Adding colour to greyscale image - java

Im looking to add colour to a greyscale image; it doesnt have to be an accurate colour representation but adding a colour to a different shade of grey, this is just to identify different areas of interest within an image. E.g. areas of vegetation are likely to be of a similar shade of grey, by adding a colour to this range of values it should be clear which areas are vegetation, which are of water, etc.
I have the code for getting colours from an image and storing them as a colour object but this doesnt seem to give a way to modify the values.
E.g. if the grey vale is less than 85, colour red, if between 86 and 170 colour green and between 171 and 255 colour blue. I have no idea how this will look but in theory the resulting image should allow a user to identify the different areas.
The current code I have for getting pixel value is below.
int total_pixels = (h * w);
Color[] colors = new Color[total_pixels];
for (int x = 0; x < w; x++)
{
for (int y = 0; y < h; y++)
{
colors[i] = new Color(image.getRGB(x, y));
i++;
}
}
for (int i = 0; i < total_pixels; i++)
{
Color c = colors[i];
int r = c.getRed();
int g = c.getGreen();
int b = c.getBlue();
System.out.println("Red " + r + " | Green " + g + " | Blue " + b);
}
I appreciate any help at all! Thanks a lot

You are going to have to choose your own method of converting colours from the greyscale scheme to whatever colour you want.
In the example you've given, you could do something like this.
public Color newColorFor(int pixel) {
Color c = colors[pixel];
int r = c.getRed(); // Since this is grey, the G and B values should be the same
if (r < 86) {
return new Color(r * 3, 0, 0); // return a red
} else if (r < 172) {
return new Color(0, (r - 86) * 3, 0); // return a green
} else {
return new Color(0, 0, (r - 172) * 3); // return a blue
}
}
You may have to play around a bit to get the best algorithm. I suspect that the code above will actually make your image look quite dark and dingy. You'd be better off with lighter colours. For example, you might change every 0 in the code above to 255, which will give you shades of yellow, magenta and cyan. This is going to be a lot of trial and error.

I recommend you to take a look at Java2D. It has many classes that can make your life much easier. You may end up reinventing the wheel if you ignore it.
Here is a short showcase of what you can do:
int width = 100;
int height = 100;
BufferedImage image = new BufferedImage(width, height, BufferedImage.TYPE_INT_ARGB);
image.getRGB(x, y);
Graphics2D g2d = (Graphics2D)image.getGraphics();
g2d.setColor(Color.GREEN);
g2d.fillRect(x, y, width, height);

Related

How to detect all pixels of specific color (and similar ones) in a bitmap?

I'm working on Bitmap images in Android Studio, and I would know how to do to detect all red pixels for examples, but not just the pixels that are strictly equals to Color.RED. I just give an example with RED color, but I want to do it with all different color possible.
I tried to do this:
...
int[] pixels = new int[width * height];
myBitmap.getPixels(pixels, 0, width, 0, 0, width, height);
for (int i = 0; i < width * height; i++) {
if (pixels[i] == Color.RED) {
// color detected
}
...
But this doesn't work as my image does not contains red pixel that is (255, 0, 0) but contains pixels that could be (251, 30, 77) or (239, 23, 42), which is also "red", etc...
So how could I do to such thing ? I also tried something like :
int reference; // color as rgb
if ( (Color.red(pixels[i]) > Color.red(reference) - 20) &&
(Color.red(pixels[i]) < Color.red(reference) + 20 &&
...
{
// pixel detected
}
...
Where I suppose that (r +- 20, g +- 20, b +-20) is part of (r, g, b) (I mean, for human eye)
Any idea on how I can do that ?
You can accept all pixels that are within a certain distance of the color you want. Assuming you want RED and everything within euclidian distance of 10 of RED:
boolean distance(int a, int b) {
return Math.sqrt(Math.pow(Color.red(a) - Color.red(b), 2) + Math.pow(Color.blue(a) - Color.blue(b), 2) + Math.pow(Color.green(a) - Color.green(b), 2));
}
....
int reference = Color.RED;
if (distance(reference, pixels[i]) < 10) {
//pixel accepted
}

How to convert an image to a 0-255 grey scale image

I want to convert an image to a gray scale image where pixel intensities are between 0-255.
I was able to convert images to a gray scale images with the following Java method.
public void ConvertToGrayScale(BufferedImage bufImage, int ImgWidth, int ImgHeight) {
for (int w = 0; w < ImgWidth; w++) {
for (int h = 0; h < ImgHeight; h++) {
Color color = new Color(bufImage.getRGB(w, h));
int ColAvgVal = ((color.getRed() + color.getGreen() + color.getBlue()) / 3);
Color avg = new Color(ColAvgVal, ColAvgVal, ColAvgVal);
bufImage.setRGB(w, h, avg.getRGB());
System.out.println(avg.getRGB());
}
}
}
"System.out.println(avg.getRGB());" is used to see the pixel intensities but the all the grey levels are minus values and not between 0-255.
Am I doing it wrong ? How would I convert an image to a gray scale image where pixel intensities are between 0-255.
Thanks
color.getRGB() does not return a value from 0..255, it returns an integer composited of your red, green and blue values, including the Alpha value. Presumably, this alpha value is 0xFF, which makes any combined color end up as 0xFFrrggbb, or, as you got, a huge negative number when written in decimals.
To see the "gray" level assigned, just check ColAvgVal.
Note that a better formula to convert between RGB and grayscale is to use the PAL/NTSC conversion:
gray = 0.299 * red + 0.587 * green + 0.114 * blue
because "full blue" should be darker in grayscale than "full red" and "full green".
Note: if you use this formula directly, watch out for floating point rounding errors. In theory, it should not return a value outside of 0..255 for gray; in practice, it will. So test and clamp the result.
Another option which does not require testing-and-clamping per pixel, is to use an integer-only version:
gray = (299 * red + 587 * green + 114 * blue)/1000;
which should work with only a very small rounding error.
You can check this . I hope it can help you.
You can check some differents methods like:
// The average grayscale method
private static BufferedImage avg(BufferedImage original) {
int alpha, red, green, blue;
int newPixel;
BufferedImage avg_gray = new BufferedImage(original.getWidth(), original.getHeight(), original.getType());
int[] avgLUT = new int[766];
for(int i=0; i<avgLUT.length; i++)
avgLUT[i] = (int) (i / 3);
for(int i=0; i<original.getWidth(); i++) {
for(int j=0; j<original.getHeight(); j++) {
// Get pixels by R, G, B
alpha = new Color(original.getRGB(i, j)).getAlpha();
red = new Color(original.getRGB(i, j)).getRed();
green = new Color(original.getRGB(i, j)).getGreen();
blue = new Color(original.getRGB(i, j)).getBlue();
newPixel = red + green + blue;
newPixel = avgLUT[newPixel];
// Return back to original format
newPixel = colorToRGB(alpha, newPixel, newPixel, newPixel);
// Write pixels into image
avg_gray.setRGB(i, j, newPixel);
}
}
return avg_gray;
}

java color correction on giant image on the fly

I have to handle VERY large (1-2GB) Tiff files, and only need to do some RGB manipulations on pixels, where I only make local corrections (color of a modified pixel is only depending on its old values, but not on e.g. neighbor pixels).
Is their (JAVA) a way to read the file as some kind of pixel stream, make adjustments on the RGB values, and write the stuff immediately to another file? I will not have enough memory to store the entire file in RAM (or at least I hope I could avoid it)
Thx for any hints...
THX
-Marco
Well, I don't actually know what a tiff file is 😅, but if it is a file, which you can store in a BufferedImage, it should be relatively easy.
I would do something like:
public BufferedImage correctRGB()
{
BufferedImage b = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB);
//width and height are the width and height of the original image
Graphics g = b.getGraphics();
for(int x = 0; x < b.getHeight(); x++)
{
for(int y = 0; y < b.getWidth(); y++)
{
//loop through all the pixels in the image ONCE to spare RAM
int pixels = b.getRGB(x, y);
int alpha = (pixels >> 24) &0xff;
int red = (pixels >> 16) &0xff;
int green = (pixels >> 8) &0xff;
int blue = pixels &0xff;
//in here you play around with the values
g.setColor(new Color(red, green, blue, alpha));
g.fillRect(x, y, 1, 1);
}
}
g.dispose();
return b;
}
you can basically do everything you want with the argb values now.
For example, you could turn the whole image negative by doing red = 255 - red and so on.
or turn the whole image into grayscale by doing
int average = (red + green + blue) / 3;
g.setColor(new Color(average, average, average, alpha));

Cropping image lowers quality and border looks bad

Using some math, i created the following java-function, to input a Bitmap, and have it crop out a centered square in which a circle is cropped out again with a black border around it.
The rest of the square should be transparent.
Additionatly, there is a transparent distance to the sides to not damage the preview when sending the image via Messengers.
The code of my function is as following:
public static Bitmap edit_image(Bitmap src,boolean makeborder) {
int width = src.getWidth();
int height = src.getHeight();
int A, R, G, B;
int pixel;
int middlex = width/2;
int middley = height/2;
int seitenlaenge,startx,starty;
if(width>height)
{
seitenlaenge=height;
starty=0;
startx = middlex - (seitenlaenge/2);
}
else
{
seitenlaenge=width;
startx=0;
starty = middley - (seitenlaenge/2);
}
int kreisradius = seitenlaenge/2;
int mittx = startx + kreisradius;
int mitty = starty + kreisradius;
int border=2;
int seitenabstand=55;
Bitmap bmOut = Bitmap.createBitmap(seitenlaenge+seitenabstand, seitenlaenge+seitenabstand, Bitmap.Config.ARGB_8888);
bmOut.setHasAlpha(true);
for(int x = 0; x < width; ++x) {
for(int y = 0; y < height; ++y) {
int distzumitte = (int) (Math.pow(mittx-x,2) + Math.pow(mitty-y,2)); // (Xm-Xp)^2 + (Ym-Yp)^2 = dist^2
distzumitte = (int) Math.sqrt(distzumitte);
pixel = src.getPixel(x, y);
A = Color.alpha(pixel);
R = (int)Color.red(pixel);
G = (int)Color.green(pixel);
B = (int)Color.blue(pixel);
int color = Color.argb(A, R, G, B);
int afterx=x-startx+(seitenabstand/2);
int aftery=y-starty+(seitenabstand/2);
if(x < startx || y < starty || afterx>=seitenlaenge+seitenabstand || aftery>=seitenlaenge+seitenabstand) //seitenrand
{
continue;
}
else if(distzumitte > kreisradius)
{
color=0x00FFFFFF;
}
else if(distzumitte > kreisradius-border && makeborder) //border
{
color = Color.argb(A, 0, 0, 0);
}
bmOut.setPixel(afterx, aftery, color);
}
}
return bmOut;
}
This function works fine, but there are some problems occuring that i wasn't able to resolve yet.
The quality of the image is decreased significantly
The border is not really round, but appears to be flat at the edges of the image (on some devices?!)
I'd appreciate any help regarding that problems. I got to admit that i'm not the best in math and there should probably be a better formula to ceate the border.
your source code is hard to read, since it is a mix of German and English in the variable names. Additionally you don't say which image library you use, so we don't exactly know where the classes Bitmap and Color come from.
Anyway, it is very obvious, that you are operating only on a Bitmap. Bitmap means the whole image is stored in the RAM pixel by pixel. There is no lossy compression. I don't see anything in your source code, that can affect the quality of the image.
It is very likely, that the answer is in the Code that you don't show us. Additionally, what you describe (botrh of the problems) sounds like a very typical low quality JPEG compression. I am sure, somewhere after you call you function, you convert/save the image to a JPEG. Try to do that at that position to BMP, TIFF or PNG and see that the error disappears magically. Maybe you can also set the quality level of the JPEG somewhere to avoid that.
To make it easier for others (maybe) also to find a good answer, please allow me to translate your code to English:
public static Bitmap edit_image(Bitmap src,boolean makeborder) {
int width = src.getWidth();
int height = src.getHeight();
int A, R, G, B;
int pixel;
int middlex = width/2;
int middley = height/2;
int sideLength,startx,starty;
if(width>height)
{
sideLength=height;
starty=0;
startx = middlex - (sideLength/2);
}
else
{
sideLength=width;
startx=0;
starty = middley - (sideLength/2);
}
int circleRadius = sideLength/2;
int middleX = startx + circleRadius;
int middleY = starty + circleRadius;
int border=2;
int sideDistance=55;
Bitmap bmOut = Bitmap.createBitmap(sideLength+sideDistance, sideLength+sideDistance, Bitmap.Config.ARGB_8888);
bmOut.setHasAlpha(true);
for(int x = 0; x < width; ++x) {
for(int y = 0; y < height; ++y) {
int distanceToMiddle = (int) (Math.pow(middleX-x,2) + Math.pow(middleY-y,2)); // (Xm-Xp)^2 + (Ym-Yp)^2 = dist^2
distanceToMiddle = (int) Math.sqrt(distanceToMiddle);
pixel = src.getPixel(x, y);
A = Color.alpha(pixel);
R = (int)Color.red(pixel);
G = (int)Color.green(pixel);
B = (int)Color.blue(pixel);
int color = Color.argb(A, R, G, B);
int afterx=x-startx+(sideDistance/2);
int aftery=y-starty+(sideDistance/2);
if(x < startx || y < starty || afterx>=sideLength+sideDistance || aftery>=sideLength+sideDistance) //margin
{
continue;
}
else if(distanceToMiddle > circleRadius)
{
color=0x00FFFFFF;
}
else if(distanceToMiddle > circleRadius-border && makeborder) //border
{
color = Color.argb(A, 0, 0, 0);
}
bmOut.setPixel(afterx, aftery, color);
}
}
return bmOut;
}
I think that you need to check PorterDuffXferMode.
You will find some technical informations about compositing images modes HERE.
There is some good example of making bitmap with rounded edges HERE. You just need to tweak a bit source code and you're ready to go...
Hope it will help.
Regarding the quality I can't see anything wrong with your method. Running the code with Java Swing no quality is lost. The only problem is that the image has aliased edges.
The aliasing problem will tend to disappear as the screen resolution increases and would be more noticeable for lower resolutions. This might explain why you see it in some devices only.The same problem applies to your border but in that case it would be more noticable since the color is single black.
Your algorithm defines a square area of the original image. To find the square it starts from the image's center and expand to either the width or the height of the image whichever is smaller. I am referring to this area as the square.
The aliasing is caused by your code that sets the colors (I am using pseudo-code):
if ( outOfSquare() ) {
continue; // case 1: this works but you depend upon the new image' s default pixel value i.e. transparent black
} else if ( insideSquare() && ! insideCircle() ) {
color = 0x00FFFFFF; // case 2: transparent white. <- Redundant
} else if ( insideBorder() ) {
color = Color.argb(A, 0, 0, 0); // case 3: Black color using the transparency of the original image.
} else { // inside the inner circle
// case 4: leave image color
}
Some notes about the code:
Case 1 depends upon the default pixel value of the original image i.e. transparent black. It works but better to set it explicitly
Case 2 is redundant. Handle it in the same way you handle case 1. We are only interested in what happens inside the circle.
Case 3 (when you draw the border) is not clear what it expects. Using the alpha of the original image has the potential of messing up your new image if it happens that the original alpha varies along the circle's edges. So this is clearly wrong and depending on the image, can potentially be another cause of your problems.
Case 4 is ok.
Now at your circle's periphery the following color transitions take place:
If border is not used: full transparency -> full image color (case 2 and 4 in the pseudocode)
If border is used: full transparency -> full black -> full image color (cases 2, 3 and 4)
To achieve a better quality at the edges you need to introduce some intermediate states that would make the transitions smoother (the new transitions are shown in italics):
Border is not used: full transparency -> partial transparency with image color -> full image color
Border is used: full transparency -> partial transparency of Black color -> full Black color -> partial transparency of Black color + Image color (i.e. blending) -> Full image color
I hope that helps

java image color formulas

I know the java code for grayscale is this( 0.2126 * red + 0.7152 * green + 0.0722 * blue(
I was wondering if anyone knows how I can find more variety of coloring formulas, like if i want to make the picture old fashion way, more orange, make it brighter, or darker ... sharper and so on
int pixel = image.getRGB(j, i);
int red = (pixel) & 0xff;
int green = (pixel >> 8) & 0xff;
int blue = (pixel >> 16) & 0xff;
int newPixel = (int) (0.2126 * red + 0.7152 * green + 0.0722 * blue);
image1.setRGB(j, i, newPixel);
The old fashion way you mention is called "sepia" effect. Take a look at this question particularly this answer which points out to the following code snippet (note that I did not write this code, just helping out in finding answers to your question)
/**
*
* #param img Image to modify
* #param sepiaIntensity From 0-255, 30 produces nice results
* #throws Exception
*/
public static void applySepiaFilter(BufferedImage img, int
sepiaIntensity) throws Exception
{
// Play around with this. 20 works well and was recommended
// by another developer. 0 produces a grey image
int sepiaDepth = 20;
int w = img.getWidth();
int h = img.getHeight();
WritableRaster raster = img.getRaster();
// We need 3 integers (for R,G,B color values) per pixel.
int[] pixels = new int[w*h*3];
raster.getPixels(0, 0, w, h, pixels);
// Process 3 ints at a time for each pixel. Each pixel has 3 RGB
colors in array
for (int i=0;i<pixels.length; i+=3)
{
int r = pixels[i];
int g = pixels[i+1];
int b = pixels[i+2];
int gry = (r + g + b) / 3;
r = g = b = gry;
r = r + (sepiaDepth * 2);
g = g + sepiaDepth;
if (r>255) r=255;
if (g>255) g=255;
if (b>255) b=255;
// Darken blue color to increase sepia effect
b-= sepiaIntensity;
// normalize if out of bounds
if (b<0) b=0;
if (b>255) b=255;
pixels[i] = r;
pixels[i+1]= g;
pixels[i+2] = b;
}
raster.setPixels(0, 0, w, h, pixels);
}
I would just play with the numbers.
more orange,
more red and a little more green (red + green = yellow)
brighter
increase all the factors
darker
decrease all the factors
sharper
This is specific filter which compare surrounding pixels to find edges. It not just a matter of playing with the colours.
BTW: You should add capping of the values. i.e. Math.min(255, Math.max(0, value))
You can manipulate the proportion between the color channels in order to change the scene "atmosphere". The images below were created using the ColorChannel plug-in.
The algorithm source code is presented below. The method getAttribute() gets the parameters (red,gree,blue) passed by the user. The methods getIntComponent0, getIntComponent1 and getIntComponent2 get each color channel (red, gree and blue). The method setIntColor sets back the value of each channel.
#Override
public void process
(
MarvinImage imageIn,
MarvinImage imageOut,
MarvinAttributes attrOut,
MarvinImageMask mask,
boolean preview
) {
int vr = (Integer)getAttribute("red");
int vg = (Integer)getAttribute("green");
int vb = (Integer)getAttribute("blue");
double mr = 1+Math.abs((vr/100.0)*2.5);
double mg = 1+Math.abs((vg/100.0)*2.5);
double mb = 1+Math.abs((vb/100.0)*2.5);
mr = (vr > 0? mr : 1.0/mr);
mg = (vg > 0? mg : 1.0/mg);
mb = (vb > 0? mb : 1.0/mb);
int red,green,blue;
for(int y=0; y<imageIn.getHeight(); y++){
for(int x=0; x<imageIn.getWidth(); x++){
red = imageIn.getIntComponent0(x, y);
green = imageIn.getIntComponent1(x, y);
blue = imageIn.getIntComponent2(x, y);
red = (int)Math.min(red * mr, 255);
green = (int)Math.min(green * mg, 255);
blue = (int)Math.min(blue * mb, 255);
imageOut.setIntColor(x, y, 255, red, green, blue);
}
}
}

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