I have one entity called Change where I need log changes in database like inserting, updating or deleting rows.
So my Change table contains some data and now I would like to add foreign key to record changes in another table, but I have different tables. For example I have Weather table, Group table,... So I have done some searching and I have found a little bit about #Any annotation. So I added some columns to my Change entity:
#Entity
#Table(name = "CHANGE")
public class Change {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "CHANGE_ID")
private int changeId;
...
#Any(metaColumn = #Column(name = "RECORD_TABLE"))
#AnyMetaDef(idType = "int", metaType = "string",
metaValues = {
#MetaValue(targetEntity = Weather.class, value = "WEATHER"),
#MetaValue(targetEntity = Group.class, value = "GROUP"),
...
})
#JoinColumn(name="recordID")
private Object record;
#ManyToOne
#JoinColumn(name = "USER_ID")
private User user;
public Object getRecord() {
return record;
}
public void setRecord(Object record) {
this.record = record;
}
...
And my stupid question is:
How can I insert data into database (like foreign ID and class name) and how could I retrieve them?
Please go through this Link
You should care about your entity relationship (1-1 or 1-M or M-M)
Related
I have generated master tables using liquibase. I have created the corresponding models in spring boot now I want to maintain a relation ship between those models.
I have one table called Vehicle_Type, it is already pre-populated using liquibase.
#Data
#Entity
#Table(name="VEHCILE_TYPE")
public class VehicleType {
#Id
private int id;
#Column(name="DISPLAY_NAME")
private String displayName;
#Column(name="TYPE")
private String type;
#Column(name="CREATED_DATE")
private LocalDateTime createdDate;
#Column(name="UPDATED_DATE")
private LocalDateTime updateDate;
}
now what I want to achieve is, I have one child entity, I have refer the VehicleType instance inside that entity as depicted below
#Data
#Entity
#EqualsAndHashCode(callSuper = true)
#Table(name = "NON_MSIL_VEHICLE_LAYOUT")
public class NonMsilVehicleLayout extends BaseImagesAndLayout {
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "NMV_SEQ")
#SequenceGenerator(sequenceName = "NON_MSIL_VEH_SEQUENCE", allocationSize = 1, name = "NMV_SEQ")
private int id;
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name = "VEH_TYPE", referencedColumnName = "id")
private VehicleType vehicleType;
public interface VehType {
String getVehType();
}
}
The problem is when I tries to save entity NonMsilVehicleLayout, then it tries to first insert the data in VEHICLE_TYPE table also. which should not going to be happen.
I don't want that, I want JPA will pick the correct ID from VEHICLE_TYPE table and place it inside the corresponding table for NonMsilVehicleLayout, because the id of VEHICLE_TYPE table is act as foreign key in Non_Msil_Vehicle_Layout table.
log.info("Inside saveLayout::Start preparing entity to persist");
String resourceUri = null;
NonMsilVehicleLayout vehicleLayout = new NonMsilVehicleLayout();
VehicleType vehicleType=new VehicleType();
vehicleType.setType(modelCode);
vehicleLayout.setVehicleType(modelCode);
vehicleLayout.setFileName(FilenameUtils.removeExtension(FilenameUtils.getName(object.key())));
vehicleLayout.setS3BucketKey(object.key());
I know I missed something, but unable to figure it out.
You are creating a new VehicleType instance setting only the type field and set the vehicleType field of NonMsilVehicleLayout to that new instance. Since you specified CascadeType.ALL on NonMsilVehicleLayout#vehicleType, this means to Hibernate, that it has to persist the given VehicleType, because the instance has no primary key set.
I guess what you rather want is this code:
vehicleLayout.setVehicleType(
entitManager.createQuery("from VehicleType vt where vt.type = :type", VehicleType.class)
.setParameter("type", typeCode)
.getSingleResult()
);
This will load the VehicleType object by type and set that object on NonMsilVehicleLayout#vehicleType, which will then cause the foreign key column to be properly set to the primary key value.
Finally, after some workaround, I got the mistake, the column name attribute was incorrect, so I made it correct and remove the referencedColumn and Cascading.
Incorrect:
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name = "VEH_TYPE", referencedColumnName = "id")
private VehicleType vehicleType;
Correct:
#OneToOne
#JoinColumn(name = "VEHICLE_TYPE")
private VehicleType vehicleTypes;
also I have added the annotation #Column in the referende entity VehicleImage
public class VehicleType {
#Id
#Column(name = "ID") // added this one
private int id;
}
That bit workaround solved my problem, now I have achieved what I exactly looking for.
I'm trying to create a Rest API for a school project.Therefor I'm trying to save/edit a nested Object.
I have two bidirectional entities which look like this:
EntityA
#Entity
public class EntityA {
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Id
#Column(name = "id", nullable = false)
#JsonProperty("id")
private int id;
#Column(name = "field1", nullable = false, length = -1)
#JsonProperty("field1")
private String field1;
#Column(name = "field2", nullable = false, length = -1)
#JsonProperty("field2")
private String field2;
#OneToMany(mappedBy = "entityA", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
#JsonProperty("entityB")
private List<EntityB> entityB;
public EntityA() {
}
//Getter+Setter
}
EntityB
#Entity
public class EntityB {
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Id
#Column(name = "id", nullable = false)
#JsonProperty("id")
private int id;
#Column(name = "field1", nullable = false)
#JsonProperty("field1")
private Date field1;
#ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
#JoinColumn(...)
#JsonProperty("entityA")
private EntityA entityA;
public EntityB() {
}
//Getter+Setter
}
As RequestBody I will get JSON which should look like this.
{
"field1": "Test",
"field2": "User",
"entityB": [
{
"field1": "30.03.2022"
}
]
}
Right now Spring will automatically map the fields but as soon I try to save it to my DB I will get an error, because the relation in EntityB for EntityA is empty.
I've seen a solution, that I should loop through the EntityB list and add EntityA. I tried it with a for-each but it still sais it null.
What am I doing wrong?
public EntityA createEntityA(EntityA entityA) {
for(EntityB entityB : entityA.getEntityB()){
entityB.setEntityA(entityA);
}
return entityARepository.save(entityA);
}
Edit:
Controller
#PostMapping(value = {"/json/entitya/"})
#ResponseBody
public EntityA createEntityAJson(#RequestBody EntityA entityA) {
return entityAService.createEntityA(entityA);
}
Service
#Service
public class EntityAService {
#Autowired
private EntityARepository entityARepository;
public EntityA createEntityA(EntityA entityA) {
return entityARepository.save(entityA); //in this line the error appears
}
}
Error message
null value in column "entityA" violates not-null constraint
#Service
public class EntityAService {
#Autowired
private EntityARepository entityARepository;
#Autowired
private EntityBRepository entityBRepository;
public EntityA createEntityA(EntityA entityA) {
// create an empty arrayList to stock the entities B retrieveed from the DB
List<EnityB> lst = new ArrayList<>();
// get the entities B from the JSON and sabe it to the DB
for(EntityB entityB : entityA.getEntityB()){
entityB.setEntityA(entityA);
entityBRepository.save(entityB); // you should save entities B to the DataBase before
Optional<EntityB > opt = entityBRepository.findById(entityB.getId());
EntityB b = opt.get();
// add the entities B retrieved from the DB to the arrayList
lst.add(b);
}
// set the EntityB list with the new List from the DB ( include ids ..)
entityA.setEntityB(lst);
// save the entityA to the DB
return entityARepository.save(entityA);
}
}
I'm guessing that what is happening here is that the id fields which are of a non-nullable datatype or some other hidden field from the JPA annotations get set to the wrong value by the json deserialization for JPA to understand that they are new entities. Creating these entities manually in the Java code might solve the issue.
You shouldn't reuse your entity classes as data transfer object for your API. Having classes containing both database-specific annotations and annotations for JSON serialization is a bad idea and it goes against the single-responsibility principle (SRP).
Create separate DTO classes for your API endpoint, then read the entities from the database an copy the values from the DTO object to the entities before saving.
// Receive DTO
// Read entity from DB if update or create new entities if insert
// Copy values from DTO to entitiy
// Save entity
I think your problems will go away if you apply this pattern.
I'm working on adding a feature to an already developed spring boot web application. The primary entity that has child entities is a Record. It has a few columns/variables that I want to now be in its own, separate entity (CustomerOrder) and exist in a one-to-one relationship with the Record. To summarize:
Record {
thing 1
thing 2
thing 3
}
is now becoming:
CustomerOrder {
thing 1
thing 2
thing 3
}
Record {
CustomerOrder
}
I'm having some issues with what I've produced. Here is the CustomerOrder model's relevant relationship data:
#Entity
#Table(name="customer_orders")
public class CustomerOrder {
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private Long id;
... other columns
#OneToOne(orphanRemoval = true, cascade = CascadeType.ALL, mappedBy="customerOrder", fetch = FetchType.EAGER)
private Record record;
}
And then here is the Record model's relevant data:
#Entity
#Table(name="records")
public class Record extends Auditable<String> implements Serializable {
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private Long id;
... other columns
#OneToOne
#JoinColumn(name="customer_order_id", nullable = false, unique = true)
private CustomerOrder customerOrder;
}
My issue exists when I try to POST a record, when a user tries creating one in the ui. Here is the POST method for a record:
#PostMapping
public ResponseEntity<?> saveRecord(#RequestBody Record recordBody, BindingResult result) {
if(!result.hasErrors()) {
if(recordBody.getHardwareItems().isEmpty()) {
record = recordsService.save(recordBody);
} else {
// Save the record first, recordId is required on hardwareItems
// TODO: investigate Spring Hibernate/JPA rules - is there a way to save parent before children to avoid a null recordId
CustomerOrder customerOrder = recordBody.getCustomerOrder();
recordBody.setCustomerOrder(new CustomerOrder());
customerOrder.setRecord(record);
customerOrder = customerOrdersService.save(customerOrder);
record = recordsService.save(recordBody);
}
} else {
return new ResponseEntity<>(result.getAllErrors(), HttpStatus.BAD_REQUEST);
}
// Return the location of the created resource
uri = ServletUriComponentsBuilder.fromCurrentRequest().path("/{recordId}").buildAndExpand(record.getId()).toUri();
return new ResponseEntity<>(uri, HttpStatus.CREATED);
}
The error I receive is the following:
2021-02-19 00:46:28.398 WARN 29990 --- [io-8080-exec-10] o.h.engine.jdbc.spi.SqlExceptionHelper : SQL Error: 1364, SQLState: HY000
2021-02-19 00:46:28.398 ERROR 29990 --- [io-8080-exec-10] o.h.engine.jdbc.spi.SqlExceptionHelper : Field 'record_id' doesn't have a default value
This makes sense to me at least, since I'm trying to save the CustomerOrder object that depends on a Record object, which has yet to have been persisted. So, how do I go about changing up the order and/or creating and persisting a Record object so that I can then save the CustomerOrder object to it?
You need to mark your column record_id as AI(AUTO_INCREMENT) in your table definition.
ALTER TABLE records CHANGE record_id INT(6) NOT NULL AUTO_INCREMENT;
Your primary key is record_id, add #Column(name = "record_id", nullable = false)
#Entity
#Table(name="records")
public class Record extends Auditable<String> implements Serializable {
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name = "record_id", nullable = false)
private Long id;
... other columns
#OneToOne
#JoinColumn(name="customer_order_id", nullable = false, unique = true)
private CustomerOrder customerOrder;
}
I am currently stuck on an issue of updating a parent entity field and getting the update to cascade to all its children's fields.
Here is an example of what I am trying to accomplish:
User.java
#Entity
public class User {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
#Column(nullable = false, columnDefinition = "TINYINT(1) default false")
private Boolean archived = Boolean.FALSE;
#OneToMany(mappedBy = "user")
private Set<Invoice> invoices = new HashSet<Invoice>();
// Setters & Getters
}
Invoice.java
#Entity
public class Invoice{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
#Column(nullable = false, columnDefinition = "TINYINT(1) default false")
private Boolean archived = Boolean.FALSE;
#ManyToOne(mappedBy = "invoices")
#JoinColumn(nullable = false)
private User user;
// Setters & Getters
}
When I update the archived value to true. I want all the invoices to also be updated to true as well.
I.E
public Boolean archiveUserById(Integer id) {
User user= entity_manager.find(User.class, id);
Boolean result = false;
if(auction != null) {
// This should cascade to all the invoices as well and update their archived fields to true as well
user.setArchived(true);
try {
entity_manager.getTransaction().begin();
entity_manager.merge(auction);
entity_manager.getTransaction().commit();
result = true;
} catch(Exception e) {
e.printStackTrace();
}
}
return result;
}
I've tried using cascade = CascadeType.PERSIST and #JoinTable(....) with all the referenced columns, but they are still failing to update the fields correctly.
To clarify is there a way to update a child's field through its parents' update with a Cascade effect?
Thank-you for the help.
EDIT
To clarify my question, I am trying to add a constraint cascade effect when a field on the parent entity is updated to reflect on the child entity's same field. I am trying to avoid any logic within the Entity itself. Is there a way to do this through annotations only?
Something to the same effect as this:
ALTER TABLE `child` ADD CONSTRAINT `childs-archived-mirrors-parent`
FOREIGN KEY (`archived`, `parentId`)
REFERENCES `parent`(`archived`, `id`)
ON DELETE RESTRICT ON UPDATE CASCADE;
try adding #PreUpdate method on parent where you manually change children inside the list.
Thanks for all your help.
I ended up finding a solution. I created a custom foreign key definition that will cascade any update on the archived field to its child entities.
Below is how I accomplished that.
#Entity
public class Invoice{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
#Column(nullable = false, columnDefinition = "TINYINT(1) default false")
private Boolean archived = Boolean.FALSE;
#ManyToOne(mappedBy = "invoices")
#JoinColumn(nullable = false, foreignKey = #ForeignKey(foreignKeyDefinition = "FOREIGN KEY (archived, user_id) REFERENCES user(archived, id) ON DELETE RESTRICT ON UPDATE CASCADE"))
private User user;
// Setters & Getters
}
I'm trying to set up the following tables using JPA/Hibernate:
User:
userid - PK
name
Validation:
userid - PK, FK(user)
code
There may be many users and every user may have max one validation code or none.
Here's my classes:
public class User
{
#Id
#Column(name = "userid")
#GeneratedValue(strategy = GenerationType.IDENTITY)
protected Long userId;
#Column(name = "name", length = 50, unique = true, nullable = false)
protected String name;
...
}
public class Validation
{
#Id
#Column(name = "userid")
protected Long userId;
#OneToOne(cascade = CascadeType.ALL)
#PrimaryKeyJoinColumn(name = "userid", referencedColumnName = "userid")
protected User user;
#Column(name = "code", length = 10, unique = true, nullable = false)
protected String code;
...
public void setUser(User user)
{
this.user = user;
this.userId = user.getUserId();
}
...
}
I create a user and then try to add a validation code using the following code:
public void addValidationCode(Long userId)
{
EntityManager em = createEntityManager();
EntityTransaction tx = em.getTransaction();
try
{
tx.begin();
// Fetch the user
User user = retrieveUserByID(userId);
Validation validation = new Validation();
validation.setUser(user);
em.persist(validation);
tx.commit();
}
...
}
When I try to run it I get a org.hibernate.PersistentObjectException: detached entity passed to persist: User
I have also tried to use the following code in my Validation class:
public void setUserId(Long userId)
{
this.userId = userId;
}
and when I create a validation code I simply do:
Validation validation = new Validation();
validation.setUserId(userId);
em.persist(validation);
tx.commit();
But then since User is null I get org.hibernate.PropertyValueException: not-null property references a null or transient value: User.code
Would appreciate any help regarding how to best solve this issue!
I have been able to solve this problem of "OneToOne between two tables with shared primary key" in pure JPA 2.0 way(Thanks to many existing threads on SOF). In fact there are two ways in JPA to handle this. I have used eclipselink as JPA provider and MySql as database. To highlight once again no proprietary eclipselink classes have been used here.
First approach is to use AUTO generation type strategy on the Parent Entity's Identifier field.
Parent Entity must contain the Child Entity Type member in OneToOne relationship(cascade type PERSIST and mappedBy = Parent Entity Type member of Child Entity)
#Entity
#Table(name = "USER_LOGIN")
public class UserLogin implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name="USER_ID")
private Integer userId;
#OneToOne(cascade = CascadeType.PERSIST, mappedBy = "userLogin")
private UserDetail userDetail;
// getters & setters
}
Child Entity must not contain an identifier field. It must contain a member of Parent Entity Type with Id, OneToOne and JoinColumn annotations. JoinColumn must specify the ID field name of the DB table.
#Entity
#Table(name = "USER_DETAIL")
public class UserDetail implements Serializable {
#Id
#OneToOne
#JoinColumn(name="USER_ID")
private UserLogin userLogin;
// getters & setters
}
Above approach internally uses a default DB table named SEQUENCE for assigning the values to the identifier field. If not already present, This table needs to be created as below.
DROP TABLE TEST.SEQUENCE ;
CREATE TABLE TEST.SEQUENCE (SEQ_NAME VARCHAR(50), SEQ_COUNT DECIMAL(15));
INSERT INTO TEST.SEQUENCE(SEQ_NAME, SEQ_COUNT) values ('SEQ_GEN', 0);
Second approach is to use customized TABLE generation type strategy and TableGenerator annotation on the Parent Entity's Identifier field.
Except above change in identifier field everything else remains unchanged in Parent Entity.
#Entity
#Table(name = "USER_LOGIN")
public class UserLogin implements Serializable {
#Id
#TableGenerator(name="tablegenerator", table = "APP_SEQ_STORE", pkColumnName = "APP_SEQ_NAME", pkColumnValue = "USER_LOGIN.USER_ID", valueColumnName = "APP_SEQ_VALUE", initialValue = 1, allocationSize = 1 )
#GeneratedValue(strategy = GenerationType.TABLE, generator = "tablegenerator")
#Column(name="USER_ID")
private Integer userId;
#OneToOne(cascade = CascadeType.PERSIST, mappedBy = "userLogin")
private UserDetail userDetail;
// getters & setters
}
There is no change in Child Entity. It remains same as in the first approach.
This table generator approach internally uses a DB table APP_SEQ_STORE for assigning the values to the identifier field. This table needs to be created as below.
DROP TABLE TEST.APP_SEQ_STORE;
CREATE TABLE TEST.APP_SEQ_STORE
(
APP_SEQ_NAME VARCHAR(255) NOT NULL,
APP_SEQ_VALUE BIGINT NOT NULL,
PRIMARY KEY(APP_SEQ_NAME)
);
INSERT INTO TEST.APP_SEQ_STORE VALUES ('USER_LOGIN.USER_ID', 0);
If you use Hibernate you can also use
public class Validation {
private Long validationId;
private User user;
#Id
#GeneratedValue(generator="SharedPrimaryKeyGenerator")
#GenericGenerator(name="SharedPrimaryKeyGenerator",strategy="foreign",parameters = #Parameter(name="property", value="user"))
#Column(name = "VALIDATION_ID", unique = true, nullable = false)
public Long getValidationId(){
return validationId;
}
#OneToOne
#PrimaryKeyJoinColumn
public User getUser() {
return user;
}
}
Hibernate will make sure that the ID of Validation will be the same as the ID of the User entity set.
Are you using JPA or JPA 2.0 ?
If Validation PK is a FK to User, then you do not need the Long userId attribute in validation class, but instead do the #Id annotation alone. It would be:
Public class Validation
{
#Id
#OneToOne(cascade = CascadeType.ALL)
#PrimaryKeyJoinColumn(name = "userid", referencedColumnName = "userid")
protected User user;
#Column(name = "code", length = 10, unique = true, nullable = false)
protected String code;
...
public void setUser(User user)
{
this.user = user;
this.userId = user.getUserId();
}
...
}
Try with it and tell us your results.
You need to set both userId and user.
If you set just the user, then the id for Validation is 0 and is deemed detached. If you set just the userId, then you need to make the user property nullable, which doesn't make sense here.
To be safe, you can probably set them both in one method call:
#Transient
public void setUserAndId(User user){
this.userId = user.getId();
this.user = user;
}
I marked the method #Transient so that Hibernate will ignore it. Also, so you can still have setUser and setUserId work as expected with out any "side effects."