This question already has answers here:
Round number to only first decimal place
(3 answers)
Closed 8 years ago.
I wish I could understand how it is possible that is not rounded the decimal number obtained from the following code.
File path2 = Environment.getDataDirectory();
StatFs stat2 = new StatFs(path.getPath());
long blockSize2 = stat.getBlockSize();
long availableBlocks = stat.getAvailableBlocks();
double result = availableBlocks * blockSize;
free = (Preference)this.findPreference("free_mem");
free.setSummary(Double.toString(result)+" GB");
In a code similar to this use this instruction and works
result = Math.round(result * 10) / 10d;
Why not work here and I still see a number with many decimal places?
If I understood your question right you need NumberFormat here:
NumberFormat nf = NumberFormat.getInstance();
nf.setMaximumFractionDigits(1);
nf.format(result);
This produces a number with 1 decimal places.
So if result is 6.6789 it will produce 6.7.
Related: Round number to only first decimal place
Just a note:
If you do this:
Math.round(result * 10) / 10d;
you basically say:
Multiply result with 10
Round the result
Then divide with ten.
When you got rid of the decimals at step 2. you got another bunch of decimals after the division.
Related
This question already has answers here:
Always Round UP a Double
(8 answers)
Closed 5 years ago.
im trying to display a float number in 5 digits rounding up in the last digit, for example : 0.123455 will be displayed as 0.12346, and 0.123454 will be 0.12345.
My current code (not properly working) is as follows:
int iFactorSum = 100000;
int iRoundSum = (int) (fSumatoria * iFactorSum + 0.5);
fSumatoria = (float) iRoundSum / iFactorSum;
fSumatoria storages the number i want to convert.
Thanks
To round up, you can use Math.ceil(numberGrade).
To round to the nearest integer, use Math.round(numberGrade).
See: the Math class
From here.
Use Math.round() to round up floating point numbers
see
https://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#round(double)
This question already has answers here:
How to round a number to n decimal places in Java
(39 answers)
How to Round Decimals to 2 Places after the Decimal Point (Java)
(4 answers)
Closed 7 years ago.
I'm new to java programming. I would like to round up a price to the nearest 2 decimal places with a multiple of 5.
Eg.
38.80 stays the same.
38.81 to 38.80.
38.82 to 38.80.
38.83 to 38.85.
38.84 to 38.85.
38.85 stays the same.
38.86 to 38.85.
38.87 to 38.85.
38.88 to 38.90.
38.89 to 38.90.
38.90 stays the same.
I tried the provided duplicates but they come out only to 1 decimal place.
Eg. 38.82 to 38.8.
This is my code:
import java.text.DecimalFormat;
public class RoundUp {
public static void main(String[] args){
DecimalFormat df = new DecimalFormat("#.##");
double num = 38.84;
System.out.println(df.format(Math.round(num*10.00)/10.00));
}
}
I have looked into other model answers by experts in this web but none of them really answer my question. Setting into 2 decimal places, I'm using DemicalFormat. That I know, but rounding the number, let's say 38.83 to 38.85 and 38.87 to 38.90 is what I really want.
It is a rounding system that my country is using. Can check it out here.
**
This question has been answer by #Mureinik double rounded =
Math.round(num * 100.0 / 5.0) * 5.0 / 100.0;
**
I would recommend you to use BigDecimal instead of double when you are dealing with money.
And then it would be like
BigDecimal value = new BigDecimal(38.84);
value = value.setScale(2, BigDecimal.ROUND_HALF_UP)
You can refer Javadocs for ROUND_HALF_UP and setScale
This question already has answers here:
How can I truncate a double to only two decimal places in Java?
(18 answers)
Closed 8 years ago.
amount / 100 * 7 - I'am trying to get a percent from an amount, but the problem is that sometimes a get a number with to many digits after dot, how can I make it strictly return 2 digits after dot?
type is double
Use DecimalFormat API
double d = amount / 100 * 7;
DecimalFormat df = new DecimalFormat("#.##");
System.out.print(df.format(d));
"##" denotes the 2 digit precision
You can do this
double d = Math.round(amount * 7) / 100.0;
This will give you have value which has two decimal places. (for a modest range of values i.e. < 70e12)
If you just want to print two decimal places you can use
System.out.printf("%.2f%n", d);
This question already has answers here:
How to round a number to n decimal places in Java
(39 answers)
Closed 9 years ago.
I have the following and the question is, for example if zzi = 95 then myNum will be correctly displayed as 32.33, exactly as I want it too with two decimal places.
However if zzi = 94, myNum will be displayed as 32.0 instead of 32.00
How to display it as 32.00?
float xFunction(int zzi) {
float myNum = (zzi + 2);
myNum = myNum / 3;
int precision = 100; // keep 4 digits
myNum = (float) (Math.floor(myNum * precision + .5) / precision);
return myNum;
}
Thanks before.
Your question is not so much about rounding a number as it is about rounding a display or String representation of a number. The solution:
Use new DecimalFormat("0.00");
Or String.format("%.2f", myNumber);
Or new java.util.Formatter("%.2f", myNumber);
Or System.out.printf("%.2f", myNumber);
Note: avoid use of float whenever possible, and instead prefer use of double which greatly improves numeric precision at little cost. For financial calculations use neither but instead opt for integer calculations or use BigDecimal.
Remember:
1) printing the number displaying two decimal places is very different from rounding the actual value. In other words "representation" != actual value.
2) floating point values are always imprecise. Even with rounding, you may or may not get an "exact value".
Having said that, the simplest approach is:
float myNum = ((123.456 * 100.0) + .5) / 100.0;
new DecimalFormat("#.##").format(myNum );
You can use DecimalFormat
System.out.println(new DecimalFormat("0.00").format(xFunction(94)));
You should work on the printing function. I assume you are using a System.out.println: replace it with
System.out.format("%.2f", numberToPrint);
Read the docs for that function to discover more about format strings.
This question already has answers here:
How to round a number to n decimal places in Java
(39 answers)
Round a double to 2 decimal places [duplicate]
(13 answers)
Closed 9 years ago.
I am trying to Format my double value to exact 2 decimal places and it seems to working fine, here is the code i am trying
final NumberFormat df = DecimalFormat.getInstance();
df.setMinimumFractionDigits(2);
df.setMaximumFractionDigits(2);
df.setRoundingMode(RoundingMode.DOWN);
df.format(value)
Till now everything is working, but i need to return double value as it is being used for other calculations and i tried
Double.parseDouble(df.format(value))
with big decimal like
BigDecimal price = new BigDecimal(df.format(number));
but it is not working as expected
like 18.50 is being converted as 18.5
Though this is not an issue with calculations but i need to show amount on the UI where i have to show exactly up to 2 decimal places.
Is there any was i can handle it in java class or i have to take care in JSP with JSTL
This is what BigDecimal is made for!
BigDecimal number = new BigDecimal(123.456);
// set 2 fraction digits
// Note that setScale() does not change the original,
// but returns a new BigDecimal.
number = number.setScale(2, RoundingMode.DOWN);
// get string representation
String text = number.toPlainString();
// get double value
double dbl = number.doubleValue();
And use BigDecimal for other calculations as well if you can.