Using Scanner count elements on line - java

If I am using Scanner in Java, how do I count the elements on the line so I know not to process the input if it doesn't have the required elements or continue to next line? All are integers. This is not homework.
Example input:
1 <-- ignore
1 2 3 <-- use this
1 2 <-- ignore

A Little bit late but alternatively, you can also use Scanner#findInLine to implement desired behavior here is a sample i wrote to test your input
Scanner s = new Scanner(new File("text"));
Pattern p = Pattern.compile("^(\\d+) (\\d+) (\\d+)$", Pattern.MULTILINE);
while(s.hasNextLine()){
if(s.findInLine(p)!=null){
//just printing the result. you can do needful here.
MatchResult result = s.match();
System.out.println("full line:" + result.group(0));
System.out.println("individuals");
for (int i=1; i<=result.groupCount(); i++)
System.out.println(result.group(i));
}
s.nextLine();
}
Hope this help someone :)

Read a line at a time, and split it into elements yourself.
while(scanner.hasNextLine())
String line = scanner.nextLine();
String[] elements = line.split(" ");
if(elements.length ==3) {
process(elements);
} else {
// deal with it somehow
}
}
... or with slightly different logic (since it returns null when it's done), you could use a BufferedReader.readLine()

Related

Input multiple lines using hasNextLine() is not working in the way that I expected it to

I'm trying to input multiple lines in java by using hasNextline() in the while loop.
Scanner sc = new Scanner(System.in);
ArrayList<String> lines = new ArrayList<>();
while (sc.hasNextLine()) {
lines.add(sc.nextLine());
System.out.println(lines)
}
The code is inside the main method. But the print method in thewhile loop doesn't print the last line of my input. Also, while loop doesn't seem to break.
What should I do to print whole lines of input and finally break the while loop and end the program?
Since an answer that explains why hasNextLine() might be giving "unexpected" result has been linked / given in a comment, instead of repeating the answer, I'm giving you two examples that might give you "expected" result. Whether any of them suits your needs really depends on what kind of input you need the program to deal with.
Assuming you want the loop to be broken by an empty line:
while (true) {
String curLine = sc.nextLine();
if (curLine.isEmpty())
break;
lines.add(curLine);
System.out.println(curLine);
}
Assuming you want the loop to be broken by two consecutive empty lines:
while (true) {
String curLine = sc.nextLine();
int curSize = lines.size();
String LastLine = curSize > 0 ? lines.get(curSize-1) : "";
if (curLine.isEmpty() && LastLine.isEmpty())
break;
lines.add(curLine);
System.out.println(curLine);
}
// lines.removeIf(e -> e.isEmpty());

Using Scanner and Arrays's to add BigInts

This is a project from school, but i'm only asking for help in the logic on one small part of it. I got most of it figured out.
I'm being given a file with lines of string integers, for example:
1234 123
12 153 23
1234
I am to read each line, compute the sum, and then go to the next one to produce this:
1357
188
1234
I'm stuck on the scanner part.
public static void doTheThing(Scanner input) {
int[] result = new int[MAX_DIGITS];
while(input.hasNextLine()) {
String line = input.nextLine();
Scanner linesc = new Scanner(line);
while(linesc.hasNext()) {
String currentLine = linesc.next();
int[] currentArray = convertArray(stringToArray(currentLine));
result = addInt(result, currentArray);
}
result = new int[MAX_DIGITS];
}
}
In a nutshell, I want to grab each big integer, put it an array of numbers, add them, and then i'll do the rest later.
What this is doing it's basically reading all the lines and adding everything and putting it into a single array.
What i'm stuck on is how do I read each line, add, reset the value to 0, and then read the next line? I've been at this for hours and i'm mind stumped.
Edit 01: I realize now that I should be using another scanner to read each line, but now i'm getting an error that looks like an infinite loop?
Edit 02: Ok, so after more hints and advice, I'm past that error, but now it's doing exactly what the original problem is.
Final Edit: Heh....fixed it. I was forgetting to reset the value to "0" before printing each value. So it makes sense that it was adding all of the values.
Yay....coding is fun....
hasNext method of the Scanner class can be used to check if there is any data available in stream or not. Accordingly, next method used to retrieve next continuous sequence of characters without white space characters. Here use of the hasNext method as condition of if doesn't make any sense as what you want is to check if the there are any numerical data left in the current line. You can use next(String pattern).
In addition, you can try this solution even though it is not optimal solution...
// In a loop
String line = input.nextLine(); //return entire line & descard newline character.
String naw[] = line.split(" "); //split line into sub strings.
/*naw contains numbers of the current line in form of string array.
Now you can perfom your logic after converting string to int.*/
I would also like to mention that it can easily & efficiently be done using java-8 streams.
An easier approach would be to abandon the Scanner altogether, let java.nio.io.Files to the reading for you and then just handle each line:
Files.lines(Paths.get("/path/to/my/file.txt"))
.map(s -> Arrays.stream(s.split("\\s+")).mapToInt(Integer::parseInt).sum())
.forEach(System.out::println);
If i were you i would be using the BufferedReader insted of the Scanner like this:
BufferedReader br = new BufferedReader(new FileReader("path"));
String line = "";
while((line = br.readLine()) != null)
{
int sum = 0;
String[] arr = line.split(" ");
for(String num : arr)
{
sum += Integer.parseInt(num);
}
System.out.println(sum);
}
Considering the level you're on, I think you should consider this solution. By using only the scanner, you can split the lines into an array of tokens, then iterate and sum the tokens by parsing them and validating that they're not empty.
import java.util.*;
class SumLines {
public static void main(String[] args) {
Scanner S = new Scanner(System.in);
while(S.hasNext()) {
String[] tokens = S.nextLine().split(" ");
int sum = 0;
for(int i = 0; i < tokens.length; i++) {
if(!tokens[i].equals("")) sum += Integer.parseInt(tokens[i]);
}
System.out.println(sum);
}
}
}

Is there a way around not advancing a line with Scanner (Java)

Okay so I'm having a slight problem with scanner advancing an extra line. I have a file that has many lines containing integers each separated by one space. Somewhere in the file there is a line with no integers and just the word "done".
When done is found we exit the loop and print out the largest prime integer that is less than each given integer in each line(if integer is already prime do nothing to it). We do this all the way up until the line with "done".
My problem: lets say the file contains 6 lines and on the 6th line is the word done. My output would skip lines 1, 3 and 5. It would only return the correct values for line 2 and 4.
Here's a snippet of code where I read the values in:
Scanner in = new Scanner(
new InputStreamReader(socket.getInputStream()));
PrintStream out = new PrintStream(socket.getOutputStream());
while(in.nextLine() != "done"){
String[] arr = in.nextLine().split(" ");
Now I sense the problem is that the nextLine call in my loop advances the line and then the nextline.split call also advances the line. Thus, all odd number lines will be lost. Would there be another way to check for "done" without advancing a line or is there a possible command I could call to somehow reset the scanner back to the start of the loop?
The problem is you have 2 calls to nextLine() try something like this
String line = in.nextLine();
while (!"done".equals(line)) {
String[] arr = line.split(" ");
// Process the line
if (!in.hasNextLine()) {
// Error reached end of file without finding done
}
line = in.nextLine();
}
Also note I fixed the check for "done" you should be using equals().
I think you are looking for this
while(in.hasNextLine()){
String str = in.nextLine();
if(str.trim().equals("done"){
break;
}else{
String[] arr = str.split("\\s+");
//then do whatever you want to do
}
}

How to pull int value from text file of strings and ints?

I'm trying to write a program that is practically a stack. Given a text file with certain keywords, I want my program to evaluate the text line by line and perform the requested action to the stack.
For example, if the input file is:
push 10
push 20
push 30
The resulting stack should look like:
30
20
10
However, I don't know how to push these values into the stack without hardcoding an int value after the word push. I made a String variable and assigned it to scanner.nextLine()
From there, I compare the line with strLine: if strLine is equal to push followed by some Number, then that number would be pushed on the stack.
However, it seems that the method nextInt() isn't taking this number from the input stream.
Scanner input = new Scanner(file)
int number;
String strLine;
while (input.hasNextLine()){
strLine = input.nextLine();
number = input.nextInt();
if(strLine.equals("push " + number)){
stack.push(number);
}
How can I fix this?
Thank you.
Get the input and split it with space " "!
That will give ["push","1"]
convert the first index to int and then push the value to stack!
while (input.hasNextLine()){
String[] strLine = input.nextLine().split(" ");
if(strLine[0].equals("push")){
stack.push(Integer.parseInt(strLine[1]));
}
else if(strLine[0].equals("pop")){
stack.pop();
}
else{
system.out.println("Please enter a valid input!");
}
}
Hope it helps!
input.nextLine reads the whole line, including the number. What you can do instead is to use input.next() to get the "push" and input.nextInt() to get the number. This example is using Scanner with System.in (so it needs "quit" to exit the while loop), but it should also work with a file (in which case you don't need to type "quit" to exit the program, as it will do so automatically when the input file has no more input). The advantage of using parseInt (as some of the other answers have suggested) is that you can catch any errors in integer input using a try/catch block.
import java.util.Scanner;
import java.util.Stack;
import java.util.InputMismatchException;
public class StackScanner {
public static void main(String args[]) {
Stack<Integer> stack = new Stack<Integer>();
Scanner input = new Scanner(System.in);
int number;
String strLine;
while (input.hasNext()){
strLine = input.next();
if(strLine.equals("push")){
try {
number = input.nextInt();
stack.push(number);
} catch ( InputMismatchException e) {
System.out.println("Invalid input. Try again.");
input.nextLine();
continue;
}
} else {
break;
}
}
System.out.println(stack);
}
}
Sample output:
push 5
push 6
push 3
quit
[5, 6, 3]
change this:
number = input.nextInt();
to this:
number = Integer.parseInt(input.nextLine());
nextLine method parses the whole line including any numbers in the line. So, you need to take care of splitting the line and parsing the number in your code.
Something like below will work where I split the line with spaces. Although, there are many such ways possible.
Scanner input = new Scanner(file);
String strLine;
Stack<Integer> stack = new Stack<>();
int number;
while (input.hasNextLine()){
strLine = input.nextLine();
if(strLine.startsWith("push")){
String[] sArr = strLine.split("\\s+");
System.out.println(strLine);
if(sArr.length==2){
number=Integer.parseInt(sArr[1]);
stack.push(number);
System.out.println(number);
}
}
}
If I understand your problem, I would simply tokenize the line by splitting on whitespace.
It looks like your input is relatively structured: you have a keyword of some kind then whitespace then a number. If your data is indeed of this structure, split the line into two tokens. Read the value from the second one. For example:
String tokens[] = strLine.split(" ");
// tokens[0] is the keyword, tokens[1] is the value
if(tokens[0].equals("push")){
// TODO: check here that tokens[1] is an int
stack.push(Integer.parseInt(tokens[1]));
} else if (tokens[0].equals("pop")) { // maybe you also have pop
int p = stack.pop();
} else if ... // maybe you have other operations

Not able to find out the number of Sentences in a File

I am writing a code to find out the number of sentences in a file.
My code is as :
try{
int count =0;
FileInputStream f1i = new FileInputStream(s);
Scanner sc = new Scanner(f1i);
while(sc.hasNextLine()){
String g = sc.nextLine();
if(g.indexOf(".")!= -1)
count++;
sc.nextLine();
}
System.out.println("The number of sentences are :"+count);
}
catch(Exception e) {
System.out.println(e);
}
I guess my logic is right to check for the number of periods. I wrote the above code which i think is right but it displays a javautilNoElementfound : No line foundexception . I tried some other logics but this one was the best understandable. But i am stuck here. I used google on that exception and it says that it is thrown when we iterate over something that has no element.But my file contains data. Is there some way this exception could have made way?? Or is there some other error? Hints are appreciated ! Thanks
You are calling sc.nextLine() two times inside the while loop that is why the error occurs.
Also your logic doesn't account for cases when there are 2 sentences on the same line.
You can try something like this:
int sentencesPerLine = g.split(".").length;
The loop should be:
while(sc.hasNextLine()){
String g = sc.nextLine();
if(g.indexOf('.')!= -1){//check if the line contains a '.' character
count += g.split("\\.").length; // split the line into an array of Strings using '.' as a delimiter
}
}
In the split(...) method I'm using "\\." instead of "." because . is a regex element and needs to be escaped.

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