Develop Reference

where to store file in android project

I have a file with some data that I want only my application to have access to.
I was wondering in which folder I should put the file in my android project in order to have access to it using
File file = new File(context.getFilesDir(), filename);
Thanks

This is just an empty folder in Android device.
To access your files in assets
InputStream is = getAssets().open("subfolder/anyfile.txt");
to access files inside raw use
InputStream XmlFileInputStream = getResources().openRawResource(R.raw.somesrc);
getFilesDir() is just a folder that uses for openFileOutput(String, int) method. More detailed: https://stackoverflow.com/a/21230946/1979882

Use Assets Folder For files that will be bundled with the application and will be stored inside the apk as is. you can add an "asset" folder to your project by right clicking your app in the project explorer then select
New=> Folder=> Assets Folder.
you can open the files stored in the assets folder using the assets manager for example to open an image kept in /assets/img/image1.png:
InputStream is = assetManager.open("img/image1.png");
for HTML files you can load the file by its URL :
webView.loadUrl("file:///android_asset/"+name);

Here you can get a clear functionality of saving,retrieving a file
Here is the Link:http://www.mysamplecode.com/2012/06/android-internal-external-storage.html

Cannot Construct An Image Object With Relative File Path WIthout Using file: Prefix

I have been trying to create an image object like this:
Image img = new Image("images/jack.png");
or
Image img = new Image("jack.png");
or /jack.png or /images/jack.pngetc.
I have looked up the working directory using System.getProperty("user.dir") and it is indeed where I put my image file. When I use file: prefix, it does work, like so:
Image img = new Image("file:images/jack.png");
However, it is also supposed to work without using it. In the textbook it is done without file:. I've seen other codes that work without it.
At the end of a bunch of chained exceptions, it says:
Caused by: java.lang.IllegalArgumentException: Invalid URL or resource not found
I also tried to read source code from OpenJDK and I could figure anything out because many methods were native and from what I traced I didn't understand how it didn't work. Also, I can create files the same way, I just can't create images. For instance, this works:
File file = new File("fileName.txt");
What causes this problem, what should I do to fix it?
I'm using NetBeans, if that matters.

Note that System.getProperty("user.dir") does not return the working directory. It returns the user directory.
A path relative to the working directory can be specified using a relative file path in the File constructor. However it's bad practice to rely on the working directory. Starting the application from NetBeans results in the working directory being the project directory, but this is not the case, If started in a different way.
Images you need in your application should therefore be added to the jar.
In this case you can retrieve the image URL via Class.getResource(). (convert to String using toExternalForm().)
If you have a File that references a image file, you can use the File instance to get a URL:
File file = ...
String urlString = file.toURI().toURL().toExternalForm();
Those URLs can be used with the Image constructor.
Note that
File file = new File("fileName.txt");
does not create a file. It just represents a file path. This file may or may not exist. Simply invoking the File constructor does not create a new one.

File file = new File("name.txt");
creates a file somewhere. It doesn't read the existing file whereas
Image image = new Image("pathToImage.png");
tries to read the existing image. In order to be able to read an image stored somewhere you need either the absolute path, which requires the protocol (http, file, ftp etc.) or you put your image into the 'known' directory, like the resources dir of your project.
Say, you have your java sources under src/main/java. The resources dir could be src/main/resources. Put your image there and try working with relative path relative to src/main/resources.

Java - read file from directory for jar

I have an application that creates a temporary mp3-file and puts it in a directory like C:\
File tempfile = File.createTempFile("something", ".mp3", new File("C:\\));
I'm able to read it by just using that same tempfile again.
Everything works fine in the Eclipse IDE.
But when I export my project for as a Runnable jar, my files are still being made correctly (I can play them with some normal music player like iTunes) but I can't seem to read them anymore in my application.
I found out that I need to use something like getClass().getResource("/relative/path/in/jar.mp3") for using resource files that are in the jar. But this doesn't seem to work if I want to select a file from a certain location in my file system like C:\something.mp3
Can somebody help me on this one?

It seems you dont have file name of the temp files . When you was running your program in eclipse that instance was creating a processing files, but after you made a runable you are not able to read those file that instance in eclipse created, You runable file can create its own temp file and can process them,
To make temp files globe put there (path + name ) entries in some db or property file
For example of you will create a temp file from the blow code
File tempfile = File.createTempFile("out", ".txt", new File("D:\\"));
FileWriter fstream = new FileWriter(tempfile);//write in file
out = new BufferedWriter(fstream);
the out will not be out.txt file it will be
out6654748541383250156.txt // it mean a randum number will be append with file
and you code in runable jar is no able to find these temp files

getClass().getResource() only reads resources that are on your classpath. The path that is passed to getResource() is, in fact, a path relative to any paths on your current classpath. This sounds a bit confusing, so I'll give an example:
If your classpath includes a directory C:\development\resources, you would be able to load any file under this directory using getResource(). For example, there is a file C:\development\resources\mp3\song.mp3. You could load this file by calling
getClass().getResource("mp3/song.mp3");
Bottom line: if you want to read files using getResource(), you will need those files to be on your classpath.

For loading from both privileged JARs and the file system, I have had to use two different mechanisms:
getClass().getClassLoader().getResource(path), and if that returns null,
new File(path).toURI().toURL();
You could turn this into a ResourceResolver strategy that uses the classpath method and one or more file methods (perhaps using different base paths).

How to access class file in android

I want to acess class file from bin folder in android.
I was doing it using
File f = new File("/bin/filename.class");
Its working fine in java but in android giving path doesnt work, so
please suggest me other way to access class file of any java file in android.

You can't access file like
File f = new File("/bin/filename.class");
from bin folder. Android can't recognize this path.

Java .class files are converted to Dalvik Executable (.dex), in your apk there won't be any .class files, just one single dex file called classes.dex.
I think this post from Android Developers blog might help you: http://android-developers.blogspot.com/2011/07/custom-class-loading-in-dalvik.html

How to scan a file in a different directory in java?

How do you scan a file with java that isn't in the directory the java file is in?
For example: The java file is located at "C:\Files\JavaFiles\test.java" However, the file I want to scan is located at "C:\Data\DataPacket99\data.txt"
Note: I've already tried putting another java file in the "C:\Data" directory and using the test.java file as a class, but it doesn't work. It still tries to scan from the "C:\Files\JavaFiles" Directory.

By using an absolute path instead of a relative.
File file = new File("C:\\Data\\DataPacket99\\data.txt");
Then you can write code that accesses that file object, using a InputStream or similar.

You need to use absolute paths in java.io stuff. Thus not new File("data.txt"), but new File("C:/Data/DataPacket99/data.txt"). Otherwise it will be relative to the current working directory which may not per-se be the same in all environments or the one you'd expect.

You should be using an absolute path instead of a relative path.
You could use File file = new File("C:/Data/DataPacket99/data.txt"); but it might make your life easier in the future to use a file chooser dialog if at any point the user will have to enter a file path.

I would try this:
File file = new File("../../Data/DataPacket99/data.txt");