Develop Reference

I get the wrong output during the collection process

I made an order application. When I mark the radio buttons, it adds like this, I want it to write normal numbers
Screen output like this I don't want it like this I want it to collect
made the sum wrong
boolean checked=((RadioButton) view ).isChecked();
switch (view.getId()){
case R.id.rb1:
if (checked)
pizza.setPizza_size_price(15);
break;
case R.id.rb2:
pizza.setPizza_size_price(17);
break;
case R.id.rb3:
pizza.setPizza_size_price(19);
break;
case R.id.rb6:
if (checked)
pizza.setIcecek(3);
break;
case R.id.rb7:
pizza.setIcecek(2);
break;
case R.id.rb8:
pizza.setIcecek(3);
break;
case R.id.rb11:
if (checked)
pizza.setPatates(5);
break;
case R.id.rb12:
pizza.setPatates(6);
break;
case R.id.rb13:
pizza.setPatates(7);
break;
}
total.setText("Toplam Ücret:"+pizza.getPizza_size_price()+pizza.getIcecek()+pizza.getPatates()+"TL");
}

If your goal is to get the sum of pizza.getPizza_size_price(), pizza.getIcecek() and pizza.getPatates() as output you have to add parenthesis:
total.setText("Toplam Ücret:"+(pizza.getPizza_size_price()+pizza.getIcecek()+pizza.getPatates())+"TL");
Otherwise the numbers won't be sumed up but just appended to the string like "15.0"+"3.0"+"6.0" which then becomes "15.03.06.0"

How to use SecureRandom with switches in Java [duplicate]

Why doesn't the compiler automatically put break statements after each code block in the switch? Is it for historical reasons? When would you want multiple code blocks to execute?

Sometimes it is helpful to have multiple cases associated with the same code block, such as
case 'A':
case 'B':
case 'C':
doSomething();
break;
case 'D':
case 'E':
doSomethingElse();
break;
etc. Just an example.
In my experience, usually it is bad style to "fall through" and have multiple blocks of code execute for one case, but there may be uses for it in some situations.

Historically, it's because the case was essentially defining a label, also known as the target point of a goto call. The switch statement and its associated cases really just represent a multiway branch with multiple potential entry points into a stream of code.
All that said, it has been noted a nearly infinite number of times that break is almost always the default behavior that you'd rather have at the end of every case.

Java comes from C and that is the syntax from C.
There are times where you want multiple case statements to just have one execution path.
Below is a sample that will tell you how many days in a month.
class SwitchDemo2 {
public static void main(String[] args) {
int month = 2;
int year = 2000;
int numDays = 0;
switch (month) {
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
numDays = 31;
break;
case 4:
case 6:
case 9:
case 11:
numDays = 30;
break;
case 2:
if ( ((year % 4 == 0) && !(year % 100 == 0))
|| (year % 400 == 0) )
numDays = 29;
else
numDays = 28;
break;
default:
System.out.println("Invalid month.");
break;
}
System.out.println("Number of Days = " + numDays);
}
}

I think it is a mistake. As a language construct it is just as easy to have break as the default and instead have a fallthrough keyword. Most of the code I have written and read has a break after every case.

You can do all sorts of interesting things with case fall-through.
For example, lets say you want to do a particular action for all cases, but in a certain case you want to do that action plus something else. Using a switch statement with fall-through would make it quite easy.
switch (someValue)
{
case extendedActionValue:
// do extended action here, falls through to normal action
case normalActionValue:
case otherNormalActionValue:
// do normal action here
break;
}
Of course, it is easy to forget the break statement at the end of a case and cause unexpected behavior. Good compilers will warn you when you omit the break statement.

Why doesn't the compiler automatically put break statements after each code block in the switch?
Leaving aside the good desire to be able to use the identical block for several cases (which could be special-cased)...
Is it for historical reasons? When would you want multiple code blocks to execute?
It's mainly for compatibility with C, and is arguably an ancient hack from the days of old when goto keywords roamed the earth. It does enable some amazing things, of course, such as Duff's Device, but whether that's a point in its favor or against is… argumentative at best.

The break after switch cases is used to avoid the fallthrough in the switch statements. Though interestingly this now can be achieved through the newly formed switch labels as implemented via JEP-325.
With these changes, the break with every switch case can be avoided as demonstrated further :-
public class SwitchExpressionsNoFallThrough {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int value = scanner.nextInt();
/*
* Before JEP-325
*/
switch (value) {
case 1:
System.out.println("one");
case 2:
System.out.println("two");
default:
System.out.println("many");
}
/*
* After JEP-325
*/
switch (value) {
case 1 ->System.out.println("one");
case 2 ->System.out.println("two");
default ->System.out.println("many");
}
}
}
On executing the above code with JDK-12, the comparative output could be seen as
//input
1
// output from the implementation before JEP-325
one
two
many
// output from the implementation after JEP-325
one
and
//input
2
// output from the implementation before JEP-325
two
many
// output from the implementation after JEP-325
two
and of course the thing unchanged
// input
3
many // default case match
many // branches to 'default' as well

So you do not have to repeat code if you need several cases to do the same thing:
case THIS:
case THAT:
{
code;
break;
}
Or you can do things like :
case THIS:
{
do this;
}
case THAT:
{
do that;
}
In a cascade fashion.
Really bug/confusion prone, if you ask me.

As far as the historical record goes, Tony Hoare invented the case statement in the 1960s, during the "structured programming" revolution. Tony's case statement supported multiple labels per case and automatic exit with no stinking break statements. The requirement for an explicit break was something that came out of the BCPL/B/C line. Dennis Ritchie writes (in ACM HOPL-II):
For example, the endcase that escapes from a BCPL switchon statement was not present in the language
when we learned it in the 1960s, and so the overloading of the break keyword to escape
from the B and C switch statement owes to divergent evolution rather than conscious change.
I haven't been able to find any historical writings about BCPL, but Ritchie's comment suggests that the break was more or less a historical accident. BCPL later fixed the problem, but perhaps Ritchie and Thompson were too busy inventing Unix to be bothered with such a detail :-)

Java is derived from C, whose heritage includes a technique known as Duff's Device .
It's an optimization that relies on the fact that control falls through from one case to the next, in the absence of a break; statement. By the time C was standardized, there was plenty of code like that "in the wild", and it would have been counterproductive to change the language to break such constructions.

As people said before, it is to allow fall-through and it is not a mistake, it is a feature.
If too many break statements annoy you, you can easily get rid of them by using return statements instead. This is actually a good practice, because your methods should be as small as possible (for the sake of readability and maintainability), so a switch statement is already big enough for a method, hence, a good method should not contain anything else, this is an example:
public class SwitchTester{
private static final Log log = LogFactory.getLog(SwitchTester.class);
public static void main(String[] args){
log.info(monthsOfTheSeason(Season.WINTER));
log.info(monthsOfTheSeason(Season.SPRING));
log.info(monthsOfTheSeason(Season.SUMMER));
log.info(monthsOfTheSeason(Season.AUTUMN));
}
enum Season{WINTER, SPRING, SUMMER, AUTUMN};
static String monthsOfTheSeason(Season season){
switch(season){
case WINTER:
return "Dec, Jan, Feb";
case SPRING:
return "Mar, Apr, May";
case SUMMER:
return "Jun, Jul, Aug";
case AUTUMN:
return "Sep, Oct, Nov";
default:
//actually a NullPointerException will be thrown before reaching this
throw new IllegalArgumentException("Season must not be null");
}
}
}
The execution prints:
12:37:25.760 [main] INFO lang.SwitchTester - Dec, Jan, Feb
12:37:25.762 [main] INFO lang.SwitchTester - Mar, Apr, May
12:37:25.762 [main] INFO lang.SwitchTester - Jun, Jul, Aug
12:37:25.762 [main] INFO lang.SwitchTester - Sep, Oct, Nov
as expected.

It is an old question but actually I ran into using the case without break statement today. Not using break is actually very useful when you need to combine different functions in sequence.
e.g. using http response codes to authenticate user with time token
server response code 401 - token is outdated -> regenerate token and log user in.
server response code 200 - token is OK -> log user in.
in case statements:
case 404:
case 500:
{
Log.v("Server responses","Unable to respond due to server error");
break;
}
case 401:
{
//regenerate token
}
case 200:
{
// log in user
break;
}
Using this you do not need to call log in user function for 401 response because when the token is regenerated, the runtime jumps into the case 200.

Not having an automatic break added by the compiler makes it possible to use a switch/case to test for conditions like 1 <= a <= 3 by removing the break statement from 1 and 2.
switch(a) {
case 1: //I'm between 1 and 3
case 2: //I'm between 1 and 3
case 3: //I'm between 1 and 3
break;
}

because there are situations where you want to flow through the first block for example to avoid writing the same code in multiple blocks but still be able to divide them for mroe control. There are also a ton of other reasons.

You can makes easily to separate other type of number, month, count.
This is better then if in this case;
public static void spanishNumbers(String span){
span = span.toLowerCase().replace(" ", "");
switch (span){
case "1":
case "jan": System.out.println("uno"); break;
case "2":
case "feb": System.out.println("dos"); break;
case "3":
case "mar": System.out.println("tres"); break;
case "4":
case "apr": System.out.println("cuatro"); break;
case "5":
case "may": System.out.println("cinco"); break;
case "6":
case "jun": System.out.println("seis"); break;
case "7":
case "jul": System.out.println("seite"); break;
case "8":
case "aug": System.out.println("ocho"); break;
case "9":
case "sep": System.out.println("nueve"); break;
case "10":
case "oct": System.out.println("diez"); break;
}
}

I am now working on project where I am in need of break in my switch statement otherwise the code won't work. Bear with me and I will give you a good example of why you need break in your switch statement.
Imagine you have three states, one that waits for the user to enter a number, the second to calculate it and the third to print the sum.
In that case you have:
State1 - Wait for user to enter a number
State2 - Print the sum
state3 - Calculate the sum
Looking at the states, you would want the order of exaction to start on state1, then state3 and finally state2. Otherwise we will only print users input without calculating the sum. Just to clarify it again, we wait for the user to enter a value, then calculate the sum and prints the sum.
Here is an example code:
while(1){
switch(state){
case state1:
// Wait for user input code
state = state3; // Jump to state3
break;
case state2:
//Print the sum code
state = state3; // Jump to state3;
case state3:
// Calculate the sum code
state = wait; // Jump to state1
break;
}
}
If we don't use break, it will execute in this order, state1, state2 and state3. But using break, we avoid this scenario, and can order in the right procedure which is to begin with state1, then state3 and last but not least state2.

Exactly, because with some clever placement you can execute blocks in cascade.

Get current case number

I have a simple switch case statement, and I want to get the current case int.
For example:
case 5:
// some code
break;
I want to get the 5.
Ideas?

Usually to get inside a switch case you need to meet a condition. What you can do is print the condition variable inside the switch case.
int conditionVariable = 0;
At some point in execution the conditionVariable will be set to a value by something in your program. Then the switch case will execute, which will compare conditionVariable to your cases.
switch (conditionVariable)
{
case 5:
// This prints the case number to the logcat.
Log.d("tag", conditionVariable);
break;
. . .
}

scan your keyboard input
store it in int varialble
int currentcase;
switch(currentcase)
{
case 5:
System.out.println("u r in "+ currentcase)
break;
}

Behavior of switch statement with the default block at the top

I found one interesting way to use a switch statement in Java, and I can't catch all logic.
Can someone help to understand all details in depth?
Here is code:
private static int counter = 0;
public static Shape randomFactory() {
int xVal = rand.nextInt(100);
int yVal = rand.nextInt(100);
int dim = rand.nextInt(100);
switch (counter++ % 3) {
default:
case 0:
return new Circle(xVal, yVal, dim);
case 1:
return new Square(xVal, yVal, dim);
case 2:
return new Line(xVal, yVal, dim);
}
}
In general I understand this logic,
What exactly default mean here:
switch (counter++ % 3) {
default:
And how does switch (counter++ % 3) find equals case? And here isn't any brake presented.
Any suggestions?

default marks the block that would get executed if the switch expression does not match any case labels. In your example, default contains no break, so it would fall through and execute the same code as for case 0.
Note that, since you have a case label for every possible value of the switch expression, the default is effectively a no-op.

In your case you are using default block at the very beginning of case statement, which is a bit strange since default means that this part of code will execute if none of the case conditions have matched. You should also check about fall through. You avoided it with returns, but it is usually done with break.
switch (counter++ % 3) calculates first counter++ % 3 and then matches it with appropriate case.

The default clause is useless here: due to your %3 it should never happen.
Would you modify the %3 to %4 it would catch some data, but as there is neither a break nor a return statement it would execute just like case 0.

default:
It simply means of none of the conditions in switch statement are matched code corresponding to default will be executed.

default will execute when there is no matching in case.In this case default is useless since it will never execute. Consider the following case.
switch(input){
case 1:
// do something
break;
case 2:
// do something
break;
default:
// if input is not 1 or 2 this will execute.
break;
}

Default is one of the switch labels which contains statements to execute if none of the other labels match. From JLS §14.11:
At most one default label may be associated with the same switch statement.
If no case matches but there is a default label, then all statements after the matching default label in the switch block, if any, are executed in sequence. If all these statements complete normally, or if there are no statements after the default label, then the entire switch statement completes normally.
If no case matches and there is no default label, then no further action is taken and the switch statement completes normally.
So in this case default label will do nothing as there always will be a match.

There is no break inside default so it do nothing, it is just example of fallthrough.

Please read about switch statements from here -
http://docs.oracle.com/javase/tutorial/java/nutsandbolts/switch.html
default means if any case doesn't match with switch condition then default is called.
counter++ % 3 ..your counter was 0 so it will match with case 0.

Java Switch Statement

I have a problem using switch statement when I tried to deal with a special situation.
For example,
I have 3 cases: A, B, C.
for A, I want to do statement_1 and statement_3.
for B, I want to do statement_2 and statement_3.
for C, I want to do nothing
if I use if-else statement, it will look like the following:
if ( not C){
do statement_3
if B
do statement 2
else if A
do statement 1
}
If I want to use switch statement to do the same thing, I have some trouble.
switch (variable){
case A: do statement_1
case B: do statement_2
// how to do statement 3 here?
}
I am trying to avoid the duplicated codes. So I am thinking that how to make the codes as simple as I can.
UPDATE 1：
to make my codes/question more clear, I just want to make my codes
as simple/clear as I can, that is why I want to use switch statement
instead of if-else. Also, I heard that switch-statement is usually
faster than if-else. (I am not 100% sure though).
I want to use switch-case because Case A, B, C are enum type. they
are not variable. Sorry about the confusion.
each statements are more than 10 lines of codes. That is why I do not want to do the followings:
switch (enum variable) {
case A:
statement1
statement3
break;
case B:
statement2
statement3
break;
}

i would recommend to define exactly what staments should be executed:
switch (variable){
case A:
statement_1();
statement_3();
break;
case B:
statement_2();
statement_3();
break;
}
for Update-3:
create methods for those 10 lines:
public void statement_1() {
//your 10 lines of code
}
if you're always executing statement_3, except for case C you can go with if/else-blocks as you wrote them.
but in my honest opinion:
define EXACTLY what has to be done in which case if you have a small amount of cases.
it is easier to read for others

You can do this:
switch (variable){
case A: do statement_1; do statement_3; break;
case B: do statement_2; do statement_3; break;
}

Why not nest the switch into the if statement? there is no-repeat code this way.
if(!C){
statement_3;
switch(variable){
case A:
statement_1;
break;
case B:
statement_2;
break;
}
or make use of both the if-statement and the switch?
if(!C){
statement_3;
}
switch(variable){
case A:
statement_1;
break;
case B:
statement_2;
break;

I often find introducing enums adds clarity. Here I imagine each enum is an issue which can be resolved through a number of processes:
enum Issue {
A {
void handleIt () {
statement_1();
statement_3();
}
},
B {
void handleIt () {
statement_2();
statement_3();
}
},
C {
void handleIt () {
// Do nothing.
}
},
D {
void handleIt () {
A.handleIt();
B.handleIt();
}
};
abstract void handleIt();
}
Note here that you get the added benefit of being able to handle certain issues using the solutions of other issues (see my D enum).

If a case has more than 2-3 statements it's bette(from point of view of readability and clean code) to extract them as separate methods:
switch (variable){
case A: handleCaseA(); break;
case B: handleCaseB(); break;
default: handleDefaultCase(); break;
}

switch (variable) {
case A:
do statement_1;
do statement_3;
break;
case B:
do statement_2;
do statement_3;
break;
}

With Java 12 switch-expressions you can do it nicely as follows:
switch (variable) {
case A -> statement_1();
statement_3();
case B -> statement_2();
statement_3();
};

When you use "case," use a switch statement first, and make sure you've got an initialized variable in it. Here's an example.
Use an initialized variable: i.e.
(String s=sc.nextLine();)
switch (s) {
case "Pepperoni":
System.out.println("Pepperoni? Nice choice. Please wait............Ding! Here's your pepperoni pizza. Enjoy, and thanks for using the Local Pizzeria!");
case "Cheese":
System.out.println("Cheese? Okay! Soft cheese it is! Please wait............Ding! Here's your cheese pizza. Enjoy, and thank you for using the Local Pizzeria!");
break;
case "Mushrooms":
System.out.println("Mushrooms? Veggie person, right? OK! Please wait............Ding! Here's your mushroom pizza. Enjoy, and thanks for using the Local Pizzeria!");
break;
case "Beef Bits":
System.out.println("Beef bits? Like meat? Alright! Please wait............Ding! Here's your beef bit pizza. Enjoy, and thank you for using the Local Pizzeria!");
break;
case "Spicy Buffalo Chicken":
System.out.println("Spicy buffalo chicken? Way to spice things up! Please wait............Ding! Here's your spicy buffalo chicken pizza. Enjoy, and thank you for using the Local Pizzeria!");
break;
case "Exit":
System.out.println("See you soon!");
}
}

Here u must use if statement in this way because in switch there are normally default value also.
if (letter == 'A' || letter == 'B') { System.out.println("Statement 3 ");}
switch (letter) {
case 'A':
System.out.println("Statement 1 ");
break;
case 'B':
System.out.println("Statement 2 ");
break;
case 'C':
System.out.println();
break;
default:
System.out.println("You entered wrong value");
}