This is essentially a duplicate of How to locate the source of JBAS011470 error in JBoss?
But essentially, As soon as I add a second persistence unit, it gives me this error. It's ridiculous. I'm not going to disable the JPA subsystem like some people suggest - that sounds wrong.
My persistence.xml setup is as follows, where java:/NAME is set up as a datasource in standalone.xml:
<?xml version="1.0"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=
"http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="name" transaction-type="JTA">
<jta-data-source>java:/NAME</jta-data-source>
<class>za.co.classes.A</class>
<class>za.co.classes.B</class>
<class>za.co.classes.C</class>
<properties>
<property name="hibernate.transaction.jta.platform"
value="org.hibernate.service.jta.platform.internal.JBossAppServerJtaPlatform"/>
<property name="hibernate.transaction.manager_lookup_class"
value="org.hibernate.transaction.JBossTransactionManagerLookup"/>
<property name="jboss.entity.manager.factory.jndi.name"
value="java:jboss/persistence/NAME" />
<property name="jboss.entity.manager.jndi.name"
value="java:jboss/persistence/em/NAME" />
<property name="hibernate.dialect" value="za.co.equrahealth.dao.SQLServerDialect" />
</properties>
</persistence-unit>
The error starts as soon as I add a second persistence unit. So spring context is irrelevant.
Well, I luckily have multiple databases within the same schema, so I came up with a workaround. But it's obviously not going to solve the problem when there are multiple schemas. I think the cause of this issue might actually be a bug in JBoss.
#PersistenceContext
private EntityManager entityManager;
private EntityManager getEntityManager(String source)
{
if ("a".equalsIgnoreCase(source))
{
entityManager.createNativeQuery("USE A_DB;").executeUpdate();
}
else
{
entityManager.createNativeQuery("USE B_DB").executeUpdate();
}
return entityManager;
}
So here is what i am trying to achieve:
A Java App with JPA implementation usinf Embedded Derby. Once this is working , i am then planning to have Spark (with Jetty Server) and Angular js.
These are the tools/frameworks i am using
Eclipse IDE (Luna)
Maven Build system
JPA Implementation (EclipseLink)
Embedded Derby for database
Spark with Embedded Jetty server.
Angular JS
I have the persistence.xml defined with the Derby Embedded Driver and the db properties.
In the Main class i am using the EntityManger to get the EM. I also create new Instance of the EmbeddedDerby to start the Engine.
But when i run the App, it says "No Persistence provider Persistence for Entity Manager"named testSparkJettyDerby"
Here's my persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="testSparkJettyDerby" transaction-type="RESOURCE_LOCAL">
<class>model.MyUser</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:derby:sample;create=true"/>
<property name="javax.persistence.jdbc.user" value="user"/>
<property name="javax.persistence.jdbc.password" value="xxxx"/>
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.EmbeddedDriver"/>
</properties>
</persistence-unit>
Code snippet in my Main Class
createConnection();
// TODO Auto-generated method stub
factory = Persistence.createEntityManagerFactory(PERSISTENCE_UNIT_NAME);
EntityManager em = factory.createEntityManager();
private static void createConnection()
{
try
{
Class.forName("org.eclipse.persistence.jpa.PersistenceProvider");
Class.forName("org.apache.derby.jdbc.EmbeddedDriver").newInstance();
//Get a connection
conn = DriverManager.getConnection(dbURL);
if(conn != null) {
System.out.println("Connected...");
}
}
catch (Exception except)
{
except.printStackTrace();
}
}
My derby jar files are in the classpath.
I am not sure if this is possible, but i could not find any tutorial or answers who have done something like this.
Any help is appreciated.
Thanks in advance..
Make sure that your persistence.xml file is in classes(or whatever your build dir is)/META-INF.
I created a web app application like my work thesis. This application used the entire stack java EE 6: JPA2, EJB, JSF, RichFaces....
Now i'm trying to change the UI of my application from RichFaces to Vaadin. The first problems began with use of JPA container. i can't get a instance of entitymanager.
this is my persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=" http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="primary">
<jta-data-source>java:jboss/VaadinDS</jta-data-source>
<class>org.mypackage.entity.Utente</class>
<class>org.mypackage.entity.Indirizzo</class>
<class>org.mypackage.entity.Paese</class>
<properties>
<!-- Properties for Hibernate -->
<property name="hibernate.hbm2ddl.auto" value="create" />
<property name="hibernate.show_sql" value="false" />
</properties>
</persistence-unit>
</persistence>
this is my singelton class where i want to get the i instance of entitymanager
public class Utility {
private static EntityManager entityManager;
public Utility() {
// TODO Auto-generated constructor stub
}
public static EntityManager getInstance(){
if(entityManager == null)
entityManager = JPAContainerFactory.createEntityManagerForPersistenceUnit("primary");
return entityManager;
}
}
but doesn't work , i showed always the followed error:
[com.vaadin.server.DefaultErrorHandler] (http-localhost-127.0.0.1-8080-1) : java.lang.NullPointerException
where i wrong?
Your persistence.xml file needs to have a dialect property
Also, you need 2 other things that the book of vaadin explain if you are using hibernate with the jpacontainer: The use of one entity manager per reqeust pattern and the use of hibernate lazy loading delegate on your entity provider. If you need more help, I'll keep updating this answer.
We are using Hibernate at my workplace on some project and I had to modify some queryes recently. I found it really cumbersome to modify a query, run an ant smart or ant refresh and see whether my query works. When I asked one of my colleagues he told me that it is the way we use it.
Do you have any idea how can I speed up this process? I'm looking for a tool which can connect to a database (we are using PGSQL) and run my Hibernate query there and show the results without touching ant.
For example I would be able to try this:
#Query(query = "SELECT DISTINCT l FROM Line l, IN(l.workplaces) w WHERE w.workshop.sid=:wsid", params = "wsid")
JBoss Tools for eclipse has a HQL editor that you can open from the hibernate perspective, you can test hql queries there.
We have a junit-Test for hibernate which uses the derby database as a in-memory databse. This will create the database in derby with all tables and you should be able to execute the query, to see if it is valid.
We have all queries in the orm.xml, so those queries are already checked when creating the EntityManager.
setup
private static EntityManagerFactory emf;
private static EntityManager em;
#BeforeClass
public static void before()
{
emf = Persistence.createEntityManagerFactory("persistenztest");
em = emf.createEntityManager();
}
test
#Test public void test()
{
Query q = em.createQuery(YOUR_QUERY_HERE);
List<?> list = q.getResultList();
}
Persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="persistenztest" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<mapping-file>orm.xml</mapping-file>
<properties>
<property name="hibernate.hbm2ddl.auto" value="create"/>
<property name="hibernate.connection.driver_class" value="org.apache.derby.jdbc.EmbeddedDriver" />
<property name="hibernate.connection.url" value="jdbc:derby:memory:sa;create=true;territory=de_DE;collation=TERRITORY_BASED:SECONDARY;"/>
<property name="hibernate.cache.provider_class" value="org.hibernate.cache.HashtableCacheProvider"/>
<property name="hibernate.cache.use_query_cache" value="false"/>
<property name="hibernate.cglib.use_reflection_optimizer" value="false" />
</properties>
</persistence-unit>
</persistence>
I am new to JPA & Hibernate. After reading some online materials I now understand what Hibernate is and how it can be used with JPA.
Now, I am trying to run this JPA & Hibernate tutorial. I've done everything they mention in this tutorial.
I don't have Oracle DB, only MySQL. So I made some changes to persistence.xml using my understanding of JPA & Hibernate (I don't know if it's correct or not... Seems to me it is.)
Here is my persistence.xml
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemalocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
<persistence-unit name="customerManager" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>Customer</class>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect"/>
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.connection.username" value="root"/>
<property name="hibernate.connection.password" value="1234"/>
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/general"/>
<property name="hibernate.max_fetch_depth" value="3"/>
</properties>
</persistence-unit>
</persistence>
But I don't seem to get the output they describe. It's giving me:
Customer id before creation:null
log4j:WARN No appenders could be found for logger (org.hibernate.cfg.annotations.Version).
log4j:WARN Please initialize the log4j system properly.
Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named customerManager
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:33)
at CustomerDAO.create(CustomerDAO.java:8)
at CustomerDAO.main(CustomerDAO.java:22)
Any suggestions will be appreciated.
Update:
I have made the changes that are asked to done. But, still getting the asme error lines!!!
They didnt mentioned anything about orm.xml in that tutorial. may it be a problem causer!!!
Just for completeness. There is another situation causing this error:
missing META-INF/services/javax.persistence.spi.PersistenceProvider
file.
For Hibernate, it's located in hibernate-entitymanager-XXX.jar, so, if hibernate-entitymanager-XXX.jar is not in your classpath, you will got this error too.
This error message is so misleading, and it costs me hours to get it correct.
See JPA 2.0 using Hibernate as provider - Exception: No Persistence provider for EntityManager.
Your persistence.xml is not valid and the EntityManagerFactory can't get created. It should be:
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemalocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
<persistence-unit name="customerManager" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>Customer</class>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect"/>
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.connection.username" value="root"/>
<property name="hibernate.connection.password" value="1234"/>
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/general"/>
<property name="hibernate.max_fetch_depth" value="3"/>
</properties>
</persistence-unit>
</persistence>
(Note how the <property> elements are closed, they shouldn't be nested)
Update: I went through the tutorial and you will also have to change the Id generation strategy when using MySQL (as MySQL doesn't support sequences). I suggest using the AUTO strategy (defaults to IDENTITY with MySQL). To do so, remove the SequenceGenerator annotation and change the code like this:
#Entity
#Table(name="TAB_CUSTOMER")
public class Customer implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
#Column(name="CUSTOMER_ID", precision=0)
private Long customerId = null;
...
}
This should help.
PS: you should also provide a log4j.properties as suggested.
I had the same problem today. My persistence.xml was in the wrong location. I had to put it in the following path:
project/src/main/resources/META-INF/persistence.xml
I was facing the same issue. I realised that I was using the Wrong provider class in persistence.xml
For Hibernate it should be
<provider>org.hibernate.ejb.HibernatePersistence</provider>
And for EclipseLink it should be
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
If you use Hibernate 5.2.10.Final, you should change
<provider>org.hibernate.ejb.HibernatePersistence</provider>
to
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
in your persistence.xml
According to Hibernate 5.2.2: No Persistence provider for EntityManager
If you are using Maven you may have both src/{main,test}/resources/META-INF/persistence.xml. This is a common setup: test your JPA code with h2 or Derby and deploy it with PostgreSQL or some other full DBMS. If you're using this pattern, do make sure the two files have different unit names, else some versions of the Persistence class will try to load BOTH (because of course your test-time CLASSPATH includes both classes and test-classes); this will cause conflicting definitions of the persistence unit, resulting in the dreaded annoying message that we all hate so much!
Worse: this may "work" with some older versions of e.g., Hibernate, but fail with current versions. Worth getting it right anyway...
A bit too late but I got the same issue and fixed it switching schemalocation into schemaLocation in the persistence.xml file (line 1).
I have seen this error , for me the issue was there was a space in the absolute path of the persistance.xml , removal of the same helped me.
I was also facing the same issue when I was trying to get JPA entity manager configured in Tomcat 8. First I has an issue with the SystemException class not being found and hence the entityManagerFactory was not being created. I removed the hibernate entity manager dependency and then my entityManagerFactory was not able to lookup for the persistence provider. After going thru a lot of research and time got to know that hibernate entity manager is must to lookup for some configuration. Then put back the entity manager jar and then added JTA Api as a dependency and it worked fine.
my experience tells me that missing persistence.xml,will generate the same exception too.
i caught the same error msg today when i tried to run a jar package packed by ant.
when i used jar tvf to check the content of the jar file, i realized that "ant" forgot to pack the persistnece.xml for me.
after I manually repacked the jar file ,the error msg disappered.
so i believe maybe you should try simplely putting META-INF under src directory and placing your persistence.xml there.