Develop Reference

Regex: Read value between multiple brackets

I currently working on translating a website (Smarty) with Poedit. To get all the text from the .tpl files i'm using regex to get the data between the {t} and {/t}. so an example:
{t}Password incorrect, please try again{/t}
The regex will read Password incorrect, please try again and place it in a .po file. This is all working fine. It goes wrong when it gets a little more advanced.
Sometimes the text between the {t} tags uses a parameter. this looks like this:
{t 1=$email|escape 2=$mailbox}No $1 given, please check your $2{/t}
This is also working great.
The real problem start when i use brackets inside the parameter like this:
{t 1={site info='name'} 2=$mailbox}visit %1 or go to your %2{/t}
My regex will close when it sees the first closing brackets so the result will be 2=$mailbox}visit %1 or go to your %2.
My regex looks like this:
\{t.*?\}?[}]([^\{]+)\{\/t\}|\{t\}([^\{]+)\{\/t\}
The regex is used inside a java program.
Does anybody has a way to fix this problem?

The easiest solution I see on this is to normalize the .tpl files. Just use a regex which matches all tags something like this one:
{[^}]*[^{]*}
I had the same issue to solve and it worked pretty good with the normalizing.
The normalizing-method would look like this:
final String regex = "\\{[^\\}]*[^\\{]*\\}";
private String normalizeContent(String content) {
return content.replaceAll(regex, "");
}

Java - Regex String replacement

I want to replace some parts of a String with Regex. It's the 192001Z part of the string I want to replace.
Code:
String met = "192001Z 17006KT 150V210 CAVOK 11/07 Q1004 NOSIG";
String regexZ = "[0-9].{5}Z";
met = met.replaceAll(regexZ, "${.now?string(\"ddHHmm\")}Z");
I get an error when I want to replace a part of the String with ${.now?string(\"ddHHmm\")}Z.
But when I e.g. replace ${.now?string(\"ddHHmm\")}Z with ThisNeedsToBeReplaced everything works just fine. So my guess is that something is wrong with the string I want to use to replace parts of my original string (met).
The error I receive is Illegal group reference.
Does anyone have an idea what's wrong with ${.now?string(\"ddHHmm\")}Z?

You need to use:
met = met.replaceAll("\\b\\d{6}Z\\b", "\\${.now?string(\"ddHHmm\")}Z");
Correct regex to match 192001Z is \b\d{6}Z\b
You need to escape $ in replacement as well otherwise it is considered a back reference e.g. $1, $2 etx.

Why doesn't this Java regex compile?

I am trying to extract the pass number from strings of any of the following formats:
PassID_132
PassID_64
Pass_298
Pass_16
For this, I constructed the following regex:
Pass[I]?[D]?_([\d]{2,3})
-and tested it in Eclipse's search dialog. It worked fine.
However, when I use it in code, it doesn't match anything. Here's my code snippet:
String idString = filename.replaceAll("Pass[I]?[D]?_([\\d]{2,3})", "$1");
int result = Integer.parseInt(idString);
I also tried
java.util.regex.Pattern.compile("Pass[I]?[D]?_([\\d]{2,3})")
in the Expressions window while debugging, but that says "", whereas
java.util.regex.Pattern.compile("Pass[I]?[D]?_([0-9]{2,3})")
compiled, but didn't match anything. What could be the problem?

Instead of Pass[I]?[D]?_([\d]{2,3}) try this:
Pass(?:I)?(?:D)?_([\d]{2,3})

There's nothing invalid with your tegex, but it sucks. You don't need character classes around single character terms. Try this:
"Pass(?:ID)?_(\\d{2,3})"

cannot parse String with Java Regex

I have a string formatted as below:
source1.type1.8371-(12345)->source2.type3.3281-(38270)->source4.type2.903..
It's a path, the number in () is the weight for the edge, I tried to split it using java Pattern as following:
[a-zA-Z.0-9]+-{1}({1}\\d+){1}
[a-zA-Z_]+.[a-zA-Z_]+.(\\d)+-(\\d+)
[a-zA-Z.0-9]+-{1}({1}\\d+){1}-{1}>{1}
hopefully it split the string into fields like
source1.type1.8371-(12345)
source2.type3.3281-(38270)
..
but none of them work, it always return the whole string as the field.

It looks like you just want String.split("->") (javadoc). This splits on the symbol -> and returns an array containing the parts between ->.
String str = "source1.type1.8371-(12345)->source2.type3.3281-(38270)->source4.type2.903..";
for(String s : str.split("->")){
System.out.println(s);
}
Output
source1.type1.8371-(12345)
source2.type3.3281-(38270)
source4.type2.903..

It seems to me like you want to split at the ->'s. So you could use something like str.split("->") If you were more specific about why you need this maybe we could understand why you were trying to use those complicated regexes

Java: reading a string in a particular format

I am not posting any code I am struck with. I am trying this in Java:
Issue:
I have words like:
,xxxx-1223
yyyyy,xxdd-345
$,xxxxr-7
sdsdsdd-18
so what ever format I have I should be able to read the last one:
xxxx-1223
xxdd-345
xxxxr-7
sdsdsdd-18
what so may be the words, all I need to to get the words as shown.

Use String#lastIndexOf(int) to find where the last comma occurs, and use String#substring(int) to get the rest of the string that follows.
String input = /* whatever */;
int lastComma = input.lastIndexOf(',');
String output = input.substring(lastComma + 1);

String[] str=yourWord.split(",");
String output=str[str.length-1];

You can use this Regex: -
(\\w+-\\d+)$
Or this specific problem can simply be solved using String.split() or String.substring(int) methods