I'm don't understand, why code below prints 0.0.9.229 instead 127.0.0.1. Can anybody tell me, hot to fix that?
String ha = InetAddress.getLocalHost().getHostAddress();
System.out.println(ha);
UPD:
Code running on Ubuntu
/etc/hosts
127.0.0.1 localhost
127.0.1.1 2533
InetAddress.getLocalHost() doesn't do what most people think that it does. It actually returns the hostname of the machine, and the IP address associated with that hostname. This may be the address used to connect to the outside world. It may not. It just depends on how you have your system configured.
On my windowsbox it gets the machine name and the external ip address. On my linux box it returns hostname and 127.0.0.1 because I have it set so in /etc/hosts
The problem is that my hostname will consists only of numbers and could not be resolved.
I change my /etc/hostname with characters at first position and problem has solved.
Use NetworkInterface to enumerate network interfaces; InetAddress.getLocalHost() always returns loopback.If you want to get all IP's associated with your machine use NetworkInterface then you will get 127.0.0.1 also.
Enumeration<NetworkInterface> nInterfaces = NetworkInterface.getNetworkInterfaces();
while (nInterfaces.hasMoreElements()) {
Enumeration<InetAddress> inetAddresses = nInterfaces.nextElement().getInetAddresses();
while (inetAddresses.hasMoreElements()) {
String address = inetAddresses.nextElement().getHostAddress();
System.out.println(address);
}
}
Related
Under what circumstances does InetAddress.getLocalHost().getHostAddress() return a different IP address than InetAddress.getByName("localhost")?
On my system, one returns 192.168.0.2 while the other returns 127.0.0.1
seems, InetAddress.getLocalHost().getHostAddress() is returning your system ip and InetAddress.getByName("localhost") the loopback address.
I doubt the security manager case described by Parthian for getByName, As per InetAddress API specification for getByName():
http://docs.oracle.com/javase/7/docs/api/java/net/InetAddress.html#getByName%28java.lang.String%29
The method throws: SecurityException - if a security manager exists and its checkConnect method doesn't allow the operation.
whereas getLocalHost() doesn't throw any such exception but returns loopback address as failsafe.
http://docs.oracle.com/javase/7/docs/api/java/net/InetAddress.html#getLocalHost%28%29
getByName() needs to connect to DNS to resolve hostname.
getByName() in this case is resolving 'localhost' from /etc/hosts(linux) or C:\Windows\System32\drivers\etc (windows). The hostname ip pair is user configurable in these files.
To check, you can provide any value to localhost, e.g: localhost 127.0.0.2 in hosts file, and getByName will return it.
According to this:
"[InetAddress.getLocalHost()] Returns the address of the local host. This is achieved by retrieving the name of the host from the system, then resolving that name into an InetAddress.
Note: The resolved address may be cached for a short period of time.
If there is a security manager, its checkConnect method is called with the local host name and -1 as its arguments to see if the operation is allowed. If the operation is not allowed, an InetAddress representing the loopback address is returned."
Probably what's happened is you're getting the loopback address because your security manager doesn't allow you to connect using the local subnet's 192 address.
InetAddress.getByName("localhost") justs asks the operating system to perform a name resolution, from what I can tell, anyway.
Java is giving 127.0.0.1 as IP for InetAddress.getByName("localhost").getHostAddress()
But why java not gives "localhost" for InetAddress.getByName("127.0.0.1").getHostName. For later one I get "127.0.0.1" as host name. Please clarify this.
The javadoc of InetAddress.getByName(String) states
The host name can either be a machine name, such as "java.sun.com", or
a textual representation of its IP address. If a literal IP address is
supplied, only the validity of the address format is checked.
So it doesn't actually go to your hosts file (or DNS) for an IP address. It just creates a InetAddress object with both hostname and address created from the String you provided.
For your first example
InetAddress.getByName("localhost").getHostAddress()
Assuming you have a hosts file entry like
127.0.0.1 localhost
then the InetAddress object returned will have that information, ie. a hostname of localhost and an address of 127.0.0.1.
Similarly, if you had
1.2.3.4 this.is.a.name
and
InetAddress localhost = InetAddress.getByName("this.is.a.name");
The returned InetAddress would be constructed with a hostname of this.is.a.name and an address of 1.2.3.4, because it actually went and checked.
I have the DNS server IP address and a hostname.
Using Java, how can I find the IP address of the hostname as returned by that DNS server using the IP address and the hostname?
Take a look at InetAddress and the getHostAddress() method.
InetAddress address = InetAddress.getByName("www.example.com");
System.out.println(address.getHostAddress());
You can do it like this:
for(InetAddress addr : InetAddress.getAllByName("stackoverflow.com"))
System.out.println(addr.getHostAddress());
You can use InetAddress for this. Try the below code,
InetAddress address = InetAddress.getByName("www.yahoo.com");
System.out.println(address.getHostAddress());
System.out.println(address.getHostName());
As suggested by all above, you can use
InetAddress.getByName("hostName") but this can give you a cached IP, Read the java documentation for the same.
If you want to get a IP from DNS you can use:
InetAddress[] ipAddress = DNSNameService.lookupAllHostAddr("hostName");
I've tried many examples on web and one of them is this:
http://zerioh.tripod.com/ressources/sockets.html
All of the server-client socket examples work fine when they are tested with 127.0.0.1
BUT it never ever EVAR works on two different computers with actual raw real IP address ("could not connect to host" on telnet and "connection timed out" when tested on java client - the server program just waits for connection)
Note:
Firewall is turned off for sure
IP address from ipconfig didn't work
IP address from myipaddress.com (which is totally different for no reason than that from ipconfig) didn't work
What is it that I'm missing?
If I can only figure this out...
Try binding on 0.0.0.0. This tells your socket to accept connections on every IP your local can accept upon.
Based on the comment where the the following snippet of code is mentioned:
requestSocket = new Socket("10.0.0.5", 2004); // ip from ipconfig
it would be better to use the hostname instead of the IP address in the constructor, as the two-parameter Socket constructor with a String argument expects the hostname as the String, and not an IP address. A lookup of the IP address is then performed on the provided hostname.
If you need to pass in an IP address, use the two-parameter constructor that accepts the InetAddress as an argument. You can then provide a raw IP address to the InetAddress.getByAddress method, as shown in the following snippet:
InetAddress addr = InetAddress.getByAddress(new byte[]{10,0,0,5});
You'll need to be careful when specifying arguments via the byte array, as bytes are signed in Java (-127 through +128), and numbers beyond this range (but valid octets of IP addresses) may have to be specified using Integer.byteValue.
Finally, it should be noted that it is important to specify the IP address of the remote machine, as visible to the client. The IP address listed at myipaddress.com may be the address of a proxy, as that is the public IP of your entire network as visible to the host server at myipaddress.com. Therefore, you ought to be specify the IP address of the remote machine that is visible to your machine and not myipaddress.com.
import java.net.*;
class check {
public static void main(String args[])throws Exception {
InetAddress address=InetAddress.getLocalHost();
System.out.println(address);
}
}
Now the first output is when i am connected to internet and second output is when i am not connected to internet.
What type of ip address is the second one? (the one encapsulated in InetAddress with internet not working)
Please help me in this.
127.0.0.1 is the loopback address. It's always present on your computer. When you don't have an externally accessible IP assigned to your machine, that's your local address.
127.0.0.1 is the canonical loopback address, in short, it's an always-available address of your own machine.
Actually, just googling this address brings relevant info instantly.
127.0.0.1 is the default loopback address of any machine when its no assigned particular ip