I have a byte array which size is 640*480*3 and its byte order is r,g,b. I'm trying to convert it into Image. The following code doesn't work:
BufferedImage img = ImageIO.read(new ByteArrayInputStream(data));
with the excepton
Exception in thread "main" java.lang.IllegalArgumentException: image == null!
at javax.imageio.ImageTypeSpecifier.createFromRenderedImage(ImageTypeSpecifier.java:925)
at javax.imageio.ImageIO.getWriter(ImageIO.java:1591)
at javax.imageio.ImageIO.write(ImageIO.java:1520)
I also tried this code:
ImageIcon imageIcon = new ImageIcon(data);
Image img = imageIcon.getImage();
BufferedImage bi = new BufferedImage(img.getWidth(null),img.getHeight(null),BufferedImage.TYPE_3BYTE_BGR); //Exception
but unsuccessfully:
Exception in thread "main" java.lang.IllegalArgumentException: Width (-1) and height (-1) must be > 0
How can I receive the Image from this array?
A plain byte array is not a gnerally recognized image format. You have to code the conversion yourself. Luckily its not very hard to do:
int w = 640;
int h = 480;
BufferedImage i = new BufferedImage(w, h, BufferedImage.TYPE_INT_RGB);
for (int y=0; y<h; ++y) {
for (int x=0; x<w; ++x) {
// calculate index of pixel
// depends on exact organization of image
// sample assumes linear storage with r, g, b pixel order
int index = (y * w * 3) + (x * 3);
// combine to RGB format
int rgb = ((data[index++] & 0xFF) << 16) |
((data[index++] & 0xFF) << 8) |
((data[index++] & 0xFF) ) |
0xFF000000;
i.setRGB(x, y, rgb);
}
}
The exact formula for pixel index depends on how you organized the data in the array - which you didn't really specify precisely. The prinicple is always the same though, combine the R, G, B value into an RGB (ARGB to be precise) value and put it in the BufferedImage using setRGB() method.
Related
I'm currently having an issue with alpha channels when reading PNG files with ImageIO.read(...)
fileInputStream = new FileInputStream(path);
BufferedImage image = ImageIO.read(fileInputStream);
//Just copying data into an integer array
int[] pixels = new int[image.getWidth() * image.getHeight()];
image.getRGB(0, 0, width, height, pixels, 0, width);
However, when trying to read values from the pixel array by bit shifting as seen below, the alpha channel is always returning -1
int a = (pixels[i] & 0xff000000) >> 24;
int r = (pixels[i] & 0xff0000) >> 16;
int g = (pixels[i] & 0xff00) >> 8;
int b = (pixels[i] & 0xff);
//a = -1, the other channels are fine
By Googling the problem I understand that the BufferedImage type needs to be defined as below to allow for the alpha channel to work:
BufferedImage image = new BufferedImage(width, height BufferedImage.TYPE_INT_ARGB);
But ImageIO.read(...) returns a BufferedImage without giving the option to specify the image type. So how can I do this?
Any help is much appreciated.
Thanks in advance
I think, your "int unpacking" code might be wrong.
I used (pixel >> 24) & 0xff (where pixel is the rgba value of a specific pixel) and it worked fine.
I compared this with the results of java.awt.Color and they worked fine.
I "stole" the "extraction" code directly from java.awt.Color, this is, yet another reason, I tend not to perform these operations this way, it's to easy to screw them up
And my awesome test code...
BufferedImage image = ImageIO.read(new File("BYO image"));
int width = image.getWidth();
int height = image.getHeight();
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
int pixel = image.getRGB(x, y);
//value = 0xff000000 | rgba;
int a = (pixel >> 24) & 0xff;
Color color = new Color(pixel, true);
System.out.println(x + "x" + y + " = " + color.getAlpha() + "; " + a);
}
}
nb: Before some one tells that this is inefficient, I wasn't going for efficiency, I was going for quick to write
You may also want to have a look at How to convert get.rgb(x,y) integer pixel to Color(r,g,b,a) in Java?, which I also used to validate my results
I think the problem is that you're using arithmetic shift (>>) instead of logical shift (>>>). Thus 0xff000000 >> 24 becomes 0xffffffff (i.e. -1)
I have a requirement to use a native library which reads some proprietary image file formats (something about not reinventing our own wheel). The library works fine, it's just sometimes the images can get pretty big (the record I've seen being 13k x 15k pixels). The problem is my poor JVM keeps dying a painful death and / or throwing OutOfMemoryError's any time the images start getting huge.
Here's what I have running
//the bands, width, and height fields are set in the native code
//And the rawBytes array is also populated in the native code.
public BufferedImage getImage(){
int type = bands == 1 ? BufferedImage.TYPE_BYTE_GRAY : BufferedImage.TYPE_INT_BRG;
BufferedImage bi = new BufferedImage(width, height, type);
ImageFilter filter = new RGBImageFilter(){
#Override
public int filterRGB(int x, int y, int rgb){
int r, g, b;
if (bands == 3) {
r = (((int) rawBytes[y * (width / bands) * 3 + x * 3 + 2]) & 0xFF) << 16;
g = (((int) rawBytes[y * (width / bands) * 3 + x * 3 + 1]) & 0xFF) << 8;
b = (((int) rawBytes[y * (width / bands) * 3 + x * 3 + 0]) & 0xFF);
} else {
b = (((int) rawBytes[y * width + x]) & 0xFF);
g = b << 8;
r = b << 16;
}
return 0xFF000000 | r | g | b;
}
};
//this is the problematic block
ImageProducer ip = new FilteredImageSource(bi.getSource(), filter);
Image i = Toolkit.getDefaultToolkit().createImage(ip);
Graphics g = bi.createGraphics();
//with this next line being where the error tends to occur.
g.drawImage(i, 0, 0, null);
return bi;
}
This snippet works great for most images so long as they're not obscenely large. Its speed is also just fine. The problem is that that Image drawing onto the BufferedImage step swallows way too much memory.
Is there a way I could skip that step and go directly from raw bytes to buffered image?
Use the RawImageInputStream from jai. This does require knowing information about the SampleModel, which you appear to have from the native code.
Another option would be to put your rawBytes into a DataBuffer, then create a WritableRaster, and finally create a BufferedImage.
This is essentially what the RawImageInputStream would do.
How do I calculate the middle gray level (max(z)+min(z)/2 over the points where the structuring element is 1 and sets the output pixel to that value?
I just know a little about how to get the RGB value each pixel by using image.getRGB(x,y). I have no idea how to get gray level value each pixel of the image and what is z in the formula and all that?
Please help me with this. Thanks in advance.
I'm going to assume that z are the pixels within your structuring element. I'm also going to assume that "structuring element" is in the case of morphology. Here are a few pointers before we start:
You can convert a colour pixel to its graylevel intensity by using the Luminance formula. By consulting the SMPTE Rec. 709 standard, the output graylevel intensity, given the RGB components is: Y = 0.2126*R + 0.7152*G + 0.0722*B.
We're going to assume that the structuring element is odd. This will allow for the symmetric analysis of the structuring element for each pixel in your image where it is placed
I'm going to assume that your image is already loaded in as a BufferedImage.
Your structuring element will be a 2D array of int.
I'm not going to process those pixels where the structuring element traverses out of bounds to make things easy.
As such, the basic algorithm is this:
For each pixel in our image, place the centre of the structuring element at this location
For each pixel location where the structuring element is 1 that coincides with this position, find the max and minimum graylevel intensity
Set the output image pixel at this location to be (max(z) + min(z)) / 2).
Without further ado:
public BufferedImage calculateMiddleGray(BufferedImage img, int[][] mask)
{
// Declare output image
BufferedImage outImg = new BufferedImage(img.getWidth(),
img.getHeight(), BufferedImage.TYPE_INT_RGB);
// For each pixel in our image...
for (int i = mask.length/2; i < img.getWidth() - mask.length/2; i++) {
for (int j = mask[0].length/2; j < img.getHeight() - mask[0].length/2; j++) {
int maxPix = -1;
int minPix = 256;
// For each pixel in the mask...
for (int x = -mask.length/2; x <= mask.length/2; x++) {
for (int y = -mask[0].length/2; y <= mask[0].length/2; y++) {
//Obtain structuring element pixel
int structPix = mask[y+mask.length/2][x+mask[0].length/2];
// If not 1, continue
if (structPix != 1)
continue;
// Get RGB pixel
int rgb = img.getRGB(i+x, j+y);
// Get red, green and blue channels individually
int redPixel = (rgb >> 16) & 0xFF;
int greenPixel = (rgb >> 8) & 0xFF;
int bluePixel = rgb & 0xFF;
// Convert to grayscale
// Performs SMPTE Rec. 709 lum. conversion using integer logic
int lum = (77*red + 150*green + 29*blue) >> 8;
// Find max and min appropriately
if (lum > maxPix)
maxPix = lum;
if (lum < minPix)
minPix = lum;
}
}
// Set output pixel
// Grayscale image has all of its RGB pixels equal
int outPixel = (maxPix + minPix) / 2;
// Cap output - Ensure we don't go out of bounds
if (outPixel > 255)
outPixel = 255;
if (outPixel < 0)
outPixel = 0;
int finalOut = (outPixel << 16) | (outPixel << 8) | outPixel;
outImg.setRGB(i, j, finalOut);
}
}
}
To call this method, create an image img using any standard method, then create a structuring element mask that is a 2D integer array. After, place this method in your class, then invoke the method by:
BufferedImage outImg = calculateMiddleGray(img, mask);
Also (and of course), make sure you import the necessary package for the BufferedImage class, or:
import java.awt.image.BufferedImage;
Note: This is untested code. Hope it works!
I'm coding a Java LWJGL game, and everything's going along great, except whenever I try to figure out a way to create a BufferedImage of the current game area. I've searched the internet, browsed all of the opengl functions, and I am getting no where... Anyone have any ideas? Here's all I have so far, but it only makes a blank .png:
if(Input.getKeyDown(Input.KEY_F2)) {
try {
String fileName = "screenshot-" + Util.getSystemTime(false);
File imageToSave = new File(MainComponent.screenshotsFolder, fileName + ".png");
int duplicate = 0;
while(true) {
duplicate++;
if(imageToSave.exists() == false) {
imageToSave.createNewFile();
break;
}
imageToSave = new File(MainComponent.screenshotsFolder, fileName + "_" + duplicate + ".png");
}
imageToSave.createNewFile();
// Create a buffered image:
BufferedImage image = new BufferedImage(MainComponent.WIDTH, MainComponent.HEIGHT, BufferedImage.TYPE_INT_ARGB);
//Wrtie the new buffered image to file:
ImageIO.write(image, "png", imageToSave);
} catch (IOException e) {
e.printStackTrace();
}
}
You never actually write something into your BufferedImage.
Read the Buffer
You can use glReadPixels to access the selected buffer. (I assume WIDTH and HEIGHT as your OpenGLContext dimensions.)
FloatBuffer imageData = BufferUtils.createFloatBuffer(WIDTH * HEIGHT * 3);
GL11.glReadPixels(0, 0, WIDTH, HEIGHT, GL11.GL_RGB, GL11.GL_FLOAT, imageData);
imageData.rewind();
Use whatever parameters suit your needs best, I just picked floats randomly.
Set the Image Data
You already figured out how to create and save your image, but in between you should also set some content to the image. You can do this with BufferedImage().setRGB() (Note that I don't use a good naming as you do, to keep this example concise.)
// create image
BufferedImage image = new BufferedImage(
WIDTH, HEIGHT, BufferedImage.TYPE_INT_RGB
);
// set content
image.setRGB(0, 0, WIDTH, HEIGHT, rgbArray, 0, WIDTH);
// save it
File outputfile = new File("Screenshot.png");
try {
ImageIO.write(image, "png", outputfile);
} catch (IOException e) {
e.printStackTrace();
}
The most tricky part is now getting the rgbArray. The problems are that
OpenGL gives you three values (in this case, i.e. using GL11.GL_RGB), while the BufferedImage expects one value.
OpenGL counts the rows from bottom to top while BufferedImage counts from top to bottom.
Calculate one Integer from three Floats
To get rid of problem one you have to calculate the integer value which fits the three number you get.
I will show this with a simple example, the color red which is (1.0f, 0.0f, 0.0f) in your FloatBuffer.
For the integer value it might be easy to think of numbers in hex values, as you might know from CSS where it's very common to name colors with those. Red would be #ff0000 in CSS or in Java of course 0xff0000.
Colors in RGB with integers are usually represented from 0 to 255 (or 00 to ff in hex), while you use 0 to 1 with floats or doubles. So first you have to map them to the correct range by simply multiplying the values by 255 and casting them to integers:
int r = (int)(fR * 255);
Now you can think of the hex value as just putting those numbers next to each other:
rgb = 255 0 0 = ff 00 00
To achieve this you can bitshift the integer values. Since one hex value (0-f) is 4 byte long, you have to shift the value of green 8 bytes to the left (two hex values) and the value of red 16 bytes. After that you can simply add them up.
int rgb = (r << 16) + (g << 8) + b;
Getting from BottomUp to TopDown
I know the terminology bottom-up -> top-down is not correct here, but it was catchy.
To access 2D data in a 1D array you usually use some formula (this case row-major order) like
int index = offset + (y - yOffset) * stride + (x - xOffset);
Since you want to have the complete image the offsets can be left out and the formula simplified to
int index = y * stride + x;
Of course the stride is simply the WIDTH, i.e. the maximum achievable x value (or in other terms the row length).
The problem you now face is that OpenGL uses the bottom row as row 0 while the BufferedImage uses the top row as row 0. To get rid of that problem just invert y:
int index = ((HEIGHT - 1) - y) * WIDTH + x;
Filling the int[]-array with the Buffer's Data
Now you know how to calculate the rgb value, the correct index and you have all data you need. Let's fill the int[]-array with those information.
int[] rgbArray = new int[WIDTH * HEIGHT];
for(int y = 0; y < HEIGHT; ++y) {
for(int x = 0; x < WIDTH; ++x) {
int r = (int)(imageData.get() * 255) << 16;
int g = (int)(imageData.get() * 255) << 8;
int b = (int)(imageData.get() * 255);
int i = ((HEIGHT - 1) - y) * WIDTH + x;
rgbArray[i] = r + g + b;
}
}
Note three things about this little piece of code.
The size of the array. Obviously it's just WIDTH * HEIGHT and not WIDTH * HEIGHT * 3 as the buffer's size was.
Since OpenGL uses row-major order, you have to use the column value (x) as the inner loop for this 2D array (and of course there are other ways to write this, but this seemed to be the most intuitive one).
Accessing imageData with imageData.get() is probably not the safest way to do it, but since the calculations are carefully done it should do the job just fine. Just remember to flip() or rewind() the buffer before calling get() the first time!
Putting it all together
So with all the information available now we can just put a method saveScreenshot() together.
private void saveScreenshot() {
// read current buffer
FloatBuffer imageData = BufferUtils.createFloatBuffer(WIDTH * HEIGHT * 3);
GL11.glReadPixels(
0, 0, WIDTH, HEIGHT, GL11.GL_RGB, GL11.GL_FLOAT, imageData
);
imageData.rewind();
// fill rgbArray for BufferedImage
int[] rgbArray = new int[WIDTH * HEIGHT];
for(int y = 0; y < HEIGHT; ++y) {
for(int x = 0; x < WIDTH; ++x) {
int r = (int)(imageData.get() * 255) << 16;
int g = (int)(imageData.get() * 255) << 8;
int b = (int)(imageData.get() * 255);
int i = ((HEIGHT - 1) - y) * WIDTH + x;
rgbArray[i] = r + g + b;
}
}
// create and save image
BufferedImage image = new BufferedImage(
WIDTH, HEIGHT, BufferedImage.TYPE_INT_RGB
);
image.setRGB(0, 0, WIDTH, HEIGHT, rgbArray, 0, WIDTH);
File outputfile = getNextScreenFile();
try {
ImageIO.write(image, "png", outputfile);
} catch (IOException e) {
e.printStackTrace();
System.err.println("Can not save screenshot!");
}
}
private File getNextScreenFile() {
// create image name
String fileName = "screenshot_" + getSystemTime(false);
File imageToSave = new File(fileName + ".png");
// check for duplicates
int duplicate = 0;
while(imageToSave.exists()) {
imageToSave = new File(fileName + "_" + ++duplicate + ".png");
}
return imageToSave;
}
// format the time
public static String getSystemTime(boolean getTimeOnly) {
SimpleDateFormat dateFormat = new SimpleDateFormat(
getTimeOnly?"HH-mm-ss":"yyyy-MM-dd'T'HH-mm-ss"
);
return dateFormat.format(new Date());
}
I also uploaded a very simple full working example.
I need to create a simple demo for image manipulation in Java. My code is swing based. I don't have to do anything complex, just show that the image has changed in some way. I have the image read as byte[]. Is there anyway that I can manipulate this byte array without corrupting the bytes to show some very simple manipulation. I don't wish to use paint() etc. Is there anything that I can do directly to the byte[] array to show some change?
edit:
I am reading jpg image as byteArrayInputStream using apache io library. The bytes are read ok and I can confirm it by writing them back as jpeg.
You can try to convert your RGB image to Grayscale. If the image as 3 bytes per pixel rapresented as RedGreenBlue you can use the followinf formula: y=0.299*r+0.587*g+0.114*b.
To be clear iterate over the byte array and replace the colors. Here an example:
byte[] newImage = new byte[rgbImage.length];
for (int i = 0; i < rgbImage.length; i += 3) {
newImage[i] = (byte) (rgbImage[i] * 0.299 + rgbImage[i + 1] * 0.587
+ rgbImage[i + 2] * 0.114);
newImage[i+1] = newImage[i];
newImage[i+2] = newImage[i];
}
UPDATE:
Above code assumes you're using raw RGB image, if you need to process a Jpeg file you can do this:
try {
BufferedImage inputImage = ImageIO.read(new File("input.jpg"));
BufferedImage outputImage = new BufferedImage(
inputImage.getWidth(), inputImage.getHeight(),
BufferedImage.TYPE_INT_RGB);
for (int x = 0; x < inputImage.getWidth(); x++) {
for (int y = 0; y < inputImage.getHeight(); y++) {
int rgb = inputImage.getRGB(x, y);
int blue = 0x0000ff & rgb;
int green = 0x0000ff & (rgb >> 8);
int red = 0x0000ff & (rgb >> 16);
int lum = (int) (red * 0.299 + green * 0.587 + blue * 0.114);
outputImage
.setRGB(x, y, lum | (lum << 8) | (lum << 16));
}
}
ImageIO.write(outputImage, "jpg", new File("output.jpg"));
} catch (IOException e) {
e.printStackTrace();
}