I need to know which day and day name is on a specific date. And somehow I made a mistake because for years with 19.. it works but at 2000 I can't get the right day anymore. For example if I use the date 9.1.2001 it doesn't say me the day, instead the error of the switch I made occurs.
and i shouldn't use the calendar methods
here is my code:
public class FindDay {
public static void main(String[] args) {
System.out.println("Type a day: ");
int day = In.readInt();
System.out.println("Type a month: ");
int month = In.readInt();
System.out.println("Type a year: ");
int year = In.readInt();
if(day < 1 || day > 32) {
System.out.println("Type valid day");
}else if (month < 1 || month >12) {
System.out.println("Type valid month");
}else if (year < 1900) {
System.out.println("Type valid year");
}
int wholeDaysYear; //to calculate how much days a year has
if (year % 4 == 0 && !(year % 100 == 0 && year % 400 != 0) ) {
wholeDaysYear = 366;
}else {
wholeDaysYear = 365;
}
int monthDays = 0; //calculates days to this month
int february; //if February has 28 or 2 days
if(wholeDaysYear ==366) {
february = 29;
}else {
february = 28;
}
switch(month) {
case 1: monthDays= 0; break;
case 2: monthDays =31; break;
case 3: monthDays= 31+february; break;
case 4: monthDays= 31+february+31; break;
case 5: monthDays= 31+february+31+30; break;
case 6: monthDays= 31+february+31+30+31; break;
case 7: monthDays= 31+february+31+30+31+30; break;
case 8: monthDays= 31+february+31+30+31+30+31; break;
case 9: monthDays= 31+february+31+30+31+30+31+31; break;
case 10: monthDays= 31+february+31+30+31+30+31+31+30; break;
case 11: monthDays= 31+february+31+30+31+30+31+31+30+31; break;
case 12: monthDays= 31+february+31+30+31+30+31+31+30+31+30; break;
default: System.out.println("Enter valid month!");break;
}
int leapYear = ((year-1) / 4 - 474) - ((year-1) / 100 - 18) + ((year-1) / 400 - 4); //calculates the leap years
int allDays =(((year - leapYear)-1900)*wholeDaysYear)+monthDays+day-1; //Calculates all days
System.out.println(allDays);
int dayName = allDays % 7;
String dayNames = null; //gives the days their name
switch (dayName) {
case 1: dayNames = "Monday";break;
case 2: dayNames = "Tuesday";break;
case 3: dayNames = "Wendesday";break;
case 4: dayNames = "Thursday";break;
case 5: dayNames = "Friday";break;
case 6: dayNames = "Saturday";break;
case 7: dayNames = "Sunday";break;
default: System.out.println("Type valid Input");break;
}
System.out.println(dayNames);
}
}
You don't have to work so hard... assuming you have the day of the month, month of the year and full-year, you can simply do (example):
LocalDate ld = LocalDate.of(1999, 12, 12);
System.out.println(ld.getDayOfWeek()); // prints SUNDAY
LocalDate is available since Java 8.
As for your code, two bugs that are easy to spot are:
The cases in the switch go from 1 to 7 while they should go from 0 to 6 since you're calculating the reminder out of 7.
int dayName = allDays % 7; here you assume that the first day of the year is Monday (according to your case switch) which is not necessarily true.
You can try something like this:
Date yourDate;
Calendar cal = Calendar.getInstance();
cal.setTime(yourDate);
int year = cal.get(Calendar.YEAR);
int month = cal.get(Calendar.MONTH);
int day = cal.get(Calendar.DAY_OF_MONTH); //or Calendar.DAY_OF_WEEK
// etc.
How to know how many days has particular month of particular year?
String date = "2010-01-19";
String[] ymd = date.split("-");
int year = Integer.parseInt(ymd[0]);
int month = Integer.parseInt(ymd[1]);
int day = Integer.parseInt(ymd[2]);
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR,year);
calendar.set(Calendar.MONTH,month);
int daysQty = calendar.getDaysNumber(); // Something like this
Java 8 and later
#Warren M. Nocos.
If you are trying to use Java 8's new Date and Time API, you can use java.time.YearMonth class. See Oracle Tutorial.
// Get the number of days in that month
YearMonth yearMonthObject = YearMonth.of(1999, 2);
int daysInMonth = yearMonthObject.lengthOfMonth(); //28
Test: try a month in a leap year:
yearMonthObject = YearMonth.of(2000, 2);
daysInMonth = yearMonthObject.lengthOfMonth(); //29
Java 7 and earlier
Create a calendar, set year and month and use getActualMaximum
int iYear = 1999;
int iMonth = Calendar.FEBRUARY; // 1 (months begin with 0)
int iDay = 1;
// Create a calendar object and set year and month
Calendar mycal = new GregorianCalendar(iYear, iMonth, iDay);
// Get the number of days in that month
int daysInMonth = mycal.getActualMaximum(Calendar.DAY_OF_MONTH); // 28
Test: try a month in a leap year:
mycal = new GregorianCalendar(2000, Calendar.FEBRUARY, 1);
daysInMonth= mycal.getActualMaximum(Calendar.DAY_OF_MONTH); // 29
Code for java.util.Calendar
If you have to use java.util.Calendar, I suspect you want:
int days = calendar.getActualMaximum(Calendar.DAY_OF_MONTH);
Code for Joda Time
Personally, however, I'd suggest using Joda Time instead of java.util.{Calendar, Date} to start with, in which case you could use:
int days = chronology.dayOfMonth().getMaximumValue(date);
Note that rather than parsing the string values individually, it would be better to get whichever date/time API you're using to parse it. In java.util.* you might use SimpleDateFormat; in Joda Time you'd use a DateTimeFormatter.
You can use Calendar.getActualMaximum method:
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month);
int numDays = calendar.getActualMaximum(Calendar.DATE);
java.time.LocalDate
From Java 1.8, you can use the method lengthOfMonth on java.time.LocalDate:
LocalDate date = LocalDate.of(2010, 1, 19);
int days = date.lengthOfMonth();
This is the mathematical way:
For year (e.g. 2012), month (1 to 12):
int daysInMonth = month !== 2 ?
31 - (((month - 1) % 7) % 2) :
28 + (year % 4 == 0 ? 1 : 0) - (year % 100 == 0 ? 1 : 0) + (year % 400 == 0 ? 1 : 0)
if (month == 4 || month == 6 || month == 9 || month == 11) {
daysInMonth = 30;
} else if (month == 2) {
daysInMonth = (leapYear) ? 29 : 28;
else {
daysInMonth = 31;
}
I would go for a solution like this:
int monthNr = getMonth();
final Month monthEnum = Month.of(monthNr);
int daysInMonth;
if (monthNr == 2) {
int year = getYear();
final boolean leapYear = IsoChronology.INSTANCE.isLeapYear(year);
daysInMonth = monthEnum.length(leapYear);
} else {
daysInMonth = monthEnum.maxLength();
}
If the month isn't February (92% of the cases), it depends on the month only and it is more efficient not to involve the year. This way, you don't have to call logic to know whether it is a leap year and you don't need to get the year in 92% of the cases.
And it is still clean and very readable code.
Simple as that,no need to import anything
public static int getMonthDays(int month, int year) {
int daysInMonth ;
if (month == 4 || month == 6 || month == 9 || month == 11) {
daysInMonth = 30;
}
else {
if (month == 2) {
daysInMonth = (year % 4 == 0) ? 29 : 28;
} else {
daysInMonth = 31;
}
}
return daysInMonth;
}
In Java8 you can use get ValueRange from a field of a date.
LocalDateTime dateTime = LocalDateTime.now();
ChronoField chronoField = ChronoField.MONTH_OF_YEAR;
long max = dateTime.range(chronoField).getMaximum();
This allows you to parameterize on the field.
Lets make it as simple if you don't want to hardcode the value of year and month and you want to take the value from current date and time:
Date d = new Date();
String myDate = new SimpleDateFormat("dd/MM/yyyy").format(d);
int iDayFromDate = Integer.parseInt(myDate.substring(0, 2));
int iMonthFromDate = Integer.parseInt(myDate.substring(3, 5));
int iYearfromDate = Integer.parseInt(myDate.substring(6, 10));
YearMonth CurrentYear = YearMonth.of(iYearfromDate, iMonthFromDate);
int lengthOfCurrentMonth = CurrentYear.lengthOfMonth();
System.out.println("Total number of days in current month is " + lengthOfCurrentMonth );
// 1 means Sunday ,2 means Monday .... 7 means Saturday
//month starts with 0 (January)
MonthDisplayHelper monthDisplayHelper = new MonthDisplayHelper(2019,4);
int numbeOfDaysInMonth = monthDisplayHelper.getNumberOfDaysInMonth();
Following method will provide you the no of days in a particular month
public static int getNoOfDaysInAMonth(String date) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
return (cal.getActualMaximum(Calendar.DATE));
}
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
/*
* 44. Return the number of days in a month
* , where month and year are given as input.
*/
public class ex44 {
public static void dateReturn(int m,int y)
{
int m1=m;
int y1=y;
String str=" "+ m1+"-"+y1;
System.out.println(str);
SimpleDateFormat sd=new SimpleDateFormat("MM-yyyy");
try {
Date d=sd.parse(str);
System.out.println(d);
Calendar c=Calendar.getInstance();
c.setTime(d);
System.out.println(c.getActualMaximum(Calendar.DAY_OF_MONTH));
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static void main(String[] args) {
dateReturn(2,2012);
}
}
public class Main {
private static LocalDate local=LocalDate.now();
public static void main(String[] args) {
int month=local.lengthOfMonth();
System.out.println(month);
}
}
The use of outdated Calendar API should be avoided.
In Java8 or higher version, this can be done with YearMonth.
Example code:
int year = 2011;
int month = 2;
YearMonth yearMonth = YearMonth.of(year, month);
int lengthOfMonth = yearMonth.lengthOfMonth();
System.out.println(lengthOfMonth);
You can use Calendar.getActualMaximum method:
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month-1);
int numDays = calendar.getActualMaximum(Calendar.DATE);
And month-1 is Because of month takes its original number of month while in method takes argument as below in Calendar.class
public int getActualMaximum(int field) {
throw new RuntimeException("Stub!");
}
And the (int field) is like as below.
public static final int JANUARY = 0;
public static final int NOVEMBER = 10;
public static final int DECEMBER = 11;
An optimal and performant variance:
public static int daysInMonth(int month, int year) {
if (month != 2) {
return 31 - (month - 1) % 7 % 2;
}
else {
if ((year & 3) == 0 && ((year % 25) != 0 || (year & 15) == 0)) { // leap year
return 29;
} else {
return 28;
}
}
}
For more details on the leap algorithm check here
Number of days in particular year - Java 8+ solution
Year.now().length()
An alternative solution is to use a Calendar object. Get the current date and set the day so it is the first of the month. Then add one month and take away one day to get the last day of the current month. Finally fetch the day to get the number of days in the month.
Calendar today = getInstance(TimeZone.getTimeZone("UTC"));
Calendar currMonthLastDay = getInstance(TimeZone.getTimeZone("UTC"));
currMonthLastDay.clear();
currMonthLastDay.set(YEAR, today.get(YEAR));
currMonthLastDay.set(MONTH, today.get(MONTH));
currMonthLastDay.set(DAY_OF_MONTH, 1);
currMonthLastDay.add(MONTH, 1);
currMonthLastDay.add(DAY_OF_MONTH, -1);
Integer daysInMonth = currMonthLastDay.get(DAY_OF_MONTH);
String MonthOfName = "";
int number_Of_DaysInMonth = 0;
//year,month
numberOfMonth(2018,11); // calling this method to assign values to the variables MonthOfName and number_Of_DaysInMonth
System.out.print("Number Of Days: "+number_Of_DaysInMonth+" name of the month: "+ MonthOfName );
public void numberOfMonth(int year, int month) {
switch (month) {
case 1:
MonthOfName = "January";
number_Of_DaysInMonth = 31;
break;
case 2:
MonthOfName = "February";
if ((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))) {
number_Of_DaysInMonth = 29;
} else {
number_Of_DaysInMonth = 28;
}
break;
case 3:
MonthOfName = "March";
number_Of_DaysInMonth = 31;
break;
case 4:
MonthOfName = "April";
number_Of_DaysInMonth = 30;
break;
case 5:
MonthOfName = "May";
number_Of_DaysInMonth = 31;
break;
case 6:
MonthOfName = "June";
number_Of_DaysInMonth = 30;
break;
case 7:
MonthOfName = "July";
number_Of_DaysInMonth = 31;
break;
case 8:
MonthOfName = "August";
number_Of_DaysInMonth = 31;
break;
case 9:
MonthOfName = "September";
number_Of_DaysInMonth = 30;
break;
case 10:
MonthOfName = "October";
number_Of_DaysInMonth = 31;
break;
case 11:
MonthOfName = "November";
number_Of_DaysInMonth = 30;
break;
case 12:
MonthOfName = "December";
number_Of_DaysInMonth = 31;
}
}
This worked fine for me.
This is a Sample Output
import java.util.*;
public class DaysInMonth {
public static void main(String args []) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a year:");
int year = input.nextInt(); //Moved here to get input after the question is asked
System.out.print("Enter a month:");
int month = input.nextInt(); //Moved here to get input after the question is asked
int days = 0; //changed so that it just initializes the variable to zero
boolean isLeapYear = (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
switch (month) {
case 1:
days = 31;
break;
case 2:
if (isLeapYear)
days = 29;
else
days = 28;
break;
case 3:
days = 31;
break;
case 4:
days = 30;
break;
case 5:
days = 31;
break;
case 6:
days = 30;
break;
case 7:
days = 31;
break;
case 8:
days = 31;
break;
case 9:
days = 30;
break;
case 10:
days = 31;
break;
case 11:
days = 30;
break;
case 12:
days = 31;
break;
default:
String response = "Have a Look at what you've done and try again";
System.out.println(response);
System.exit(0);
}
String response = "There are " + days + " Days in Month " + month + " of Year " + year + ".\n";
System.out.println(response); // new line to show the result to the screen.
}
} //abhinavsthakur00#gmail.com
String date = "11-02-2000";
String[] input = date.split("-");
int day = Integer.valueOf(input[0]);
int month = Integer.valueOf(input[1]);
int year = Integer.valueOf(input[2]);
Calendar cal=Calendar.getInstance();
cal.set(Calendar.YEAR,year);
cal.set(Calendar.MONTH,month-1);
cal.set(Calendar.DATE, day);
//since month number starts from 0 (i.e jan 0, feb 1),
//we are subtracting original month by 1
int days = cal.getActualMaximum(Calendar.DAY_OF_MONTH);
System.out.println(days);
I'm trying to write a program that counts through days of the week when given a number. I want to write this without using Arrays., or enum types, just methods How can I do this? I also want to be able to set a day of the week as starting point.
Thanks
public static void main(String[] args);
{
int sunday, monday, tuesday, wednesday, thursday, friday, saturday;
int week;
int day;
System.out.println(" Day of the week is" + day);
public void count()
public void week()
public void printday()
public void nextday()
public void previousday()
I'm not the best at this, but I figure practice makes perfect
This should do your trick, if i correctly understood your question :)
/**
*
* #param startingDay - day of the week starting point ( need to be between 0-6 )
* #param noDays number of days to count
* #return result Day of the week
*/
private static WeekDays getWeekDay(int startingDay, int noDays){
int dayNr = noDays % 7;
int finalDayNr = (startingDay + dayNr) % 7;
return WeekDays.values()[finalDayNr];
}
private static enum WeekDays {
SUNDAY,
MONDAY,
TUESDAY,
WEDNESDAY,
THURSDAY,
FRIDAY,
SATURDAY
}
And the version with no ENUM, however the Enum version is desirable... from any point of view you might think of.
/**
*
* #param startingDay
* - day of the week starting point ( need to be between 0-6 )
* #param noDays
* number of days to count
* #return result Day of the week
*/
private static String getWeekDay(int startingDay, int noDays) {
int dayNr = noDays % 7;
int finalDayNr = (startingDay + dayNr) % 7;
return getDay(finalDayNr);
}
private static String getDay(int dayNr) {
switch (dayNr) {
case 0:
return "SUNDAY";
case 1:
return "MONDAY";
case 2:
return "TUESDAY";
case 3:
return "WEDNESDAY";
case 4:
return "THURSDAY";
case 5:
return "FRIDAY";
case 6:
return "SATURDAY";
}
throw new IllegalArgumentException("Wrong input. Day nr must be between 0-6.");
}
Usage sample ( for any of the two approach ):
public static void main(String[] args) {
System.out.println(getWeekDay(0, 15));
System.out.println(getWeekDay(1, 15));
System.out.println(getWeekDay(5, 3));
}
This looks like homework, but if you are not going to use arrays of days, I guess you can use a switch statement with the days of the week.
This particular sample iterates from day 3 (0 being Monday) to day 14 included.
for (int i = 3; i < 15; i++) {
String s = null;
switch (i % 7) {
case 0: s = "Monday"; break;
case 1: s = "Tuesday"; break;
case 2: s = "Wednesday"; break;
case 3: s = "Thursday"; break;
case 4: s = "Friday"; break;
case 5: s = "Saturday"; break;
case 6: s = "Sunday"; break;
}
System.out.println(s);
}
public static void main(String[] args) {
int day = 1;
System.out.println(isWeek(day));
printday(day);
}
public static boolean isWeek(int day) {
// Sunday or Saturday
if (day == 1 || day == 7) {
return false;
}
return true;
}
public static void printday(int day) {
switch (day) {
case 1:
System.out.println("Sunday");
break;
case 2:
System.out.println("Monday");
break;
// Until Saturday
default:
break;
}
}
Bad code but without arrays or enums someting like that ?
i am making a program that reads in the month 1-12 and the start day, 1-7 for sunday, monday, etc. it prints the first week fine but im having problems printing the rest of the days after the first week. it wont format the output to have a space between the rest of the days, only the first day after the first week.
side note: Keyboard is a class i have included in my project
heres my code:
import java.io.*;
public class CalendarMonth
{
static final int WEEK = 7;
public static void main(String[] args) throws IOException
{
String proceed;
char repeatCheck;
int days;
String leapYear;
char leapYearCheck;
int startDay;
do
{
days = getDays();
System.out.println(days);
System.out.println("Please enter a number 1-7 that the month starts on: (1 for sunday, 2 for monday, etc)");
startDay = Keyboard.readInt();
while(startDay < 1 || startDay > 7)
{
System.out.println("You did not enter a number 1-7, Try again: ");
startDay = Keyboard.readInt();
}
System.out.println(" s m t w th f sa");
printMonth(days,startDay);
System.out.println("\nWould you like to print another month?");
proceed = Keyboard.readString();
repeatCheck = proceed.charAt(0);
}while(repeatCheck == 'y');
}
public static int getDays() throws IOException
{
int month;
String leapYear;
int startDay;
int days = 0;
char leapYearCheck;
System.out.println("Please input a number 1-12 to print the corresponding month: ");
month = Keyboard.readInt();
while (month < 1 || month > 12)
{
System.out.println("You did not put a number 1-12, Try again: ");
month = Keyboard.readInt();
}
switch(month)
{
case 1: days = 31;
break;
case 2:
System.out.println("is it a leap year? ");
leapYear = Keyboard.readString();
leapYearCheck = leapYear.charAt(0);
while(leapYearCheck != 'y' && leapYearCheck != 'n')
{
System.out.println("you did not enter a yes or no answer, is it a leap year?");
leapYear = Keyboard.readString();
leapYearCheck = leapYear.charAt(0);
}
if (leapYearCheck == 'y')
{
days= 29;
}
else
{
days = 28;
}
break;
case 3: days = 31;
break;
case 4: days = 30;
break;
case 5: days = 31;
break;
case 6: days = 30;
break;
case 7: days = 31;
break;
case 8: days = 31;
break;
case 9: days = 30;
break;
case 10: days = 31;
break;
case 11: days = 30;
break;
case 12: days = 31;
break;
}
return days;
}
public static void printMonth(int days, int startDay)
{
int count;
count = startDay;
for (int counter = 1; counter <= 7; counter++)
{
if (counter < startDay)
{
System.out.print(" ");
count = count-1;
}
else
{
System.out.printf("%2d", count);
count++;
}
}
//int restOfTheMonth = (WEEK - startDay);
System.out.println();
for(int restOfTheMonth = count; restOfTheMonth <= days; restOfTheMonth++)
{
if (restOfTheMonth%WEEK==0)
{
System.out.println();
}
System.out.printf("%2d", restOfTheMonth);
}
}
}
The guidelines for this program follow
Problem B: Year Dates. Objectives: Understanding the Switch structure, helper methods, and using a While loop with a sentinel value.
You are to make a class called Year2012 to manipulate dates when given a month(mm), or a month plus a day(dd) as integer values. It has the following get methods: 1) MonthName which returns a String value that is the name of the Month, e.g. September, June, May, etc. 2) DaysInMonth which returns the number of days in the month. 3)DayOfTheYear which returns the ordinal year date (a number between 1-365, often called the Julian date). Hint, use a for loop to add the days in each prior month, and then add the current month's days. 4) DayOfWeek which returns a String value which is the name of the day, e.g. Monday, Tuesday, etc.
Some of these methods can be used as 'helper' methods for others. All methods will use a switch statement either directly or indirectly. Each method computes a return value from the values sent to it, therefore there are no class attributes, and only a default constructor. All logic must be contained in your own methods. (ie. You will not use existing API classes for your logic.)
Design a tester application that asks the user for a month and day, and then displays the name of the month, the number of days in the month, the day of the week for this date, and the Julian date for this day. Write your program to process dates using a While loop until a sentinel value is entered. Run your program multiple times to test out different days, but turn in a final run using the following five dates: Jan.1, Apr.18, Aug.2, Nov.28, & Dec.15.
I'm having troubles with certain parts of this program. Specifically with the Julian date method and the dayofTheWeek method. Julian date keeps printing out a 1 (I haven't tested many dates), and is a helper method to the dayofTheWeek method, could you take a look at my code and see what my problem is?
public String monthName(int month)
{
String mon = null;
switch (month)
{
case 1:
mon = "January";
break;
case 2:
mon = "February";
break;
case 3:
mon = "March";
break;
case 4:
mon = "April";
break;
case 5:
mon = "May";
break;
case 6:
mon = "June";
break;
case 7:
mon = "July";
break;
case 8:
mon = "August";
break;
case 9:
mon = "September";
break;
case 10:
mon = "October";
break;
case 11:
mon = "November";
break;
case 12:
mon = "December";
break;
default:
mon = "Inccorect entry";
break;
}
return mon;
}
public int daysInMonth(int month)
{
int days = 0;
switch (month)
{
case 1:
days = 31;
break;
case 2:
days = 28;
break;
case 3:
days = 31;
break;
case 4:
days = 30;
break;
case 5:
days = 31;
break;
case 6:
days = 30;
break;
case 7:
days = 31;
break;
case 8:
days = 31;
break;
case 9:
days = 30;
break;
case 10:
days = 31;
break;
case 11:
days = 30;
break;
case 12:
days = 31;
break;
default:
days = 0;
}
return days;
}
public int dayOfTheYear(int month, int day)
{
int julian = 0;
for (int count = 1; count == month; count++)
{
julian += daysInMonth(count);
}
return julian;
}
public String dayOfWeek(int month, int day)
{
int daysSoFar = dayOfTheYear(month, day);
int weekDay = daysSoFar % 7;
String dayName = null;
switch (weekDay)
{
case 1:
dayName = "Sunday";
break;
case 2:
dayName = "Monday";
break;
case 3:
dayName = "Tuesday";
break;
case 4:
dayName = "Wednesday";
break;
case 5:
dayName = "Thursday";
break;
case 6:
dayName = "Friday";
break;
case 7:
dayName = "Saturday";
break;
default:
dayName = "Incorrect entry";
}
return dayName;
}
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
Year2012 year = new Year2012();
System.out.println("Please enter a month using integers (Jan = 1): ");
int month = keyboard.nextInt();
System.out.println("Please enter a day within that month: ");
int day = keyboard.nextInt();
System.out.println("Month: " + year.monthName(month));
System.out.println("Number of days in month: " + year.daysInMonth(month));
System.out.println("Day of the week: " + year.dayOfWeek(month, day));
System.out.println("Julian date: " + year.dayOfTheYear(month, day));
}
}
You got it wrong in the for loop setting the julian value. Try this:
int julian = 0;
for (int count = 1; count < month; count++)
{
julian += daysInMonth(count);
}
return julian + day;
This loop uses count < month instead of count == month. It also returns julian + day.
You have a couple issues in the julian value calculation. Try this:
public int dayOfTheYear(int month, int day)
{
int julian = 0;
for (int count = 1; count < month; count++) //note this loop will not run for Jan(as the logic below will cover that
{
julian += daysInMonth(count);
}
julian += day;
return julian;
}
This loop uses count < month instead of count == month, and then adds the days from the input before returning the answer.
note this loop will not run for Jan as in that case you just want to add the days entered.
Your for loop condition is count == month.
public int dayOfTheYear(int month, int day)
{
int julian = 0;
for (int count = 1; count == month; count++)
{
julian += daysInMonth(count);
}
return julian;
}
This means the loop body will only execute when the month input is 1, and then only once. Did you mean count < month?