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Java : Unexpected end of ZLIB input stream while attempting to merge split zip files

I have split zip files that I'm trying to merge using Java. But I get Unexpected end of ZLIB input stream error. Any thoughts on what I'm doing wrong?
File bigZip = new File("bigZip.zip");
List<String> zipList = Arrays.asList("src/14thmayreceipts.zip.001","src/14thmayreceipts.zip.002", "src/14thmayreceipts.zip.003");
Collections.sort(zipList);
ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(bigZip));
for (String entry : zipList) {
readWriteZip(outputStream, entry);
}
outputStream.close();
}
private static void readWriteZip(ZipOutputStream out, String fileName) throws IOException, EOFException {
File file = new File(fileName);
ZipInputStream inStream = new ZipInputStream(new FileInputStream(file));
byte[] buffer = new byte[1024];
int len = 0;
for (ZipEntry e; (e = inStream.getNextEntry()) != null; ) {
out.putNextEntry(e);
while ((len = inStream.read(buffer)) > 0) {
out.write(buffer, 0, len);
}
}
inStream.close();
}

JDK's zip does not support split zip files. And moreover you cannot work with Input/Outpustreams when working with split zip files. And also when merging a split zip files a lot of headers in the zip file have to be updated. zip4j supports such a feature. Sample code:
ZipFile zipFile = new ZipFile("splitZipFileThatHasToBeMerged.zip");
zipFile.mergeSplitZipFiles("mergedOutputZipFile.zip");

Zip Jasper reports [duplicate]

I am trying to create a zip file of multiple image files. I have succeeded in creating the zip file of all the images but somehow all the images have been hanged to 950 bytes. I don't know whats going wrong here and now I can't open the images were compressed into that zip file.
Here is my code. Can anyone let me know what's going here?
String path="c:\\windows\\twain32";
File f=new File(path);
f.mkdir();
File x=new File("e:\\test");
x.mkdir();
byte []b;
String zipFile="e:\\test\\test.zip";
FileOutputStream fout=new FileOutputStream(zipFile);
ZipOutputStream zout=new ZipOutputStream(new BufferedOutputStream(fout));
File []s=f.listFiles();
for(int i=0;i<s.length;i++)
{
b=new byte[(int)s[i].length()];
FileInputStream fin=new FileInputStream(s[i]);
zout.putNextEntry(new ZipEntry(s[i].getName()));
int length;
while((length=fin.read())>0)
{
zout.write(b,0,length);
}
zout.closeEntry();
fin.close();
}
zout.close();

This is my zip function I always use for any file structures:
public static File zip(List<File> files, String filename) {
File zipfile = new File(filename);
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// create the ZIP file
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipfile));
// compress the files
for(int i=0; i<files.size(); i++) {
FileInputStream in = new FileInputStream(files.get(i).getCanonicalName());
// add ZIP entry to output stream
out.putNextEntry(new ZipEntry(files.get(i).getName()));
// transfer bytes from the file to the ZIP file
int len;
while((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
// complete the entry
out.closeEntry();
in.close();
}
// complete the ZIP file
out.close();
return zipfile;
} catch (IOException ex) {
System.err.println(ex.getMessage());
}
return null;
}

Change this:
while((length=fin.read())>0)
to this:
while((length=fin.read(b, 0, 1024))>0)
And set buffer size to 1024 bytes:
b=new byte[1024];

Reading data from multiple zip files and combining them to one

I want to read data from lets say 4 zip files called zip1, zip2, zip3, zip4. All of these zip files are split from this 1 big zip file called "BigZip". I want to combine the zip files into one and then compare the bytes if the 1 bigzip file matches the size of bytes with the combined zip file of (zip1+zip2+zip3+zip4). I am getting a very small file size when I combine the size of 4 zip files. What am I doing wrong?
Here is my code for the same:
targetFilePath1, targetFilePath2, targetFilePath3, targetFilePath4 belongs to path of 4 zip files.
sourceFilePath is the path to BigZip file
class Test {
public static void main(String args[]) {
ZipOutputStream outStream = new ZipOutputStream(new FileOutputStream(sourceBigZip));
readZip(sourceFilePath, targetFilePath1);
readZip(sourceFilePath, targetFilePath2);
readZip(sourceFilePath, targetFilePath3);
readZip(sourceFilePath, targetFilePath4);
outStream.close();
}
static void readZip(String sourceBigZip, String targetFile) throws Exception {
ZipInputStream inStream = new ZipInputStream(new FileInputStream(targetFile));
byte[] buffer = new byte[1024];
int len = inStream.read(buffer);
while (len != -1) {
outStream.write(buffer, 0, len);
len = inStream.read(buffer);
System.out.print(len);
}
inStream.close();
}
}

Create ZipOutputStream once and pass it to readZip() method, like:
public static void main(String args[]) {
ZipOutputStream outStream = new ZipOutputStream(new FileOutputStream(sourceFilePath));
readZip(outStream , targetFilePath1);
readZip(outStream , targetFilePath2);
readZip(outStream , targetFilePath3);
readZip(outStream , targetFilePath4);
}
Then you have an error dealing with copying the data from one zip to another...
You need to copy each file in the zip file like this:
static void readZip(ZipOutputStream outStream, String targetFile)
throws Exception {
ZipInputStream inStream = new ZipInputStream(new FileInputStream(
targetFile));
byte[] buffer = new byte[1024];
int len = 0;
for (ZipEntry e; (e = inStream.getNextEntry()) != null;) {
outStream.putNextEntry(e);
while ((len = inStream.read(buffer)) > 0) {
outStream.write(buffer, 0, len);
}
}
inStream.close();
}
}

Every time you call new ZipOutputStream, it creates a new empty file, and wipes out everything you have written to it before.
You have to create the stream outside of readZip, and pass it in to each call rather than creating a new stream every time.

Copying a file.Finding a path to it

I want to copy file to another directory.I know this has been asked million times,I read tons of answers about this but I just can't seem to make it work.This is the code I am currently using:
copyFile(new File(getClass().getResource("/jars/TurnOffClient.jar").toString()),
new File("C:\\Documents and Settings\\All Users\\Start Menu\\Programs\\Startup\\karioc.jar"));
And this is the method:
public static void copyFile(File sourceFile, File destFile) throws IOException {
if(!destFile.exists()) {
destFile.createNewFile();
}
FileChannel source = null;
FileChannel destination = null;
try {
source = new FileInputStream(sourceFile).getChannel();
destination = new FileOutputStream(destFile).getChannel();
destination.transferFrom(source, 0, source.size());
}
finally {
if(source != null) {
source.close();
}
if(destination != null) {
destination.close();
}
}
}
This is my dir:
Directories http://imageshack.com/a/img820/6418/5g3m.png
//////////////////////////////////////////////////////////////////////////////////////////
And this is the exception I get:

Standard ways to copy a file don't work because you are trying to copy the file out of the JAR. When you get a file out of a JAR, you can't get a File object for it. You can get a URL, and from that an InputStream.
An existing answer includes code to copy data from one input stream to another. Here it is, adapted for the file inside a JAR:
InputStream in = getClass().getResourceAsStream("/jars/TurnOffClient.jar");
OutputStream out = new FileOutputStream(new File("C:\\Documents and Settings\\All Users\\Start Menu\\Programs\\Startup\\karioc.jar"));
// Transfer bytes from in to out
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) != -1) {
out.write(buf, 0, len);
}
in.close();
out.close();

Have you tried using java.nio.Files.copy(); ?
There's built in methods for doing this.
If that doesn't work then go ahead and transfer bytes from a file inputstream to an output file stream.
public void copy(File src, File dst) throws IOException {
InputStream in = new FileInputStream(src);
OutputStream out = new FileOutputStream(dst);
// Transfer bytes from in to out
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
in.close();
out.close();
}
As described here: Standard concise way to copy a file in Java?

Unable to unzip zip file created with java

I have a list of files from different locations. I create a zip file using the following the code which works without error. But when I try to unzip the file in Windows using Extract All it fails seeing unable to find any bytes, yet if I double click into the zip file itself with Windows Explorer I can see the files and individual ones can be opened and contains the correct data
ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(zipFile));
for (File next : files)
{
ZipEntry zipEntry = new ZipEntry(next.getName());
zos.putNextEntry(zipEntry);
FileInputStream in = new FileInputStream(next);
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0)
{
zos.write(buf, 0, len);
}
zos.closeEntry();
in.close();
}
zos.close();

This may or may not be related but I've found using fixed byte length can lead to a loss of new line characters.
This may help:
final byte[] newLine = System.getProperty(
"line.separator").getBytes("UTF-8");
while ((line = in.readLine()) != null)
final byte[] buffer = line.getBytes("UTF-8");
out.write(buffer, 0, buffer.length);
out.write(newLine, 0, newLine.length);
}