Develop Reference

Scan a number of names, print names (number==amount of names) and print Hello to each of them

I am new to Java and have a task: Scanner a number of "strangers' " names, then read these names and print "Hello+name" to the console. If number of strangers is zero, then print "Looks empty", if the number is negative, then print "Looks negative to me".
So the input and output to console should look like this:
3
Den
Ken
Mel
Hello, Den
Hello, Ken
Hello, Mel
So I have this code edited from someone with some related task, but it seems I miss something as I am new to Java...
Scanner input = new Scanner(System.in);
System.out.println("Enter the size of an Array");
int num = input.nextInt();
while (num==0) {
System.out.println("Oh, it looks like there is no one here");
break;
} while (num<0) {
System.out.println("Seriously? Why so negative?");
break;
}
String[] numbers = new String[num];
for (int i=0; i< numbers.length;i++) {
System.out.println("Hello, " +input.nextLine());
}

With using do while loop you can ask the number to the user again and again if it is negative number.
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
int num;
String name;
Scanner scan = new Scanner(System.in);
//The loop asks a number till the number is nonnegative
do{
System.out.print("Please enter the number of strangers: ");
num = scan.nextInt();
if(num<0) {
System.out.println("It cannot be a negative number try again.");
}else if(num==0) {
System.out.println("Oh, it looks like there is no one here");
break;
}else{
String[] strangers = new String[num];
//Takes the names and puts them to the strangers array
for(int i=0;i<num;i++) {
System.out.print("Name " + (i+1) + " : ");
name = scan.next();
strangers[i] = name;
}
//Printing the array
for(int j=0; j<num; j++) {
System.out.println("Hello, " + strangers[j]);
}
break;
}
}while(num<0);
}
}

import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter the size of an Array");
int num = input.nextInt();
if(num==0) {
System.out.println("Oh, it looks like there is no one here");
}
else if(num<0) {
System.out.println("Seriously? Why so negative?");
}
else {
String numbers[] = new String[num];
input.nextLine();
for (int i=0; i< num;i++) {
numbers[i]=input.nextLine();
}
for (int i=0; i< numbers.length;i++) {
System.out.println("Hello, " +numbers[i]);
}
}
}
}
This is how your code will look and you'll need to add member function input.nextLine(); to read newline character, so there can't be problem regarding input

Java Bar Chart Printing Program

here is the question:
Write an application that reads five numbers between 1 and 30. For
each number that’s read, your program should display the same number of adjacent asterisks. For
example, if your program reads the number 7, it should display *******. Display the bars of asterisks
after you read all five numbers.
here is my code:
package Assignment.Q034;
import java.util.Scanner;
public class Q034_trial
{
public static void main (String[] args)
{
Scanner input = new Scanner (System.in);
int num;
num = 1-30;
for (int i = 0; i < 5; i++)// system asks for no more than 5 numbers
{
System.out.printf("Enter a number: ");
num = input.nextInt();
}
for (int j = 0; j < num; j++)
{
System.out.printf("*");
}
System.out.println();
}
}
program IDe used: Apache Netbeans IDE 12.4
the code does not sure any error but when I run and debug it, the output shows like this:
Enter a number: 1
Enter a number: 2
Enter a number: 3
Enter a number: 4
Enter a number: 5
*****
but the output I need is:
Enter a number: 1
Enter a number: 2
Enter a number: 3
Enter a number: 4
Enter a number: 5
*
**
***
****
*****
I am new to java programming. please help me t find the solution.

You can try to break them down individually and try to incorporate an approach like this or use these ideas for your project:
import java.util.Scanner;
public class Array {
public static void main(String[] args){
Array asteriskGenerator = new Array();
int nb[]=new int[5];
Scanner input = new Scanner (System.in);
for(int i=0;i<5;i++)
{
System.out.print("Please, Enter a number between 1 - 30 ");
nb[i]=input.nextInt();
}
input.close();
asteriskGenerator.asteriskGenerator(nb);
}
void asteriskGenerator(int nb[])
{
for(int i = 0; i < nb.length; i++)
{
for(int j=1;j<=nb[i];j++)
{
System.out.print("*");
}
System.out.println();
}
}
}
I hope this helps in what you are trying to accomplish!

You need to read in five integers, and then when you are done, do something with them. This means you need some way to store all five integers.
The obvious solution is to store them in an array.
public class Q034_trial
{
public static void main (String[] args)
{
Scanner input = new Scanner (System.in);
int[] nums = new int[5];
for (int i = 0; i < 5; i++)
{
System.out.printf("Enter a number: ");
int num = input.nextInt();
nums[i] = num;
}
}
}
Having done that you merely need to iterate over each number in the array to print the correct number of asterisks.
public class Q034_trial
{
public static void main (String[] args)
{
Scanner input = new Scanner (System.in);
int[] nums = new int[5];
for (int i = 0; i < 5; i++)
{
System.out.printf("Enter a number: ");
int num = input.nextInt();
nums[i] = num;
}
for (int i = 0; i < 5; i++)
{
for (int j = 0; j < nums[i]; j++)
System.out.printf("*");
System.out.println();
}
}
}

Java how to read a certain Number and display it as a figure

RightTriangle.java: Write code that reads in a number R from the user, and displays a figure with R rows of "$" characters as the following pattern. For instance, if the user enters a 4 for R, your program should display:
$$$$
$$$
$$
$
Heres my code currently.
import java.util.Scanner;
public class RightTriangle {
public static void main(String[] args) {
int R;
Scanner sc = new Scanner(System.in);
System.out.println("Please enter a number: ");
R = sc.nextInt($);
System.out.println(R);
}
}

You could solve this task like so:
import java.util.Scanner;
public class triangle{
public static void main(String[] args){
int R;
Scanner sc = new Scanner(System.in);
System.out.println("Please enter a number: ");
R = sc.nextInt();
int k = R;
for(int i=0; i<R; i++){
for(int j=k; j>0; j--){
System.out.print('$');
}
k = k - 1;
System.out.print('\n');
}
}
}
We use two for loops. The first for loop is used to print a newline after the nested for loop printed the correct amount of $ for that line. Note how we decrease the value of the inner loop counter inside the outer for loop to decrease the amount of $ printed each line.

Use a descending for-loop with the input as the index.
In each iteration, print the $ symbol i times. You could do this using a loop or using another way.
EDIT:
import java.util.Scanner;
public class RightTriangle {
public static void main(String[] args) {
int R;
Scanner sc = new Scanner(System.in);
System.out.println("Please enter a number: ");
R = sc.nextInt(10);
for (int i = R; i >0; i--) {
StringBuilder sb = new StringBuilder();
for (int j = 0; j < i; j++) {
sb.append("$");
}
System.out.println(sb.toString());
}
}
}
A little late, but here it is anyway :)

Console bar graph using loop, without graphics JAVA

Currently working on example from a book loop chapter. Basically, there are 4 car sellers and each should have input how many cars they sold. Below inputs, their names should be printed out and in same line number of cars they sold(from input), but not in numbers, using X or star *. x or star represents that number input.
Here is my code so far. I am stuck on printing that X or star next to a name. It prints out next to wrong name. Any way using loops only without array?
import java.io.*;
public class BarGraphCarSold {
public static void main(String[] args)throws IOException {
BufferedReader buf = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter no of cars Bob sold >> ");
int bobSold = Integer.parseInt(buf.readLine());
System.out.print("Enter no of cars Pam sold >> ");
int pamSold = Integer.parseInt(buf.readLine());
System.out.print("Enter no of cars John sold >> ");
int johnSold = Integer.parseInt(buf.readLine());
System.out.print("Enter no of cars Kim sold >> ");
int kimSold = Integer.parseInt(buf.readLine());
System.out.println();
System.out.println("Car Sales for Month");
System.out.print("Bob \n");
System.out.print("Pam \n");
System.out.print("John \n");
System.out.print("Kim ");
for(int i = 1; i<=bobSold;i++){
System.out.print("X");
}
}
}
OUTPUT
Enter no of cars Bob sold >> 5
Enter no of cars Pam sold >> 7
Enter no of cars John sold >> 4
Enter no of cars Kim sold >> 6
Car Sales for Month
Bob
Pam
John
Kim XXXXX

You are close.
try something like this.
System.out.print("Bob ");
for(int i = 0; i < bobSold; i++){
System.out.print("X");
}
System.out.print("\n");
You are printing out each of the names then have newline (\n) then you try to print the X's. So you will need to print their name then the X's then the new line. You will need a loop like that for each of the names you want to print out with their X's.
There are many different ways to do this. You can have a String with their name then loop through and add the X's to the string then print it all out at one time.
String dealer = "Bob ";
for(int i = 0; i < bobSold; i++){
dealer += "X";
}
dealer += "\n";
System.out.print(dealer);
With Arrays
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) {
BufferedReader buf = new BufferedReader(new InputStreamReader(System.in));
String[] dealers = {"Bob","Pam","John","Kim"};
int[] sales = new int[4];
try {
for(int i=0; i < dealers.length; i++){
System.out.print("Enter number of cars "+dealers[i]+" sold: ");
sales[i] = Integer.parseInt(buf.readLine());
}
}catch(IOException e){
System.err.println("Error Reading input");
System.err.println(e.getMessage());
}
System.out.println();
System.out.println("Car Sales for Month");
for(int i = 0; i < dealers.length; i++) {
System.out.print(dealers[i]+" ");
for(int j = 0; j < sales[i]; j++) {
if(j == (sales[i]-1)) {
System.out.println("X");
}else {
System.out.print("X");
}
}
}
}
}
Have fun. Code On.

You need to print the X's for each person.
System.out.print("Bob - ");
for(int i = 1; i<=bobSold;i++){
System.out.print("X");
}
System.out.print("\nPam - ");
for(int i = 1; i<=pamSold;i++){
System.out.print("X");
}
System.out.print("\nSame - ");
for(int i = 1; i<=samSold;i++){
System.out.print("X");
}
System.out.print("\nKim - ");
for(int i = 1; i<=kimSold;i++){
System.out.print("X");
}

Creating a program that will give the number of A's both lower and upper case in the user entered string (java)

Alright, so here is my dilemma. Unfortunately my Java teacher does not teach how to start the projects in class, nor does he tell us where to find the information to start the program. This is my first programming course, so I'm still trying to learn a few things.
So, lets get to the point, he wants it to look like this:
This program is written by Ben Barcomb
Enter a String: Alaska
Number of A: 3
//End of program
That is it. I just don't know where to start. Any help would be greatly appreciated!
This is what I have right now. The program ends after I enter Alaska.
import java.util.Scanner;
public class P4_BenjaminBarcomb
{
public static void main(String[] args)
{
System.out.println("This program is written by Benjamin Barcomb\n");
Scanner kb = new Scanner(System.in);
int counter = 0;
System.out.print("Enter a String: ");
String word = kb.next();
for (int i = 0; i < word.length(); i++) {
if (word.substring(i, i+1).equalsIgnoreCase("a"))
counter++;
}
}
}

If you loop through the length of the string, you can check to see whether each letter is an "A".
For example,
for (int i = 0; i < s.length(); i++) {
if (s.substring(i, i+1).equalsIgnoreCase("a")) counter++;
}

you can also do like this:
int count=0;
String s ="Alaska";
for(char ch : s.toCharArray()){
if(ch=='A' || ch=='a'){
count++;
}
}
System.out.println("Number of A: "+count);

An example is this:
import java.util.Scanner;
public class Junk {
public static void main(String[] args) {
Scanner Keyboard = new Scanner(System.in);
System.out.print("Enter a String: ");
String str = Keyboard.nextLine();
for (int i = 0; i < str.length(); i++){
if (str.substring(i, i+1).equalsIgnoreCase("a")){
count++;
}
}
System.out.println("Number of A: "+count);