Develop Reference

Remove parts of String? [duplicate]

I want to remove a part of string from one character, that is:
Source string:
manchester united (with nice players)
Target string:
manchester united

There are multiple ways to do it. If you have the string which you want to replace you can use the replace or replaceAll methods of the String class. If you are looking to replace a substring you can get the substring using the substring API.
For example
String str = "manchester united (with nice players)";
System.out.println(str.replace("(with nice players)", ""));
int index = str.indexOf("(");
System.out.println(str.substring(0, index));
To replace content within "()" you can use:
int startIndex = str.indexOf("(");
int endIndex = str.indexOf(")");
String replacement = "I AM JUST A REPLACEMENT";
String toBeReplaced = str.substring(startIndex + 1, endIndex);
System.out.println(str.replace(toBeReplaced, replacement));

String Replace
String s = "manchester united (with nice players)";
s = s.replace(" (with nice players)", "");
Edit:
By Index
s = s.substring(0, s.indexOf("(") - 1);

Use String.Replace():
http://www.daniweb.com/software-development/java/threads/73139
Example:
String original = "manchester united (with nice players)";
String newString = original.replace(" (with nice players)","");

originalString.replaceFirst("[(].*?[)]", "");
https://ideone.com/jsZhSC
replaceFirst() can be replaced by replaceAll()

Using StringBuilder, you can replace the following way.
StringBuilder str = new StringBuilder("manchester united (with nice players)");
int startIdx = str.indexOf("(");
int endIdx = str.indexOf(")");
str.replace(++startIdx, endIdx, "");

You should use the substring() method of String object.
Here is an example code:
Assumption: I am assuming here that you want to retrieve the string till the first parenthesis
String strTest = "manchester united(with nice players)";
/*Get the substring from the original string, with starting index 0, and ending index as position of th first parenthesis - 1 */
String strSub = strTest.subString(0,strTest.getIndex("(")-1);

I would at first split the original string into an array of String with a token " (" and the String at position 0 of the output array is what you would like to have.
String[] output = originalString.split(" (");
String result = output[0];

Using StringUtils from commons lang
A null source string will return null. An empty ("") source string will return the empty string. A null remove string will return the source string. An empty ("") remove string will return the source string.
String str = StringUtils.remove("Test remove", "remove");
System.out.println(str);
//result will be "Test"

If you just need to remove everything after the "(", try this. Does nothing if no parentheses.
StringUtils.substringBefore(str, "(");
If there may be content after the end parentheses, try this.
String toRemove = StringUtils.substringBetween(str, "(", ")");
String result = StringUtils.remove(str, "(" + toRemove + ")");
To remove end spaces, use str.trim()
Apache StringUtils functions are null-, empty-, and no match- safe

Kotlin Solution
If you are removing a specific string from the end, use removeSuffix (Documentation)
var text = "one(two"
text = text.removeSuffix("(two") // "one"
If the suffix does not exist in the string, it just returns the original
var text = "one(three"
text = text.removeSuffix("(two") // "one(three"
If you want to remove after a character, use
// Each results in "one"
text = text.replaceAfter("(", "").dropLast(1) // You should check char is present before `dropLast`
// or
text = text.removeRange(text.indexOf("("), text.length)
// or
text = text.replaceRange(text.indexOf("("), text.length, "")
You can also check out removePrefix, removeRange, removeSurrounding, and replaceAfterLast which are similar
The Full List is here: (Documentation)

// Java program to remove a substring from a string
public class RemoveSubString {
public static void main(String[] args) {
String master = "1,2,3,4,5";
String to_remove="3,";
String new_string = master.replace(to_remove, "");
// the above line replaces the t_remove string with blank string in master
System.out.println(master);
System.out.println(new_string);
}
}

You could use replace to fix your string. The following will return everything before a "(" and also strip all leading and trailing whitespace. If the string starts with a "(" it will just leave it as is.
str = "manchester united (with nice players)"
matched = str.match(/.*(?=\()/)
str.replace(matched[0].strip) if matched

delete dynamic character from string

I have a string containing numbers separated with ,. I want to remove the , before the first character.
The input is ,1,2,3,4,5,6,7,8,9,10, and this code does not work:
results.replaceFirst(",","");

Strings are immutable in Java. Calling a method on a string will not modify the string itself, but will instead return a new string.
In order to capture this new string, you need to assign the result of the operation back to a variable:
results = results.replaceFirst(",", "");

Try this
String str = ",1,2,3,4,5,6,7,8,9,10";
str = str .startsWith(",") ? str .substring(1) : str ;
System.out.println("output"+str); // 1,2,3,4,5,6,7,8,9,10

you can also do like this ..
String str = ",1,2,3,4,5,6,7,8,9,10";
String stre = str.replaceFirst("^,", "");
Log.e("abd",stre);

Try this
String str = ",1,2,3,4,5,6,7,8,9,10";
if(Objects.nonNull(str) && str.startsWith(",")){
str = str.substring(1, str.length());
}
it will remove , at first position

Java get the same String after split

In Java if you want to split a String by a char or a String you can do that by the split method as follow:
String[] stringWords = myString.split(" ");
But let's say i want now to create a new String using the strings in stringWords using the char * between them. Is there any solutions to do it without for/while instructions?
Here is a clear example:
String myString = "This is how the string should be";
String iWant = "This*is*how*the*string*should*be";
Somebody asks me to be more clear why i don't want just to use replace() function. I don't want to use it simply because the content of the array of strings (array stringWords in my example) changes it's content.
Here is an example:
String myString = "This is a string i wrote"
String[] stringWords = myString.split(" ");
myAlgorithmFucntion(stringWords);
Here is an example of how tha final string changes:
String iWant = "This*is*something*i*wrote*and*i*don't*want*to*do*it*anymore";

If you don't want to use replace or similar, you can use the Apache Commons StringUtils:
String iWant = StringUtils.join(stringWords, "*");
Or if you don't want to use Apache Commons, then as per comment by Rory Hunter you can implement your own as shown here.

yes there is solution to, split String with special characters like '*','.' etc. you have to use special backshlas.
String myString = "This is how the string should be";
iWant = myString.replaceAll(" ","*"); //or iWant = StringUtils.join(Collections.asList(myString.split(" ")),"*");
iWant = "This*is*how*the*string*should*be";
String [] tab = iWant.split("\\*");

Try something like this as you don't want to use replace() function
char[] ans=myString.toCharArray();
for(int i =0; i < ans.length; i++)
{
if(ans[i]==' ')ans[i]='*';
}
String answer=new String(ans);

Try looping the String array:
String[] stringWords = myString.split(" ");
String myString = "";
for (String s : stringWords){
myString = myString + "s" + "*";
}
Just add the logic to deleting the last * of the String.
Using StringBuilder option:
String[] stringWords = myString.split(" ");
StringBuilder myStringBuilder = new StringBuilder("");
for (String s : stringWords){
myStringBuilder.append(s).append("*");
}

Checking whether the String contains multiple words

I am getting the names as String. How can I display in the following format: If it's single word, I need to display the first character alone. If it's two words, I need to display the first two characters of the word.
John : J
Peter: P
Mathew Rails : MR
Sergy Bein : SB
I cannot use an enum as I am not sure that the list would return the same values all the time. Though they said, it's never going to change.
String name = myString.split('');
topTitle = name[0].subString(0,1);
subTitle = name[1].subString(0,1);
String finalName = topTitle + finalName;
The above code fine, but its not working. I am not getting any exception either.

There are few mistakes in your attempted code.
String#split takes a String as regex.
Return value of String#split is an array of String.
so it should be:
String[] name = myString.split(" ");
or
String[] name = myString.split("\\s+);
You also need to check for # of elements in array first like this to avoid exception:
String topTitle, subTitle;
if (name.length == 2) {
topTitle = name[0].subString(0,1);
subTitle = name[1].subString(0,1);
}
else
topTitle = name.subString(0,1);

The String.split method split a string into an array of strings, based on your regular expression.
This should work:
String[] names = myString.split("\\s+");
String topTitle = names[0].subString(0,1);
String subTitle = names[1].subString(0,1);
String finalName = topTitle + finalName;

First: "name" should be an array.
String[] names = myString.split(" ");
Second: You should use an if function and the length variable to determine the length of a variable.
String initial = "";
if(names.length > 1){
initial = names[0].subString(0,1) + names[1].subString(0,1);
}else{
initial = names[0].subString(0,1);
}
Alternatively you could use a for loop
String initial = "";
for(int i = 0; i < names.length; i++){
initial += names[i].subString(0,1);
}

You were close..
String[] name = myString.split(" ");
String finalName = name[0].charAt(0)+""+(name.length==1?"":name[1].charAt(0));
(name.length==1?"":name[1].charAt(0)) is a ternary operator which would return empty string if length of name array is 1 else it would return 1st character

This will work for you
public static void getString(String str) throws IOException {
String[] strr=str.split(" ");
StringBuilder sb=new StringBuilder();
for(int i=0;i<strr.length;i++){
sb.append(strr[i].charAt(0));
}
System.out.println(sb);
}

string manipulation in java, getting first characters

Lets say I have a string whose format is "name_surname". I mean there are 2 dynamic parts, and between them an underscore. I want to separate them and have in a variable the left part (name) and in another the right (surname).
Basically i want the reverse of this: String temp=name+"_"+surname;

Use split();
String[] parts = temp.split("_");
String name = parts[0];
String surname = parts[1]; // <-- comment
Commented line will throw an ArrayIndexOutOfBoundsException if your name does not contain the underscore.

You should use split.
String fullName = "name_surname";
String[] components = fullName.split("_");
String firstName = components[0];
String lastName = components[1];

Just use StringTokenizer
StringTokenizer st = new StringTokenizer(str, "_");
while (st.hasMoreElements()) {
System.out.println(st.nextElement());
}