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I'm trying to make the code scan for palindrome but I feel like something added in there that isn't needed. New to java so sorry if it make no sense

// I'm looking for any errors or mistakes I made in the code or another way to do it with if-then statements or usage of array. (very new to java)
import java.util.Scanner;
public class Palindrome {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter a string");
String letter = input.nextLine();
int n = letter.length();
int numberOfLetters = 0;
for (int i = 0; i < letter.length(); i++) {
numberOfLetters++;
}
if(letter.charAt(0) != letter.charAt(n-1)){
String letter2 = letter.toLowerCase();
if (letter2.charAt(0) == letter2.charAt(n - 1)) {
System.out.println("This is a palindrome " + letter);
}
else {
System.out.println("This is not a palindrome " + letter);
}
}
}
}

Java; loop stops unexpectedly while deleting a char from string

I want to write a code that deletes a character from a string(stringbuilder)and continue until the loop finishes. when I delete a character in a string the loop which include this string stop immediately.
for(i=1;i<n;i++){
for(j=0;j<x[i].length();j++){
if((x[i].contains(v)) || (x[i].contains(other))){
}
else{
for(m=0;m<u;m++){
for(l=0;l<x[i].length();l++){
System.out.format("d[i][l]%s charat(m)%s \n",d[i][l],v.charAt(m));
if(d[i][l] != v.charAt(m)){
count++;
System.out.println(m);
System.out.format("count:%d\n",count);
}
if(count == x[i].length()){
v.deleteCharAt(m);
others.deleteCharAt(v.length()-m-1);
System.out.format("count%d \n",count);
System.out.format("u%d ",u);
System.out.println(v);
count=0;
}
}
count=0;
}
}
}
}

Here is the code for delete no.of given chars from given String.
import java.util.*;
class Test{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
System.out.print("Enter String : ");
String str=sc.nextLine();
System.out.print("\nEnter No.of Deletion : ");
int n=sc.nextInt();
//convert String char Array
char[] st = str.toCharArray();
if(st.length>n)
{
for(int i=0;i<n;i++)
{
st[i]='\0';
}
}
else{
for(int j=0;j<st.length;j++)
{
st[j]='\0';
}
}
System.out.println("Rest String : "+String.valueOf(st));
}
}

get script to run again if user input is yes in java

I need help making it so that the entire script will loop from the beginning if the user types y at the end and the script ends if the user types n at the end. Thanks for any help.
package test123;
import java.util.Scanner;
public class test321 {
public static void main(String[] args) {
int n = 1;
int c;
String playAgain;
do {
System.out.println("Enter a number");
Scanner scanner = new Scanner(System.in);
n = scanner.nextInt();
if ( n < 0 )
System.out.println("Number cant be a negative.");
else
{
int x=n*(n-1)*(n-2);
System.out.println("Factorial= "+x);
System.out.println("Do you want to continue? (y/n):");
playAgain = scanner.nextLine();
}while (!playAgain.equals("y"));
}
}
}

package test123;
import java.util.Scanner;
public class test321 {
public static void main(String[] args) {
int n = 1;
int c;
String playAgain;
do {
System.out.println("Enter a number");
Scanner scanner = new Scanner(System.in);
n = scanner.nextInt();
if ( n < 0 )
System.out.println("Number cant be a negative.");
else
{
int x=n*(n-1)*(n-2);
System.out.println("Factorial= "+x);
System.out.println("Do you want to continue? (y/n):");
playAgain = scanner.nextLine();
} // end else
} // end do
while (playAgain.equals("y"));
}// end main
} // end class

Change
while (!playAgain.equals("y"));
to
while (!playAgain.equals("n"));

how to prompt user to break in a for loop?

package task;
import java.util.*;
public class Task {
public static void main(String[] args) {
System.out.println("Enter \"t\" to terminate.");
for(;;){
Scanner input = new Scanner(System.in);
int i;
double I = Double.POSITIVE_INFINITY;
for(i = 0; i <= I; i++){
System.out.println("Integer " + i);
String a = input.next();
if(a.equals("c")){
break;
}
}
}
}
}
I am having trouble in prompting the user to enter "t" to end the for loop. I basically want the for loop to print out every single positive integer, and when I decide to end, I enter "t".
If I could get some help, I'd appreciate it. Thanks!

You could simply use a do while instead of a for+break
Do while :
System.out.println("Enter \"t\" to terminate.");
Scanner input = new Scanner(System.in);
String pressed;
int i = 0;
while (true) {
i=0;
do {
System.out.println("Integer " + i);
pressed = input.next();
i++;
} while (!pressed.equals("t"));
}
Note that you are not testing if the input is an integer.

Java palindrome until EOF

I have a program that is supposed to ask the user for a number and it will determine whether it is a palindrome or not. It's supposed to keep asking for numbers until EOF is input - So far it asks for the number twice and doesn't seem to be doing the while loop correctly.
Any insight is appreciated
import java.util.Scanner;
public class PalindromeEOF
{
public static void main(String args[])
{
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a number to check if it is a palindrome:");
String num = scanner.nextLine();
String reverse = "";
while (scanner.hasNextLine())
{
for ( int i = 0; i<num.length(); i++ )
{
reverse = num.charAt(i) + reverse;
}
if (num.equals(reverse))
{
System.out.println("\nEntered number IS a palindrome.");
}
else
{
System.out.println("\nEntered number is NOT a palindrome.");
}
System.out.println("\nEnter a number to check if it is a palindrome:");
num = scanner.nextLine();
reverse = "";
}
System.out.println("\nProgram ended on request");
}
}

This worked for me; unless you need num or reverse outside the while loop it should work.
import java.util.Scanner;
public class PalindromeEOF
{
public static void main(String args[])
{
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a number to check if it is a palindrome:");
while (scanner.hasNextLine())
{
String num = scanner.nextLine();
String reverse = "";
for ( int i = 0; i<num.length(); i++ )
{
reverse = num.charAt(i) + reverse;
}
if (num.equals(reverse))
{
System.out.println("\nEntered number IS a palindrome.");
}
else
{
System.out.println("\nEntered number is NOT a palindrome.");
}
System.out.println("\nEnter a number to check if it is a palindrome:");
}
System.out.println("\nProgram ended on request");
}
}

I would separate the palindrome test into its' own method. You could do that in a one line method like
public static boolean isPalindrome(String str) {
return new StringBuilder(str).reverse().toString().equals(str);
}
but I would prefer to iterate the first half of the characters and compare them to the second half in reverse like
public static boolean isPalindrome(String str) {
if (str == null) {
return false;
}
char[] chars = str.toCharArray();
for (int i = 0; i * 2 <= chars.length; i++) {
if (chars[i] != chars[chars.length - i - 1]) {
return false;
}
}
return true;
}
Then your main can invoke that in an infinite loop (terminating on the lack of input) like
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while (true) {
System.out.println("Enter a number to check if it is a palindrome:");
if (!scanner.hasNextLine()) {
break;
}
String num = scanner.nextLine();
if (isPalindrome(num)) {
System.out.printf("%s is a palindrome%n", num);
} else {
System.out.printf("%s is NOT a palindrome%n", num);
}
}
System.out.println("Program ended on request");
}