Develop Reference

Java Android FCM sending message to user Server returned HTTP response code

I did this :
public class PushNotifictionHelper {
public final static String AUTH_KEY_FCM = "AIzaSyD63pfTvnwhe9WVuIe.........";
public final static String API_URL_FCM = "https://fcm.googleapis.com/fcm/send";
public static String sendPushNotification(String deviceToken)
throws IOException, JSONException {
String result = "";
URL url = new URL(API_URL_FCM);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setUseCaches(false);
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Authorization", "key=" + AUTH_KEY_FCM);
conn.setRequestProperty("Content-Type", "application/json");
JSONObject json = new JSONObject();
json.put("to", deviceToken.trim());
JSONObject info = new JSONObject();
info.put("title", "notification title"); // Notification title
info.put("body", "message body"); // Notification
// body
json.put("notification", info);
try {
OutputStreamWriter wr = new OutputStreamWriter(
conn.getOutputStream());
wr.write(json.toString());
wr.flush();
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
result = "OK";
} catch (Exception e) {
e.printStackTrace();
result = "BAD";
}
System.out.println("GCM Notification is sent successfully");
return result;
}
public static void main(String [] args){
try {
PushNotifictionHelper.sendPushNotification("ep51x3Ckmig:APA91bG4PdoJC7zGlV0JPmCA49jmqJCkeSPH1QzF9byxdH1nRlFOVyAi9ppO2ygoSpp8s44o1oGO8n-HCJDB_oZAZ6WCwFD2a9yAFmKIpKhmPXakeLf-ktqPnzwf-GFziv7_nMdVPIci");
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
}
}
And when I run this in console I see
java.io.IOException: Server returned HTTP response code: 401 for URL: https://fcm.googleapis.com/fcm/send
an AUTH_KEY_FCM I get from web from this:
Klucz interfejsu Web API AIzaSyD63pfTvnwhe9WVuIe.........

The 401 error refers to an Authentication error. From the docs:
The sender account used to send a message couldn't be authenticated. Possible causes are:
Authorization header missing or with invalid syntax in HTTP request.
Invalid project number sent as key.
Key valid but with FCM service disabled.
Request originated from a server not whitelisted in the Server key IPs.
Check that the token you're sending inside the Authentication header is the correct Server key associated with your project. See Checking the validity of a Server key for details.
When using FCM, you should always make use of the Server Key (not the Web API Key) seen in the Cloud Messaging Tab in your Firebase Console.

Querying Data from SUGARCRM

I have SugarCRM trail account. I can able to get Authenticate and get the AccessToken by the following url.
https://xxxxxxx.trial.sugarcrm.eu/rest/v10/oauth2/token
Method : POST
POST Data : postData: { "grant_type":"password", "client_id":"sugar", "client_secret":"", "username":"admin", "password":"Admin123", "platform":"base" }
Code I used to get the AccessToken
public static String getAccessToken() throws JSONException {
HttpURLConnection connection = null;
JSONObject requestBody = new JSONObject();
requestBody.put("grant_type", "password");
requestBody.put("client_id", CLIENT_ID);
requestBody.put("client_secret", CLIENT_SECRET);
requestBody.put("username", USERNAME);
requestBody.put("password", PASSWORD);
requestBody.put("platform", "base");
try {
URL url = new URL(HOST_URL + AUTH_URL);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "application/json");
connection.setUseCaches(false);
connection.setDoOutput(true);
connection.connect();
BufferedWriter out = new BufferedWriter(new OutputStreamWriter(connection.getOutputStream()));
out.write(requestBody.toString());
out.close();
int responseCode = connection.getResponseCode();
BufferedReader in = new BufferedReader(
new InputStreamReader(connection.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
JSONObject jObject = new JSONObject(response.toString());
if(!jObject.has("access_token")){
return null;
}
String accessToken = jObject.getString("access_token");
return accessToken;
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
Now I have retrive Leads from CRM using rest API I can not able to find the appropriate method and Url to do the thing.
I can see the list rest of API's from /help but I cant understand what should be my module name and what I have to :record and how do I pass my access token for authentication.
Can anyone please help me?

The module name is simply the module you which to fetch records from, so in your case you'll want to do a GET request to rest/v10/Leads for a list of Leads. If you want to fetch a specific Lead you replace :record with the id of a Lead - for example: GET rest/v10/Leads/LEAD-ID-HERE
SugarCRM's documentation has a lot of relevant information that might not be included in /help plus working examples.
http://support.sugarcrm.com/Documentation/Sugar_Developer/Sugar_Developer_Guide_7.8/Integration/Web_Services/v10/Endpoints/module_GET/
http://support.sugarcrm.com/Documentation/Sugar_Developer/Sugar_Developer_Guide_7.8/Integration/Web_Services/v10/Examples/PHP/How_to_Fetch_Related_Records/

You need to include your retrieved token into an OAuth-Token header for subsequent requests, and then just use the module name as the endpoint i.e. in your case: "rest/v10/Leads" and call the GET method to retrieve them. Try something akin to this:
String token = getAccessToken();
HttpURLConnection connection = null;
try {
URL url = new URL(HOST_URL + "/rest/v10/Leads");
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("OAuth-Token", token);
connection.setUseCaches(false);
connection.setDoOutput(true);
connection.connect();
int responseCode = connection.getResponseCode();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
JSONObject jObject = new JSONObject(response.toString());
System.out.println(jObject);
} catch (Exception e) {
e.printStackTrace();
}
In the case you want to filter it down to specific id's to cut down on the amount of returned data, you can specify it after the module name i.e. "rest/v10/Leads/{Id}"

Use webservice in Android

I need to send data to a web service that is write in c# .net,
if I use a c# program it can get the names of the web service and
the function that I can use I guess cause it's java it can't do the same
as c#, if someone know how to do this it's will be great.
thanks for the help!
I use httpURLConnection and write this code to send and get the response
from connection.
BufferedReader reader = null;
try {
URL url = new URL(uri);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
StringBuilder sb = new StringBuilder();
reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
String line;
while ((line = reader.readLine()) != null) {
sb.append(line + '\n');
}
Log.i("","here "+sb.toString());
return sb.toString();
} catch (Exception e) {
Log.i("","problem in connection");
return null;
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}

If I'm not mistaken, C# web services uses SOAP protocol, so you'll probably need to parse the soap response which will give the information about the web service api:
check this thread:
Parsing SoapObject Responst in android

Strange FileNotFoundException in AVD on Tomcat connect

My android servlet is designed to post request and receive responses with a tomcat servlet on an Apache Tomcat server. For debugging, I have set up the Servlet with identical POST and GET methods so I can try the functionalities and accessability via browsers.
To cut the long story short: When I deploy the app, I can easily access it from the AVD device browser via 10.0.2.2:8080/my_app?request=test and I get a result that's just fine. Same is true for access from my machine with localhost:8080/my_app?request=test.
But when I try it from my app, I always get a java.io.FileNotFoundException: http://10.0.2.2:8080/my_app.
Why?
What did I try so far: The app has internet permissions and they also work, for to get to the Servlet communication point, I have to go through a login procedure via PHP first, and it's on the same server and works normally.
My AsyncTaskconnecting to the servlet looks like this:
AsyncTask<Void,Void,String> getDBdata = new AsyncTask<Void, Void, String>() {
#Override
protected String doInBackground(Void... params) {
URL url = null;
try {
url = new URL("http://10.0.2.2:8080/my_app");
} catch (MalformedURLException e) {
e.printStackTrace();
}
String text;
text = null;
JsonArray js = null;
try {
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestMethod("POST");
connection.setRequestProperty("action", "getDBData");
connection.setDoInput(true);
connection.connect();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
StringBuilder builder = new StringBuilder();
String aux = "";
while ((aux = in.readLine()) != null) {
builder.append(aux);
}
text = builder.toString();
} catch (IOException e) {
e.printStackTrace();
}
return text;

Alright, of course I've been trying to send params in the header, and this led to BS. Rookie mistake!
bcody's answer from this question helped me a lot with debugging! Also, taking a look at the server protocol from the servlet might have led me to the error earlier.
This is the code that finally worked:
AsyncTask<Void,Void,String> getDBdata = new AsyncTask<Void, Void, String>() {
#Override
protected String doInBackground(Void... params) {
URL url = null;
try {
url = new URL(Constants.SERVER_URL + getDBdataURL);
} catch (MalformedURLException e) {
e.printStackTrace();
}
String text;
text = null;
try {
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("Accept-Charset", "UTF-8");
connection.setRequestProperty("User-Agent", "Mozilla/5.0 ( compatible ) ");
connection.setRequestProperty("Accept", "*/*");
connection.setChunkedStreamingMode(0);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setDoOutput(true);
connection.setRequestMethod("POST");
String request = "action=getDBdata";
PrintWriter pw = new PrintWriter(connection.getOutputStream());
pw.print(request);
pw.close();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
StringBuilder builder = new StringBuilder();
String aux = "";
while ((aux = in.readLine()) != null) {
builder.append(aux);
}
text = builder.toString();
} catch (IOException e) {
e.printStackTrace();
}
return text;
}

Java HTTPS Client [duplicate]

I'm trying to find Java's equivalent to Groovy's:
String content = "http://www.google.com".toURL().getText();
I want to read content from a URL into string. I don't want to pollute my code with buffered streams and loops for such a simple task. I looked into apache's HttpClient but I also don't see a one or two line implementation.

Now that some time has passed since the original answer was accepted, there's a better approach:
String out = new Scanner(new URL("http://www.google.com").openStream(), "UTF-8").useDelimiter("\\A").next();
If you want a slightly fuller implementation, which is not a single line, do this:
public static String readStringFromURL(String requestURL) throws IOException
{
try (Scanner scanner = new Scanner(new URL(requestURL).openStream(),
StandardCharsets.UTF_8.toString()))
{
scanner.useDelimiter("\\A");
return scanner.hasNext() ? scanner.next() : "";
}
}

This answer refers to an older version of Java. You may want to look at ccleve's answer.
Here is the traditional way to do this:
import java.net.*;
import java.io.*;
public class URLConnectionReader {
public static String getText(String url) throws Exception {
URL website = new URL(url);
URLConnection connection = website.openConnection();
BufferedReader in = new BufferedReader(
new InputStreamReader(
connection.getInputStream()));
StringBuilder response = new StringBuilder();
String inputLine;
while ((inputLine = in.readLine()) != null)
response.append(inputLine);
in.close();
return response.toString();
}
public static void main(String[] args) throws Exception {
String content = URLConnectionReader.getText(args[0]);
System.out.println(content);
}
}
As #extraneon has suggested, ioutils allows you to do this in a very eloquent way that's still in the Java spirit:
InputStream in = new URL( "http://jakarta.apache.org" ).openStream();
try {
System.out.println( IOUtils.toString( in ) );
} finally {
IOUtils.closeQuietly(in);
}

Or just use Apache Commons IOUtils.toString(URL url), or the variant that also accepts an encoding parameter.

There's an even better way as of Java 9:
URL u = new URL("http://www.example.com/");
try (InputStream in = u.openStream()) {
return new String(in.readAllBytes(), StandardCharsets.UTF_8);
}
Like the original groovy example, this assumes that the content is UTF-8 encoded. (If you need something more clever than that, you need to create a URLConnection and use it to figure out the encoding.)

Now that more time has passed, here's a way to do it in Java 8:
URLConnection conn = url.openConnection();
try (BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream(), StandardCharsets.UTF_8))) {
pageText = reader.lines().collect(Collectors.joining("\n"));
}

Additional example using Guava:
URL xmlData = ...
String data = Resources.toString(xmlData, Charsets.UTF_8);

Java 11+:
URI uri = URI.create("http://www.google.com");
HttpRequest request = HttpRequest.newBuilder(uri).build();
String content = HttpClient.newHttpClient().send(request, BodyHandlers.ofString()).body();

If you have the input stream (see Joe's answer) also consider ioutils.toString( inputstream ).
http://commons.apache.org/io/api-1.4/org/apache/commons/io/IOUtils.html#toString(java.io.InputStream)

The following works with Java 7/8, secure urls, and shows how to add a cookie to your request as well. Note this is mostly a direct copy of this other great answer on this page, but added the cookie example, and clarification in that it works with secure urls as well ;-)
If you need to connect to a server with an invalid certificate or self signed certificate, this will throw security errors unless you import the certificate. If you need this functionality, you could consider the approach detailed in this answer to this related question on StackOverflow.
Example
String result = getUrlAsString("https://www.google.com");
System.out.println(result);
outputs
<!doctype html><html itemscope="" .... etc
Code
import java.net.URL;
import java.net.URLConnection;
import java.io.BufferedReader;
import java.io.InputStreamReader;
public static String getUrlAsString(String url)
{
try
{
URL urlObj = new URL(url);
URLConnection con = urlObj.openConnection();
con.setDoOutput(true); // we want the response
con.setRequestProperty("Cookie", "myCookie=test123");
con.connect();
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
StringBuilder response = new StringBuilder();
String inputLine;
String newLine = System.getProperty("line.separator");
while ((inputLine = in.readLine()) != null)
{
response.append(inputLine + newLine);
}
in.close();
return response.toString();
}
catch (Exception e)
{
throw new RuntimeException(e);
}
}

Here's Jeanne's lovely answer, but wrapped in a tidy function for muppets like me:
private static String getUrl(String aUrl) throws MalformedURLException, IOException
{
String urlData = "";
URL urlObj = new URL(aUrl);
URLConnection conn = urlObj.openConnection();
try (BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream(), StandardCharsets.UTF_8)))
{
urlData = reader.lines().collect(Collectors.joining("\n"));
}
return urlData;
}

URL to String in pure Java
Example call to get payload from http get call
String str = getStringFromUrl("YourUrl");
Implementation
You can use the method described in this answer, on How to read URL to an InputStream and combine it with this answer on How to read InputStream to String.
The outcome will be something like
public String getStringFromUrl(URL url) throws IOException {
return inputStreamToString(urlToInputStream(url,null));
}
public String inputStreamToString(InputStream inputStream) throws IOException {
try(ByteArrayOutputStream result = new ByteArrayOutputStream()) {
byte[] buffer = new byte[1024];
int length;
while ((length = inputStream.read(buffer)) != -1) {
result.write(buffer, 0, length);
}
return result.toString(UTF_8);
}
}
private InputStream urlToInputStream(URL url, Map<String, String> args) {
HttpURLConnection con = null;
InputStream inputStream = null;
try {
con = (HttpURLConnection) url.openConnection();
con.setConnectTimeout(15000);
con.setReadTimeout(15000);
if (args != null) {
for (Entry<String, String> e : args.entrySet()) {
con.setRequestProperty(e.getKey(), e.getValue());
}
}
con.connect();
int responseCode = con.getResponseCode();
/* By default the connection will follow redirects. The following
* block is only entered if the implementation of HttpURLConnection
* does not perform the redirect. The exact behavior depends to
* the actual implementation (e.g. sun.net).
* !!! Attention: This block allows the connection to
* switch protocols (e.g. HTTP to HTTPS), which is <b>not</b>
* default behavior. See: https://stackoverflow.com/questions/1884230
* for more info!!!
*/
if (responseCode < 400 && responseCode > 299) {
String redirectUrl = con.getHeaderField("Location");
try {
URL newUrl = new URL(redirectUrl);
return urlToInputStream(newUrl, args);
} catch (MalformedURLException e) {
URL newUrl = new URL(url.getProtocol() + "://" + url.getHost() + redirectUrl);
return urlToInputStream(newUrl, args);
}
}
/*!!!!!*/
inputStream = con.getInputStream();
return inputStream;
} catch (Exception e) {
throw new RuntimeException(e);
}
}
Pros
It is pure java
It can be easily enhanced by adding different headers as a map (instead of passing a null object, like the example above does), authentication, etc.
Handling of protocol switches is supported