Develop Reference

How can I convert each integer/double value to String from JSON data containing nested objects and arrays?

I want to convert each integer/double value to String present in json request before storing in MongoDB database.
There can be multiple fields like amountValue in the json. I am looking for a generic way which can parse json with any number of such attributes value to string. My request will have around 200 fields.
ex: "amountValue": 200.00, to "amountValue": "200.00",
{
"templateName": "My DC Template 14",
"templateDetails": {
"beneficiaryName": "Snow2",
"dcOpenAmount": {
"amountValue": 200.00,
}
}
}
My mongoDB Document is of the form
#Document
public class TemplateDetails {
#Id
private long templateId;
private String templateName;
private Object templateDetail;
}
Because we are storing document in mongodb as an object(Which can accept any type of json request) we dont have field level control on it.
In my controller, converting the request object to json.
This is how I tried. But its not meeting my expectation. It is still keeping the amount value to its original double form.:
ObjectMapper mapper = new ObjectMapper();
try {
String json = mapper.writeValueAsString(templateRequestVO);
System.out.println("ResultingJSONstring = " + json);
} catch (JsonProcessingException e) {
e.printStackTrace();
}
Output :
ResultingJSONstring = {"id":null,"userId":"FU.ZONKO","txnType":"LCI","accessIndicator":"Public","templateId":null,"templateName":"My DC Template 14","tags":null,"templateDetails":{"applicantDetail":{"applicantName":"Tom","applicantAddress":{"addressLine1":"Infosys, Phase 2","city":"PUNE","state":"MAHARASHTRA","country":"INDIA","zip":"40039"},"accountId":"Account1234","customerId":"JPMORGAN"},"beneficiaryName":"Snow2","dcOpenAmount":{"amountValue":200.0,"currency":"USD"}}}
Is there any way to accomplish the result ? Or anything which can help to store documents in mongodb with attribute type as String ?

You can use Json manipulation avaliable in "org.json.JSONObject" to convert Double value to Stirng .
If your Json structure won't change and will remain as said above , you can do the following.
import org.json.JSONObject;
public static void main(String args[]) {
String j = "{ \"templateName\": \"My DC Template 14\", \"templateDetails\": { \"beneficiaryName\": \"Snow2\", \"dcOpenAmount\": { \"amountValue\": 200.00 } } }";
JSONObject jo = new JSONObject(j);
jo.getJSONObject("templateDetails")
.getJSONObject("dcOpenAmount")
.put("amountValue", String.valueOf(jo.getJSONObject("templateDetails").getJSONObject("dcOpenAmount").getDouble("amountValue")));
System.out.println(jo.toString());
}
Following will be the output
{"templateDetails":{"dcOpenAmount":{"amountValue":"200.0"},"beneficiaryName":"Snow2"},"templateName":"My DC Template 14"}

I don't know for mongodb but for a json string you can replace them with a regex and the function replace like this :
public class Test {
public static void main(String[] args) {
String json = "{\"id\":null,\"userId\":\"FU.ZONKO\",\"txnType\":\"LCI\",\"accessIndicator\":\"Public\",\"templateId\":null,\"templateName\":\"My DC Template 14\",\"tags\":null,\"templateDetails\":{\"applicantDetail\":{\"applicantName\":\"Tom\",\"applicantAddress\":{\"addressLine1\":\"Infosys, Phase 2\",\"city\":\"PUNE\",\"state\":\"MAHARASHTRA\",\"country\":\"INDIA\",\"zip\":\"40039\"},\"accountId\":\"Account1234\",\"customerId\":\"JPMORGAN\"},\"beneficiaryName\":\"Snow2\",\"dcOpenAmount\":{\"amountValue\":200.0,\"currency\":\"USD\"}}}";
System.out.println(replaceNumberByStrings(json));
}
public static String replaceNumberByStrings(String str){
return str.replaceAll("(?<=:)\\d+(\\.\\d+)?(?=(,|}))","\"$0\"");
}
}
It will look for all fields with a numeric value in the json string and add quotes to the value. This way they will be interpreted as strings when the json willl be parsed.
It will not work if the value is in an array though, but in this case it should not be a problem.

Converting a JSON string to custom objects in java [duplicate]

This question already has answers here:
Converting JSON data to Java object
(14 answers)
Closed 6 years ago.
I'm trying to convert a the following string so that I can get the properties out of it. I'm trying to insert these in the DB by getting their properties and then making objects out of them
[{"ParkingSpaces;;;;":"Name;CarPlate;Description;ExpirationDate;Owner"},{"ParkingSpaces;;;;":"A5;T555;Parkingspace A5;;"},{"ParkingSpaces;;;;":"A6;T666;Parkingspace A6;;"},{"ParkingSpaces;;;;":"A7;T777;Parkingspace A7;;"},{"ParkingSpaces;;;;":""}]
I got this string from a CSV file.
Anyone who has an idea on how I can approach this?
Thanks in advance.

Your code is quite messy, but it's doable. You can either use simple JSON parsing method like in the example:
final String json = "[{\"ParkingSpaces;;;;\":\"Name;CarPlate;Description;ExpirationDate;Owner\","
{\"ParkingSpaces;;;;\":\"A5;T555;Parkingspace A5;;\"},{\"ParkingSpaces;;;;\":\"A6;T666;Parkingspace A6;;\"},{\"ParkingSpaces;;;;\":\"A7;T777;Parkingspace A7;;\"},{\"ParkingSpaces;;;;\":\"\"}]";
final org.json.JSONArray jSONArray = new JSONArray(json);
for (int i = 0; i < jSONArray.length(); i++) {
final org.json.JSONObject jSONObject = jSONArray.getJSONObject(i);
final String parkingSpaces = jSONObject.getString("ParkingSpaces;;;;");
final String spaces[] = parkingSpaces.split(";");
System.out.println(Arrays.toString(spaces));
}
}
or use some bindings like Jackson.

What you have there is JSON with some semicolon separated strings in it. I wouldn't call this a CSV format at all.
You could parse the JSON to Java objects with a JSON parser like Gson, but you'll still need to pick the "columns" out of the Java object since they are not properly defined in JSON.
Something like this should work, I recommend you add more error checking than I have though:
public class DBEntry {
#SerializedName("ParkingSpaces;;;;")
#Expose
private String ParkingSpaces;
public String getParkingSpaces() {
return ParkingSpaces;
}
public void setParkingSpaces(String ParkingSpaces) {
this.ParkingSpaces = ParkingSpaces;
}
}
public static void main(String[] args) {
String json = "[{\"ParkingSpaces;;;;\":\"Name;CarPlate;Description;ExpirationDate;Owner\"},{\"ParkingSpaces;;;;\":\"A5;T555;Parkingspace A5;;\"},{\"ParkingSpaces;;;;\":\"A6;T666;Parkingspace A6;;\"},{\"ParkingSpaces;;;;\":\"A7;T777;Parkingspace A7;;\"},{\"ParkingSpaces;;;;\":\"\"}]";
// Convert JSON to java objects using the popular Gson library
Gson gson = new Gson();
Type collectionType = new TypeToken<ArrayList<DBEntry>>(){}.getType();
List<DBEntry> results = gson.fromJson(json, collectionType);
boolean header = true;
for (DBEntry result : results) {
// Ignore the header and empty rows
if (header || result.getParkingSpaces().isEmpty()) { header = false; continue; }
// Grab the columns from the parking spaces string
String[] columns = result.getParkingSpaces().split(";");
// TODO: Store this record in your database
System.out.println("New entry: " + StringUtils.join(columns, ", "));
}
}

How should I initialize an array with some objects in it?

I want to create a JSON data with two objects in an array
String message = "{ "animal" : [{"name":"alice", "type":"cat"}, {"name":"john", "type":"dog"}, {"name":"peter", "type":"bird"} ] }";
But this will make some errors and cannot run in eclipse
How can I resolve it

You have to escape double quotes with backslashes as shown below:
String message = "{ \"animal\" : [{\"name\":\"alice\", \"type\":\"cat\"}, {\"name\":\"john\", \"type\":\"dog\"}, {\"name\":\"peter\", \"type\":\"bird\"} ] }";
Eclipse has an option "Escape text when pasting into a string literal" (Preferences->Java->Editor->Typing) that copy-paste multi-line text into String literals will result in quoted new lines. Please note that after enabling this feature you still have to first write two quotation marks and then paste your text inside those marks.
Adding the the code samples to parse your json data.
package com.stackoverflow.answer;
import org.json.JSONArray;
import org.json.JSONObject;
public class JsonParserExample {
public static void main(String[] args) {
String message = "{ \"animal\" : [{\"name\":\"alice\", \"type\":\"cat\"}, {\"name\":\"john\", \"type\":\"dog\"}, {\"name\":\"peter\", \"type\":\"bird\"} ] }";
JSONObject messageJson = new JSONObject(message);
JSONArray animals = messageJson.getJSONArray("animal");
int n = animals.length();
for (int i = 0; i < n; ++i) {
JSONObject animal = animals.getJSONObject(i);
System.out.println(String.format("animal.%d.name: %s", i, animal.getString("name")));
System.out.println(String.format("animal.%d.type: %s", i, animal.getString("type")));
}
}
}
Hope you are clear now. It's too late. I'm going to sleep. Happy coding!!!

Is it possible to maintain ordering in JSON while converting it from xml and vice versa

I need to convert XML to JSON and then after applying some business logic need to reconvert back in XML,
But when i try to convert a XML to JSON and then reconvert back the JSON back to XML I am getting its attributes in Different order.
Eg Following XML
<breakfast_menu><food><name>Belgian Waffles</name><price>$5.95</price></food></breakfast_menu>
is converted to following JSON
{"breakfast_menu":{"food":{"price":"$5.95","name":"Belgian Waffles"}}}
and is reconverted to following XML
<breakfast_menu><food><price>$5.95</price><name>Belgian Waffles</name></food></breakfast_menu>
As there is name tag is replaced by price tag .
Is there any way so that we can maintain ordering so the conversion and reconversion produce same output .
import org.json.JSONException;
import org.json.JSONObject;
import org.json.XML;
public class XmlToJson {
public static int PRETTY_PRINT_INDENT_FACTOR = 4;
public static String TEST_XML_STRING =
"<breakfast_menu>\n" +
"<food>\n" +
"<name>Belgian Waffles</name>\n" +
"<price>$5.95</price>\n" +
"</food>\n" +
"</breakfast_menu>";
public static void main(String[] args) {
try {
JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING);
String jsonString = xmlJSONObj.toString();
System.out.println(jsonString);
System.out.println("================================");
JSONObject jsonObj = new JSONObject(jsonString);
String s1 = XML.toString(jsonObj);
System.out.println(s1);
s1 = s1.replace("\n", "").replace("\r", "");
TEST_XML_STRING = TEST_XML_STRING.replace("\n", "").replace("\r", "");
System.out.println("================================");
System.out.println(TEST_XML_STRING);
System.out.println("================================");
System.out.println(s1.equals(TEST_XML_STRING));
} catch (JSONException je) {
System.out.println(je.toString());
}
}
}

It might be naturally wrong because by default the definition of JSON is:
An object is an unordered set of name/value pairs.
However, you might want to check JSON.simple library which read the JSON string and keep the order of keys

While there are mechanisms that you might use to provide some sort of ordering, JSON does not guarantee a processor of any particular order. If you are interfacing with some process that requires a particular order (and that is under your control), I would recommend changing that process so it conforms to the normal JSON process to handle unordered input.

json.org Java: JSON array parsing bug [duplicate]

This question already has answers here:
How to parse JSON in Java
(36 answers)
Closed 4 years ago.
I have JSON object as follows:
member = "{interests : [{interestKey:Dogs}, {interestKey:Cats}]}";
In Java I want to parse the above json object and store the values in an arraylist.
I am seeking some code through which I can achieve this.

I'm assuming you want to store the interestKeys in a list.
Using the org.json library:
JSONObject obj = new JSONObject("{interests : [{interestKey:Dogs}, {interestKey:Cats}]}");
List<String> list = new ArrayList<String>();
JSONArray array = obj.getJSONArray("interests");
for(int i = 0 ; i < array.length() ; i++){
list.add(array.getJSONObject(i).getString("interestKey"));
}

public class JsonParsing {
public static Properties properties = null;
public static JSONObject jsonObject = null;
static {
properties = new Properties();
}
public static void main(String[] args) {
try {
JSONParser jsonParser = new JSONParser();
File file = new File("src/main/java/read.json");
Object object = jsonParser.parse(new FileReader(file));
jsonObject = (JSONObject) object;
parseJson(jsonObject);
} catch (Exception ex) {
ex.printStackTrace();
}
}
public static void getArray(Object object2) throws ParseException {
JSONArray jsonArr = (JSONArray) object2;
for (int k = 0; k < jsonArr.size(); k++) {
if (jsonArr.get(k) instanceof JSONObject) {
parseJson((JSONObject) jsonArr.get(k));
} else {
System.out.println(jsonArr.get(k));
}
}
}
public static void parseJson(JSONObject jsonObject) throws ParseException {
Set<Object> set = jsonObject.keySet();
Iterator<Object> iterator = set.iterator();
while (iterator.hasNext()) {
Object obj = iterator.next();
if (jsonObject.get(obj) instanceof JSONArray) {
System.out.println(obj.toString());
getArray(jsonObject.get(obj));
} else {
if (jsonObject.get(obj) instanceof JSONObject) {
parseJson((JSONObject) jsonObject.get(obj));
} else {
System.out.println(obj.toString() + "\t"
+ jsonObject.get(obj));
}
}
}
}}

Thank you so much to #Code in another answer. I can read any JSON file thanks to your code. Now, I'm trying to organize all the elements by levels, for could use them!
I was working with Android reading a JSON from an URL and the only I had to change was the lines
Set<Object> set = jsonObject.keySet();
Iterator<Object> iterator = set.iterator();
for
Iterator<?> iterator = jsonObject.keys();
I share my implementation, to help someone:
public void parseJson(JSONObject jsonObject) throws ParseException, JSONException {
Iterator<?> iterator = jsonObject.keys();
while (iterator.hasNext()) {
String obj = iterator.next().toString();
if (jsonObject.get(obj) instanceof JSONArray) {
//Toast.makeText(MainActivity.this, "Objeto: JSONArray", Toast.LENGTH_SHORT).show();
//System.out.println(obj.toString());
TextView txtView = new TextView(this);
txtView.setText(obj.toString());
layoutIzq.addView(txtView);
getArray(jsonObject.get(obj));
} else {
if (jsonObject.get(obj) instanceof JSONObject) {
//Toast.makeText(MainActivity.this, "Objeto: JSONObject", Toast.LENGTH_SHORT).show();
parseJson((JSONObject) jsonObject.get(obj));
} else {
//Toast.makeText(MainActivity.this, "Objeto: Value", Toast.LENGTH_SHORT).show();
//System.out.println(obj.toString() + "\t"+ jsonObject.get(obj));
TextView txtView = new TextView(this);
txtView.setText(obj.toString() + "\t"+ jsonObject.get(obj));
layoutIzq.addView(txtView);
}
}
}
}

1.) Create an arraylist of appropriate type, in this case i.e String
2.) Create a JSONObject while passing your string to JSONObject constructor as input
As JSONObject notation is represented by braces i.e {}
Where as JSONArray notation is represented by square brackets i.e []
3.) Retrieve JSONArray from JSONObject (created at 2nd step) using "interests" as index.
4.) Traverse JASONArray using loops upto the length of array provided by length() function
5.) Retrieve your JSONObjects from JSONArray using getJSONObject(index) function
6.) Fetch the data from JSONObject using index '"interestKey"'.
Note : JSON parsing uses the escape sequence for special nested characters if the json response (usually from other JSON response APIs) contains quotes (") like this
`"{"key":"value"}"`
should be like this
`"{\"key\":\"value\"}"`
so you can use JSONParser to achieve escaped sequence format for safety as
JSONParser parser = new JSONParser();
JSONObject json = (JSONObject) parser.parse(inputString);
Code :
JSONParser parser = new JSONParser();
String response = "{interests : [{interestKey:Dogs}, {interestKey:Cats}]}";
JSONObject jsonObj = (JSONObject) parser.parse(response);
or
JSONObject jsonObj = new JSONObject("{interests : [{interestKey:Dogs}, {interestKey:Cats}]}");
List<String> interestList = new ArrayList<String>();
JSONArray jsonArray = jsonObj.getJSONArray("interests");
for(int i = 0 ; i < jsonArray.length() ; i++){
interestList.add(jsonArray.getJSONObject(i).optString("interestKey"));
}
Note : Sometime you may see some exceptions when the values are not available in appropriate type or is there is no mapping key so in those cases when you are not sure about the presence of value so use optString, optInt, optBoolean etc which will simply return the default value if it is not present and even try to convert value to int if it is of string type and vice-versa so Simply No null or NumberFormat exceptions at all in case of missing key or value
From docs
Get an optional string associated with a key. It returns the
defaultValue if there is no such key.
public String optString(String key, String defaultValue) {
String missingKeyValue = json_data.optString("status","N/A");
// note there is no such key as "status" in response
// will return "N/A" if no key found
or To get empty string i.e "" if no key found then simply use
String missingKeyValue = json_data.optString("status");
// will return "" if no key found where "" is an empty string
Further reference to study
How to convert String to JSONObject in Java
Convert one array list item into multiple Items

There are many JSON libraries available in Java.
The most notorious ones are: Jackson, GSON, Genson, FastJson and org.json.
There are typically three things one should look at for choosing any library:
Performance
Ease of use (code is simple to write and legible) - that goes with features.
For mobile apps: dependency/jar size
Specifically for JSON libraries (and any serialization/deserialization libs), databinding is also usually of interest as it removes the need of writing boiler-plate code to pack/unpack the data.
For 1, see this benchmark: https://github.com/fabienrenaud/java-json-benchmark I did using JMH which compares (jackson, gson, genson, fastjson, org.json, jsonp) performance of serializers and deserializers using stream and databind APIs.
For 2, you can find numerous examples on the Internet. The benchmark above can also be used as a source of examples...
Quick takeaway of the benchmark: Jackson performs 5 to 6 times better than org.json and more than twice better than GSON.
For your particular example, the following code decodes your json with jackson:
public class MyObj {
private List<Interest> interests;
static final class Interest {
private String interestKey;
}
private static final ObjectMapper MAPPER = new ObjectMapper();
public static void main(String[] args) throws IOException {
MyObj o = JACKSON.readValue("{\"interests\": [{\"interestKey\": \"Dogs\"}, {\"interestKey\": \"Cats\" }]}", MyObj.class);
}
}
Let me know if you have any questions.