In my Android application I use http link for get JSON response from server, now they changed to https. My code is return No peer certificate exception.
What the things need to get response from server using https in Android. This is the code I used for get response from server for http.
public static DefaultHttpClient httpClient;
public static ResponseHandler<String> resHandler;
public static List<NameValuePair> nameValuePairs;
public static HttpPost httpPost;
....
httpClient = new DefaultHttpClient();
resHandler = new BasicResponseHandler();
httpPost = new HttpPost("https://www.xxx.com/.../user/renting");
nameValuePairs = new ArrayList<NameValuePair>(6);
nameValuePairs.add(new BasicNameValuePair("parking_spot_id".trim(),
spotID));
....
for (int i = 0; i < array.length; i++) {
nameValuePairs.add(new BasicNameValuePair("date[]", array[i]));
}
try {
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
jsonResponse = httpClient.execute(httpPost, resHandler);
Log.e("rent by day", jsonResponse);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
The above code working well for using http.
1) What are the things I need to get for https.
2) What are the changes in the code.
Please help me.
Related
I have following situation:
Sending http post (post data contains json string) request to my remote server.
Getting http post response from my server in json: {"result":true}
Disconnecting all internet connections in my tablet.
Repeating post request described in step 1.
Getting the same cached "response" - {"result":true} which I didn't expected to get... I don't want that my http client would cache any data. I expect to get null or something like this.
How to prevent http client caching data?
My service handler looks like this:
public String makeServiceCall(String url, int method,
List<NameValuePair> params, String requestAction) {
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpEntity httpEntity = null;
HttpResponse httpResponse = null;
// Checking http request method type
if (method == POST) {
HttpPost httpPost = new HttpPost(url);
// adding post params
if (params != null) {
httpPost.setEntity(new UrlEncodedFormEntity(params));
}
httpResponse = httpClient.execute(httpPost);
}
else if (method == GET) {
// appending params to url
if (params != null) {
String paramString = URLEncodedUtils
.format(params, "utf-8");
url += "?" + paramString;
}
HttpGet httpGet = new HttpGet(url);
httpResponse = httpClient.execute(httpGet);
}
httpEntity = httpResponse.getEntity();
response = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
// Toast.makeText(Globals.getContext(), "check your connection", Toast.LENGTH_SHORT).show();
}
return response;
}
I just noticed that response is a member variable. Why do you need a member variable to return this result. You're probably returning the same result on the 2nd try. Re-throw the exception that you catch instead and let the caller handle it.
I have a post request working successfully in Postman, but when I make the same request from my Android app, I get "Internal Server Error". Do you see any difference between these two requests?
Postman
Android App
class MakeRequest extends AsyncTask<Void, Void, Void> {
#Override
protected Void doInBackground(Void... voids) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("https://sample.com/test");
httppost.setHeader("Content-type", "application/json");
httppost.setHeader("Authorization", getB64Auth("username", "password"));
try {
JSONObject identity = new JSONObject();
identity.put("type", "number");
identity.put("endpoint", "12345");
JSONObject options = new JSONObject();
options.put("num", "12345");
JSONObject body = new JSONObject();
body.put("identity", identity);
body.put("method", "test");
body.put("options", options);
StringEntity se = new StringEntity(body.toString());
httppost.setEntity(se);
} catch (IOException e) {
Log.d("IOException", e.toString());
} catch (JSONException e) {
Log.d("JSONException", e.toString());
}
try {
ResponseHandler handler = new BasicResponseHandler();
HttpResponse response = httpclient.execute(httppost);
Log.d("HttpResponse", handler.handleResponse(response).toString());
} catch (ClientProtocolException e) {
Log.d("ClientProtocolException", e.toString());
} catch (IOException e) {
Log.d("IOException", e.toString());
}
return null;
}
private String getB64Auth (String key, String secret) {
String source=key+":"+secret;
String ret="Basic "+Base64.encodeToString(source.getBytes(),Base64.URL_SAFE|Base64.NO_WRAP);
return ret;
}
}
Other thoughts/hints:
Authentication is working properly in the java code. I tried with wrong username & password, and I got "Invalid Authorization"
The JSON string is exactly the same as the one in postman. I printed body.toString(), copied and pasted into Postman, and the request worked fine in Postman.
you should change httppost.setHeader("Content-type", "application/json"); to httppost.setHeader("Content-type", "application/form-data"); or httppost.setHeader("Content-type", "application/x-www-form-urlencoded");
this should solve your issue.
I am working on a login service that logs a user in then after a successful login it posts again to a new script with a cookie that was given on the login to get more info. here is my login post:
#Override
protected Boolean doInBackground(Void... params) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://testsite.com/login");
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("userid", "john"));
nameValuePairs.add(new BasicNameValuePair("password", "test"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
String TAG = "com.imtins.worryfree";
String responseAsText = EntityUtils.toString(response.getEntity());
Log.d(TAG, "Response from server: " + responseAsText.toString());
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
Now from what ive read if I use the same hpptClient without starting a new one, when i do another post it will use the cookie that i recieved? where could I add a second post in my example or how would it look. Just getting started with android/Java so this is a little confusing for me.
Thanks.
You can use an HttpContext + CookieStore to keep track of cookie state between requests. I think something like this would work for you (untested):
#Override
protected Boolean doInBackground(Void... params) {
HttpClient httpclient = new DefaultHttpClient();
CookieStore cookieStore = new BasicCookieStore();
HttpContext localContext = new BasicHttpContext();
localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);
HttpPost httppost = new HttpPost("http://testsite.com/login");
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("userid", "john"));
nameValuePairs.add(new BasicNameValuePair("password", "test"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost, localContext);
String TAG = "com.imtins.worryfree";
String responseAsText = EntityUtils.toString(response.getEntity());
Log.d(TAG, "Response from server: " + responseAsText.toString());
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
And for your 2nd request, reuse the localContext variable:
// replace XXX below with correct URL
httppost = new HttpPost("http://testsite.com/XXXXXX");
try {
// set entities here ...
HttpResponse response = httpclient.execute(httppost, localContext);
String TAG = "com.imtins.worryfree";
String responseAsText = EntityUtils.toString(response.getEntity());
Log.d(TAG, "Response from server: " + responseAsText.toString());
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
I am using Play and Faye on my Server. Play is used for API calls, while Faye is used for communication with the clients.
So, I have this method in the server:
public static Result broadcast(String channel, String message)
{
try
{
FayeClient faye = new FayeClient("localhost");
int code = faye.send(channel, message);
// print the code (prints 200).
return ok("Hello"); <------------ This is what we care about.
}
catch(Exception e)
{
return ok("false");
}
}
this is the code on the client, which is an android phone.
(it's the HTTP post method, which sends something to the server and gets a response back
The problem is, I can't print the message of the response.
public static String post(String url, List<BasicNameValuePair> params)
{
HttpClient httpclient = new DefaultHttpClient();
String result = "";
// Prepare a request object
HttpPost httpPost;
httpPost = new HttpPost(url);
httpPost.setHeader("Content-type", "application/json");
httpPost.setHeader("Accept", "application/json");
JSONObject obj = new JSONObject();
try
{
for (NameValuePair pair : params)
obj.put(pair.getName(), pair.getValue());
}
catch (JSONException e)
{
return e.getMessage();
}
// Add your data
try
{
httpPost.setEntity(new StringEntity(obj.toString(), "UTF-8"));
}
catch (UnsupportedEncodingException e)
{
return e.getMessage();
}
HttpResponse httpResponse;
try
{
httpResponse = httpclient.execute(httpPost);
// Get hold of the response entity
HttpEntity entity = httpResponse.getEntity();
String str = EntityUtils.toString(entity);
Log.e("RestClient", "result = \"" + str + "\""); // hello should be printed here??
}
catch(Exception e)
{
// ...
}
The problem is that in logcat, what is printed is [result = ""]. Am I doing something wrong?
Thank you.
Use a tool such as Fiddler and see what the HTTP response contains.
I need a simple code example of sending http post request with post parameters that I get from form inputs.
I have found Apache HTTPClient, it has very reach API and lots of sophisticated examples, but I couldn't find a simple example of sending http post request with input parameters and getting text response.
Update: I'm interested in Apache HTTPClient v.4.x, as 3.x is deprecated.
Here's the sample code for Http POST, using Apache HTTPClient API.
import java.io.InputStream;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.methods.PostMethod;
public class PostExample {
public static void main(String[] args){
String url = "http://www.google.com";
InputStream in = null;
try {
HttpClient client = new HttpClient();
PostMethod method = new PostMethod(url);
//Add any parameter if u want to send it with Post req.
method.addParameter("p", "apple");
int statusCode = client.executeMethod(method);
if (statusCode != -1) {
in = method.getResponseBodyAsStream();
}
System.out.println(in);
} catch (Exception e) {
e.printStackTrace();
}
}
}
I pulled this code from an Android project by Andrew Gertig that I have used in my application. It allows you to do an HTTPost. If I had time, I would create an POJO example, but hopefully, you can dissect the code and find what you need.
Arshak
https://github.com/AndrewGertig/RubyDroid/blob/master/src/com/gertig/rubydroid/AddEventView.java
private void postEvents()
{
DefaultHttpClient client = new DefaultHttpClient();
/** FOR LOCAL DEV HttpPost post = new HttpPost("http://192.168.0.186:3000/events"); //works with and without "/create" on the end */
HttpPost post = new HttpPost("http://cold-leaf-59.heroku.com/myevents");
JSONObject holder = new JSONObject();
JSONObject eventObj = new JSONObject();
Double budgetVal = 99.9;
budgetVal = Double.parseDouble(eventBudgetView.getText().toString());
try {
eventObj.put("budget", budgetVal);
eventObj.put("name", eventNameView.getText().toString());
holder.put("myevent", eventObj);
Log.e("Event JSON", "Event JSON = "+ holder.toString());
StringEntity se = new StringEntity(holder.toString());
post.setEntity(se);
post.setHeader("Content-Type","application/json");
} catch (UnsupportedEncodingException e) {
Log.e("Error",""+e);
e.printStackTrace();
} catch (JSONException js) {
js.printStackTrace();
}
HttpResponse response = null;
try {
response = client.execute(post);
} catch (ClientProtocolException e) {
e.printStackTrace();
Log.e("ClientProtocol",""+e);
} catch (IOException e) {
e.printStackTrace();
Log.e("IO",""+e);
}
HttpEntity entity = response.getEntity();
if (entity != null) {
try {
entity.consumeContent();
} catch (IOException e) {
Log.e("IO E",""+e);
e.printStackTrace();
}
}
Toast.makeText(this, "Your post was successfully uploaded", Toast.LENGTH_LONG).show();
}
HTTP POST request example using Apache HttpClient v.4.x
HttpClient httpClient = HttpClients.createDefault();
HttpPost httpPost = new HttpPost(url);
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.addTextBody("param1", param1Value, ContentType.TEXT_PLAIN);
builder.addTextBody("param2", param2Value, ContentType.TEXT_PLAIN);
HttpEntity multipart = builder.build();
httpPost.setEntity(multipart);
HttpResponse response = httpClient.execute(httpMethod);
http://httpunit.sourceforge.net/doc/cookbook.html
use PostMethodWebRequest and setParameter method
shows a very simple exapmle where you do post from Html page, servlet processes it and sends a text response..
http://java.sun.com/developer/onlineTraining/Programming/BasicJava1/servlet.html