I have a string xyz a z. How to split it into xyz az. That is splitting the string into two parts taking first white space as the split point. Thanks
Use String.split with the second limit parameter. Use a limit of 2.
The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times
Try this
String givenString = "xyz a z";
String[] split = givenString.split(" ");
StringBuffer secondPart = new StringBuffer();
for (int i = 1; i < split.length; i++) {
secondPart.append(split[i]);
}
StringBuffer finalPart = new StringBuffer();
finalPart.append(split[0]);
finalPart.append(" ");
finalPart.append(secondPart.toString());
System.out.println(finalPart.toString());
Do like this
public static void main(String []args){
String a= "xyz a z";
String[] str_array=a.split(" ");
System.out.print(str_array[0]+" ");
System.out.println(str_array[1]+str_array[2]);
}
Try this
String Str = new String("xyz a z");
for (String retval: Str.split(" ", 2)){
System.out.println(retval);
You need to use String.split with limit of 2 as it will be applied (n-1) times, in your case (2-1 = 1 ) time
So it will consider first space only.
But still you will get the result as xyz and a z, you will still have to get rid of that one more space between a z
Try this
String path="XYZ a z";
String arr[] = path.split(" ",2);
String Str = new String("xyz a z");
for(int i=0;i<arr.length;i++)
arr[i] = arr[i].replace(" ","").trim();
StringBuilder builder = new StringBuilder();
for(String s : arr) {
builder.append(s);
builder.append(" ");
}
System.out.println(builder.toString());
In the for loop you can append a space between two arrays using builder.append(" ").
Related
Thanks for checking out my question.
Here the user enter the string in the format: "xD xS xP xH". The program takes the string, splits it on the space bar, then uses regex to parse the string. There is an issue with my "final string regex" and I am not sure where.
final String regex = "([0-9]+)[D|d]| ([0-9]+)[S|s]| ([0-9]+)[P|p]| ([0-9]+)[H|h]";
Lastly, the loop prints out only the value for D so I suspect it reaches an error moving to match S or s.
public class parseStack
{
public parseStack()
{
System.out.print('\u000c');
String CurrencyFormat = "xD xS xP xH";
System.out.println("Please enter currency in the following format: \""+CurrencyFormat+"\" where x is any integer");
Scanner scan = new Scanner(System.in);
String currencyIn = scan.nextLine();
currencyFinal = currencyIn.toUpperCase();
System.out.println("This is the currency you entered: "+currencyFinal);
String[] tokens = currencyFinal.split(" ");
final String input = tokens[0];
final String regex = "([0-9]+)[D|d]| ([0-9]+)[S|s]| ([0-9]+)[P|p]| ([0-9]+)[H|h]";
if (input.matches(regex) == false) {
throw new IllegalArgumentException("Input is malformed.");
}
long[] values = Arrays.stream(input.replaceAll(regex, "$1 $2 $3 $4").split(" "))
.mapToLong(Long::parseLong)
.toArray();
for (int i=0; i<values.length; i++)
{
System.out.println("value of i: "+i+ " |" +values[i]+ "|");
}
//pause to print
System.out.println("Please press enter to continue . . . ");
Scanner itScan = new Scanner(System.in);
String nextIt = itScan.nextLine();
}
}
Your regular expression should be [\d]+[DdSsPpHh].
The problem you are having is you split the string into chunks, then you match chunks with a RegEx that matches the original string that you have split.
HOWEVER this answer only addresses a problem in your code. Your routine doesn't seem to cater your expectation. And your expectation is not clear at all.
EDIT
Added the multidigit requirement.
Your regex can be simplified somewhat.
"(?i)(\d+d) (\d+s) (\d+p) (\d+h)"
will do a case-insensitive match against multiple digits ( \d+ )
This can be further simplified into
"(?i)(\d+[dsph])"
which will iteratively match the various groups in your currency string.
First of all your regex looks a bit to complex. You input format is "xD xS xP xH" also you are converting the input to uppercase currencyIn = currencyIn.toUpperCase(); but this isn't the problem.
The problem is
String[] tokens = currencyIn.split(" ");
final String input = tokens[0];
You are splitting the input and only use the first part which would be "xD"
The fixed code would look like:
String currencyIn = scan.nextLine();
currencyIn = currencyIn.toUpperCase();
System.out.println("This is the currency you entered: "+currencyIn);
final String regex = "([0-9]+)D ([0-9]+)S ([0-9]+)P ([0-9]+)H";
if (!currencyIn.matches(regex)) {
throw new IllegalArgumentException("Input is malformed.");
}
long[] values = Arrays.stream(currencyIn.replaceAll(regex, "$1 $2 $3 $4").split(" "))
.mapToLong(Long::parseLong)
.toArray();
for (int i=0; i<values.length; i++) {
System.out.println("value of i: "+i+ " |" +values[i]+ "|");
}
I am attempting to write a program that reverses a string's order, even the punctuation. But when my backwards string prints. The punctuation mark at the end of the last word stays at the end of the word instead of being treated as an individual character.
How can I split the end punctuation mark from the last word so I can move it around?
For example:
When I type in : Hello my name is jason!
I want: !jason is name my Hello
instead I get: jason! is name my Hello
import java.util.*;
class Ideone
{
public static void main(String[] args) {
Scanner userInput = new Scanner(System.in);
System.out.print("Enter a sentence: ");
String input = userInput.nextLine();
String[] sentence= input.split(" ");
String backwards = "";
for (int i = sentence.length - 1; i >= 0; i--) {
backwards += sentence[i] + " ";
}
System.out.print(input + "\n");
System.out.print(backwards);
}
}
Manually rearranging Strings tends to become complicated in no time. It's usually better (if possible) to code what you want to do, not how you want to do it.
String input = "Hello my name is jason! Nice to meet you. What's your name?";
// this is *what* you want to do, part 1:
// split the input at each ' ', '.', '?' and '!', keep delimiter tokens
StringTokenizer st = new StringTokenizer(input, " .?!", true);
StringBuilder sb = new StringBuilder();
while(st.hasMoreTokens()) {
String token = st.nextToken();
// *what* you want to do, part 2:
// add each token to the start of the string
sb.insert(0, token);
}
String backwards = sb.toString();
System.out.print(input + "\n");
System.out.print(backwards);
Output:
Hello my name is jason! Nice to meet you. What's your name?
?name your What's .you meet to Nice !jason is name my Hello
This will be a lot easier to understand for the next person working on that piece of code, or your future self.
This assumes that you want to move every punctuation char. If you only want the one at the end of the input string, you'd have to cut it off the input, do the reordering, and finally place it at the start of the string:
String punctuation = "";
String input = "Hello my name is jason! Nice to meet you. What's your name?";
System.out.print(input + "\n");
if(input.substring(input.length() -1).matches("[.!?]")) {
punctuation = input.substring(input.length() -1);
input = input.substring(0, input.length() -1);
}
StringTokenizer st = new StringTokenizer(input, " ", true);
StringBuilder sb = new StringBuilder();
while(st.hasMoreTokens()) {
sb.insert(0, st.nextToken());
}
sb.insert(0, punctuation);
System.out.print(sb);
Output:
Hello my name is jason! Nice to meet you. What's your name?
?name your What's you. meet to Nice jason! is name my Hello
Like the other answers, need to separate out the punctuation first, and then reorder the words and finally place the punctuation at the beginning.
You could take advantage of String.join() and Collections.reverse(), String.endsWith() for a simpler answer...
String input = "Hello my name is jason!";
String punctuation = "";
if (input.endsWith("?") || input.endsWith("!")) {
punctuation = input.substring(input.length() - 1, input.length());
input = input.substring(0, input.length() - 1);
}
List<String> words = Arrays.asList(input.split(" "));
Collections.reverse(words);
String reordered = punctuation + String.join(" ", words);
System.out.println(reordered);
The below code should work for you
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class ReplaceSample {
public static void main(String[] args) {
String originalString = "TestStr?";
String updatedString = "";
String regex = "end\\p{Punct}+|\\p{Punct}+$";
Pattern pattern = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(originalString);
while (matcher.find()) {
int start = matcher.start();
updatedString = matcher.group() + originalString.substring(0, start);<br>
}
System.out.println("Original -->" + originalString + "\nReplaced -->" + updatedString);
}
}
You need to follow the below steps:
(1) Check for the ! character in the input
(2) If input contains ! then prefix it to the empty output string variable
(3) If input does not contain ! then create empty output string variable
(4) Split the input string and iterate in reverse order (you are already doing this)
You can refer the below code:
public static void main(String[] args) {
Scanner userInput = new Scanner(System.in);
System.out.print("Enter a sentence: ");
String originalInput = userInput.nextLine();
String backwards = "";
String input = originalInput;
//Define your punctuation chars into an array
char[] punctuationChars = {'!', '?' , '.'};
String backwards = "";
//Remove ! from the input
for(int i=0;i<punctuationChars.length;i++) {
if(input.charAt(input.length()-1) == punctuationChars[i]) {
input = input.substring(0, input.length()-1);
backwards = punctuationChars[i]+"";
break;
}
}
String[] sentence= input.split(" ");
for (int i = sentence.length - 1; i >= 0; i--) {
backwards += sentence[i] + " ";
}
System.out.print(originalInput + "\n");
System.out.print(input + "\n");
System.out.print(backwards);
}
Don't split by spaces; split by word boundaries. Then you don't need to care about punctuation or even putting spaces back, because you just reverse them too!
And it's only 1 line:
Arrays.stream(input.split("\\b"))
.reduce((a, b) -> b + a)
.ifPresent(System.out::println);
See live demo.
I have a string as follows
Esophageal have not 45.3
The end is nigh 23
Maybe (just) (maybe>32) 45.2
Every line ends in a number (both with and without decimal points)
I want to split the line before the last number
I have tried this regex:
myarray[]=null;
myarray=match.split("/\\s+(?=\\S*+$)/");
but it doesn't split it
You can use this
String Str = "Maybe (just) (maybe>32) 45.2";
for (String retval: Str.split("\\s(?=\\b(\\d+(?:\\.\\d+)?)$)")){
System.out.println(retval);
}
Ideone Demo
Just split the string and get the last value of array:
String[] array = "Maybe (just) (maybe>32) 45.2".split(" ");
String firstPart = array[0];
String lastPart = array[array.length-1];
for (int i = 1; i < array.length - 1; i++) {
firstPart += " " + array[i];
}
System.out.println(firstPart);
System.out.println(lastPart);
match.split("[ \\t](?=[.\\d]+([\\n\\r]+|$))");
Results should look like:
Esophageal have not
45.3 The end is nigh
23 Maybe (just) (maybe>32)
45.2
I'm looking for the way of replacing each char of a Java String for the character+ a blank (except the last one or removing the trailing blank at the end)
The idea is from STACKOVERFLOW return S T A C K O V E R F L O W. Is possible to do this with a regexp or should I iterate the string?
Thanks
"StackOverFlow".replaceAll(".(?!$)", "$0 "));
Go with
str.replaceAll("(?<!^)(?!$)", " ");
or equivalent
str.replaceAll("(?<=.)(?!$)", " ");
...or if you want to add space character just behind non-space character, then use
str.replaceAll("(?<=\S)(?!$)", " ");
...and if you want to prevent double spaces (in case some space is already there), then use
str.replaceAll("(?<=\S)(?!\s)(?!$)", " ");
There's no need for a regex.
Just iterate over the String and use a StringBuilder:
String withSpaces = addSpaces("StackOverflow");
public String addSpaces(String s) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
sb.append(s.charAt(i)).append(" ");
}
return sb.substring(0, sb.length() - 1);
}
I need to retrieve out the nominator and denominator into two int type variables, from a string. It could be:
"1/-2", "4 /0", "-2/ 1234", or " 5"(in this case the denominator is 1);
There might be spaces between the integers and "/", no spaces inside a integer.
And there might be only one integer in the string and no "/".
Any ideas? Thanks.
Hi, I combined your guys' answers, and it works! Thanks!
s is the string
s = s.trim();
String[] tokens = s.split("[ /]+");
int inputNumerator = Integer.parseInt(tokens[0]);
int inputDenominator = 1;
if (tokens.length != 1)
inputDenominator = Integer.parseInt(tokens[1]);
String[] parts = s.split(" */ *");
int num = Integer.parseInt(parts[0]),
den = Integer.parseInt(parts[1]);
Separate the string using '/' as a delimiter, then remove all spaces.
After that use Integer.parseInt();
To remove spaces well, you can try and check for the last of the 1st string and the 1st char of the 2nd string, compare them to ' ', if match remove them.
Take a look at this
http://docs.oracle.com/javase/1.4.2/docs/api/java/util/StringTokenizer.html
hope it helps!
Hope this helps..,
StringTokenizer st= new StringTokenizer(s, "/");
int inputDenominator,inputNumerator;
if(st.hasMoreTokens())
{
String string1= st.nextToken();
string1=string1.trim();
inputNumerator = Integer.parseInt(string1);
}
if(st.hasMoreTokens())
{
String string2= st.nextToken();
string2=string2.trim();
inputDenominator = Integer.parseInt(string2);
}
else{
inputDenominator=1;
}