object property (Java)

I have simple json which looks like this :
[
{
"id":"0",
"name":"Bob",
"place":"Colorado",
},
{
"id":"1",
"name":"John",
"place":"Chicago",
},
{
"id":"2",
"name":"Marry",
"place":"Miami",
}
]
What I want is using Java to create list of strings (List<String>) that contains all 'names'. I have some experience using Gson and I think about something like:
Gson gson = new Gson();
String[] stringArray= gson.fromJson(jsonString, " ".class);
The problem with this method is that I should create some POJO class which I didn`t in this case. Is it any way I can achieve it without creating separate class with this 'name' property ?

Using Jackson to parse, and Java 8 Streams API for extracting only the name field; the following may help you:
// Your string
jsonString = "[{ \"id\":\"0\", \"name\":\"Bob\", \"place\":\"Colorado\" }, { \"id\":\"1\", \"name\":\"John\", \"place\":\"Chicago\"}, { \"id\":\"2\", \"name\":\"Marry\", \"place\":\"Miami\" }]";
// using Jackson to parse
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.getTypeFactory();
List<MyInfo> myObjectList = objectMapper.readValue(jsonString, typeFactory.constructCollectionType(List.class, MyInfo.class));
// Java 8 Collections
List<String> nameList = myObjectList.stream().map(MyInfo::getName).collect(Collectors.toList());
Beware, it implies the usage of a MyInfo class representing your a Java class in which Json objects of yours would fit in.

You can use JSONArray to get value from key 'name'. Like this:
JSONArray jSONArray = new JSONArray(yourJson);
List<String> list = new ArrayList<>();
for (int i = 0; i < jSONArray.length(); i++) {
JSONObject object = (JSONObject) jSONArray.get(i);
String value = object.getString("name");
System.out.println(value);
list.add(value);
}

You may try the following code snippet,
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
List<String> ls = new ArrayList<String>();
JSONObject jsonObj = new JSONObject();
JSONArray jsonArr = new JSONArray();
JSONParser jsonParse = new JSONParser();
String str = "[{\"id\": \"0\",\"name\": \"Bob\",\"place\": \"Colorado\"},"
+ "{\"id\": \"1\",\"name\": \"John\",\"place\": \"Chicago\"},"
+ "{\"id\": \"2\",\"name\": \"Marry\",\"place\": \"Miami\"}]";
try {
jsonArr= (JSONArray) jsonParse.parse(str); //parsing the JSONArray
if(jsonArr!=null){
int arrayLength =jsonArr.size(); //size is 3 here
for(int i=0;i<arrayLength;i++){
jsonObj = (JSONObject) jsonParse.parse(jsonArr.get(i).toString());
ls.add(jsonObj.get("name").toString()); //as we need only value of name into the list
}
System.out.println(ls);
}
} catch (ParseException e) {
e.printStackTrace();
}catch(Exception e1){
e1.printStackTrace();
}
As you have array, use JSONArray and used jsonParse to avoid any parsing error.
I have used json-simple API to acheive the above.