Develop Reference

Android SimpleDateFormat always returns wrong week day

I have the following code:
String s = "08-12-2014 05:00:00"
SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.ENGLISH);
SimpleDateFormat outputFormat = new SimpleDateFormat("EEEE, HH:mm a");
Date oneWayTripDate = null;
try {
oneWayTripDate = inputFormat.parse(s);
} catch (ParseException e) {
e.printStackTrace();
}
String datetime = outputFormat.format(oneWayTripDate);
but for some weird reason it always returns the wrong day of the week. what am i doing wrong?

The input SimpleDateFormat pattern is wrong. Given the date 08-12-2014 05:00:00 with the year part at the end, and assuming 08 is the month, the format should be:
SimpleDateFormat inputFormat = new SimpleDateFormat("MM-dd-yyyy HH:mm:ss", Locale.ENGLISH);
See the Javadoc of SimpleDateFormat for how to define date patterns.

java.text.parseException:unparsable date

i am getting this error while i am trying to convert a string into date.
unparasable data
Below is my code:-
String str = "hello"

Second is missing at your parse String str. So, to parse it you should not include second format at SimpleDateFormat pattern. Also correct the day and Month format. Look at the declaration of df
SimpleDateFormat df = new SimpleDateFormat("dd-MMM-yyyy hh:mm a");//Remove :ss
To know details of pattern, go through this docs.
Edit
String date2 = sdformatter.format(date1);// format method return String.
//Should declare with String
Full Code
String str = "25-Nov-2013 06:00 AM";
SimpleDateFormat df = new SimpleDateFormat("dd-MMM-yyyy hh:mm a");//Remove :ss
SimpleDateFormat sdformatter = new SimpleDateFormat("MM-dd-yyyy hh:mm:ss a");
Date date1=null;
try {
date1 = df.parse(str);
} catch (ParseException ex) {
ex.printStackTrace();
}
String date2 = sdformatter.format(date1);
System.out.println(date2);

According to str format you should write your SimpleDateFormat,
(25-Nov-2013 06:00 AM ---> dd-MMM-yyyy hh:mm a) and for
(25-Nov-2013 06:00:30 AM-----> dd-MMM-yyyy hh:mm:ss a)
will work

Try this
long newerdate = new Date().parse("25-Nov-2013 06:30 AM");
java.text.SimpleDateFormat df = new java.text.SimpleDateFormat("dd-MM-yyyy hh:mm a");
String data = df.format(newerdate);
System.out.println(data);

SimpleDateFormat - Unparseable?

Take a look at my code:
try {
// String date = "30Jul2013";
SimpleDateFormat sdf = new SimpleDateFormat("ddMMMyyyy", Locale.ENGLISH);
Date d = sdf.parse(date);
SimpleDateFormat nsdf = new SimpleDateFormat("MMMM dd, yyyy h:mm a", Locale.ENGLISH);
String nd = nsdf.format(d);
System.out.println(nd);
return nd;
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Im am getting a error:
java.text.ParseException: Unparseable date: "2013-07-30 10:58:55.171"
at java.text.DateFormat.parse(DateFormat.java:337)
I would like to have an output of July 30, 2013 11:10 AM from the simpledateformat. There's LOCALE in my code. So what else should I do?
Thanks in advance!

try {
// String date = "30Jul2013";
SimpleDateFormat sdf = new SimpleDateFormat("ddMMMyyyy", Locale.ENGLISH);
Date d = sdf.parse(date);
Your date String variable line is commented out, so who's to know what String you're parsing? -- the JVM that's who.
As Robert Harvey points out, the String that you're actually trying to parse is printed for you in the exception message. If you print that String before you parse you'll also see that it's not what you expect it is and that the compiler's right.
In sum, you are somehow expecting that your sdf SimpleDateFormat object is formatting a String of a format similar to "30Jul2013", but the JVM is telling you that this simply is not so, that the String you are trying to parse in fact looks nothing like this, but rather is "2013-07-30 10:58:55.171".

Date format issue in android

In android
am getting date in
(date = "04-01-2013") this format
but i want to show same date in
en.US format like (date="Friday,January 04,2013")

use SimpleDateFormat.
set input pattern matching input date string: "04-01-2013" -> "dd-MM-yyyy".
And output pattern like output: "Friday, January 04, 2013" -> "EEEE, MMMM dd, yyyy"
public String formatDate(String input){
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
Date d = sdf.parse(input);
sdf.applyPattern("EEEE, MMMM dd, yyyy");
return sdf.format(d,new StringBuffer(),0).toString();
}

try {
DateFormat df1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
DateFormat df2 = new SimpleDateFormat("dd-MMM-yyyy");
return df2.format(df1.parse(input));
}
catch (ParseException e) {
return null;
}

You can use something like this
android.text.format.DateFormat.format("EEEE, MMMM dd, yyyy", new java.util.Date());
Take a look at DateFormat.

This is how you do it in java
SimpleDateFormat df=new SimpleDateFormat("EEEE,MMMM dd,yyyy");
java.util.Date date=df.parse("04-01-2013");
refer this

DateTime formatter

I am developing an application and I am stuck in converting string like 01/01/2037 01:00:00 AM
to Date
I used
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy hh.mm.ss.S aa")
Date d = dateFormat.parse(dateString);
but I get an error, any help will be appreciated.

you are converting this 01/01/2037 01:00:00 AM
therefore use
SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss aa")
(more info in [documentation])1
then
Date date = dateFormat.parse("01/01/2037 01:00:00 AM");
keep in mind you have to wrap a try-catch around the parse method.

The problem is that the format you declared is nothing like the String you are trying to parse:
your String uses / to separate day, month, year while in your formatter you use -
your string separates hours with a dot, while in the formatter you use :
you do not have milliseconds in your string while you declared them in the formatter.
The following code should work:
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy hh.mm.ss.S aa");
try {
Date date = dateFormat.parse("01-01-2037 01.00.00.000 AM");
System.out.println(date);
} catch (ParseException e) {
e.printStackTrace();
}