I have this problem with calculating time difference in minutes.
Its working fine with exampples like calculating the difference between
2045 and 2300.
But when I want to calculate the difference between for example
2330 (today) and 0245 (tomorrow) I get a incorrect answer.
Code below:
// This example works
String dateStart = "2045";
String dateStop = "2300";
// This example doesnt work
//String dateStart = "2330";
//String dateStop = "0245";
// Custom date format
SimpleDateFormat format = new SimpleDateFormat("HHmm");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
} catch (Exception e) {
e.printStackTrace();
}
long diff = d2.getTime() - d1.getTime();
long minutes = TimeUnit.MILLISECONDS.toMinutes(diff);
System.out.println("Time in minutes: " + minutes + " minutes.");
Thanks in advance
Consider using LocalDate, LocalDateTime, LocalTime ZonedDateTime classes from java.time.* package introduced in Java 8. They are very handy in use as they can address various corner cases (e.g. measuring minutes across different time zones, or during autumn and spring time change).
The thing to you need to know when you calculate time difference is that:
LocalTime contains time only
LocalDate contains date only (no time)
LocalDateTime contains both (date + time.)
ZonedDateTime contains date + time + timezone
This implies that difference between times will be different when you compare with:
LocalTime you can diff only time so 20:45 and 23:30 gives 2:45 of difference
LocalDate you cannot calculate any time diffs (contains no time)
LocalDateTime you can specify date and time, e.g.: 20:45 on 1Jan and 23:30 on 3Jan . Time difference will be 2:45 and 2 days of difference, or 50:45.
ZonedDateTime - same as LocalDateTime plus you takes into account DayLightSavings, so if the clock is changed overnight - it will get reflected.
Here is a snippet for a LocalDateTime:
LocalDateTime today2045 = LocalDateTime.of(
LocalDate.now(),
LocalTime.parse("20:45"));
LocalDateTime tomorrow0230 = LocalDateTime.of(
LocalDate.now().plusDays(1),
LocalTime.parse("02:30"));
System.out.println("Difference [minutes]: " +
Duration.between(today2045, tomorrow0230).toMinutes());
For ZonedDateTime taking into account spring/autumn clock changes:
ZonedDateTime today2045 = ZonedDateTime.of(
LocalDate.now(),
LocalTime.parse("20:45"),
ZoneId.systemDefault());
ZonedDateTime tomorrow0230 = ZonedDateTime.of(
LocalDate.now().plusDays(1),
LocalTime.parse("02:30"),
ZoneId.systemDefault());
System.out.println("Difference [minutes]: " +
Duration.between(today2045, tomorrow0230).toMinutes());
Some info on constructors can be found in Oracle's tutorial here.
This is not working because when you create a new date with just a time in it, it's assuming the day is "today".
What you could do is:
// This example works
String dateStart = "2045";
String dateStop = "2300";
// This example doesnt work
//String dateStart = "2330";
//String dateStop = "0245";
// Custom date format
SimpleDateFormat format = new SimpleDateFormat("HHmm");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
} catch (Exception e) {
e.printStackTrace();
}
// MY ADDITION TO YOUR CODE STARTS HERE
if(d2.before(d1)){
Calendar c = Calendar.getInstance();
c.setTime(d2);
c.add(Calendar.DATE, 1);
d2 = c.getTime();
}
// ENDS HERE
long diff = d2.getTime() - d1.getTime();
long minutes = TimeUnit.MILLISECONDS.toMinutes(diff);
System.out.println("Time in minutes: " + minutes + " minutes.");
But you should consider using Java 8 new Date/Time features, or Joda Time.
You can add if statement to check if this is today, and if no you can add one day to this, since you are comparing time it wont be problem if you add full day
if(d2.before(d1)){
d2.setTime(d2.getTime()+86400000);
}
Try it out
This is a solved problem. If you look at the Joda Time library you'll find all the time and date manipulation functions you could possibly want:
In your case something along the lines of:
DateTime first = new DateTime(larger-time);
DateTime second = new DateTime(smaller-time);
DateTime difference = first.minusMillis(second.getMillis())
Joda will cope with all the odd edge conditions like rolling over between days/months/years, lengths of months, leap years, daylight savings, timezones...
I am having java.sql.date and java.sql.time objects, I need to find the time duration between the dates.
So i am creating java.sql.timestamp object by using above date and time object
Timestamp timestamp1 = new Timestamp(StartDate.getYear(),
StartDate.getMonth(), StartDate.getDay(),
StartTime.getHours(), StartTime.getMinutes(), 00,
00);
Here is mycode
String date = "2010-01-05";
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date date3 = null;
try {
date3 = sdf1.parse(date);
} catch (ParseException e) {
e.printStackTrace();
}
Date StartDate = new Date(date3.getTime());
System.out.println("Date " + StartDate);
String date2 = "2010-01-06";
java.util.Date date4 = null;
try {
date4 = sdf1.parse(date2);
} catch (ParseException exception) {
exception.printStackTrace();
}
Date EndDate = new Date(date4.getTime());
System.out.println("Date " + EndDate);
String time = "01:00";
DateFormat formatter = new SimpleDateFormat("HH:mm");
java.sql.Time StartTime = null;
try {
StartTime = new java.sql.Time(formatter.parse(time).getTime());
} catch (ParseException exception2) {
exception2.printStackTrace();
}
System.out.println("TIMEEEEEEEEEE====" + StartTime);
String time2 = "02:00";
java.sql.Time EndTime = null;
try {
EndTime = new java.sql.Time(formatter.parse(time2).getTime());
} catch (ParseException exception3) {
exception3.printStackTrace();
}
System.out.println("TIMEEEEEEEEEE====" + EndTime);
Timestamp timestamp1 = new Timestamp(StartDate.getYear(),
StartDate.getMonth(), StartDate.getDay(),
StartTime.getHours(), StartTime.getMinutes(), 00,
00);
Timestamp timestamp2 = new Timestamp(EndDate.getYear(),
EndDate.getMonth(), EndDate.getDay(),
EndTime.getHours(), EndTime.getMinutes(), 00, 00);
long milliseconds = timestamp2.getTime() - timestamp1.getTime();
int seconds = (int) milliseconds / 1000;
// calculate hours minutes and seconds
int hours = seconds / 3600;
int minutes = (seconds % 3600) / 60;
seconds = (seconds % 3600) % 60;
System.out.println(hours+"h:"+minutes+"m:"+"00s");
Test case
when I give date as 2010-01-05 and date2 as 2010-01-06 I am getting output as below
Date 2010-01-05
Date 2010-01-06
TIMEEEEEEEEEE====01:00:00
TIMEEEEEEEEEE====02:00:00
25h:0m:00s
when I give date as 2010-01-05 and date2 as 2010-01-11 I am getting output in negative value as below
Date 2010-01-05
Date 2010-01-11
TIMEEEEEEEEEE====01:00:00
TIMEEEEEEEEEE====02:00:00
-23h:0m:00s
Help me to correct if I am doing something wrong.
Thanks in advance.
Manual time calculation:-
Converts Date in milliseconds (ms) and calculate the differences between two dates, with following rules :
1000 milliseconds = 1 second
60 seconds = 1 minute
60 minutes = 1 hour
24 hours = 1 day
Sample Example:-
package com.dps2.practice.dyuti;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateDifferentExample {
public static void main(String[] args) {
String dateStart = "08/11/2016 09:29:58";
String dateStop = "08/12/2016 10:31:48";
//HH converts hour in 24 hours format (0-23), day calculation
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
//in milliseconds
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");
} catch (Exception e) {
e.printStackTrace();
}
}
}
The problem with your calculation is this: StartDate.getDay() etc.
getDay() will return the number of day of the week (read the JavaDoc) and not the day of the month. You'll need to use getDate() instead.
To illustrate the problem using your values: 2010-01-05 will return 2 for getDay() and thus you are getting 2010-01-02 as your timestamp. 2010-01-11 will return 1 for getDay() (it's 6 days later, i.e. (2 + 6) % 7 = 1) and hence your second timestamp becomes 2010-01-01. Now the second timestamp is before the first and hence you get a negative value.
However, as I already stated in my comments you should try and use some library or at least the non-deprecated built-in functionality for those calculations to save you a lot of headaches (I suggest you watch this video to get an idea of the challenges: https://youtube.com/watch?v=-5wpm-gesOY ).
The java.sql date-time classes are meant only for exchanging data with databases. Do not use them for business logic. Also, they are part of the troublesome, poorly designed, and confusing old legacy date-time classes. Avoid them all.
java.time
The java.time classes built into Java 8 and later supplant the old classes you are using. Much simpler now.
LocalDate ld = LocalDate.parse ( "2010-01-06" );
LocalTime lt = LocalTime.parse ( "01:00" );
LocalDateTime earlier = LocalDateTime.of ( ld , lt );
LocalDateTime later = earlier.plusHours ( 7 );
The Duration class represents a span of time as a total number of seconds and nanoseconds. Its toString method generates a String in the standard ISO 8601 format PnYnMnDTnHnMnS. This format uses P to mark the beginning, and the T to separate year-months-days from hours-minutes-seconds portion. The Duration and Period classes can both parse and generate such Strings.
Duration duration = Duration.between ( earlier , later );
In Java 8, Duration class inexplicably lacks getter methods for each part: days, hours, minutes, seconds, fraction-of-second. Java 9 rectifies this omission with new getPart methods.
Dump to console.
System.out.println ( "earlier: " + earlier + " | later: " + later + " | duration: " + duration );
earlier: 2010-01-06T01:00 | later: 2010-01-06T08:00 | duration: PT7H
Time zone
Be aware that your inputs lacked any information about offset-from-UTC or time zone. So the math seen above is performed assuming generic 24-hour days. Real-world anomalies such as Daylight Saving Time (DST) are ignored.
If you did indeed intend time zones, assign them via the atZone method to instantiate OffsetDateTime or ZonedDateTime objects.
That's a complicated code you have in your question there. You can make it quite easy by using java.util.concurrent.TimeUnit class.
Output
Date Tue Jan 05 00:00:00 UTC 2010
Date Wed Jan 06 00:00:00 UTC 2010
difference is:
24 hours : 1440 minutes : 86400 seconds
Code
import java.util.*;
import java.text.SimpleDateFormat;
import java.util.concurrent.TimeUnit;
public class HelloWorld {
public static void main(String[] args) {
String date = "2010-01-05";
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date date3 = null;
try {
date3 = sdf1.parse(date);
} catch (Exception e) {
e.printStackTrace();
}
Date StartDate = new Date(date3.getTime());
System.out.println("Date " + StartDate);
String date2 = "2010-01-06";
java.util.Date date4 = null;
try {
date4 = sdf1.parse(date2);
} catch (Exception exception) {
exception.printStackTrace();
}
Date EndDate = new Date(date4.getTime());
System.out.println("Date " + EndDate);
long dateStart = StartDate.getTime(), dateStop = EndDate.getTime();
long diff = dateStop - dateStart;
long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(diff);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(diff);
long diffInHours = TimeUnit.MILLISECONDS.toHours(diff);
System.out.println("\n\ndifference is:\n");
System.out.println(diffInHours + " hours : " + diffInMinutes + " minutes : " + diffInSeconds + " seconds");
}
}
I have the string date "3.9.1991". And I want to obtain how many years have passed since the date. For example 23. How can I achieve it using Calendar or Date?
EDIT:
I have been trying this:
private String parseVkBirthday(String birthdayString) {
// 3.9.1991
SimpleDateFormat formatter = new SimpleDateFormat("d.M.yyyy");
String formattedDate = null;
Calendar date = Calendar.getInstance();
int year = 0;
try {
Date currentDate = new Date();
Date birthdayDate = formatter.parse(birthdayString);
Log.d(LOG_TAG, "year1 = " + currentDate.getTime() + " year2 = " + birthdayDate.getTime());
long diff = currentDate.getTime() - birthdayDate.getTime();
birthdayDate.setTime(diff);
date.setTime(birthdayDate);
year = date.get(Calendar.YEAR);
} catch (ParseException e) {
e.printStackTrace();
}
return "" + year;
}
But it returns me 1993.
Answer:
There are while 3 ways for solving this problem:
1) As codeaholicguy answered, we can use Joda-Time library(what I prefer for Android).
2) As Basil Bourque answered, we can use ThreeTen-Backport library for using java.time classes from java 8.
3) And we can use java 8 and classes from java.time.
Thanks to everyone.
Use SimpleDateFormat and Period of Joda-Time library, example below:
String pattern = "dd.MM.yyyy";
SimpleDateFormat format = new SimpleDateFormat(pattern);
Date date = format.parse("3.9.1991");
System.out.println(date);
Period period = new Period(date.getTime(), (new Date()).getTime());
System.out.println(period.getYears());
String fullDate="3.9.1991";
String[] splitDate=fullDate.split(".");
int year=Integer.parseInt(splitDate[2]);
int currentYear = Calendar.getInstance().get(Calendar.YEAR);
int passedYears=currentYear-year;
Calendar.YEAR can be used to add or subtract year from current date in the same fashion we added days and month into date.
http://javarevisited.blogspot.in/2012/12/how-to-add-subtract-days-months-years-to-date-time-java.html
sample program:
import java.util.Calendar;
public class Years {
public static void main(String[] args) {
//create Calendar instance
Calendar now = Calendar.getInstance();
System.out.println("Current date : " + (now.get(Calendar.MONTH) + 1)
+ "-"
+ now.get(Calendar.DATE)
+ "-"
+ now.get(Calendar.YEAR));
//add year to current date using Calendar.add method
now.add(Calendar.YEAR,1);
System.out.println("date after one year : " + (now.get(Calendar.MONTH) + 1)
+ "-"
+ now.get(Calendar.DATE)
+ "-"
+ now.get(Calendar.YEAR));
//substract year from current date
now =Calendar.getInstance();
now.add(Calendar.YEAR,-100);
System.out.println("date before 100 years : " + (now.get(Calendar.MONTH) + 1)
+ "-"
+ now.get(Calendar.DATE)
+ "-"
+ now.get(Calendar.YEAR));
}
}
http://forgetcode.com/Java/1568-Adding-or-Subtracting-Years-to-Current-Date#
Based on example code by xrcwrn with the Joda-Time 2.8 library:
// get the current year with #xrcwm's code
Calendar mydate = new GregorianCalendar();
String mystring = "3.9.1991";
Date thedate = new SimpleDateFormat("d.m.yyyy", Locale.ENGLISH).parse(mystring);
DateTime myDateTime = new DateTime(thedate.getTime()); // joda DateTime object
// get he current date
DateTime currentDateTime = new DateTime();
// get the years value
long years = Years.between(currentDateTime, myDateTime).getYears()
The code above should give you the correct value. Mind you, this code may have some syntax errors.
As a side note, Java 8 has a time package which seems to provide more of the same functionality.
java.time
The new java.time package in Java 8 and later supplants the old java.util.Date/.Calendar & SimpleTextFormat classes.
First parse the string using new DateTimeFormatter class. Do not use SimpleTextFormat. And read the doc as there may be subtle differences in the symbol codes between the old and new classes.
Get today's date, to calculate elapsed years. Note that we need a time zone. Time zone is crucial in determining a date. A new day dawns earlier in Paris, for example, than it does in Montréal.
The Period class considers a span of time as a number of years, months and days not tied to any points on the timeline.
The between method uses the "Half-Open" approach common to date-time handling. The beginning is inclusive while the ending is exclusive.
The default formatting of java.time follows the ISO 8601 standard. Apply formatter if you wish a different string representation of your date-time values.
String input = "3.9.1991" ;
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("d.M.yyyy") ;
LocalDate then = LocalDate.parse( input, formatter ) ;
ZoneId zone = ZoneId.of( "America/Montreal" ) ;
LocalDate today = LocalDate.now( zone ) ; // Specify time zone to get your locality’s current date.
Period period = Period.between( then , today ) ;
int years = period.getYears() ;
System.out.println( "Between " + then + " and " + today + " is " + years + " years.");
Between 1991-09-03 and 2015-07-09 is 23 years.
Joda-Time
Android currently lacks Java 8 features. So you cannot use java.time. Unless perhaps the ThreeTen-Backport project (a) supports the classes used in the above example and (b) works on Android (I do not know about either).
Alternatively, you can use Joda-Time, the third-party library that inspired java.time. The Joda-Time code version of the above code example would be very similar. In this case, java.time and Joda-Time parallel one another with similar classes.
Calendar mydate = new GregorianCalendar();
String mystring = "3.9.1991";
Date thedate = new SimpleDateFormat("d.m.yyyy", Locale.ENGLISH).parse(mystring);
mydate.setTime(thedate);
//breakdown
System.out.println("year -> "+mydate.get(Calendar.YEAR));
Reference
This question already has answers here:
Java method to find difference between 2 date objects in years, months and days
(7 answers)
Closed 9 years ago.
I have two dates. Wants to get amount of months between dates DOD and DDO.
Best if I do it in a for loop, increasing the date of every month.
I need all the months, which are between date1 and date2.
For example, when I have a date: d1 = 2013-07-28, d2 = 2013-09-02
I want to get 3 (to July, August and September).
String przekazaneDataOd = "2013-10-26" ;
String przekazaneDataDo = "2014-03-11" ;
SimpleDateFormat dfIn = new SimpleDateFormat("yyyy-MM-dd");
Date d1 = null;
Date d2 = null;
try {
d1=dfIn.parse(przekazaneDataOd);
d2=dfIn.parse(przekazaneDataDo);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
GregorianCalendar DOD = new GregorianCalendar();
DOD.setTime(d1);
GregorianCalendar DDO = new GregorianCalendar();
DDO.setTime(d2);
Date-Time Library
A good date-time library such as:
Joda-Time
New java.time.* JSR 310 classes bundled with Java 8
…makes this kind of work much easier and more reliable.
Joda-Time Example
In Joda-Time 2.3, basically one line of code… Months.monthsBetween( start, stop )
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
// import org.joda.time.format.*;
String przekazaneDataOd = "2013-10-26" ;
String przekazaneDataDo = "2014-03-11" ;
DateTime start = new DateTime( przekazaneDataOd );
DateTime stop = new DateTime( przekazaneDataDo );
// Exclusive of the months of the dates. Just the full months *between* the dates.
Months monthsBetween = Months.monthsBetween( start, stop );
int monthsNumber = monthsBetween.getMonths();
// Inclusive of the months of the dates.
DateTimeZone timeZone_Warsaw = DateTimeZone.forID("Europe/Warsaw" );
// Get first day of the month containing start date.
DateTime outside_begin = new DateTime( przekazaneDataOd, timeZone_Warsaw ).withDayOfMonth( 1 ).withTimeAtStartOfDay();
// Get first day of the month *after* the month containing the stop date.
DateTime outside_end = new DateTime( przekazaneDataDo, timeZone_Warsaw ).plusMonths(1).withDayOfMonth( 1 ).withTimeAtStartOfDay();
int outside_months = Months.monthsBetween( outside_begin, outside_end ).getMonths();
Dump to console…
System.out.println( "start: " + start );
System.out.println( "stop: " + stop );
System.out.println( "monthsNumber: " + monthsNumber );
System.out.println( "outside_begin: " + outside_begin );
System.out.println( "outside_end: " + outside_end );
System.out.println( "outside_months: " + outside_months );
When run…
start: 2013-10-26T00:00:00.000-07:00
stop: 2014-03-11T00:00:00.000-07:00
monthsNumber: 4
outside_begin: 2013-10-01T00:00:00.000+02:00
outside_end: 2014-04-01T00:00:00.000+02:00
outside_months: 6
CAVEAT Generally, a better practice is to always specify a named time zone such as Europe/Warsaw. (Pass a DateTimeZone instance to constructor of DateTime.) But in this case, time zones may not matter, but I'm not sure. Note that in the Inclusive chunk of code, I included a time zone. The zone is Warsaw because The Google says przekazane is Polish.
Try this:
int m = DDO.get(Calendar.MONTH) - DOD.get(Calendar.MONTH);
if(!DOD.before(DDO)) m = -m;
int y = Math.abs(DOD.get(Calendar.YEAR) - DDO.get(Calendar.YEAR));
if(y > 0){
return 12*y+m;
}
else if(y == 1 && m == 0){
return 12;
}
else{
return m;
}
I am getting the current date (in format 12/31/1999 i.e. mm/dd/yyyy) as using the below code:
Textview txtViewData;
txtViewDate.setText("Today is " +
android.text.format.DateFormat.getDateFormat(this).format(new Date()));
and I am having another date in format as: 2010-08-25 (i.e. yyyy/mm/dd) ,
so I want to find the difference between date in number of days, how do I find difference in days?
(In other words, I want to find the difference between CURRENT DATE - yyyy/mm/dd formatted date)
Not really a reliable method, better of using JodaTime
Calendar thatDay = Calendar.getInstance();
thatDay.set(Calendar.DAY_OF_MONTH,25);
thatDay.set(Calendar.MONTH,7); // 0-11 so 1 less
thatDay.set(Calendar.YEAR, 1985);
Calendar today = Calendar.getInstance();
long diff = today.getTimeInMillis() - thatDay.getTimeInMillis(); //result in millis
Here's an approximation...
long days = diff / (24 * 60 * 60 * 1000);
To Parse the date from a string, you could use
String strThatDay = "1985/08/25";
SimpleDateFormat formatter = new SimpleDateFormat("yyyy/MM/dd");
Date d = null;
try {
d = formatter.parse(strThatDay);//catch exception
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Calendar thatDay = Calendar.getInstance();
thatDay.setTime(d); //rest is the same....
Although, since you're sure of the date format...
You Could also do Integer.parseInt() on it's Substrings to obtain their numeric values.
This is NOT my work, found the answer here. did not want a broken link in the future :).
The key is this line for taking daylight setting into account, ref Full Code.
TimeZone.setDefault(TimeZone.getTimeZone("Europe/London"));
or try passing TimeZone as a parameter to daysBetween() and call setTimeZone() in the sDate and eDate objects.
So here it goes:
public static Calendar getDatePart(Date date){
Calendar cal = Calendar.getInstance(); // get calendar instance
cal.setTime(date);
cal.set(Calendar.HOUR_OF_DAY, 0); // set hour to midnight
cal.set(Calendar.MINUTE, 0); // set minute in hour
cal.set(Calendar.SECOND, 0); // set second in minute
cal.set(Calendar.MILLISECOND, 0); // set millisecond in second
return cal; // return the date part
}
getDatePart() taken from here
/**
* This method also assumes endDate >= startDate
**/
public static long daysBetween(Date startDate, Date endDate) {
Calendar sDate = getDatePart(startDate);
Calendar eDate = getDatePart(endDate);
long daysBetween = 0;
while (sDate.before(eDate)) {
sDate.add(Calendar.DAY_OF_MONTH, 1);
daysBetween++;
}
return daysBetween;
}
The Nuances:
Finding the difference between two dates isn't as straightforward as subtracting the two dates and dividing the result by (24 * 60 * 60 * 1000). Infact, its erroneous!
For example: The difference between the two dates 03/24/2007 and 03/25/2007 should be 1 day; However, using the above method, in the UK, you'll get 0 days!
See for yourself (code below). Going the milliseconds way will lead to rounding off errors and they become most evident once you have a little thing like Daylight Savings Time come into the picture.
Full Code:
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.TimeZone;
public class DateTest {
public class DateTest {
static SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yyyy");
public static void main(String[] args) {
TimeZone.setDefault(TimeZone.getTimeZone("Europe/London"));
//diff between these 2 dates should be 1
Date d1 = new Date("01/01/2007 12:00:00");
Date d2 = new Date("01/02/2007 12:00:00");
//diff between these 2 dates should be 1
Date d3 = new Date("03/24/2007 12:00:00");
Date d4 = new Date("03/25/2007 12:00:00");
Calendar cal1 = Calendar.getInstance();cal1.setTime(d1);
Calendar cal2 = Calendar.getInstance();cal2.setTime(d2);
Calendar cal3 = Calendar.getInstance();cal3.setTime(d3);
Calendar cal4 = Calendar.getInstance();cal4.setTime(d4);
printOutput("Manual ", d1, d2, calculateDays(d1, d2));
printOutput("Calendar ", d1, d2, daysBetween(cal1, cal2));
System.out.println("---");
printOutput("Manual ", d3, d4, calculateDays(d3, d4));
printOutput("Calendar ", d3, d4, daysBetween(cal3, cal4));
}
private static void printOutput(String type, Date d1, Date d2, long result) {
System.out.println(type+ "- Days between: " + sdf.format(d1)
+ " and " + sdf.format(d2) + " is: " + result);
}
/** Manual Method - YIELDS INCORRECT RESULTS - DO NOT USE**/
/* This method is used to find the no of days between the given dates */
public static long calculateDays(Date dateEarly, Date dateLater) {
return (dateLater.getTime() - dateEarly.getTime()) / (24 * 60 * 60 * 1000);
}
/** Using Calendar - THE CORRECT WAY**/
public static long daysBetween(Date startDate, Date endDate) {
...
}
OUTPUT:
Manual - Days between: 01-Jan-2007 and 02-Jan-2007 is: 1
Calendar - Days between: 01-Jan-2007 and 02-Jan-2007 is: 1
Manual - Days between: 24-Mar-2007 and 25-Mar-2007 is: 0
Calendar - Days between: 24-Mar-2007 and 25-Mar-2007 is: 1
Most of the answers were good and right for your problem of
so i want to find the difference between date in number of days, how do i find difference in days?
I suggest this very simple and straightforward approach that is guaranteed to give you the correct difference in any time zone:
int difference=
((int)((startDate.getTime()/(24*60*60*1000))
-(int)(endDate.getTime()/(24*60*60*1000))));
And that's it!
Use jodatime API
Days.daysBetween(start.toDateMidnight() , end.toDateMidnight() ).getDays()
where 'start' and 'end' are your DateTime objects. To parse your date Strings into DateTime objects use the parseDateTime method
There is also an android specific JodaTime library.
This fragment accounts for daylight savings time and is O(1).
private final static long MILLISECS_PER_DAY = 24 * 60 * 60 * 1000;
private static long getDateToLong(Date date) {
return Date.UTC(date.getYear(), date.getMonth(), date.getDate(), 0, 0, 0);
}
public static int getSignedDiffInDays(Date beginDate, Date endDate) {
long beginMS = getDateToLong(beginDate);
long endMS = getDateToLong(endDate);
long diff = (endMS - beginMS) / (MILLISECS_PER_DAY);
return (int)diff;
}
public static int getUnsignedDiffInDays(Date beginDate, Date endDate) {
return Math.abs(getSignedDiffInDays(beginDate, endDate));
}
This is Simple and best calculation for me and may be for you.
try {
/// String CurrDate= "10/6/2013";
/// String PrvvDate= "10/7/2013";
Date date1 = null;
Date date2 = null;
SimpleDateFormat df = new SimpleDateFormat("M/dd/yyyy");
date1 = df.parse(CurrDate);
date2 = df.parse(PrvvDate);
long diff = Math.abs(date1.getTime() - date2.getTime());
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.println(diffDays);
} catch (Exception e1) {
System.out.println("exception " + e1);
}
tl;dr
ChronoUnit.DAYS.between(
LocalDate.parse( "1999-12-28" ) ,
LocalDate.parse( "12/31/1999" , DateTimeFormatter.ofPattern( "MM/dd/yyyy" ) )
)
Details
Other answers are outdated. The old date-time classes bundled with the earliest versions of Java have proven to be poorly designed, confusing, and troublesome. Avoid them.
java.time
The Joda-Time project was highly successful as a replacement for those old classes. These classes provided the inspiration for the java.time framework built into Java 8 and later.
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport and further adapted to Android in ThreeTenABP.
LocalDate
The LocalDate class represents a date-only value without time-of-day and without time zone.
Parsing strings
If your input strings are in standard ISO 8601 format, the LocalDate class can directly parse the string.
LocalDate start = LocalDate.parse( "1999-12-28" );
If not in ISO 8601 format, define a formatting pattern with DateTimeFormatter.
String input = "12/31/1999";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( "MM/dd/yyyy" );
LocalDate stop = LocalDate.parse( input , formatter );
Elapsed days via ChronoUnit
Now get a count of days elapsed between that pair of LocalDate objects. The ChronoUnit enum calculates elapsed time.
long totalDays = ChronoUnit.DAYS.between( start , stop ) ;
If you are unfamiliar with Java enums, know they are far more powerful and useful that conventional enums in most other programming languages. See the Enum class doc, the Oracle Tutorial, and Wikipedia to learn more.
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
Where to obtain the java.time classes?
Java SE 8 and SE 9 and later
Built-in.
Part of the standard Java API with a bundled implementation.
Java 9 adds some minor features and fixes.
Java SE 6 and SE 7
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
The ThreeTenABP project adapts ThreeTen-Backport (mentioned above) for Android specifically.
See How to use ThreeTenABP….
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.
The Correct Way from Sam Quest's answer only works if the first date is earlier than the second. Moreover, it will return 1 if the two dates are within a single day.
This is the solution that worked best for me. Just like most other solutions, it would still show incorrect results on two days in a year because of wrong day light saving offset.
private final static long MILLISECS_PER_DAY = 24 * 60 * 60 * 1000;
long calculateDeltaInDays(Calendar a, Calendar b) {
// Optional: avoid cloning objects if it is the same day
if(a.get(Calendar.ERA) == b.get(Calendar.ERA)
&& a.get(Calendar.YEAR) == b.get(Calendar.YEAR)
&& a.get(Calendar.DAY_OF_YEAR) == b.get(Calendar.DAY_OF_YEAR)) {
return 0;
}
Calendar a2 = (Calendar) a.clone();
Calendar b2 = (Calendar) b.clone();
a2.set(Calendar.HOUR_OF_DAY, 0);
a2.set(Calendar.MINUTE, 0);
a2.set(Calendar.SECOND, 0);
a2.set(Calendar.MILLISECOND, 0);
b2.set(Calendar.HOUR_OF_DAY, 0);
b2.set(Calendar.MINUTE, 0);
b2.set(Calendar.SECOND, 0);
b2.set(Calendar.MILLISECOND, 0);
long diff = a2.getTimeInMillis() - b2.getTimeInMillis();
long days = diff / MILLISECS_PER_DAY;
return Math.abs(days);
}
best and easiest way to do this
public int getDays(String begin) throws ParseException {
long MILLIS_PER_DAY = 24 * 60 * 60 * 1000;
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy", Locale.ENGLISH);
long begin = dateFormat.parse(begin).getTime();
long end = new Date().getTime(); // 2nd date want to compare
long diff = (end - begin) / (MILLIS_PER_DAY);
return (int) diff;
}
Use the following functions:
/**
* Returns the number of days between two dates. The time part of the
* days is ignored in this calculation, so 2007-01-01 13:00 and 2007-01-02 05:00
* have one day inbetween.
*/
public static long daysBetween(Date firstDate, Date secondDate) {
// We only use the date part of the given dates
long firstSeconds = truncateToDate(firstDate).getTime()/1000;
long secondSeconds = truncateToDate(secondDate).getTime()/1000;
// Just taking the difference of the millis.
// These will not be exactly multiples of 24*60*60, since there
// might be daylight saving time somewhere inbetween. However, we can
// say that by adding a half day and rounding down afterwards, we always
// get the full days.
long difference = secondSeconds-firstSeconds;
// Adding half a day
if( difference >= 0 ) {
difference += SECONDS_PER_DAY/2; // plus half a day in seconds
} else {
difference -= SECONDS_PER_DAY/2; // minus half a day in seconds
}
// Rounding down to days
difference /= SECONDS_PER_DAY;
return difference;
}
/**
* Truncates a date to the date part alone.
*/
#SuppressWarnings("deprecation")
public static Date truncateToDate(Date d) {
if( d instanceof java.sql.Date ) {
return d; // java.sql.Date is already truncated to date. And raises an
// Exception if we try to set hours, minutes or seconds.
}
d = (Date)d.clone();
d.setHours(0);
d.setMinutes(0);
d.setSeconds(0);
d.setTime(((d.getTime()/1000)*1000));
return d;
}
There's a simple solution, that at least for me, is the only feasible solution.
The problem is that all the answers I see being tossed around - using Joda, or Calendar, or Date, or whatever - only take the amount of milliseconds into consideration. They end up counting the number of 24-hour cycles between two dates, rather than the actual number of days. So something from Jan 1st 11pm to Jan 2nd 1am will return 0 days.
To count the actual number of days between startDate and endDate, simply do:
// Find the sequential day from a date, essentially resetting time to start of the day
long startDay = startDate.getTime() / 1000 / 60 / 60 / 24;
long endDay = endDate.getTime() / 1000 / 60 / 60 / 24;
// Find the difference, duh
long daysBetween = endDay - startDay;
This will return "1" between Jan 2nd and Jan 1st. If you need to count the end day, just add 1 to daysBetween (I needed to do that in my code since I wanted to count the total number of days in the range).
This is somewhat similar to what Daniel has suggested but smaller code I suppose.
All of these solutions suffer from one of two problems. Either the solution isn't perfectly accurate due to rounding errors, leap days and seconds, etc. or you end up looping over the number of days in between your two unknown dates.
This solution solves the first problem, and improves the second by a factor of roughly 365, better if you know what your max range is.
/**
* #param thisDate
* #param thatDate
* #param maxDays
* set to -1 to not set a max
* #returns number of days covered between thisDate and thatDate, inclusive, i.e., counting both
* thisDate and thatDate as an entire day. Will short out if the number of days exceeds
* or meets maxDays
*/
public static int daysCoveredByDates(Date thisDate, Date thatDate, int maxDays) {
//Check inputs
if (thisDate == null || thatDate == null) {
return -1;
}
//Set calendar objects
Calendar startCal = Calendar.getInstance();
Calendar endCal = Calendar.getInstance();
if (thisDate.before(thatDate)) {
startCal.setTime(thisDate);
endCal.setTime(thatDate);
}
else {
startCal.setTime(thatDate);
endCal.setTime(thisDate);
}
//Get years and dates of our times.
int startYear = startCal.get(Calendar.YEAR);
int endYear = endCal.get(Calendar.YEAR);
int startDay = startCal.get(Calendar.DAY_OF_YEAR);
int endDay = endCal.get(Calendar.DAY_OF_YEAR);
//Calculate the number of days between dates. Add up each year going by until we catch up to endDate.
while (startYear < endYear && maxDays >= 0 && endDay - startDay + 1 < maxDays) {
endDay += startCal.getActualMaximum(Calendar.DAY_OF_YEAR); //adds the number of days in the year startDate is currently in
++startYear;
startCal.set(Calendar.YEAR, startYear); //reup the year
}
int days = endDay - startDay + 1;
//Honor the maximum, if set
if (maxDays >= 0) {
days = Math.min(days, maxDays);
}
return days;
}
If you need days between dates (uninclusive of the latter date), just get rid of the + 1 when you see endDay - startDay + 1.
One another way:
public static int numberOfDaysBetweenDates(Calendar fromDay, Calendar toDay) {
fromDay = calendarStartOfDay(fromDay);
toDay = calendarStartOfDay(toDay);
long from = fromDay.getTimeInMillis();
long to = toDay.getTimeInMillis();
return (int) TimeUnit.MILLISECONDS.toDays(to - from);
}
Date userDob = new SimpleDateFormat("yyyy-MM-dd").parse(dob);
Date today = new Date();
long diff = today.getTime() - userDob.getTime();
int numOfDays = (int) (diff / (1000 * 60 * 60 * 24));
int hours = (int) (diff / (1000 * 60 * 60));
int minutes = (int) (diff / (1000 * 60));
int seconds = (int) (diff / (1000));
use these functions
public static int getDateDifference(int previousYear, int previousMonthOfYear, int previousDayOfMonth, int nextYear, int nextMonthOfYear, int nextDayOfMonth, int differenceToCount){
// int differenceToCount = can be any of the following
// Calendar.MILLISECOND;
// Calendar.SECOND;
// Calendar.MINUTE;
// Calendar.HOUR;
// Calendar.DAY_OF_MONTH;
// Calendar.MONTH;
// Calendar.YEAR;
// Calendar.----
Calendar previousDate = Calendar.getInstance();
previousDate.set(Calendar.DAY_OF_MONTH, previousDayOfMonth);
// month is zero indexed so month should be minus 1
previousDate.set(Calendar.MONTH, previousMonthOfYear);
previousDate.set(Calendar.YEAR, previousYear);
Calendar nextDate = Calendar.getInstance();
nextDate.set(Calendar.DAY_OF_MONTH, previousDayOfMonth);
// month is zero indexed so month should be minus 1
nextDate.set(Calendar.MONTH, previousMonthOfYear);
nextDate.set(Calendar.YEAR, previousYear);
return getDateDifference(previousDate,nextDate,differenceToCount);
}
public static int getDateDifference(Calendar previousDate,Calendar nextDate,int differenceToCount){
// int differenceToCount = can be any of the following
// Calendar.MILLISECOND;
// Calendar.SECOND;
// Calendar.MINUTE;
// Calendar.HOUR;
// Calendar.DAY_OF_MONTH;
// Calendar.MONTH;
// Calendar.YEAR;
// Calendar.----
//raise an exception if previous is greater than nextdate.
if(previousDate.compareTo(nextDate)>0){
throw new RuntimeException("Previous Date is later than Nextdate");
}
int difference=0;
while(previousDate.compareTo(nextDate)<=0){
difference++;
previousDate.add(differenceToCount,1);
}
return difference;
}
public void dateDifferenceExample() {
// Set the date for both of the calendar instance
GregorianCalendar calDate = new GregorianCalendar(2012, 10, 02,5,23,43);
GregorianCalendar cal2 = new GregorianCalendar(2015, 04, 02);
// Get the represented date in milliseconds
long millis1 = calDate.getTimeInMillis();
long millis2 = cal2.getTimeInMillis();
// Calculate difference in milliseconds
long diff = millis2 - millis1;
// Calculate difference in seconds
long diffSeconds = diff / 1000;
// Calculate difference in minutes
long diffMinutes = diff / (60 * 1000);
// Calculate difference in hours
long diffHours = diff / (60 * 60 * 1000);
// Calculate difference in days
long diffDays = diff / (24 * 60 * 60 * 1000);
Toast.makeText(getContext(), ""+diffSeconds, Toast.LENGTH_SHORT).show();
}
I found a very easy way to do this and it's what I'm using in my app.
Let's say you have the dates in Time objects (or whatever, we just need the milliseconds):
Time date1 = initializeDate1(); //get the date from somewhere
Time date2 = initializeDate2(); //get the date from somewhere
long millis1 = date1.toMillis(true);
long millis2 = date2.toMillis(true);
long difference = millis2 - millis1 ;
//now get the days from the difference and that's it
long days = TimeUnit.MILLISECONDS.toDays(difference);
//now you can do something like
if(days == 7)
{
//do whatever when there's a week of difference
}
if(days >= 30)
{
//do whatever when it's been a month or more
}
Joda-Time
Best way is to use Joda-Time, the highly successful open-source library you would add to your project.
String date1 = "2015-11-11";
String date2 = "2013-11-11";
DateTimeFormatter formatter = new DateTimeFormat.forPattern("yyyy-MM-dd");
DateTime d1 = formatter.parseDateTime(date1);
DateTime d2 = formatter.parseDateTime(date2);
long diffInMillis = d2.getMillis() - d1.getMillis();
Duration duration = new Duration(d1, d2);
int days = duration.getStandardDays();
int hours = duration.getStandardHours();
int minutes = duration.getStandardMinutes();
If you're using Android Studio, very easy to add joda-time. In your build.gradle (app):
dependencies {
compile 'joda-time:joda-time:2.4'
compile 'joda-time:joda-time:2.4'
compile 'joda-time:joda-time:2.2'
}