Develop Reference

Method to check if the string contains certain elements that accepts a parameter String

I am a student and kind of new to Java. For my homework I have to:
Ask the user to input a number (at least 7) using a do while loop.
Using a for loop I am required to ask the user to input that number of words.
Then I have to check if one of the words fulfills the given conditions:
The word must:
Start with an uppercase letter
End with a number
Contain the word "cse".
I am asked to create a method inside some code homework that does a specific task, the method should check all the required conditions, the name of the method should be countTest and it accepts the String as a parameter.
I will show you my code but I don't know how to create this specific method.
Output format
System.out.println("There as a total number of words " + count + " and
the ones that fulfill the condition are: " + condition);
The problem is, I dont know how to create the method or constructor or whatever it is called that calls all of the 3 methods inside it, and then connect that particular method to the main method!
I hope you guys can understand I am new to this, thank you in advance!
public class D6_6 {
public static void main(String[]args){
Scanner sc = new Scanner(System.in);
System.out.println("Type a number that is at least 7");
int number = sc.nextInt();
int count = 0;
int condition = 0;
do{
if(number<7){
System.out.println("You should type a number that is at least 7 or higher");
number = sc.nextInt();
}
}
while(number<7);
sc.nextLine();
String str;
for(int i =0; i<number; i++){
System.out.println("Type a word");
str = sc.nextLine();
count++;
}
}
public boolean countTest(String str) {
}```

To check if the word start with an uppercase:
You can do that by first selecting the character you want to check by str.charAt(0). This will return a char that is the first letter of the input str.
To check if this char is an uppercase letter, you can easily use char.isUppercase(). This will return a boolean. You have to replace char by the name of the variable were you put the char of str.charAt(0) in.
To check if the last character is a number:
You can do that again by first selecting the last character by str.charAt(str.length()-1), were string.length-1 is the number of the last character.
To check if this character is a number, you can use the ascii table. Every character has it's own number. So if you want to check if your character is between 0 and 9, you can use char >= 48 || char <= 57 (look up in the ascii table). Again, char is the name of the variable were you put the char of str.charAt(str.length()-1) in.
To check if the word contains "cse":
There is a very easy method for that: str.contains("cse") will return a boolean that is true when "cse" is in the word and false when the word does not contain "cse".
I hope it is clear for you now!

I think I did it, thank you guys very much, I appreciate it!
public class D6_6 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Type a number that is at least 7");
int number = sc.nextInt();
int count = 0;
int condition = 0;
do {
if (number < 7) {
System.out.println("You should type a number that is at least 7 or higher");
number = sc.nextInt();
}
}
while (number < 7);
sc.nextLine();
String str;
for (int i = 0; i < number; i++) {
System.out.println("Type a word");
str = sc.nextLine();
count++;
if((countTest(str))){
condition++;
}
}
if(count == 0){
System.out.println("No words typed");
} else {
System.out.println("Total number of words typed: " + count + ", which fulfill the condition: "+ condition);
}
}
public static boolean countTest(String str) {
return Character.isUpperCase(str.charAt(0)) && str.charAt(str.length() - 1) >= 48 || str.charAt(str.length() - 1) <= 57 || str.contains("cse");
}
}```

Counting upper-case characters in array with strings

So i'm trying to count the number of upper-case characters in a array with strings. I'm at a brick wall here. If someone could shed some light on my problem that would be fantastic.
I assume the same loop can be done with just Character.isLowerCase(item) as well right?
After this is completed I also have to tell the user the longest string in the array and how many characters the longest string has as well which I really don't know how to do.
Professor really threw a curve ball at us with this one..
So here's my code so far:
// Program3.java
// Brandin Yoder
// 2/23/18
// Store strings in an array and tell user number of upper-case and lower-case characters,
// and spaces
import java.util.Scanner;
public class Program3
{
public static void main(String[] args)
{
// Set up keyboard.
Scanner keyboard = new Scanner(System.in);
// Input number of strings to store.
System.out.print("Number of strings to input: ");
int nrStrings = keyboard.nextInt();
// Clear keyboard buffer.
keyboard.nextLine();
// Set up array to hold strings.
String[] strings = new String[nrStrings];
// Input strings from keyboard.
System.out.println("\nInput strings:");
for(int ctr = 0; ctr < nrStrings; ctr++)
{
System.out.print("String #" + (ctr+1) + " :");
strings[ctr] = keyboard.next();
}
// Print back strings input.
System.out.println("\nStrings input:");
for(int ctr = 0; ctr < nrStrings; ctr++)
{
System.out.println("String #" + (ctr+1) + ": " + strings[ctr]);
}
// Set up variables for upper-case, lower-case and white space calculator.
int UpperNr = 0;
int LowerNr = 0;
int Spaces = 0;
// For loop that determines amount of Upper-Case numbers.
for(int ctr = 0; ctr < nrStrings; ctr++)
{
char item = strings[ctr].charAt(ctr);
if(Character.isUpperCase(item))
UpperNr++;
}
System.out.println(UpperNr);
}
}

You need to create variables to hold the data that you want to print out at the end. In this case you need to maintain an array that has the number of Uppercases for each string as well as the index and length of the longest string. You have to use a nested for loop to iterate through the array of strings that you have and also the strings themselves in order to check how many Uppercase characters you have. I have modified/commented the last part of your code below.
//array that contains number of uppercase letters in each string
int[] upperAmount = new int[nrStrings];
//index of the longest string
int maxLenIndex = 0;
//length of longest string
int maxLength = 0;
//array that iterates through all the strings in the array strings[]
for(int i = 0; i<strings.length;i++){
//if the new string is the longest
if(strings[i].length() > maxLength){
//set maxlength to the new length and record index of string
maxLength = strings[i].length();
maxLenIndex = i;
}
// For loop that determines amount of Upper-Case numbers.
for(int ctr = 0; ctr < strings[i].length(); ctr++)
{
char item = strings[i].charAt(ctr);
if(Character.isUpperCase(item))
UpperNr++;
}
//add number of uppercases to upperAmount array indexes will be the same
upperAmount[i] = UpperNr;
//reset upper number
UpperNr = 0;
}
// Print back strings input.
System.out.println("\nStrings input:");
for(int ctr = 0; ctr < nrStrings; ctr++)
{
System.out.println("String #" + (ctr+1) + ": " + strings[ctr]);
System.out.println("Number of Uppercase Letters: " + upperAmount[ctr]);
}
System.out.println("MaxStringLength: " + maxLength);
System.out.println("Max String: " + strings[maxLenIndex]);
}

I hope this solves your problem
//after you finish printing the strings
String strMax="";
int ctr=0;
for(String str :strings ){
strMax = str.length()>strMax.length()?str:strMax;
if(!str.equals(str.toLowerCase())){
for(char c : str.toCharArray()){
if(Character.isUpperCase(c))
ctr++;
}
}
}
System.out.println("Longeset String"+strMax );
System.out.println("total Upper case chars" +ctr);

Is it neccesarry to input the count of strings? I think you can accept one whole string and convert it into array of chars
char[] charArray = acceptedString.toCharArray;
Then go throw all chars, and where charArray[n] > 64 && charArray[n] < 91 increase your variable to counting UpperCases. Hope you understand) Ask if you have questions.
Scanner keyboard = new Scanner(System.in);
String inString = keyboard.nextLine();
char[] symbol = inString.toCharArray();
int count =0;
for(int i =0; i < symbol.length; i++){
if(symbol[i] > 64 && symbol[i] < 91){ //cause every char has its own number in Unicode. 'A' = 65 and 'Z' = 90
count++;
}
}
System.out.print(count);

I have to make a tweet tester in java, but can't figure out how to count the amount of times a character shows up in the tweet

Alright, so for a class I am taking I have to make a program that tests tweets. It asks you to input a tweet, then tells you if the tweet is valid (less than 140 characters), tells you the amount of mentions (indicated by the character #) and the number of hashtags (indicated by a #), and tells you whether or not it is a retweet (if it contains "RT:" it is considered a retweet).
I can tell whether it is a valid tweet and can tell if it is a retweet (I coded it so that if the index of "RT:" is greater than or equal to 0, it says it is a retweet), but can't figure out how to count the number of # and # in the string the user enters. I know how to find the index, but am having trouble finding out where to go from there. I don't know what to do as a next course of action. Is there a way to count the amount of a certain character in a string?
I know what the code is currently doing, outputting the index of the first time the character shows up, but I am lost on what else I could do. I thought that maybe I could truncate every letter before and including the # and use a loop to count the amount of times that I get an index for #, then do the same for the #, but I don't know how to truncate every letter before and including a certain character. Or is there a better option? Any help is appreciated
import java.util.Scanner;
import java.lang.Math;
public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter a tweet:");
String s = scan.nextLine();
int length = s.length();
if(length > 140)
System.out.println("Excess Characters: " + ( length - 140));
else{
System.out.println("Length Correct");
int at = s.indexOf('#');
System.out.println("Number of Mentions: " + (at));
int hash = s.indexOf('#');
System.out.println("Number of Hashtags: " + (hash));
if (s.indexOf("RT:") >=0)
System.out.println("The input was a retweet.");
else
System.out.println("The input was not a retweet.");
}}}

.indexOf will return the index of that character in your String.
That might not be the best approach to resolve your problem.
You could do something like this :
for(int i=0; i<s.length(); i++) {
if(s.charAt(i) == '#') {
count++; //or whatever mechanism you want to keep track of those chars.
}
}

Improving slightly on Caleb's answer:
Since you know which two characters you need to count, '#' and '#,' you can have a counter for each and just iterate over the tweet once. Then you just check if a character is one you're looking for, and if it is, the counter is incremented!
int mentions = 0;
int hashtags = 0;
for(int i = 0; i < s.length; i++) {
if(s.charAt(i) == '#') {
mentions++;
} else if(s.charAt(i) == '#') {
hashtags++;
}
}
Now mentions and hashtags should have the countes of #'s and #'s respectively.

You can solve this problem by implementing a simple counting method:
public int charCount(char c, String tweet) {
int count = 0;
for(int i = 0; i < tweet.length()) {
if(tweet.charAt(i) == c) count++;
}
return count;
}
With this, you can count the number of times a character appears in a tweet.
System.out.println("Length Correct");
int at = charCount('#', s);
System.out.println("Number of Mentions: " + at);
int hash = charCount('#', s);
System.out.println("Number of Hashtags: " + hash);
if (s.indexOf("RT:") >= 0)
System.out.println("The input was a retweet.");
else
System.out.println("The input was not a retweet.");

Problems with a word guessing game

I'm trying to get Java to recognize the output of a while loop as a variable and to use that output in further operations.
I wanted to try and upgrade it by letting one player set the word and the other one guess it. The problem came from making the number of dashes equal to the number of letters in the word that the player entered, so I separated the code out, which worked.
But when I put it all back in main, it would not recognize how many dashes are there after the loop finishes; it only recognizes the initial one which is only 1 dash, and so it poses a problem.
EDIT: Thank you so much guys, its my first time on stack overflow, tnx again.
Works like a charm :D
package iB;
import java.util.Scanner;
import java.lang.String;
public class WordGuess {
/**
* #param args
*/
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String secretWord ;
String guess, dash = "-", upWord;
int numGuesses = 0;
int numWord;
final String SENTINEL = "!";
System.out.println("Player 2, please look away. Player 1, please enter the secter word: \n");
secretWord = input.next().toUpperCase().trim();
numWord = secretWord.length();
//System.out.println("\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n");
for(int dashNum = 1; dashNum < numWord; dashNum++) {
dash += "-" ;
}
System.out.println("WordGuess game!\n");
do {
System.out.println("Enter a letter (" + SENTINEL + "to guess entire word): ");
guess = input.next().toUpperCase().trim();
numGuesses ++;
if (secretWord.contains(guess) && guess.length() == 1) {
upWord = dash.substring(0, secretWord.indexOf(guess));
upWord += guess;
upWord += dash.substring(secretWord.indexOf(guess) + 1, dash.length());
dash = upWord.toUpperCase();
System.out.println(dash);
if (dash.equals(secretWord)) {
System.out.println("You won!\n" + "The secret word is " + secretWord);
System.out.println("You made " + numGuesses + " guesses."); }
} else if (guess.length() >= 2) {
System.out.println("Please only enter one letter at a time! \n"); }
if (guess.contains(SENTINEL)) {
System.out.println("What is your guess? ");
guess = input.next().toUpperCase().trim();
if (guess.equals(secretWord)) {
System.out.println("You won!\n" + "The secret word is " + secretWord);
System.out.println("You made " + numGuesses + " guesses.");
break;
} else {
System.out.println("You Lose!");
System.out.println("The secret word was " + secretWord);
System.out.println("You made " + numGuesses + " guesses.");
break;
}
}
} while(!guess.contains(SENTINEL));
input.close();
}
}

The problem
The following piece of code appears to be trying to show where in a word the correctly chosen letter can be found
if (SecretWord.indexOf(guess) >= 0) {
UpWord = dash.substring(0, SecretWord.indexOf(guess));
UpWord += guess;
UpWord += dash.substring(SecretWord.indexOf(guess) + 1, dash.length());
System.out.println(UpWord);
} else {
So if the word was this and you guessed i then the output should be
--i-
dash.substring does not repeat dash, it takes a sub part of dash, as dash is 1 letter long, anything other than substring(0,1) will lead to an exception.
Basic solution
I believe you want to repeat dash until you get to the guessed letter, and then after it till the end of the word. Something along the lines of:
if (SecretWord.indexOf(guess) >= 0) {
int guessedIndex=SecretWord.indexOf(guess);
String outString="";
for(int i=0;i<guessedIndex;i++){
outString+=dash; //repeat dash until we get to the correctly guessed letter
}
outString+=guess; //put the letter in
for(int i=guessedIndex;i<SecretWord.length();i++){
outString+=dash; //repeat dash until we get to end of the word
}
System.out.println(outString);
} else {
Better Solution
This however leaves the problem that only the first instance of the letter is shown. This can be solved using annother stack overflow answer in which we see that we can get all the occurances of a character using a function
public static ArrayList<Integer> getAllIndexes(String testChar, String string){
int index=string.indexOf(testChar);
ArrayList<Integer> indexes=new ArrayList<Integer>();
while(index>0){
indexes.add(index);
index=string.indexOf(testChar,index+1);
}
return indexes;
}
Then using that function to find all the indexes at which the letter occurs we can deal with repeated letters
if (SecretWord.indexOf(guess) >= 0) {
int guessedIndex=SecretWord.indexOf(guess);
ArrayList<Integer> indexes=getAllIndexes(guess,SecretWord);
String outString="";
for(int i=0;i<SecretWord.length();i++){
if (indexes.contains(i)){
outString+=guess; //if its one of the guessed letters, put that in
}else{
outString+=dash; //otherwise add a dash
}
}
System.out.println(outString);
} else {
Now a word of hello and a guess of l correctly outputs --LL-
Notes
It is usual to follow the naming convention that variable names are
in lower camel case, meaning they start with a lower case letter, as
such SecretWord should be secretWord. As it is currently written
it looks like SecretWord is a class, which are usually writen in
upper camel case.
It would be nice, if once you've guessed a letter it stops putting a dash in and starts putting the letter in every time after that, this could be achieved by using an array of booleans to check if the letter has been guessed but that is beyond the scope of this question
All of these solutions have appended strings, which can be slow for huge numbers, in your case this is the right thing to do, but is joining lots of strings together in a loop consider using a StringBuilder to remove the overhead of creating loads of intermediate strings

Solution
If the secret word is pony, the String dash should be equal to ----. The problem is that you never actually change dash from being equal to -. Therefore, when you do things like dash.substring(SecretWord.indexOf(guess) + 1, dash.length()), you get errors because dash only contains one character. Here's how I'd make dash the same length as the secret word:
for(int i = 0; i < NumWord; i++) {
dash += "-";
}
With this one change inserted directly before your do-while loop, your program works like a charm. Below are some other things to consider in order to further improve your program.
Improving readability
Java convention dictates that the first word of method and variable names is lowercase. So NumWord should be numWord, SecretWord should be secretWord, etc.
SecretWord.indexOf(guess) >= 0 should be changed to
SecretWord.contains(guess)
Gameplay suggestions
As in hang man, you should probably show all the spots where the guessed letter occurs. For example, if the secret word is happy, a guess of p should produce the output of --PP- instead of --P--.
As a rule, never accept bad input even if it doesn't cause errors. The program shouldn't allow any of the scenarios below:
A user enters a String containing non-alphabetic characters or multiple words as the secret word
When making guesses, non-alphabetic characters are input (excluding !)
When guessing letters, multiple characters are input.

I have made a couple of modifications to your code, it seems to work fine now.
First though, I added an extra method, just to make it a little easier:
public static String printOutWord(String[] UpWord){
String out = "";
for(int i = 0; i < UpWord.length; i++){
out += UpWord[i];
}
return out;
}
Here are the first few changes to you code:
String[] UpWord = new String[NumWord];
for(int i = 0; i < NumWord; i++){
UpWord[i] = "-";
}
printOutWord(UpWord);
System.out.println("\nWordGuess game!");
So, you no longer need the variable dash, and the variable UpWord has been changed to an array of Strings.
And this is the rest of it:
do {
System.out.println("Enter a letter (! to guess entire word): ");
guess = input.next().toUpperCase().trim();
Numguesses++;
if(guess.length() > 1){
System.out.println("Please only enter one letter at a time");
}else if (SecretWord.indexOf(guess) >= 0) {
int index = SecretWord.indexOf(guess);
UpWord[index] = guess;
while(SecretWord.indexOf(guess, index+1) >= index){
index = SecretWord.indexOf(guess, index+1);
System.out.println(index);
UpWord[index] = guess;
}
System.out.println(printOutWord(UpWord));
if(printOutWord(UpWord).equals(SecretWord)){
System.out.println("You won!\n" + "The secret word is " + SecretWord);
return;
}
} else {
if (guess.contains("!")) {
System.out.println("What is your guess? ");
guess = input.next().toUpperCase();
if (guess.equals(SecretWord)) {
System.out.println("You won!\n" + "The secret word is " + SecretWord);
System.out.println("You made " + Numguesses + " guesses");
} else if (!guess.equals(SecretWord)) {
System.out.println("You Lose!");
System.out.println("You made " + Numguesses + " guesses");
}
}
}
} while (!SecretWord.equals(guess));
input.close();
}
Most of the changes are within the first if statement.
I hope this helped, if any clarification is needed about anything, just ask, I'd be happy to help :)

Can not figure out Javas strings?

I am a student at the moment so I am still learning. I picked up VB pretty quick and it was simple Java on the other hand I am pretty confused on.
The Assignment I have been given this time has me confused "Write a method to determine the number of positions that two strings differ by. For Example,"Peace" and "Piece" differ in two positions. The method is declared int compare(String word1, String word2); if the strings are identical, the method returns 0. It returns -1 if the two strings have different lengths."
Additional "Write a main method to test the method. The main method should tell how many, positions the strings differ, or that they are identical, or if they are different lengths, state the lengths. Get the strings from the console.
So far this is where I am at and I am looking for someone to help break this down in I DUMDUM terms if they can I don't need a solution only help understanding it.
package arraysandstrings;
import java.util.Scanner;
public class differStrings {
public static void main (String agrs[]){
Scanner scanner = new Scanner (System.in);
System.out.print("Enter a word");
String word1;
String word2;
word1 = scanner.next();
System.out.print("Enter another word");
word2 = scanner.next();
int count = 0;
int length = word1.length();
for(int x = 0; x >= length; x = x+1) {
if (word1.charAt(x) == word2.charAt(x)) {
count = count + 1;
System.out.print (count);
}
}
}
}
Additional Question
package arraysandstrings;
import java.util.Scanner;
public class differStrings {
public static void main (String agrs[]){
Scanner scanner = new Scanner (System.in);
System.out.println("Enter a word");
String word1 = scanner.next();
System.out.println("Enter another word");
String word2 = scanner.next();
int count = 0;
int word1Length = word1.length();
int word2Length = word2.length();
if (word1Length != word2Length) {
System.out.println ("Words are a diffrent length");
System.out.println (word1 + "Has" + word1.length() + " chars");
System.out.println (word2 + "Has" + word2.length() + " chars");
}
for(int x = 0; x < word1Length; x = x+1) {
if (word1.charAt(x) != word2.charAt(x)) {
count = count + 1;
}}}
System.out.println (count+" different chars");
}
After implementing the knowledge Iv gained from your responses I have ran in to a problem with the last line:
System.out.println (count+" different chars");
It says Error expected however it worked before I added the next part of my assignment which was this:
if (word1Length != word2Length) {
System.out.println ("Words are a diffrent length");
System.out.println (word1 + "Has" + word1.length() + " chars");
System.out.println (word2 + "Has" + word2.length() + " chars");
}

for(int x = 0; x >= length; x = x+1) {
You probably mean
for(int x = 0; x < length; x = x+1) {

Shifting around some code, adding some line breaks and making 2 small tweaks to the logic produces a program that is closer to what you are trying to build.
package arraysandstrings;
import java.util.Scanner;
public class differStrings {
public static void main (String agrs[]){
Scanner scanner = new Scanner (System.in);
System.out.println("Enter a word");
String word1 = scanner.next();
System.out.println("Enter another word");
String word2 = scanner.next();
int count = 0;
int length = word1.length();
for(int x = 0; x < length; x = x+1) {
if (word1.charAt(x) != word2.charAt(x)) {
count = count + 1;
}
}
System.out.println (count+" different chars");
}
}
It looks like in addition to the for loop that #LouisWasserman pointed out you had code that was trying to find characters that are the same.

What you need is a loop which compares the two strings and counts the places where they are not equal.
Your logic counts the number of places where the two characters are the same. You are also printing the count each time the two characters are equal.
What it sounds like you need is a loop that iterates over the characters in the two strings comparing each character and incrementing the count of mis-matched or different characters. Then after getting a count of different characters by comparing all of the characters, you would print out the count of different characters.
So the basics would be: (1) read each of the strings, (2) check that the lengths are the same, (3) if same length then loop over the string comparing each character and incrementing the count of mis-matched characters each time there is a difference, (4) print out the count. If the string lengths are different then just set the count to negative one (-1) and do not bother to compare the two strings.
What would be kind of neat to do is to create a string of underscores and asterisk, in which each matching character position is represented by an underscore and each mis-matching character position is represented by an asterisk or perhaps the string would contain all of the matching characters and the mis-matching characters would be replaced by an asterisk.
Edit: adding example program
The example below is an annotated rewrite of your program. One change that I made was to use a function to perform the counting of the non-matching characters. The function, countNonMatchChars () is a static function in order to work around the object oriented nature of Java. This function is a utility type function and not really part of a class. It should be available to anyone who wants to use it.
Also rather than incrementing variables with the syntax of var = var + 1; I instead use the postincrement operator of ++ as in var++;.
package arraysandstrings;
import java.util.Scanner;
public class so_strings_main {
// function to compare two strings and count the number
// of characters that do not match.
//
// this function returns an integer indicating the number
// of characters that did not match or a negative one if the
// strings are not equal in length.
//
// "john" "john" returns 0
// "john1" "john2" returns 1
// "mary1" "john1" returns 4
// "john" "john1" returns -1 (lengths are not equal)
public static int countNonMatchChars (String s1, String s2)
{
// initialize the count to negative one indicating strings unequal in length
// get the lengths of the two strings to see if any comparison is needed
int count = -1;
int word1Length = s1.length();
int word2Length = s2.length();
if (word1Length == word2Length) {
// the lengths of the two strings are equal so we now do our comparison
// we start count off at zero. as we find unmatched characters, we
// will increment our count. if no unmatched characters found then
// we will return a count of zero.
count = 0;
for(int iLoop = 0; iLoop < word1Length; iLoop++) {
if (s1.charAt(iLoop) != s2.charAt(iLoop)) {
// the characters at this position in the string do not match
// increment our count of non-matching characters
count++;
}
}
}
// return the count of non-matching characters we have found.
return count;
}
public static void main (String agrs[]){
Scanner scanner = new Scanner (System.in);
System.out.println("Count non-matching characters in two strings.");
System.out.println("Enter first word");
String word1 = scanner.next();
System.out.println("Enter second word");
String word2 = scanner.next();
int count = countNonMatchChars (word1, word2);
if (count < 0) {
System.out.println ("Words are a diffrent length");
System.out.println (" " + word1 + " Has " + word1.length() + " chars");
System.out.println (" " + word2 + " Has " + word2.length() + " chars");
} else {
System.out.println (count + " different chars");
}
}
}