I have String data in which I am interested to extract a substring but I am stuck on creating the regex pattern for that.The String data I have is following:
$.ajax({url:"Q" + "uestions?"
+ "" + "action="
+ "maxim" + "um&"
+ "p043366329446409=08315891235072667&"
+ "c" + "ity="
+ k.val() + "&"
+ e + "=888",success:succFun,error:errFun,async:false});
};
I want to extract p043366329446409=08315891235072667 part from the above string.This data changes everytime I make request to server but "p0" will always start the string and &" will end the string.
Thanks EveryOne.
Try this one:
String mydata = "<query string>";
Pattern pattern = Pattern.compile("p0([0-9]+)=([0-9]+)&");
Matcher matcher = pattern.matcher(mydata);
int start=0,end=0;
if(matcher.find())
{
start=matcher.start();
end=matcher.end();
System.out.println(mydata.substring(start,end-1));
}
try this
String p0 = s.replaceAll(".*&(p0.+?=.+?)&.*", "$1");
Related
Trying to parse out names with given samples
++++++++++++++++++SELIZABETH+COLLAZO+++++++++++++++++++
+++++++++++++++++++PALOMA+CORREA+++++++++++++++++++++++
+++++++++++++++++++NOAH+BLAKEMORE++++++++++++++++++++++
I've tried
//++(.*?)+(.*?)//++
but that's way off.
Would like to parse out the first and last name to two strings.
You can use this regex (\w+)\+(\w+) or \+{2,}(.*?)\+(.*?)\+{2,} with Pattern like this :
String str = "++++++++++++++++++SELIZABETH+COLLAZO+++++++++++++++++++\n"
+ "+++++++++++++++++++PALOMA+CORREA+++++++++++++++++++++++\n"
+ "+++++++++++++++++++NOAH+BLAKEMORE++++++++++++++++++++++";
Pattern pattern = Pattern.compile("(\\w+)\\+(\\w+)");// or instead "\\+{2,}(.*?)\\+"(.*?)\\+{2,}
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
System.out.println(matcher.group(1) + " " + matcher.group(2));
}
Outputs
SELIZABETH COLLAZO
PALOMA CORREA
NOAH BLAKEMORE
I am trying to find and replace in the file using java but unable to get the solution.
File contents are
"ProductCode" = "8:{3E3CDCB6-286C-4B7F-BCA6-D347A4AE37F5}"
"ProductCode" = "8:.NETFramework,Version=v4.5"
I have to update the guid of first one which is 3E3CDCB6-286C-4B7F-BCA6-D347A4AE37F5
String line = "\"ProductCode\" = \"8:{3E3CDCB6-286C-4B7F-BCA6-D347A4AE37F5}\"";
String pattern = "[\"]([P][r][o][d][u][c][t][C][o][d][e]).+([\"])(\\s)[\"][8][:][{]";
Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(line);
System.out.println(m.matches());
I am getting false.
please provide the solution if possible.
Thanks in advance.
"ProductCode" = "8:{3E3CDCB6-286C-4B7F-BCA6-D347A4AE37F5}" This is of the form:
quote + ProductCode + quote + whitespace + equals + whitespace +
quote + number + colon + any + quote
A simple Regex for this is \"ProductCode\"\s*=\s*\"\d:(.+)\"
When we escape this to a Java string we get \\\"ProductCode\\\"\\s*=\\s*\\\"\\d:(.+)\\\"
Try this pattern:
String pattern = "^\\\"(ProductCode)\\\"\\s\\=\\s\\\"\\w\\:\\{(\\w+\\-*\\w+\\-\\w+\\-\\w+\\-\\w+)\\}\\\"$";
Using regex for this problem is like taking a sledgehammer to break a nut. Rather simple:
final String line = "\"ProductCode\" = \"8:{3E3CDCB6-286C-4B7F-BCA6-D347A4AE37F5}\"";
final String prefix = "\"ProductCode\" = \"8:{";
final int prefixIndex = line.indexOf(prefix);
final String suffix = "}\"";
final int suffixIndex = line.indexOf(suffix);
final String guid = line.substring(prefixIndex + prefix.length(), suffixIndex);
I have a string some thing like this:
If message contains sensitive info like: {Password:123456, tmpPwd : tesgjadgj, TEMP_PASSWORD: kfnda}
My pattern should look for the particular words Password or tmpPwd or TEMP_PASSWORD.
How can I create a pattern for this kind of search?
I think you are looking for the values after these words. You need to set capturing groups to extract those values, e.g.
String content = "If message contains sensitive info like: {Password:123456, tmpPwd : tesgjadgj, TEMP_PASSWORD: kfnda} ";
Pattern p = Pattern.compile("\\{Password\\s*:\\s*([^,]+)\\s*,\\s*tmpPwd\\s*:\\s*([^,]+)\\s*,\\s*TEMP_PASSWORD:\\s*([^,]+)\\s*\\}");
Matcher m = p.matcher(content);
while (m.find()) {
System.out.println(m.group(1) + ", " + m.group(2) + ", " + m.group(3));
}
See IDEONE demo
This will output 123456, tesgjadgj, kfnda.
To just find out if there are any of the substrings, use contains method:
System.out.println(content.contains("Password") ||
content.contains("tmpPwd") ||
content.contains("TEMP_PASSWORD"));
See another demo
And if you want a regex-solution for the keywords, here it is:
String str = "If message contains sensitive info like: {Password:123456, tmpPwd : tesgjadgj, TEMP_PASSWORD: kfnda} ";
Pattern ptrn = Pattern.compile("Password|tmpPwd|TEMP_PASSWORD");
Matcher m = ptrn.matcher(str);
while (m.find()) {
System.out.println("Match found: " + m.group(0));
}
See Demo 3
Finally I am using it like as per my requirement .
private final static String censoredWords =
"(?i)PASSWORD|pwd";
The (?i) makes it case-insensitive
I am trying to do a replacement using regex. The relevant piece of code is as follows:
String msg =" <ClientVerificationResult>\n " +
" <VerificationIDCheck>Y</VerificationIDCheck>\n" +
" </ClientVerificationResult>\n";
String regex = "(<VerificationIDCheck>)([Y|N])(</VerificationIDCheck>)";
String replacedMsg= msg.replaceAll(regex, "$2".matches("Y") ? "$1YES$3" : "$1NO$3") ;
System.out.println(replacedMsg);
The output of this is
<ClientVerificationResult>
<VerificationIDCheck>NO</VerificationIDCheck>
</ClientVerificationResult>
When it should be
<ClientVerificationResult>
<VerificationIDCheck>YES</VerificationIDCheck>
</ClientVerificationResult>
I guess the problem is that "$2".matches("Y") is returning false. I have tried doing "$2".equals("Y"); and weird combinations inside matches() like "[Y]" or "([Y])", but still nothing.
If I print "$2" the output is Y. Any hints on what am I doing wrong?
You cannot use Java code as the replacement argument for replaceAll which is supposed to be a string only. Better use Pattern and Matcher APIs and evaluate matcher.group(2) for your replacement logic.
Suggested Code:
String msg =" <ClientVerificationResult>\n " +
" <VerificationIDCheck>Y</VerificationIDCheck>\n" +
" </ClientVerificationResult>\n";
String regex = "(<VerificationIDCheck>)([YN])(</VerificationIDCheck>)";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher( msg );
StringBuffer sb = new StringBuffer();
while (m.find()) {
String repl = m.group(2).matches("Y") ? "YES" : "NO";
m.appendReplacement(sb, m.group(1) + repl + m.group(3));
}
m.appendTail(sb);
System.out.println(sb); // replaced string
You are checking the literal string "$2" to see if it matches "Y". This will never happen.
I'm not new to Java, but have not dealt with Regex and Patterns before. What I'm looking to do is take a string like
"Class: " + data1 + "\nFrom: " + data2 + " To: " + data3 + "\nOccures: " + data4 + " In: " + data5 + " " + data6;
and pull out only data_1 to data_n.
I appreciate any help.
Use this regex:
Pattern pattern = Pattern.compile("Class: (.+?)\nFrom: (.+?) To: (.+?)\nOccures: (.+?) In: (.+?) (.+?)");
Matcher matcher = pattern.matcher(yourInputString);
if (matcher.find())
{
String data1 = matcher.group(1);
String data2 = matcher.group(2);
String data3 = matcher.group(3);
String data4 = matcher.group(4);
String data5 = matcher.group(5);
String data6 = matcher.group(6);
} else
{
// String didn't match the specified format
}
Explanation:
.+? will match any character for undefined times, but non-greedy.
(), using brackets will create a group. A group is given an index starting by 1 (since group 0 is the entire match)
So, (.+?) will creates groups of any character.
And what the matcher does, is searching for the whole pattern somewhere in the input string. But since you specified the format, we know exactly how your entire string is going to look like. The only thing you have to do is copy the format and replace the data you want to extract with "something" (.+?), which you give an index by creating a group of it.
Afterwards, the matcher will try to find the pattern (done by matcher.find()) and you ask them what the content is of the groups 1 up to 6.
how about using split() with ":", then from the splitted String[] get string[2i+1] ? (i from 0)