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I need to display a error Message.I have declared a counter.Whenever the counter is 3 it has to display a different error message.So i have written the below snippet.
It returns error: <identifier> expected on the declaration.
//declaration
private static attempts = 0;
//operation
switch (xmlRpcFault.getFaultCode()) {
case 403:
attempts++;
if(attempts = 3)
{
mErrorMsgId = R.string.username_or_password_incorrect;
//reinitialize counter
attempts = 0;
}
else
mErrorMsgId = R.string.username_or_password_incorrectfull;
break;
The statement:
if(attempts = 3)
probably should be:
if (attempts == 3)
?
The source of the error you asked about is that you need to specify the actual type of the variable in your declaration. You have:
//declaration
private static attempts = 0;
You probably mean:
//declaration
private static int attempts = 0;
Note the int (or whatever type you want it to be).
Also, the issue that Harmlezz mentions (attempts = 3 vs. attempts == 3) is another problem.
As an aside: Most of the code you posted, as well as the question you asked, was irrelevant. The correct code to post would have been only the line with the compiler error. The correct question is "why does 'private static attempts = 0' cause a compiler error". Even the tags: This was not an Android question, or a question about while loops or if statements or counters. I mention this constructively: Think about the problem at hand, and try narrowing it down. It's a general thought process that will help you in all cases.
Granted, by posting all of it, it let us spot a few other issues, but that was incidental; your general problem solving thought-process did not match the problem itself.
Question titles are a good window into a person's thought process; in general, you can learn a lot by reexamining your question titles here after your problem is solved.
Related
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I am in my first semester of a Java Course. I am struggling to understand how I put exclusiveness on a statement. I am writing a Class for an Object Couch. I have tried to build a well formed class, but for the outcome from my main, in the console it must only have 4 or 8 legs on the couch. There is no user input as I am hard coding the variables, but I want to be sure that if I hard code for 5 legs it will stop me or an error message will pop up. Any suggestions?
public void setNbrLegs(int nbrLegs){
if ((nbrLegs == 2) || (nbrLegs == 4)){
this.nbrLegs = nbrLegs;
}
}
I tried putting an "else" with a message that that number is bad, but what is did was bypass my error message and just insert the incorrect number ofLegs as 5.
Consider looking for the opposite: a condition where you must fail. From there, you can use runtime exceptions to ensure a few things:
The invalid state is not applied
A developer passing this invalid state will get an exception, and have a clear reason to fix their code
You no longer have to worry about invalid state further on in the method (i.e. legs will only be 2 or 4 further on).
In doing so, your method may end up looking like this:
public void setNbrLegs(int legs) {
if (legs != 4 && legs != 2) {
throw new IllegalArgumentException("Can only have 2 or 4 legs");
}
this.nbrLegs = legs;
}
This preconditional checking is also good to do early in your methods (fast-fail), as it will prevent excess work being done for a method that will only "fail".
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I have this sample from my project and I need to know why the result is what it is.
public class Main
{
public static void main(String[] args)
{
//url: https://classicpartyrentals.com/products/24681-gothic-silver-coffee-cup, websiteList: http://classicpartyrentals.com/, URL Contains Returns bool: false
String url = "https://classicpartyrentals.com/products/24681-gothic-silver-coffee-cup";
String contains = "http://classicpartyrentals.com/";
System.out.println("Returns bool: " + url.contains(contains));
}
}
Output:
Returns bool: false
Code is always doing what you ask it to do:
String url = "https://classicpartyrentals.com/products/24681-gothic-
but
String contains = "http://classicpartyrentals.com/";
https versus http!
So the real answer is: especially when you are a beginner, chances that your code uncovered "some Java bug" is relatively small (very close to zero in reality!)
There is a much higher chance that your assumptions are wrong. You either don't fully understand the methods you are calling, or there is a subtle flaw in your input data.
Finally: also work on your naming. contains isn't a very good name here; you better call it expectedUrl, or something alike!
In your Code Url "https://classicpartyrentals.com/products/24681-gothic-silver-coffee-cup" contains https
but your compare string "http://classicpartyrentals.com/" contain http so its not match and return false
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The problem seems to be in the increment, but I need it to decrease by 2. The "length" variable is for the length of a series of numbers
public int longMethodName()
{
int length = cardNumber.length();
longMethodName = 0
for(int i=length-1; i<0; i-2)
{
int cardNumberInt = Integer.parseInt(cardNumber.charAt(i));
int tempVar = cardNumberInt*2;
longMethodName = longMethodName + tempVar;
}
return longMethodName;
}
You need to change it to i=i-2 or i-=2 to decrement by 2.
You might be trying to emulate the i++/i-- syntax, which is simply shorthand for i = i+1 or i=i-1. However, that syntax only works for change by 1 (formally speaking ++ and -- are unary operators ), so i-2 won't work directly.
You also need to fix the other errors, as detailed in the other answer.
1.) longMethodName = 0 // Semicolon missing
2.) i-2, need to change to i = i-2
3.) Integer.parseInt(), cardNumber.charAt(i)returns char which is not allowed
You can also use i-=2 so you don't have to write i a second time ;-)
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I couldn't figure out why my code is printing forever. I tried a block (will show where I had it originally) but I want it to continue after printing the "help". My code goes as follows. I think it's the for loop... but I haven't touched much on it.
boolean yes = true;
while(yes) {
if(str1.equalsIgnoreCase("Exit")) {
System.exit(0);
} else if (str1.equalsIgnoreCase("Help")) {
for(int g = 0; g < 2; g++) {
System.out.println(" Accepted commands:\n exit\n help\n load [filename]\n students\n search [partial name]\n assignments\n grades\n student [student name]\n assignment [assignment name]\n");
}
//I added the break here and it did print out once but I did not want it to end the program. With the break I did not need the for statement.
} else if (str1.equalsIgnoreCase("Load")) {
}
The value of str1 is never changed inside the loop. Perhaps you are missing some statement that takes new input from the user.
First off
boolean yes = true;
while(yes) {
You are never setting yes to false
Secondly
if(str1.equalsIgnoreCase("Exit")) {
System.exit(0);
str1 is never set inside the loop, even to "Exit"
yes is set to true and you never changed it in the loop
read str1 inside the loop:
DataInputStream in = new DataInputStream(System.in);
str1=in.readLine();
while(true) {
str1=in.readLine();
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In this code, the user types in yes if they would like to play again
I have to use functions for this code, I cannot simply state while(again.equals("yes"));.
Part of code:
do{
System.out.print("Play Again? Yes/No: ");
String again=keyboard.nextLine();
boolean running=playAgain(again);
} while(running == true);
My question is why is }while(running==true); a syntax error? I declared the variable above it, shouldn't that allow it to run?
You need a "do" statement first, i.e. do { statements; } while (condition). Also
you don't need to save the return from playAgain() into a variable, you can call it directly from the while().
There are many Java tutorials out there, try the official Oracle ones from starters: The while and do-while Statements
Update
String again; // <== declared here because conditions inside
// while cannot see variables defined inside the do {} block
do {
System.out.print("Play Again? Yes/No: ");
again = keyboard.nextLine();
} while (playAgain(again));