Open multiple link with browser with delay - java

I did this program that opens multiple link with default browser:
ArrayList<String> linkList = new ArrayList<>();
for (int i = 0; i < linkList.size(); i++) {
ClassRunnable_OpenLink obj = new ClassRunnable_OpenLink ( linkList.get(i) );
Thread thread = new Thread(obj);
thread.start();
}
private class ClassRunnable_OpenLink implements Runnable {
private URL link;
private String string;
public ClassRunnable_OpenLink (String string) {
this.string = string;
}
private void OpenWithBrowser () {
try {
link = new URL ( string );
edu.stanford.ejalbert.BrowserLauncher launcher = null;
try {
launcher = new BrowserLauncher(null);
} catch ( BrowserLaunchingInitializingException | UnsupportedOperatingSystemException ex) { }
launcher.openURLinBrowser( link );
} catch ( MalformedURLException ex | IOException | URISyntaxException ex) { }
}
#Override
public void run() {
OpenWithBrowser( );
}
}
This works great only if browser (say it's firefox) is already opened, but if it's not, my program only opens the first link and then I have a firefox message that tells me the the browser is still running so I need to close it first.
Same thing with chromium.
So I thought, if I had a way to check when the browser is closed I could use ProcessBuilder to open new firefox process, but I don't know if it's the best way to do this. Besides my java program allows user to select default browser so it could be complicated to use ProcessBuilder in that case.
So do you a have any idea to solve my problem? Maybe I could set a delay between each Thread in this way the system has the time to execute browser process first time, then opening first link and after the browser is running, opening other links, but how about the delay time in seconds? I'm not able to know the time that browser needs to open so it's not a good idea.
I hope you can help me. Thanks

Since java 6 you don't have to use 3rd party implementations to open a webpage with the standard browser. Try
java.awt.Desktop.getDesktop().browse(uri);
Since this maps to the underlying OS functions chances are high multiple calls will work as expected.

A workaround to this (without knowing your exact expectations), could be to do the following:
After first URL open, you could build a delay of for example 10 seconds.
Then in any consecutive URL openings, you can assume that the browser is now surely open, and start opening the next URL's fast after each other.
One note though: Always add some delay to opening URL's (not sure if your framework already does this), because else the browser might crash from the number of URL openings.
UPDATE: You say that Thread.sleep() causes your program to block, this should never happen.
You should always seperate long-during actions from the rest of your program (The (Graphical) User Interface).
So it would be better to write your 'URL opener facility' in another thread.
You can read more about that here: http://docs.oracle.com/javase/tutorial/essential/concurrency/

Related

How to set a Java Gui listener for unexpected program end

I am making a personal planning program. I utilize XML documents to store user data and login data. This does not utilize a server and all accounts created in the program are localized to the computer it is stored on (in the XML documents.)
In the login XML document, I keep track of the users that are logged in so that one user can't have two windows at the same time to prevent any conflicts with data. This feature runs smoothly and I have no problem with it.
The only thing I want to know is if there is some way to catch an unexpected shut down of a program (such as a task-manager close or a forced close when shutting down the computer) so that I can "log" the user off of the XML document. Otherwise the user would never be able to get back on after an unexpected program close without going into the XML document and deleting the username from the logged in list.
It seems a shutdown hook does not work well with the event queue for a java GUI. much like this thread
I tried setting up my code exactly as shown and the shutdown hook doesn't work for me either. Are there any suggestions for ways of catching an unexpected shutdown without shutdown hooks?
this is my code:
import java.awt.EventQueue;
public class Gui {
private static Controller controller;
public static void main (String[] args) {
controller = new Controller();
Runtime.getRuntime().addShutdownHook(new Thread() {
#Override
public void run() {
controller.saveState();
controller.logUserOut();
}
});
EventQueue.invokeLater(
new Runnable() {
public void run() {
controller.start();
}
});
}
}
This is a closer look at my controller that logs the user out
public void logUserOut() {
loginDatabase.logUserOut(username);
saveLoginState();
}
All loginDatabase does is removes that username from the list of logged in users so that user is free to log in again
public void saveLoginState() {
XStream xStream = new XStream(new DomDriver());
OutputStream outFile;
try {
String filePath = "data" + File.separator + "loginDatabase.xml";
outFile = new BufferedOutputStream(new FileOutputStream(filePath));
xStream.toXML(loginDatabase, outFile); // This writes your state to the outputFile;
outFile.close(); //close the writer
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
This is my process for writing on the login state xml file. I suspect it might be too long for a Shutdown Hook even if it were actually being called as I expect.
Any suggestions? I thought for a long time about possibly using simple variables to solve the problem but because I have the program set so that the user can be logged into multiple accounts, the use of variables is impossible.
Also, will the controller object contained in the scope of the shutdown hook be the same controller that is modified in the event queue scope?
The shutdown hook can be a solution here. For details see e.g. this answer: https://stackoverflow.com/a/2541618/2045440
[Off topic] However, if you're at risk that unexpected termination of your application can result in lost of important data, maybe it would be worth to consider the more persistent way of processing this data (autosaving, backup files etc).
I resolved the problem by checking the task manager of the operating system. It allowed me to see if the user the xml document said was logged in actually had a program open. If not then I knew there was a problem. This is a fix for my particular program but it might be a help for others as well.
The link to that thread is here.

Selenium Web driver gets blocked after getting a popup from another popup (IE driver)

I'm facing an issue when application I'm testing is opening a second level popup (I mean, a popup that rises another popup). I'm using Selenium for Java, version 2.42.2, with IE Driver.
My code currently manages all other flows and single pop ups windows, but when a second level popup appears my webdriver object gets irresponsive and just stuck in any method that try to get invoked. When this happens, I need to manually close the popup window and then driver method continues the execution of invoked method.
Maybe it worth mentioning, if I call the second popup from the main page (not from another popup) I am able to manage it without problems, so the problem seems to be related with the number of nested windows more than a specific problem for the page.
Take a look on below code:
String url = "/example.jsp"
int counter = 0;
boolean windowDetected = false;
// Waiting until page with given url gets detected
// It tries 10 times before it continues
while (counter++ < 10 && !windowDetected) {
waitForSeconds(1); // Just invokes Thread.sleep method,
System.out.println("before getting handlers, iteration " + counter + " of 10");
Set<String> handlers = driver.getWindowHandles();
System.out.println("after getting handlers, number of handlers: " + handlers.size());
for (String handler : handlers) {
try {
System.out.println("Moving to " + handler);
driver.switchTo().window(handler);
}
catch (NoSuchWindowException e) {
System.out.println("Window not found, it probably redirected to a different window");
break;
}
if (driver.getCurrentUrl().contains(url)) {
windowDetected = true;
waitForPageLoading(); // It just verify current page status to be completed
break;
}
}
}
I am able to position properly the driver in specific window with above code in other application pages, but when having the second level popup it just hangs on line Set handlers = driver.getWindowHandles(); that is the first method called on driver object after popup appeared. Similarly, if I had called another driver method like driver.getPageSource() the same would have happened in that method.
I am not able to change application structure (my scope is only for testing it), so doing changes in web application code is not an option for me now. I have read on different options like trying Robot class, but I think it will be difficult to implement with more complex pages and difficult to maintain.
Any idea of how can I solve this issue? Many thanks in advance.
Best regards,
Alberto.
After taking a look on IEDriverServer changelog, moving to a newer version of this driver solved the issue. Previous was 2.24.2, and now using 2.44. A slightly different behavior but that accomplishes what I wanted

Launch Jade agents using swing

i have coded a database update software which allows me to deploy a jade mobile agent in order to update the database. In order for it to run, i need to launch it using the AMS gui. I wanted to be able to launch it from gui. I have now done a nice swing gui and i only need to know the code which allows me to launch my mobile agent when the "Update" button is clicked. What is the code? Thanks in advance.
To launch an agent or do whatever related to JADE you need to write YOUR code using JADE libraries and API, irrespective of what Front End you have used (Swing in this case)
One suggestion would be, to keep the modularity, is create another file which does one of many such operations you want, and let your Swing GUI interact (say via sockets) to that file, triggering your operation.
That file, which would act as a server, would listen to the front end and do the respective work. But all commands are to be coded using JADE API. One such code is:
ContainerController cc = Runtime.instance().createAgentContainer(newProfileImpl());
Object arguments[] = new Object[1];``arguments[0]=new Object();
AgentController dummy = cc.createNewAgent("mob2","mobiletrial", arguments);
dummy.start();
This is a method I wrote for launching one agent from another.You'll have to edit it for multiple container use.
void launchAgent( final String AgentName, final String AgentType)
{
log(Level.FINER,"attempting to launch angent name: "+AgentName+" type: "+AgentType);
CreateAgent ca = new CreateAgent();
ca.setAgentName(AgentName);
ca.setClassName(AgentType);
ca.setContainer(new ContainerID(AgentContainer.MAIN_CONTAINER_NAME, null));
Action actExpr = new Action(this.getAMS(), ca);
ACLMessage request = new ACLMessage(ACLMessage.REQUEST);
request.addReceiver(this.getAMS());
request.setOntology(JADEManagementOntology.getInstance().getName());
request.setLanguage(FIPANames.ContentLanguage.FIPA_SL);
request.setProtocol(FIPANames.InteractionProtocol.FIPA_REQUEST);
try {
getContentManager().fillContent(request, actExpr);
addBehaviour(new AchieveREInitiator(this, request) {
protected void handleInform(ACLMessage inform) {
log(Level.INFO,"Agent successfully created name:"+AgentName+" type: "+AgentType);
}
protected void handleFailure(ACLMessage failure) {
log(Level.SEVERE,"Agent launch failed name: "+AgentName+" type: "+AgentType);
}
} );
}
catch (Exception e) {
e.printStackTrace();
}
}

only one swing frame window opened at time

I developed one swing application but each time you run application new window is opened.
I want that if one window is already opened other not allow to open.
Here is an example of a Java Single Application Instance:
A single instance application is one that only allows for 1 of the application to run no matter how many times the user tries to launch.
See also: A shorter example that does not notify the running instance.
The application tries to open a Socket on a specific port. In case another instance of your application is already running, opening the Socket fails.
This should already be sufficient for you, so you would not have to use the part of the code used to register new applications to the first one started.
Using a Socket has one great advantage compared to writing some sort of flag to the filesystem/registry/whatever:
It is removed even if your application crashes.
It actually sounds like you only want one application open at a time. In which case why not take out a file lock or similar when the application runs, and check that on start up. The headache (of course) is clearing up that lock in the event that your program doesn't exit cleanly.
My preferred solution is, as Peter Lang linked to, to use Sockets. When your app starts you can start a server socket listening for incoming connections on localhost (plus port of your choice). Before this happens in your code though you can try and make a connection to the server socket and if it is successful you know there is another instance already open, so you can quit the current instance with an appropriate message.
In your server socket implementation you can also add functionality that on receiving an incoming connection you actually force the current instance of the app to the foreground.
Do you mean run the GUI like a Singleton?, I have done this in the past by making a Static private "view manager" such that it is null and not created or visible until the first time the gui is created, after that just as with a classic singleton, the GUI is set to visible when the app is run again... I have a couple of Frameworks that follow this design--In these frameworks the GUI is not "primary" there are also command line and the like interfaces so the GUI is summoned via the command line...
public class Samp {
JFrame f=new JFrame();
File ff=new File("D:\\a.txt");
FileWriter fw;
public Samp() {
f.setBounds(0, 0, 200, 200);
try {
Scanner sc=new Scanner(ff);
if(!sc.hasNext()) {
fw=new FileWriter(ff);
fw.write("Running");
fw.close();
} else {
System.exit(0);
}
} catch(Exception e) {
System.out.println(e.getMessage());
}
WindowListener wndCloser = new WindowAdapter() {
public void windowClosing(WindowEvent e) {
try {
Scanner sc = new Scanner(ff);
if(sc.hasNext()) {
fw=new FileWriter(ff);
fw.write("");
fw.close();
}
} catch (Exception ex) { }
}
};
f.setVisible(true);
f.addWindowListener(wndCloser);
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
public static void main(String args[]) {
new Samp();
}
}
Use Singletone Pattern as shown in the example!

How do you get selenium to recognize that a page loaded?

In certain unknown situations selenium does not detect that a page has loaded when using the open method. I am using the Java API. For example (This code will not produce this error. I don't know of an externally visible page that will.):
Selenium browser = new DefaultSelenium("localhost", 4444, "*firefox", "http://www.google.com");
browser.start();
browser.open("http://www.google.com/webhp?hl=en");
browser.type("q", "hello world");
When the error occurs, the call to 'open' times out, even though you can clearly see that the page has loaded successfully before the timeout occurs. Increasing the timeout does not help. The call to 'type' never occurs, no progress is made.
How do you get selenium to recognize that the page has loaded when this error occurs?
I faced this problem quite recently.
All JS-based solutions didn't quite fit ICEFaces 2.x + Selenium 2.x/Webdriver combination I have.
What I did and what worked for me is the following:
In the corner of the screen, there's connection activity indicator.
<ice:outputConnectionStatus id="connectStat"
showPopupOnDisconnect="true"/>
In my Java unit test, I wait until its 'idle' image comes back again:
private void waitForAjax() throws InterruptedException {
for (int second = 0;; second++) {
if (second >= 60) fail("timeout");
try {
if ("visibility: visible;".equals(
selenium.getAttribute("top_right_form:connectStat:connection-idle#style"))) {
break;
}
} catch (Exception e) {
}
Thread.sleep(1000);
}
}
You can disable rendering of this indicator in production build, if showing it at the page is unnecessary, or use empty 1x1 gifs as its images.
Works 100% (with popups, pushed messages etc.) and relieves you from the hell of specifying waitForElement(...) for each element separately.
Hope this helps someone.
Maybe this will help you....
Consider the following method is in page called Functions.java
public static void waitForPageLoaded(WebDriver driver) {
ExpectedCondition<Boolean> expectation = new
ExpectedCondition<Boolean>() {
public Boolean apply(WebDriver driver) {
return ((JavascriptExecutor)driver).executeScript("return document.readyState").equals("complete");
}
};
WebDriverWait wait = new WebDriverWait(driver,30);
try {
wait.until(expectation);
} catch(Throwable error) {
Assert.assertFalse(true, "Timeout waiting for Page Load Request to complete.");
}
}
And you can call this method into your function. Since it is a static method, you can directly call with the class name.
public class Test(){
WebDriver driver;
#Test
public void testing(){
driver = new FirefoxDriver();
driver.get("http://www.gmail.com");
Functions.waitForPageLoaded(driver);
}
}
When I do Selenium testing, I wait to see if a certain element is visible (waitForVisible), then I do my action. I usually try to use an element after the one I'm typing in.
Using 'openAndWait' in place of 'open' will do the trick.
From the website:
Many Actions can be called with the "AndWait" suffix, e.g. "clickAndWait". This suffix tells Selenium that the action will cause the browser to make a call to the server, and that Selenium should wait for a new page to load.
Enabling the 'multiWindow' feature solved the issue, though I am not clear why.
SeleniumServer(int port, boolean slowResources, boolean multiWindow)
SeleniumServer server = new SeleniumServer(4444, false, true);
Any clarification would be helpful.
I've run into similar issues when using Selenium to test an application with iFrames. Basically, it seemed that once the primary page (the page containing the iframes) was loaded, Selenium was unable to determine when the iframe content had finished loading.
From looking at the source for the link you're trying to load, it looks like there's some Javascript that's creating additional page elements once the page has loaded. I can't be sure, but it's possible that this is what's causing the problem since it seems similar to the situation that I've encountered above.
Do you get the same sort of errors loading a static page? (ie, something with straight html)
If you're unable to get a better answer, try the selenium forums, they're usually quite active and the Selenium devs do respond to good questions.
http://clearspace.openqa.org/community/selenium_remote_control
Also, if you haven't already tried it, add a call to browser.WaitForPageToLoad("15000") after the call to open. I've found that doing this after every page transition makes my tests a little more solid, even though it shouldn't technically be required. (When Selenium detects that the page actually has loaded, it continues, so the actual timeout variable isn't really a concern..
Not a perfect solution, but I am using this method
$t1 = time(); // current timestamp
$this->selenium->waitForPageToLoad(30);
$t2 = time();
if ($t2 - $t1 >= 28) {
// page was not loaded
}
So, it is kind of checking if the page was not loaded during the specified time, so it is not loaded.
another idea is to modify AJAX API (to add some text after AJAX actions).
After ajax action was finished, before return, set invisible field to TRUE, selenium will find it and read as green-light
in html:
<input type='hidden' id="greenlight">
in selenium
if(driver.findElement(By.id("greenlight")).getAttr("value").equals("TRUE")){
// do something after page loading
}
If you page has no AJAX, try to seek footer of page (I also use Junit fail(""), you may use System.err.println() instead):
element.click();
int timeout =120;
// one loop = 0.5 sec, co it will be one minute
WebElement myFooter = null;
for(int i=0; i<timeout; i++){
myFooter = driver.findElement(By.id("footer"));
if(myFooter!= null){
break;
}
else{
timeout--;
}
}
if(timeout==0 && myFooter == null){
fail("ERROR! PAGE TIMEOUT");
}

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