I'm trying to parse this String
2014-04-04T14:28:38+02:00
It should be ISO 8601 format. But i can't parse it to a correct Date.
I've tried the following:
String example = "2014-04-04T14:28:38+02:00"
public final static SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssz")
Date tempDate = df.parse(example)
But I get always the message "unparseable Date"
I can not change the example because it's a value from a webservice.
Could it be there is a probleme with "+02:00" instead of "+0200" ?
Thanks a lot
java.time
The modern date-time API is based on ISO 8601 and thus, you do not need to use a parser (e.g. DateTimeFormatter) explicitly in order to parse the given date-time string as it is already in ISO 8601 format.
Demo:
import java.time.OffsetDateTime;
import java.util.Date;
public class Main {
public static void main(String args[]) {
OffsetDateTime odt = OffsetDateTime.parse("2014-04-04T14:28:38+02:00");
System.out.println(odt);
// In case you need java.util.Date
Date date = Date.from(odt.toInstant());
// ...
}
}
Output:
2014-04-04T14:28:38+02:00
Learn more about the the modern date-time API* from Trail: Date Time.
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
Starting from Java7, to handle +02:00, you can use the following format:
"yyyy-MM-dd'T'hh:mm:ssXXX"
This can be seen in the SimpleDateFormat documentation
The ISO8601 date format can be most easily parsed using Joda Time which can be use as a library.
It seems that a form of Joda Time got into Java 8 as JSR310 but I have not worked with it.
Related
In my Spring Boot project, I have this array of objects (List<Object> values)
["2021-06-13T08:50:04.707Z", 3197691, 1933]
The first element is a String and represents a timestamp with timezone.
I can get the first element like this:
String time = (String) values.get(0);
How can I convert it in date or time format in order to insert in a PostgreSQL table?
The given timestamp string conforms to the ISO 8601 standards.
The modern Date-Time API* is based on ISO 8601 and does not require using a DateTimeFormatter object explicitly as long as the Date-Time string conforms to the ISO 8601 standards.
Demo:
import java.time.OffsetDateTime;
public class Main {
public static void main(String[] args) {
OffsetDateTime odt = OffsetDateTime.parse("2021-06-13T08:50:04.707Z");
System.out.println(odt);
}
}
Output:
2021-06-13T08:50:04.707Z
Check this answer to learn how to use OffsetDateTime with JDBC.
Learn more about the modern Date-Time API from Trail: Date Time.
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
First thing you must understand the timestamp format, and for your timestamp format is
yyyy-MM-dd'T'hh:mm:ss.SSS'Z'
Don't forget to add 'T' and 'Z'
Then, to convert from string date to Date class you can use SimpleDateFormat class
String dateInString = "2021-06-13T08:50:04.707Z";
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSS'Z'");
Date date = dateFormat.parse(dateInString);
Then use the data object to insert to your query. Or if you are using JPA, simply just create the entity and put data object to the variable.
I have the following date: 2011-08-12T20:17:46.384Z. What format is this? I'm trying to parse it with Java 1.4 via DateFormat.getDateInstance().parse(dateStr) and I'm getting
java.text.ParseException: Unparseable date: "2011-08-12T20:17:46.384Z"
I think I should be using SimpleDateFormat for parsing, but I have to know the format string first. All I have for that so far is yyyy-MM-dd, because I don't know what the T means in this string--something time zone-related? This date string is coming from the lcmis:downloadedOn tag shown on Files CMIS download history media type.
The T is just a literal to separate the date from the time, and the Z means "zero hour offset" also known as "Zulu time" (UTC). If your strings always have a "Z" you can use:
SimpleDateFormat format = new SimpleDateFormat(
"yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.US);
format.setTimeZone(TimeZone.getTimeZone("UTC"));
Or using Joda Time, you can use ISODateTimeFormat.dateTime().
tl;dr
Standard ISO 8601 format is used by your input string.
Instant.parse ( "2011-08-12T20:17:46.384Z" )
ISO 8601
This format is defined by the sensible practical standard, ISO 8601.
The T separates the date portion from the time-of-day portion. The Z on the end means UTC (that is, an offset-from-UTC of zero hours-minutes-seconds). The Z is pronounced “Zulu”.
java.time
The old date-time classes bundled with the earliest versions of Java have proven to be poorly designed, confusing, and troublesome. Avoid them.
Instead, use the java.time framework built into Java 8 and later. The java.time classes supplant both the old date-time classes and the highly successful Joda-Time library.
The java.time classes use ISO 8601 by default when parsing/generating textual representations of date-time values.
The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds. That class can directly parse your input string without bothering to define a formatting pattern.
Instant instant = Instant.parse ( "2011-08-12T20:17:46.384Z" ) ;
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.* classes. Hibernate 5 & JPA 2.2 support java.time.
Where to obtain the java.time classes?
Java SE 8, Java SE 9, Java SE 10, Java SE 11, and later - Part of the standard Java API with a bundled implementation.
Java 9 brought some minor features and fixes.
Java SE 6 and Java SE 7
Most of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
Later versions of Android (26+) bundle implementations of the java.time classes.
For earlier Android (<26), a process known as API desugaring brings a subset of the java.time functionality not originally built into Android.
If the desugaring does not offer what you need, the ThreeTenABP project adapts ThreeTen-Backport (mentioned above) to Android. See How to use ThreeTenABP….
Not sure about the Java parsing, but that's ISO8601: http://en.wikipedia.org/wiki/ISO_8601
There are other ways to parse it rather than the first answer. To parse it:
(1) If you want to grab information about date and time, you can parse it to a ZonedDatetime(since Java 8) or Date(old) object:
// ZonedDateTime's default format requires a zone ID(like [Australia/Sydney]) in the end.
// Here, we provide a format which can parse the string correctly.
DateTimeFormatter dtf = DateTimeFormatter.ISO_DATE_TIME;
ZonedDateTime zdt = ZonedDateTime.parse("2011-08-12T20:17:46.384Z", dtf);
or
// 'T' is a literal.
// 'X' is ISO Zone Offset[like +01, -08]; For UTC, it is interpreted as 'Z'(Zero) literal.
String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX";
// since no built-in format, we provides pattern directly.
DateFormat df = new SimpleDateFormat(pattern);
Date myDate = df.parse("2011-08-12T20:17:46.384Z");
(2) If you don't care the date and time and just want to treat the information as a moment in nanoseconds, then you can use Instant:
// The ISO format without zone ID is Instant's default.
// There is no need to pass any format.
Instant ins = Instant.parse("2011-08-12T20:17:46.384Z");
java.time
You do not need DateTimeFormatter to parse the given date-time string.
Java SE 8 Date-Time API(java.time API or the modern Date-Time API) is based on ISO 8601 and does not require using a DateTimeFormatter object explicitly as long as the Date-Time string conforms to the ISO 8601 standards.
The Z in the string is the timezone designator for zero-timezone offset. It stands for Zulu and specifies the Etc/UTC timezone (which has the timezone offset of +00:00 hours).
The T in the string is just the Date-Time separator as per the ISO-8601 standards.
Demo:
import java.time.Instant;
import java.time.OffsetDateTime;
import java.time.ZonedDateTime;
public class Main {
public static void main(String[] args) {
String strDateTime = "2011-08-12T20:17:46.384Z";
Instant instant = Instant.parse(strDateTime);
OffsetDateTime odt = OffsetDateTime.parse(strDateTime);
ZonedDateTime zdt = ZonedDateTime.parse(strDateTime);
System.out.println(instant);
System.out.println(odt);
System.out.println(zdt);
}
}
Output:
2011-08-12T20:17:46.384Z
2011-08-12T20:17:46.384Z
2011-08-12T20:17:46.384Z
Learn more about java.time, the modern Date-Time API* from Trail: Date Time.
The legacy Date-time API
The legacy Date-time API (java.util Date-Time API and their formatting API, SimpleDateFormat) are outdated and error-prone. It is recommended to stop using them completely and switch to the modern Date-Time API*.
For the sake of completeness, I've written a solution to parse this Date-Time string using the legacy API.
Do not use 'Z' in the pattern with the Date-Time parsing/formatting API.
As already described above, Z (without quotes) is the timezone designator for zero-timezone offset whereas 'Z' is just a character literal and it does not hold any meaning. Use the format, y-M-d'T'H:m:s.SSSXXX. Check the documentation to learn more about these symbols.
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Locale;
public class Main {
public static void main(String[] args) throws ParseException {
String strDateTime = "2011-08-12T20:17:46.384Z";
SimpleDateFormat sdf = new SimpleDateFormat("y-M-d'T'H:m:s.SSSXXX", Locale.ENGLISH);
Date date = sdf.parse(strDateTime);
// ...
}
}
Note that a java.util.Date object is not a real Date-Time object like the modern Date-Time types; rather, it represents the number of milliseconds since the standard base time known as "the epoch", namely January 1, 1970, 00:00:00 GMT (or UTC). Since it does not hold any format and timezone information, it applies the format, EEE MMM dd HH:mm:ss z yyyy and the JVM's timezone to return the value of Date#toString derived from this milliseconds value. If you need to print the Date-Time in a different format and timezone, you will need to use a SimpleDateFormat with the desired format and the applicable timezone e.g.
sdf.setTimeZone(TimeZone.getTimeZone("Etc/UTC"));
String formatted = sdf.format(date);
System.out.println(formatted); // 2011-8-12T20:17:46.384Z
Joda Date-Time API
Quoted below is a notice at the Home Page of Joda-Time:
Note that from Java SE 8 onwards, users are asked to migrate to java.time (JSR-310) - a core part of the JDK which replaces this project.
Again, for the sake of completeness, I've written a solution to parse this Date-Time string using the Joda Date-Time API.
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
public class Main {
public static void main(String[] args) {
String dateTimeStr = "2011-08-12T20:17:46.384Z";
DateTimeFormatter dtf = DateTimeFormat.forPattern("y-M-d'T'H:m:s.SSSZ").withOffsetParsed();
DateTime dateTime = dtf.parseDateTime(dateTimeStr);
System.out.println(dateTime);
}
}
Output:
2011-08-12T20:17:46.384Z
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
If you guys are looking for a solution for Android, you can use the following code to get the epoch seconds from the timestamp string.
public static long timestampToEpochSeconds(String srcTimestamp) {
long epoch = 0;
try {
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.O) {
Instant instant = Instant.parse(srcTimestamp);
epoch = instant.getEpochSecond();
} else {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSSSS'Z'", Locale.getDefault());
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
Date date = sdf.parse(srcTimestamp);
if (date != null) {
epoch = date.getTime() / 1000;
}
}
} catch (Exception e) {
e.printStackTrace();
}
return epoch;
}
Sample input: 2019-10-15T05:51:31.537979Z
Sample output: 1571128673
In JavaScript
let isoDateTimeString = new Date().toISOString();
Description
Date/time format like "YYYY-MM-DDThh:mm:ss.SSSZ" is ISO 8601 date/time format.
Z represent UTC time zone. With java8+, you can simply use Instant.
public static void main(String[] args) {
String time = "2022-06-08T04:55:01.000Z";
System.out.println(Instant.parse(time).toEpochMilli());
}
You can use the following example.
String date = "2011-08-12T20:17:46.384Z";
String inputPattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'";
String outputPattern = "yyyy-MM-dd HH:mm:ss";
LocalDateTime inputDate = null;
String outputDate = null;
DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern(inputPattern, Locale.ENGLISH);
DateTimeFormatter outputFormatter = DateTimeFormatter.ofPattern(outputPattern, Locale.ENGLISH);
inputDate = LocalDateTime.parse(date, inputFormatter);
outputDate = outputFormatter.format(inputDate);
System.out.println("inputDate: " + inputDate);
System.out.println("outputDate: " + outputDate);
This technique translates java.util.Date to UTC format (or any other) and back again.
Define a class like so:
import java.util.Date;
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
public class UtcUtility {
public static DateTimeFormatter UTC = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").withZoneUTC();
public static Date parse(DateTimeFormatter dateTimeFormatter, String date) {
return dateTimeFormatter.parseDateTime(date).toDate();
}
public static String format(DateTimeFormatter dateTimeFormatter, Date date) {
return format(dateTimeFormatter, date.getTime());
}
private static String format(DateTimeFormatter dateTimeFormatter, long timeInMillis) {
DateTime dateTime = new DateTime(timeInMillis);
String formattedString = dateTimeFormatter.print(dateTime);
return formattedString;
}
}
Then use it like this:
Date date = format(UTC, "2020-04-19T00:30:07.000Z")
or
String date = parse(UTC, new Date())
You can also define other date formats if you require (not just UTC)
#John-Skeet gave me the clue to fix my own issue around this. As a younger programmer this small issue is easy to miss and hard to diagnose. So Im sharing it in the hopes it will help someone.
My issue was that I wanted to parse the following string contraining a time stamp from a JSON I have no influence over and put it in more useful variables. But I kept getting errors.
So given the following (pay attention to the string parameter inside ofPattern();
String str = "20190927T182730.000Z"
LocalDateTime fin;
fin = LocalDateTime.parse( str, DateTimeFormatter.ofPattern("yyyyMMdd'T'HHmmss.SSSZ") );
Error:
Exception in thread "main" java.time.format.DateTimeParseException: Text
'20190927T182730.000Z' could not be parsed at index 19
The problem? The Z at the end of the Pattern needs to be wrapped in 'Z' just like the 'T' is. Change
"yyyyMMdd'T'HHmmss.SSSZ" to "yyyyMMdd'T'HHmmss.SSS'Z'" and it works.
Removing the Z from the pattern alltogether also led to errors.
Frankly, I'd expect a Java class to have anticipated this.
What is the correct form for parse this date?: 2015-05-29T00:00:00+02:00
DateFormat format = new SimpleDateFormat("yyyyy-mm-dd hh:mm:ss");
Date data = format.parse(dataValue);
Try with
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX");
Notice that
MM represents months, while mm represents minutes.
if you want to have 24h format use HH, hh is for 12h format
XXX represents time zone in format like -08:00
to add literal like T in format you need to surround it with single quotes ' like 'T'
java.time
The legacy date-time API (java.util date-time types and their formatting API, SimpleDateFormat) is outdated and error-prone. It is recommended to stop using it completely and switch to java.time, the modern date-time API*.
Since the modern date-time API is based on ISO 8601 standards, you are not required to use a DateTimeFormatter object explicitly to parse a date-time string conforming to the ISO 8601 standards. Your date-time string contains timezone offset string (+02:00) and therefore, the most appropriate type to be used to parse it is OffsetDateTime.
Demo:
import java.time.OffsetDateTime;
public class Main {
public static void main(String args[]) {
OffsetDateTime odt = OffsetDateTime.parse("2015-05-29T00:00:00+02:00");
System.out.println(odt);
}
}
Output:
2015-05-29T00:00+02:00
For whatsoever reason, if you need an instance of java.util.Date from this object of OffsetDateTime, you can do so as follows:
Date date = Date.from(odt.toInstant());
Learn more about the the modern date-time API* from Trail: Date Time.
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
How can I parse date time like this in Android
2014-05-19T07:16:29.63+00:00
? I've tried using "yyyy-MM-dd'T'HH:mm:ss.SSZZZZZ" according to SimpleDateFormatter, but seems the result of ZZZZZ is the same as Z.
java.time
The legacy date-time API (java.util date-time types and their formatting API, SimpleDateFormat) is outdated and error-prone. It is recommended to stop using it completely and switch to java.time, the modern date-time API*.
Also, check the following notice at the Home Page of Joda-Time;
Joda-Time is the de facto standard date and time library for Java
prior to Java SE 8. Users are now asked to migrate to java.time
(JSR-310).
Solution using the modern API:
The modern date-time API is based on ISO 8601 and does not require you to use a DateTimeFormatter object explicitly as long as the date-time string conforms to the ISO 8601 standards.
import java.time.OffsetDateTime;
public class Main {
public static void main(String[] args) {
OffsetDateTime odt = OffsetDateTime.parse("2014-05-19T07:16:29.63+00:00");
System.out.println(odt);
}
}
Output:
2014-05-19T07:16:29.630Z
The Z in the output is the timezone designator for zero-timezone offset. It stands for Zulu and specifies the Etc/UTC timezone (which has the timezone offset of +00:00 hours).
For any reason, if you need to convert this object of OffsetDateTime to an object of java.util.Date, you can do so as follows:
Date date = Date.from(odt.toInstant());
Learn more about the the modern date-time API* from Trail: Date Time.
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
Z/ZZ/ZZZ: -0800
ZZZZ: GMT-08:00
ZZZZZ: -08:00
this is the difference.
Try X for timezone, according to javadocs X is used for parsing given format. Note that for parsing the number of pattern letters does not matter.
Solved this problem by using joda-time
I have the following date: 2011-08-12T20:17:46.384Z. What format is this? I'm trying to parse it with Java 1.4 via DateFormat.getDateInstance().parse(dateStr) and I'm getting
java.text.ParseException: Unparseable date: "2011-08-12T20:17:46.384Z"
I think I should be using SimpleDateFormat for parsing, but I have to know the format string first. All I have for that so far is yyyy-MM-dd, because I don't know what the T means in this string--something time zone-related? This date string is coming from the lcmis:downloadedOn tag shown on Files CMIS download history media type.
The T is just a literal to separate the date from the time, and the Z means "zero hour offset" also known as "Zulu time" (UTC). If your strings always have a "Z" you can use:
SimpleDateFormat format = new SimpleDateFormat(
"yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.US);
format.setTimeZone(TimeZone.getTimeZone("UTC"));
Or using Joda Time, you can use ISODateTimeFormat.dateTime().
tl;dr
Standard ISO 8601 format is used by your input string.
Instant.parse ( "2011-08-12T20:17:46.384Z" )
ISO 8601
This format is defined by the sensible practical standard, ISO 8601.
The T separates the date portion from the time-of-day portion. The Z on the end means UTC (that is, an offset-from-UTC of zero hours-minutes-seconds). The Z is pronounced “Zulu”.
java.time
The old date-time classes bundled with the earliest versions of Java have proven to be poorly designed, confusing, and troublesome. Avoid them.
Instead, use the java.time framework built into Java 8 and later. The java.time classes supplant both the old date-time classes and the highly successful Joda-Time library.
The java.time classes use ISO 8601 by default when parsing/generating textual representations of date-time values.
The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds. That class can directly parse your input string without bothering to define a formatting pattern.
Instant instant = Instant.parse ( "2011-08-12T20:17:46.384Z" ) ;
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.* classes. Hibernate 5 & JPA 2.2 support java.time.
Where to obtain the java.time classes?
Java SE 8, Java SE 9, Java SE 10, Java SE 11, and later - Part of the standard Java API with a bundled implementation.
Java 9 brought some minor features and fixes.
Java SE 6 and Java SE 7
Most of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
Later versions of Android (26+) bundle implementations of the java.time classes.
For earlier Android (<26), a process known as API desugaring brings a subset of the java.time functionality not originally built into Android.
If the desugaring does not offer what you need, the ThreeTenABP project adapts ThreeTen-Backport (mentioned above) to Android. See How to use ThreeTenABP….
Not sure about the Java parsing, but that's ISO8601: http://en.wikipedia.org/wiki/ISO_8601
There are other ways to parse it rather than the first answer. To parse it:
(1) If you want to grab information about date and time, you can parse it to a ZonedDatetime(since Java 8) or Date(old) object:
// ZonedDateTime's default format requires a zone ID(like [Australia/Sydney]) in the end.
// Here, we provide a format which can parse the string correctly.
DateTimeFormatter dtf = DateTimeFormatter.ISO_DATE_TIME;
ZonedDateTime zdt = ZonedDateTime.parse("2011-08-12T20:17:46.384Z", dtf);
or
// 'T' is a literal.
// 'X' is ISO Zone Offset[like +01, -08]; For UTC, it is interpreted as 'Z'(Zero) literal.
String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSX";
// since no built-in format, we provides pattern directly.
DateFormat df = new SimpleDateFormat(pattern);
Date myDate = df.parse("2011-08-12T20:17:46.384Z");
(2) If you don't care the date and time and just want to treat the information as a moment in nanoseconds, then you can use Instant:
// The ISO format without zone ID is Instant's default.
// There is no need to pass any format.
Instant ins = Instant.parse("2011-08-12T20:17:46.384Z");
java.time
You do not need DateTimeFormatter to parse the given date-time string.
Java SE 8 Date-Time API(java.time API or the modern Date-Time API) is based on ISO 8601 and does not require using a DateTimeFormatter object explicitly as long as the Date-Time string conforms to the ISO 8601 standards.
The Z in the string is the timezone designator for zero-timezone offset. It stands for Zulu and specifies the Etc/UTC timezone (which has the timezone offset of +00:00 hours).
The T in the string is just the Date-Time separator as per the ISO-8601 standards.
Demo:
import java.time.Instant;
import java.time.OffsetDateTime;
import java.time.ZonedDateTime;
public class Main {
public static void main(String[] args) {
String strDateTime = "2011-08-12T20:17:46.384Z";
Instant instant = Instant.parse(strDateTime);
OffsetDateTime odt = OffsetDateTime.parse(strDateTime);
ZonedDateTime zdt = ZonedDateTime.parse(strDateTime);
System.out.println(instant);
System.out.println(odt);
System.out.println(zdt);
}
}
Output:
2011-08-12T20:17:46.384Z
2011-08-12T20:17:46.384Z
2011-08-12T20:17:46.384Z
Learn more about java.time, the modern Date-Time API* from Trail: Date Time.
The legacy Date-time API
The legacy Date-time API (java.util Date-Time API and their formatting API, SimpleDateFormat) are outdated and error-prone. It is recommended to stop using them completely and switch to the modern Date-Time API*.
For the sake of completeness, I've written a solution to parse this Date-Time string using the legacy API.
Do not use 'Z' in the pattern with the Date-Time parsing/formatting API.
As already described above, Z (without quotes) is the timezone designator for zero-timezone offset whereas 'Z' is just a character literal and it does not hold any meaning. Use the format, y-M-d'T'H:m:s.SSSXXX. Check the documentation to learn more about these symbols.
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Locale;
public class Main {
public static void main(String[] args) throws ParseException {
String strDateTime = "2011-08-12T20:17:46.384Z";
SimpleDateFormat sdf = new SimpleDateFormat("y-M-d'T'H:m:s.SSSXXX", Locale.ENGLISH);
Date date = sdf.parse(strDateTime);
// ...
}
}
Note that a java.util.Date object is not a real Date-Time object like the modern Date-Time types; rather, it represents the number of milliseconds since the standard base time known as "the epoch", namely January 1, 1970, 00:00:00 GMT (or UTC). Since it does not hold any format and timezone information, it applies the format, EEE MMM dd HH:mm:ss z yyyy and the JVM's timezone to return the value of Date#toString derived from this milliseconds value. If you need to print the Date-Time in a different format and timezone, you will need to use a SimpleDateFormat with the desired format and the applicable timezone e.g.
sdf.setTimeZone(TimeZone.getTimeZone("Etc/UTC"));
String formatted = sdf.format(date);
System.out.println(formatted); // 2011-8-12T20:17:46.384Z
Joda Date-Time API
Quoted below is a notice at the Home Page of Joda-Time:
Note that from Java SE 8 onwards, users are asked to migrate to java.time (JSR-310) - a core part of the JDK which replaces this project.
Again, for the sake of completeness, I've written a solution to parse this Date-Time string using the Joda Date-Time API.
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
public class Main {
public static void main(String[] args) {
String dateTimeStr = "2011-08-12T20:17:46.384Z";
DateTimeFormatter dtf = DateTimeFormat.forPattern("y-M-d'T'H:m:s.SSSZ").withOffsetParsed();
DateTime dateTime = dtf.parseDateTime(dateTimeStr);
System.out.println(dateTime);
}
}
Output:
2011-08-12T20:17:46.384Z
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
If you guys are looking for a solution for Android, you can use the following code to get the epoch seconds from the timestamp string.
public static long timestampToEpochSeconds(String srcTimestamp) {
long epoch = 0;
try {
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.O) {
Instant instant = Instant.parse(srcTimestamp);
epoch = instant.getEpochSecond();
} else {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSSSS'Z'", Locale.getDefault());
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
Date date = sdf.parse(srcTimestamp);
if (date != null) {
epoch = date.getTime() / 1000;
}
}
} catch (Exception e) {
e.printStackTrace();
}
return epoch;
}
Sample input: 2019-10-15T05:51:31.537979Z
Sample output: 1571128673
In JavaScript
let isoDateTimeString = new Date().toISOString();
Description
Date/time format like "YYYY-MM-DDThh:mm:ss.SSSZ" is ISO 8601 date/time format.
Z represent UTC time zone. With java8+, you can simply use Instant.
public static void main(String[] args) {
String time = "2022-06-08T04:55:01.000Z";
System.out.println(Instant.parse(time).toEpochMilli());
}
You can use the following example.
String date = "2011-08-12T20:17:46.384Z";
String inputPattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'";
String outputPattern = "yyyy-MM-dd HH:mm:ss";
LocalDateTime inputDate = null;
String outputDate = null;
DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern(inputPattern, Locale.ENGLISH);
DateTimeFormatter outputFormatter = DateTimeFormatter.ofPattern(outputPattern, Locale.ENGLISH);
inputDate = LocalDateTime.parse(date, inputFormatter);
outputDate = outputFormatter.format(inputDate);
System.out.println("inputDate: " + inputDate);
System.out.println("outputDate: " + outputDate);
This technique translates java.util.Date to UTC format (or any other) and back again.
Define a class like so:
import java.util.Date;
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
public class UtcUtility {
public static DateTimeFormatter UTC = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").withZoneUTC();
public static Date parse(DateTimeFormatter dateTimeFormatter, String date) {
return dateTimeFormatter.parseDateTime(date).toDate();
}
public static String format(DateTimeFormatter dateTimeFormatter, Date date) {
return format(dateTimeFormatter, date.getTime());
}
private static String format(DateTimeFormatter dateTimeFormatter, long timeInMillis) {
DateTime dateTime = new DateTime(timeInMillis);
String formattedString = dateTimeFormatter.print(dateTime);
return formattedString;
}
}
Then use it like this:
Date date = format(UTC, "2020-04-19T00:30:07.000Z")
or
String date = parse(UTC, new Date())
You can also define other date formats if you require (not just UTC)
#John-Skeet gave me the clue to fix my own issue around this. As a younger programmer this small issue is easy to miss and hard to diagnose. So Im sharing it in the hopes it will help someone.
My issue was that I wanted to parse the following string contraining a time stamp from a JSON I have no influence over and put it in more useful variables. But I kept getting errors.
So given the following (pay attention to the string parameter inside ofPattern();
String str = "20190927T182730.000Z"
LocalDateTime fin;
fin = LocalDateTime.parse( str, DateTimeFormatter.ofPattern("yyyyMMdd'T'HHmmss.SSSZ") );
Error:
Exception in thread "main" java.time.format.DateTimeParseException: Text
'20190927T182730.000Z' could not be parsed at index 19
The problem? The Z at the end of the Pattern needs to be wrapped in 'Z' just like the 'T' is. Change
"yyyyMMdd'T'HHmmss.SSSZ" to "yyyyMMdd'T'HHmmss.SSS'Z'" and it works.
Removing the Z from the pattern alltogether also led to errors.
Frankly, I'd expect a Java class to have anticipated this.